Join with a "built" field

Have a situation where I want to join two views one of which contains a column containing the entire key I want to join on and the second view has multiple columns that could be concatinated to to make the coluimn from the first view.
example: view1 columnx = trnx_8123_01
view2 columna = trnx, columnb = 8123, columnc = 01
What would be the syntax to do the join?
Further, suppose view2 could not always be depended on to have a value in columnc, but rather would sometimes need to have the value of to be used as columnc interpreted from the value of another column in view2
example: view1 columnx = trnx_8123_01
view2 columna = trnx, columnb = 8123, columnc = ' ' columnd='CCH' where CCH could be interpreted as meaning columnc should be interpreted as having value '01', but if the value was 'AAH' columnc should be interpreted as having value '02'
What would the query look like then? Is it possible to build the join field based on the content of another field?
Thanks much for any help,

well you just need to build up a composite value from the values at hand:
select *
from view1 v1
join view2 v2 on v1.columnx = v2.columna||'_'||
                                v2.columnb||'_'||
                                nvl(v2.columnc,case v2.columnd
                                               when 'CCH' then '01'
                                               when 'AAH' then '02'
                                               end)

Similar Messages

Working/Join with Two Reports field

Hey Folks,
I have read couple of post and kind of confused. I have two reports and each have their column total at the bottom(Sum).
Now on my first report i have to add my first report col1_total+second report col1_total and get my grand total.
SO, my question is how can add or call or join that second report field to my first report field and get my grand total?
I have read about Data Link Object but i wasnt sure about it. So, please give me some direction/advice. That would be greate.
Thank

Thankx but i never used two query to gether.
so basically, you want me to put second query and join it to gether...or...can you explain me little bit. Can you give me small step where i can get closer where you mention to use the same query.
Thanx

Replacing a inner join with for all entries

Hi Team,
   In a already developed program I am replacing a inner join with select query follow up with for-all-entris and passing the data to final internal table but in both the case the result should be same then only my replacement will be correct. But my no records in both cases differs. This happening because when i am selecting data from first data base table is 32 lines. then I am doing fo-all-entries moving all the duplicate entries then the no records are four. but in final internal table i am looping the first internal table. So in final internal table the no of records are 32. But in inner join query the records are 16.So please let me know how resolve this issue?
Thanks and REgards
Deepa

Hi Thomas,
Thanks for ur suggestion.
The solved that in below.
In select query I did not change anything The way I had written the code was correct.
I think many of us know how to write that how to make the performance better in that way.
I made the change when I transfered the to final internal table.
The original Inner join code:
select a~field1 a~field2 a~field3 b~field2 b~field3 b~field4
           from dbtab1 as a inner join dbtab2 as b
          on a~field1 = b~field1 into it_final where
          a~field1 in s_field1. [Field1 in both the table are key field]
Before code:
Sort itab1 by key-fields.
sort itab2 by keyfields.
loop at itab1 into wa1.
move: wa1-field1 to wa_final-field1,
           wa1-field2 to wa_final-field2,
           wa1-field3 to wa_final-field3.
read table itab2 into wa2 witk key field1 = wa1-field1 binary search.
if sy-subrc = 0.
move : wa2-field2 to wa_final-field4,
             wa2-field3 to wa_final-field5,
             wa2-field4 to wa_final-field6.
append wa_final to it_final.
endif.
Clear : wa1, wa2, wa_final.
endloop.
In this case if the one key fieild value is not present there in second internal table but its there in first internal table still it will read that row with 2nd internal values having zeroes. Normally what does not happen in inner join case if the key field value will same in both the case ,then that will fetch only those rows.
Changed Code
loop at itab1 into wa1.
read table itab2 into wa2 witk key field1 = wa1-field1 binary search.
if sy-subrc = 0.
move: wa1-field1 to wa_final-field1,
           wa1-field2 to wa_final-field2,
           wa1-field3 to wa_final-field3.
move : wa2-field2 to wa_final-field4,
             wa2-field3 to wa_final-field5,
             wa2-field4 to wa_final-field6.
append wa_final to it_final.
endif.
Clear : wa1, wa2, wa_final.
endloop.
In this case the values will read to final internal table if both key field matches.
With Regards
Deepa

Outer Join with an 'OR'

