Keep a Socket Server connection/port open for incoming requests

Question

Hi,
I have a socket server which listens to the incoming messages. The problem is that the socket server terminates the socket connection once it receives a message.
I want this Socket server to keep on running and process all the requests it receives.
Can you please advise which stream shall be kept open for this to be achieved? Below is the code for your reference.
Thanks!
import java.net.*;
import java.io.*;
public class SocketServer
     public static void main(String[] args) throws IOException
             ServerSocket serverSocket = null;
             String result = null;
             SocketServer sockServer = new SocketServer();
             try
                      serverSocket = new ServerSocket(4444);
             catch (IOException e)
                      System.exit(1);
             Socket clientSocket = null;
             try
                  clientSocket = serverSocket.accept();
                      clientSocket.setSoTimeout(30000);
             catch (IOException e)
                  System.exit(1);
             PrintWriter out = new PrintWriter(clientSocket.getOutputStream(), true);
             BufferedReader in = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));
             String inputLine;
             inputLine = in.readLine();
             if((inputLine == null) || (inputLine.length() < 1))
                      throw new IOException("could not read from request stream");
             else
                      result = sockServer.parseString(inputLine);
                      out.println("|0|OK|");
          InputStream is = null;
              FileOutputStream fout=null;
              BufferedInputStream bufIn = null;
              HttpURLConnection con = null;
              ByteArrayOutputStream baos = null;
                try
               URL url = new URL("http","10.176.96.64",8080,result);
               con = (HttpURLConnection)url.openConnection();
               is = con.getInputStream();
               bufIn = new BufferedInputStream(is);
               fout=new FileOutputStream("Z:\\Clips\\Cache\\"+result);
               baos = new ByteArrayOutputStream();
               int c = bufIn.read();
               while(c != -1)
                    baos.write(c);
                    c = bufIn.read();
               baos.writeTo(fout);
          catch(MalformedURLException mue)
               System.err.println ("*********In Download File: Invalid URL");
          catch (IOException ioe)
               System.err.println ("*********In Download File: I/O Error - " + ioe);
          finally
               try
                    baos.close();
                    bufIn.close();
                    fout.close();
                    is.close();
                    con.disconnect();
               catch(Exception ex)
                    System.out.println("*********In Download File: Exception Occured: "+ex.toString());
                  out.close();
                  in.close();
                  clientSocket.close();
                  serverSocket.close();
}

Answer 1

In a truly unexpected turn of events.. this question has been crossposted.
http://forum.java.sun.com/thread.jspa?threadID=5127579
Good job singalg. I highly recommend that instead of accepting that there is anything wrong with your understanding of how this should work and reviewing the tutorials you should instead repost this question daily, Each day choosing a different forum.