JCheckBox and TableCellRenderer

Question

I'm using a boolean value as a column within a JTable. I want to change the color of a JCheckBox from black to red in the column based on a test.
I created a class to extend JCheckBox which implements TableCellRenderer. When the JTable is displayed, the checkbox is there, but you can't see the check in the box, just a square until you press the mouse key on the checkbox, then either the checked or unchecked
condition can be seen.
Here's the setup of the JTable:
TableName.setDefaultRenderer(Boolean.class,
new gridTableCellRenderer(DisplayData));
If I comment out the line above, the checkbox appears correctly showing the checked or unchecked condition without depressing the mousebutton.
Here's the class itself:
package NewPackage;
import javax.swing.*;
import javax.swing.table.*;
import java.awt.*;
import java.util.*;
class gridTableCellRenderer extends JCheckBox implements TableCellRenderer {
private Vector DisplayData = null;
public gridTableCellRenderer( Vector DisplayData ) {
super();
// setOpaque(true);
this.DisplayData = DisplayData;
public Component getTableCellRendererComponent( JTable table,
Object value, boolean isSelected,
boolean hasFocus, int row, int column ) {
Display record = (Display) DisplayData.get(row);
if ( record.getItemID() == 0 ) {
switch( column ) {
case 0:
// setBackground(Color.red);
// setForeground(Color.black);
// setEnabled(false);
break;
default:
break;
} /* ...end of switch statement... */
} /* ...end of if ( record.getItemID() == 0... */
else {
switch( column ) {
case 0:
// setBackground(Color.lightGray);
// setForeground(Color.black);
// setEnabled(true);
break;
default:
break;
} /* ...end of switch statement... */
} /* ...end of else statement... */
return this;
} /* ...end of method getTableCellRendererComponent()... */
} /* ...end of class declaration gridTableCellRenderer... */
As you can see, I've commented out all of the logic in an effort to try to find out what was causing the problem. As I said before, the only way I can get the checkboxes to appear correctly is commenting out the line:
TableName.setDefaultRenderer(Boolean.class,
new gridTableCellRenderer(DisplayData));
Thanks in advance....

Answer 1

import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import javax.swing.table.*;
public class Test extends JFrame {
    public Test() {
     setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
     Container content = getContentPane();
     String[] head = {"Boolean","String","Boolean"};
     Object[][] data  = {{new Boolean(true), "Hello", new Boolean(false)},
                   {new Boolean(true), "There", new Boolean(true)},
                   {new Boolean(false), "Hello", new Boolean(false)},
                   {new Boolean(true), "There", new Boolean(false)}};
     JTable jt = new JTable(new MyModel(data, head));
     jt.setDefaultRenderer(Boolean.class, new MyRenderer());
     content.add(jt, BorderLayout.CENTER);
     setSize(200,200);
     show();
    public static void main(String[] arghs) { new Test(); }
class MyModel extends DefaultTableModel {
    public MyModel(Object[][] Data, Object[] Head) { super(Data, Head); }
    public Class getColumnClass(int col) {
     switch (col) {
         case 0:
         case 2: return Boolean.class;
         default: return Object.class;
class MyRenderer extends JCheckBox implements TableCellRenderer {
    public Component getTableCellRendererComponent(JTable table,
                   Object value, boolean isSelected,
                   boolean hasFocus, int row, int column ) {
     setSelected(((Boolean)value).booleanValue());
     if (((String)table.getValueAt(row, 1)).equals("Hello")) {
         setBackground(Color.red);
     } else {
         setBackground(Color.pink);
     return this;
}