I have a very complicated query to construct that requires the use of 'AND', 'OR', and Outer Joins. Oracle's 9i documentation says you can't use an outer join with an 'OR'.
Can you suggest how I may return the correct records under the following conditions. There are 3 tables to join. Table A, Table B, and Table C. Tables A & B join with an = to common fields. The problem is with Table C.
The way the application was designed, it has to track a parent and child relationship. As such, the field to relate may exist in 1 of 2 fields. Let's see if I can draw it out for you.
Table A - Record 1
(ID = 1)
Table B - Record 1
(ID =1 [this relates to Table A.ID]
PID = 12345
CID = 67899
Site = A)
Table C - Record 1
(PID = 12345 [this relates to Table B.PID]
CID = 67899
Site = A)
Table C - Record 2
(PID = 67899 [This relates to Table B.CID]
CID = 12345
Site = A)
Now, I need to relate Table A to Table B where A.ID = B.ID AND
((B.PID = C.PID AND B.CID = C.CID)
OR
(B.CID = C.PID AND B.PID = C.CID))
AND
B.SITE = C.SITE
There may or may NOT be related records in Table C. That's the problem. This is where I need the outer join to get the all the records of the 1st two joins and only those that apply from the last join.
Your help will be greatly appreciated.

I'd create two queries, a join from b to c in each of those manners and then UNION ALL the results together.
drop table junk_a;
create table junk_a (
id number );
drop table junk_b;
create table junk_b (
id number,
pid number,
cid number,
site varchar2(80) );
drop table junk_c;
create table junk_c (
pid number,
cid number,
site varchar2(80) );
insert into junk_a values (1);
insert into junk_b values (1, 12345, 67899, 'A');
insert into junk_c values (12345, 67899, 'A');
insert into junk_c values (67899, 12345, 'A');
commit;
SELECT b.*,
       c.site AS site_c
FROM junk_b b,
       junk_c c
WHERE c.pid(+) = b.pid
   AND c.cid(+) = b.cid
UNION ALL
SELECT b.*,
       c.site AS site_c
FROM junk_b b,
       junk_c c
WHERE c.cid(+) = b.pid
   AND c.pid(+) = b.cid;
SELECT a.id,
       bc.pid,
       bc.cid,
       bc.site,
       bc.site_c
FROM junk_a a,
SELECT b.*,
       c.site AS site_c
FROM junk_b b,
       junk_c c
WHERE c.pid(+) = b.pid
   AND c.cid(+) = b.cid
UNION ALL
SELECT b.*,
       c.site AS site_c
FROM junk_b b,
       junk_c c
WHERE c.cid(+) = b.pid
   AND c.pid(+) = b.cid
       ) bc
WHERE bc.id(+) = a.id;

JPA - How to map relation with NON-KEY field.

Hello.
Problem with mapping is NullPointerException when calling EntityManager em.createNativeQuery:
Table1 (Bm_Treeassoc):
MY_ID (Primary Key)
BOOKMARKID (-> MY_ID in Table2)
Text
Table2 (Bm_Bookmark):
MY_ID ( Primary Key)
Text
//CLASS BmTreeassoc
@OneToMany(targetEntity=BmBookmark.class, mappedBy="treeMaster", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
     private BmTreeassoc treeMaster = null ;
//CLASS BmBookmark
@ManyToOne(targetEntity=BmTreeassoc.class, fetch = FetchType.LAZY, cascade = CascadeType.ALL, optional = true)
     @JoinColumn(name="MY_ID", referencedColumnName="BOOKMARKID", unique=true)
     private ArrayList<BmBookmark> bookmarks = new ArrayList<BmBookmark>() ;
This Leads to the exception.
Mapping form MY_ID to MY_ID instead BOOKMARKID will not throw the exception,
so I assume I have a problem with the KEY Field?
Any ideas?
Kind regards
Frank

OK,
after reflecting (after maniacally trying for days).
Here is the answer by myself:
I do not use the mapping stuff at all no more.
I solved my join by using a view:
CREATE VIEW SAPDEMO.VTree
     AS SELECT t.TreeID, b.MY_ID, b.CLIENTID, b.Nickname, u.URL
     FROM SAPDEMO.BM_TreeAssoc as t
          JOIN SAPDEMO.BM_BOOKMARK as B ON t.BookmarkID = b.MY_ID
          JOIN SAPDEMO.BM_URL as U ON b.URL = u.MY_ID
Create the entity and then do a:
select * from VTREE where clientid=1 and treeid=446
Works great, simple, fast.

Alert view with a text field

Hi,
Is it possible on iPhone to create an alert with a text field?
Thanks,
Nava

You can subclass the alert and hack around with it, but in my experience, it would be easier to just write the functionality rather than trying to reuse the alert, but fighting it's built-in functionality.

