Junit - test for exception problem

Question

I'm trying to test if an exception is being thrown (when one is expected)
I get this error (when I shouldn't):
java.lang.AssertionError: Expected exception: exception.OutOfRangeException
The method being tested:
public void setScore ( int score ) throws exception.OutOfRangeException
  if ( ( score < 0 ) || ( score > 100 ) ) {
      throw new exception.OutOfRangeException( "Score invalid: " + score );
  else {
      this.score = score
}The test method:
@Test(expected=exception.OutOfRangeException.class)
public void testScoreOutOfRangeException() {
    try {
        record.setScore (-1);
    catch ( OutOfRangeException e ) {
         // do nothing because we expected it
}What I am doing wrong?

Answer 1

Yes, it does compile.
You are catching the exception.
junit expects to see the exception itself. You arecatching it so it doesn't see it.
I understand what you are saying. I originally didn't
type in the try/catch in the test method. But if I
remove the try/catch I get this error:
Unhandled exception type OutOfRangeExceptionI don't know much about Junit 4, but my preferred way of testing exceptions is to surround them in a try/catch as you have but to call Assert.fail() at the end of the try block
public void testScoreOutOfRangeException() {
    try {
        record.setScore (-1);
        fail("should have thrown an OutOfRangeException)";
    catch ( OutOfRangeException e ) {
         // do nothing because we expected it
}You'll have to look at Teh Docs for JUnit4 to see how to force a fail, though