All Joins with Example

Hi Experts,
Pls let me know what are all joins available in ABAP??
One example program for each for better understanding...
Any useful inputs on this will be highly rewarded.
Thanks in advance
Rgds ~ Lakshmiraj

Hi,
Joins are used to fetch data fast from Database tables:
Tables are joined with the proper key fields to fetch the data properly.
If there are no proper key fields between tables don't use Joins;
Important thing is that don't USE JOINS FOR CLUSTER tableslike BSEG and KONV.
Only use for Transparenmt tables.
You can also use joins for the database VIews to fetch the data.
JOINS
... FROM tabref1 [INNER] JOIN tabref2 ON cond
Effect
The data is to be selected from transparent database tables and/or views determined by tabref1 and tabref2. tabref1 and tabref2 each have the same form as in variant 1 or are themselves Join expressions. The keyword INNER does not have to be specified. The database tables or views determined by tabref1 and tabref2 must be recognized by the ABAP Dictionary.
In a relational data structure, it is quite normal for data that belongs together to be split up across several tables to help the process of standardization (see relational databases). To regroup this information into a database query, you can link tables using the join command. This formulates conditions for the columns in the tables involved. The inner join contains all combinations of lines from the database table determined by tabref1 with lines from the table determined by tabref2, whose values together meet the logical condition (join condition) specified using ON>cond.
Inner join between table 1 and table 2, where column D in both tables in the join condition is set the same:
Table 1 Table 2
A
B
C
D
D
E
F
G
H
a1
b1
c1
1
1
e1
f1
g1
h1
a2
b2
c2
1
3
e2
f2
g2
h2
a3
b3
c3
2
4
e3
f3
g3
h3
a4
b4
c4
3
|--|||--|
Inner Join
A
B
C
D
D
E
F
G
H
a1
b1
c1
1
1
e1
f1
g1
h1
a2
b2
c2
1
1
e1
f1
g1
h1
a4
b4
c4
3
3
e2
f2
g2
h2
|--||||||||--|
Example
Output a list of all flights from Frankfurt to New York between September 10th and 20th, 2001 that are not sold out:
DATA: DATE LIKE SFLIGHT-FLDATE,
CARRID LIKE SFLIGHT-CARRID,
CONNID LIKE SFLIGHT-CONNID.
SELECT FCARRID FCONNID F~FLDATE
INTO (CARRID, CONNID, DATE)
FROM SFLIGHT AS F INNER JOIN SPFLI AS P
ON FCARRID = PCARRID AND
FCONNID = PCONNID
WHERE P~CITYFROM = 'FRANKFURT'
AND P~CITYTO = 'NEW YORK'
AND F~FLDATE BETWEEN '20010910' AND '20010920'
AND FSEATSOCC < FSEATSMAX.
WRITE: / DATE, CARRID, CONNID.
ENDSELECT.
If there are columns with the same name in both tables, you must distinguish between them by prefixing the field descriptor with the table name or a table alias.
Note
In order to determine the result of a SELECT command where the FROM clause contains a join, the database system first creates a temporary table containing the lines that meet the ON condition. The WHERE condition is then applied to the temporary table. It does not matter in an inner join whether the condition is in the ON or WHEREclause. The following example returns the same solution as the previous one.
Example
Output of a list of all flights from Frankfurt to New York between September 10th and 20th, 2001 that are not sold out:
DATA: DATE LIKE SFLIGHT-FLDATE,
CARRID LIKE SFLIGHT-CARRID,
CONNID LIKE SFLIGHT-CONNID.
SELECT FCARRID FCONNID F~FLDATE
INTO (CARRID, CONNID, DATE)
FROM SFLIGHT AS F INNER JOIN SPFLI AS P
ON FCARRID = PCARRID
WHERE FCONNID = PCONNID
AND P~CITYFROM = 'FRANKFURT'
AND P~CITYTO = 'NEW YORK'
AND F~FLDATE BETWEEN '20010910' AND '20010920'
AND FSEATSOCC < FSEATSMAX.
WRITE: / DATE, CARRID, CONNID.
ENDSELECT.
Note
Since not all of the database systems supported by SAP use the standard syntax for ON conditions, the syntax has been restricted. It only allows those joins that produce the same results on all of the supported database systems:
Only a table or view may appear to the right of the JOIN operator, not another join expression.
Only AND is possible in the ON condition as a logical operator.
Each comparison in the ON condition must contain a field from the right-hand table.
If an outer join occurs in the FROM clause, all the ON conditions must contain at least one "real" JOIN condition (a condition that contains a field from tabref1 amd a field from tabref2.
Note
In some cases, '*' may be specified in the SELECT clause, and an internal table or work area is entered into the INTO clause (instead of a list of fields). If so, the fields are written to the target area from left to right in the order in which the tables appear in the FROM clause, according to the structure of each table work area. There can then be gaps between table work areas if you use an Alignment Request. For this reason, you should define the target work area with reference to the types of the database tables, not simply by counting the total number of fields. For an example, see below:
Variant 3
... FROM tabref1 LEFT [OUTER] JOIN tabref2 ON cond
Effect
Selects the data from the transparent database tables and/or views specified in tabref1 and tabref2. tabref1 und tabref2 both have either the same form as in variant 1 or are themselves join expressions. The keyword OUTER can be omitted. The database tables or views specified in tabref1 and tabref2 must be recognized by the ABAP-Dictionary.
In order to determine the result of a SELECT command where the FROM clause contains a left outer join, the database system creates a temporary table containing the lines that meet the ON condition. The remaining fields from the left-hand table (tabref1) are then added to this table, and their corresponding fields from the right-hand table are filled with ZERO values. The system then applies the WHERE condition to the table.
Left outer join between table 1 and table 2 where column D in both tables set the join condition:
Table 1 Table 2
A
B
C
D
D
E
F
G
H
a1
b1
c1
1
1
e1
f1
g1
h1
a2
b2
c2
1
3
e2
f2
g2
h2
a3
b3
c3
2
4
e3
f3
g3
h3
a4
b4
c4
3
|--|||--|
Left Outer Join
A
B
C
D
D
E
F
G
H
a1
b1
c1
1
1
e1
f1
g1
h1
a2
b2
c2
1
1
e1
f1
g1
h1
a3
b3
c3
2
NULL
NULL
NULL
NULL
NULL
a4
b4
c4
3
3
e2
f2
g2
h2
|--||||||||--|
Example
Output a list of all custimers with their bookings for October 15th, 2001:
DATA: CUSTOMER TYPE SCUSTOM,
BOOKING TYPE SBOOK.
SELECT SCUSTOMNAME SCUSTOMPOSTCODE SCUSTOM~CITY
SBOOKFLDATE SBOOKCARRID SBOOKCONNID SBOOKBOOKID
INTO (CUSTOMER-NAME, CUSTOMER-POSTCODE, CUSTOMER-CITY,
BOOKING-FLDATE, BOOKING-CARRID, BOOKING-CONNID,
BOOKING-BOOKID)
FROM SCUSTOM LEFT OUTER JOIN SBOOK
ON SCUSTOMID = SBOOKCUSTOMID AND
SBOOK~FLDATE = '20011015'
ORDER BY SCUSTOMNAME SBOOKFLDATE.
WRITE: / CUSTOMER-NAME, CUSTOMER-POSTCODE, CUSTOMER-CITY,
BOOKING-FLDATE, BOOKING-CARRID, BOOKING-CONNID,
BOOKING-BOOKID.
ENDSELECT.
If there are columns with the same name in both tables, you must distinguish between them by prefixing the field descriptor with the table name or using an alias.
Note
For the resulting set of a SELECT command with a left outer join in the FROM clause, it is generally of crucial importance whether a logical condition is in the ON or WHERE condition. Since not all of the database systems supported by SAP themselves support the standard syntax and semantics of the left outer join, the syntax has been restricted to those cases that return the same solution in all database systems:
Only a table or view may come after the JOIN operator, not another join statement.
The only logical operator allowed in the ON condition is AND.
Each comparison in the ON condition must contain a field from the right-hand table.
Comparisons in the WHERE condition must not contain a field from the right-hand table.
The ON condition must contain at least one "real" JOIN condition (a condition in which a field from tabref1 as well as from tabref2 occurs).
Note
In some cases, '*' may be specivied as the field list in the SELECT clause, and an internal table or work area is entered in the INTO clause (instead of a list of fields). If so, the fields are written to the target area from left to right in the order in which the tables appear in the llen in der FROM clause, according to the structure of each table work area. There can be gaps between the table work areas if you use an Alignment Request. For this reason, you should define the target work area with reference to the types of the database tables, as in the following example (not simply by counting the total number of fields).
Example
Example of a JOIN with more than two tables: Select all flights from Frankfurt to New York between September 10th and 20th, 2001 where there are available places, and display the name of the airline.
DATA: BEGIN OF WA,
FLIGHT TYPE SFLIGHT,
PFLI TYPE SPFLI,
CARR TYPE SCARR,
END OF WA.
SELECT * INTO WA
FROM ( SFLIGHT AS F INNER JOIN SPFLI AS P
ON FCARRID = PCARRID AND
FCONNID = PCONNID )
INNER JOIN SCARR AS C
ON FCARRID = CCARRID
WHERE P~CITYFROM = 'FRANKFURT'
AND P~CITYTO = 'NEW YORK'
AND F~FLDATE BETWEEN '20010910' AND '20010920'
AND FSEATSOCC < FSEATSMAX.
WRITE: / WA-CARR-CARRNAME, WA-FLIGHT-FLDATE, WA-FLIGHT-CARRID,
WA-FLIGHT-CONNID.
ENDSELECT.
Syntax
... [(] {dbtab_left [AS tabalias_left]} | join
{[INNER] JOIN}|{LEFT [OUTER] JOIN}
{dbtab_right [AS tabalias_right] ON join_cond} [)] ... .
Effect
The join syntax represents a recursively nestable join expression. A join expression consists of a left-hand and a right- hand side, which are joined either by means of [INNER] JOIN or LEFT [OUTER] JOIN . Depending on the type of join, a join expression can be either an inner ( INNER) or an outer (LEFT OUTER) join. Every join expression can be enclosed in round brackets. If a join expression is used, the SELECT command circumvents SAP buffering.
On the left-hand side, either a single database table, a view dbtab_left, or a join expression join can be specified. On the right-hand side, a single database table or a view dbtab_right as well as join conditions join_cond can be specified after ON. In this way, a maximum of 24 join expressions that join 25 database tables or views with each other can be specified after FROM.
AS can be used to specify an alternative table name tabalias for each of the specified database table names or for every view. A database table or a view can occur multiple times within a join expression and, in this case, have various alternative names.
The syntax of the join conditions join_cond is the same as that of the sql_cond conditions after the addition WHERE, with the following differences:
At least one comparison must be specified after ON.
Individual comparisons may be joined using AND only.
All comparisons must contain a column in the database table or the view dbtab_right on the right-hand side as an operand.
The following language elements may not be used: BETWEEN, LIKE, IN.
No sub-queries may be used.
For outer joins, only equality comparisons (=, EQ) are possible.
If an outer join occurs after FROM, the join condition of every join expression must contain at least one comparison between columns on the left-hand and the right-hand side.
In outer joins, all comparisons that contain columns as operands in the database table or the view dbtab_right on the right-hand side must be specified in the corresponding join condition. In the WHERE condition of the same SELECT command, these columns are not allowed as operands.
Resulting set for inner join
The inner join joins the columns of every selected line on the left- hand side with the columns of all lines on the right-hand side that jointly fulfil the join_cond condition. A line in the resulting set is created for every such line on the right-hand side. The content of the column on the left-hand side may be duplicated in this case. If none of the lines on the right-hand side fulfils the join_cond condition, no line is created in the resulting set.
Resulting set for outer join
The outer join basically creates the same resulting set as the inner join, with the difference that at least one line is created in the resulting set for every selected line on the left-hand side, even if no line on the right-hand side fulfils the join_cond condition. The columns on the right-hand side that do not fulfil the join_cond condition are filled with null values.
Example
Join the columns carrname, connid, fldate of the database tables scarr, spfli and sflight by means of two inner joins. A list is created of the flights from p_cityfr to p_cityto. Alternative names are used for every table.
PARAMETERS: p_cityfr TYPE spfli-cityfrom,
p_cityto TYPE spfli-cityto.
DATA: BEGIN OF wa,
fldate TYPE sflight-fldate,
carrname TYPE scarr-carrname,
connid TYPE spfli-connid,
END OF wa.
DATA itab LIKE SORTED TABLE OF wa
WITH UNIQUE KEY fldate carrname connid.
SELECT ccarrname pconnid f~fldate
INTO CORRESPONDING FIELDS OF TABLE itab
FROM ( ( scarr AS c
INNER JOIN spfli AS p ON pcarrid = ccarrid
AND p~cityfrom = p_cityfr
AND p~cityto = p_cityto )
INNER JOIN sflight AS f ON fcarrid = pcarrid
AND fconnid = pconnid ).
LOOP AT itab INTO wa.
WRITE: / wa-fldate, wa-carrname, wa-connid.
ENDLOOP.
Example
Join the columns carrid, carrname and connid of the database tables scarr and spfli using an outer join. The column connid is set to the null value for all flights that do not fly from p_cityfr. This null value is then converted to the appropriate initial value when it is transferred to the assigned data object. The LOOP returns all airlines that do not fly from p_cityfr.
PARAMETERS p_cityfr TYPE spfli-cityfrom.
DATA: BEGIN OF wa,
carrid TYPE scarr-carrid,
carrname TYPE scarr-carrname,
connid TYPE spfli-connid,
END OF wa,
itab LIKE SORTED TABLE OF wa
WITH NON-UNIQUE KEY carrid.
SELECT scarrid scarrname p~connid
INTO CORRESPONDING FIELDS OF TABLE itab
FROM scarr AS s
LEFT OUTER JOIN spfli AS p ON scarrid = pcarrid
AND p~cityfrom = p_cityfr.
LOOP AT itab INTO wa.
IF wa-connid = '0000'.
WRITE: / wa-carrid, wa-carrname.
ENDIF.
ENDLOOP.
Cheers,
vasavi.
kindly reward if helpful.

Partition Eliminiation on views and joins with other partitioned tables

I have a bunch of tables that are daily partioned and other which are not. We constantly join all these tables. I have noticed that partition elimination doesn't happen in most cases and I want some input or pointers on these.
Case 1
We have a view that joins a couple of partitioned tables on the id fileds and they the partition key is timestamp with local time zone.
TABLEA
tableaid
atime
TABLEB
tablebid
tableaid
btime
The view basically joins on tableaid, a.tableaid = b.tableaid(+) and a bunch of other non partitioned tables. atime and btime are the individal partition keys in the tables and these time do not match up like the id's in other words there is a little bit of correlation but they can be very different.
When I run a query against the view providing a time range for btime, I see partition elimination on tabled in the explain plan with KEY on Pstart/Pstop. But its a full tablescan on tablea. I was hoping there would be somekind of partition elimination here since its also partioned daily on the same datatype timestamp with local time zone.
Case 2
I have a couple of more partitioned tables
TABELC
tablecid
tablebid
ctime
TABLED
tabledid
tablebid
dtime
As you can see these tables are joined with tablebid and the times here generally correlate to tableb's timestamp as well.
Sub Case 1
When I join these tables to the view and give a time range on btime, I see partition elimination happening on tableb but not on tablea or any of the other tables.
Sub Case 2
Then I got rid of the view, wrote a query that us similar to the view where I join on tableaid (tablea and tableb), then on tablebid (tableb, tablec and tabled) and a few other tables and execute the query with some time range on btime and I still see that partition elimination happens only on tableb.
I thought that if other tables are also partitioned on a similark key that partition eliminition should happen? Or what am I missing here that is preventing from partition elimination on the other tables.

Performance is of utmost importance and partition pruning is going to help in that. I guess that's what I'm trying to acheive.
To achive partition elimination on tablec, d, etc I'm doing an outer join with btime and that seems to work. Also since most of the time after the partition elimination, I don't need a full tablescan since the period I will be querying most of the time will be small I also created a local index on id field that I'm using to join so that it can do a "TABLE ACCESS BY LOCAL INDEX ROWID" this way it should peform better than a global index since the index traversal path should be small when compared to the global index.
Of couse I still have problem with the tablea not being pruned, since I cannot do an outer join on two fields in the same table (id and time). So might just include the time criteria again and may be increase the time range a little more when compared to what the actual user submitted to try not to miss those rows.
Any suggestions is always welcome.

Avoid duplicates when i join with bridge table

i have a requirement with many to many relations between fact and dimention,that is the reason we have created bridge tables in the database.
if i execute only query on the fact table it is giving correct results.when ever i join with bridge tables it is returning lot of duplicate records.
Ex:
select amount from fact where column = 'xyz'
100
then it is returing one record.(this value is correct)
when ever i join this fact table with bridge table then it is returning duplicate records.
select a.amount from fact inner join bridge table b on a.fk=b.fk
100
100
100
100
100
how many number of fk's associated that many 100's are generating
in this case it is returning duplicate records.
in the RPD i have joined like one to many between fact to dimention.
if anybody face this type of situation please let me know how to resolve this?(FYI...i would have to do this before BM..because lot of other thing are coming into picture on BMM that's why i should have to achieve this in either physical or in database.
Thanks in advance
Edited by: user12077461 on Apr 3, 2011 6:39 PM
Edited by: user12077461 on Apr 17, 2011 4:51 PM

I understand what you say but partially.. please explain in more detail how to do that;
How should look the adrese_nezonate block, then? I have to add a 'name' column and set copy value from item property to 'STREETS.NAME', and database_property No?
Then the post-query trigger how should look like (the order by clause)? The post-query sends the entire query (with where/order by clauses) to the server, but in that "select... where... order by" (built dynamically) there are only columns from that block (adrese_nezonate). I need to join with streets, INSIDE that query.
Thanks.

Inner join Vs Outer join with ABAP code...?

Inner join Vs Outer join with ABAP code...?

Inner Join means, it will not select that recor at all, unless there is a matching entry in the second table.
suppose table VBAK INNER join table VBAP on VBAKVBELN = VBAPVBELN.
In this case, if there are no entries in VBAP, the header entry also will not show up.
But in case of OUTER JOIN, even if there is no items, it will show the header entry(VBAK) with blank columns for fields from item table.(VBAP)
here is one sample for inner join.
SELECT   A~EBELN
           A~EKORG
           A~EKGRP
           A~BSART
           A~LPONR
           A~LOEKZ
           A~LIFNR
           A~RESWK
           B~AEDAT
           B~WERKS
           B~MATNR
           B~MENGE
           B~EBELP
           B~ELIKZ
           B~PLIFZ
           B~PSTYP
           B~KNTTP
           B~MATKL
           B~ZZD_PLANT
           FROM EKKO AS A INNER JOIN EKPO AS B
           ON
           AEBELN = BEBELN
           INTO CORRESPONDING FIELDS OF TABLE T_DATA
           FOR ALL ENTRIES IN T_EKET
           WHERE
           A~EBELN EQ T_EKET-EBELN AND
           A~BSART EQ C_UBSTO      AND
           A~EKORG IN S_EKORG      AND
           A~EKGRP IN S_EKGRP      AND
           A~BSTYP EQ C_BSTYP      AND
           A~LOEKZ EQ SPACE        AND " Order not deleted
           A~RESWK IN S_RESWK      AND
           B~EBELN EQ T_EKET-EBELN AND
           B~EBELP EQ T_EKET-EBELP AND
           B~WERKS IN S_WERKS      AND
           B~MATNR IN S_MATNR      AND
           B~MATKL IN S_MATKL      AND
           B~LOEKZ EQ SPACE.           " Line item not deleted

Join with another table in pre-query

Hi,
We have a large data block and we need to order some columns based on street name for example, not id. The base table of db block contains an id_street column, and 'streets' table contains id and name.
Ok, in pre-query trigger of that block, we have a complex logic and we dynamically build the where clause. At the end, we set the order_By clause of the block, to order the rows, for example we need to order by the 'my_date' column asc (it's a date type column), and street desc; but street NAME, not id. We don't want to use a from clause query, because the dynamically where clause logic it's complex.
How can we join the db block table with 'streets' table in pre-query, so when constructing the order by clause to specify something like
set_block_property('ADRESE_NEZONATE', order_by, 'my_date, name desc');where 'name' is the name of the street, from the 'streets' table.
Is it possible in pre-query, somehow? Or, in my case where can I join with that table and use that column in pre-query at setting order by?
Thanks!
Edited by: Roger25 on 26.04.2013 12:31

I understand what you say but partially.. please explain in more detail how to do that;
How should look the adrese_nezonate block, then? I have to add a 'name' column and set copy value from item property to 'STREETS.NAME', and database_property No?
Then the post-query trigger how should look like (the order by clause)? The post-query sends the entire query (with where/order by clauses) to the server, but in that "select... where... order by" (built dynamically) there are only columns from that block (adrese_nezonate). I need to join with streets, INSIDE that query.
Thanks.

Problem with outer join with filter on join column

Hi,
In physical layer I have one dimension and two facts, and there's an outer join between the facts.
dim_DATE ,
fact_1 ,
fact_2
Joins:
dim_DATE inner join fact_1 on dim_DATE.DATE = fact_1.DATE
fact_1 left outer join fact_2 on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
When I run a report with a date as a filter, OBIEE executes "optimized" physical SQL:
select fact1.X, fact2.Y
from
Fact_1 left outer join on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
where Fact_1.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD' )
and Fact_2.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD')
The filter on Fact_2.DATE effectively replaces outer join with inner.
Is there a way to disable this "optimization", which is actually very good for inner joins, but doesn't allow outer joins?
Thanks in advance,
Alex
Edited by: AM_1 on Aug 11, 2009 8:20 AM

If you want to perform a Fact-based partitioning with OBIEE (two fact with the same dimension), you have to :
* create in your physical layer for each fact table the joins with the dimension
* create in the Business Model layer ONE star schema with ONE logical fact table containing the columns of your two physical fact table
In this way when you choose minimal one column of your fact1 and one column of your fact2, OBIEE will perform two query against each fact table/dimension, join them with an OUTER JOIN and your problem will disappear.
Cheers
Nico

Message: To play this movie in HD, you must have a computer with a built-in display ...

I rarely use iTunes, prefer, for obvious reasons to own physical media (which is prompting this question). But I do have an iPad 4 so I have to use it.
I bought a movie on iTunes and have downloaded it to a new brand new Windows 8 laptop. I am getting a message "To play this movie in HD, you must have a computer with a built-in display or have it connected to a display that supports HDCP."
My laptop is running a display at 1366 x 768 resolution and it is hooked up to a separate monitor using the HDMI out to the DVI input. Why am I getting this message and what is the workaround? I don't think that it's right that I have to re-buy the movie in standard definition to to watch it.
Also, as I have a 16 GB iPad, I typically don't have space available to store a 4GB movie but if I download the movie to my laptop and connect my iPad to my laptop, if I free up space will I be able to watch the movie on my iPad 4?
You can probably tell I'm not a fan of iTunes. Why does Apple insist on making everything so difficult? The iPad 4 with Retnia Display is the only Apple product I own and previously I have played this movie on my iPad.

I rarely use iTunes, prefer, for obvious reasons to own physical media (which is prompting this question). But I do have an iPad 4 so I have to use it.
I bought a movie on iTunes and have downloaded it to a new brand new Windows 8 laptop. I am getting a message "To play this movie in HD, you must have a computer with a built-in display or have it connected to a display that supports HDCP."
My laptop is running a display at 1366 x 768 resolution and it is hooked up to a separate monitor using the HDMI out to the DVI input. Why am I getting this message and what is the workaround? I don't think that it's right that I have to re-buy the movie in standard definition to to watch it.
Also, as I have a 16 GB iPad, I typically don't have space available to store a 4GB movie but if I download the movie to my laptop and connect my iPad to my laptop, if I free up space will I be able to watch the movie on my iPad 4?
You can probably tell I'm not a fan of iTunes. Why does Apple insist on making everything so difficult? The iPad 4 with Retnia Display is the only Apple product I own and previously I have played this movie on my iPad.

Billing report with due date field

Dear Friends,
Can you please tell the logic of Billing report with due date field.
Input. billing document no, date range, sales organisation
Output : billing document no, sales organisation, Amount. Due date.
If any clarification required, Please let me know.
Thanks in advance
Ranjan

Is it VF05 is suffiant for your purpose?
use further selection criteria tab.
Amit.

I need a report with the following fields

Hi All,
I need a report with the following fields & G/L "Expenses" only.
1)G/L Code.
2) G/L Name.
3) G/L Balance
& Selection Criteria From Date, To Date , & Location(for me locations is PROFITCENTRE).
Please some body suggest me an SQL Querry to fetch this result.
Thanks in Advance,
S. Mobin

Hi!
Individual G/L means i didn't understand
check this for only Expence Acc
Declare @FromDate Datetime
Declare @ToDate Datetime
Declare @Location nvarchar(20)
set @FromDate = (Select min(S0.RefDate) from jdt1 s0 where s0.Refdate >='[%0]')
set @ToDate = (Select max(S1.RefDate) from jdt1 s1 where s1.Refdate >='[%1]')
set @Location = (Select max(s2.ProfitCode) from jdt1 s2 where s2.ProfitCode = '[%2]')
select
J1.Account,
max(A0.AcctName) as Name,
j1.ProfitCode as Location,
sum(J1.debit-j1.credit) as Balance
From
JDT1 J1,OACT A0
Where
J1.Account=A0.AcctCode and
J1.RefDate >=@FromDate and
J1.RefDate<= @ToDate and
j1.ProfitCode=@Location and
A0.GroupMask = 5
Group By
J1.Account,j1.ProfitCode

Join with a "built" field

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