Large binary file reading

Hi,
I'm currently using a java.io.BufferedInputStream to read a large binary file.
I recently discovered there is a chunk of data that shows up near the end of each file. (these files are binary and are XX to XXX mb in size)
Loading it all to memory first would kill my performance so I'd like to be able to come up with an alternate method.
Does Java or the class above offer a way I can
1) get the length of the file
2) seek to a point say 2000 bytes from the end so I can start reading the binary data?
Ideally I'd like to do a backwards read as that would be quickest. Is there a way to change the operation so that a 'read' would be reading backwards (from end to beginning)?
For me speed is the #1 thing i have to worry about. So to be able to seek forward several hundred thousand bytes at a time would help tremendously.

how does the 'skip' method work? Probably by using OS specific calls to read to a point in the file.
maybe I could
'skip' length - 20k from the start or something like
that.
Yep.

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    How would you read a large binary file into memory please? I had a thought about creating a Byte Array on the fly, however you cannot createa byte array with a long so what happens when you reach the maximum value an integer can store?

    a) You can map the file, instead of reading it physically.
    b) Let's suppose that you are running Sun JVM in Windows 2000/XP/2003 and you have 4-GB of RAM in your machine (memory is so cheap nowadays...)
    - Windows can not use the full 4GB (it reserves 2GB for itself, and if you buy a special server version, it reserves only 1GB for itself.)
    - Java can't use more than 1.6 GB in Windows due to some arcane reasons. (Someone posted the Bug Database explanation in this forum.)
    So you have an upper limit of 1.6 GB.
    1.6GB is a value smaller than the size of an int, so you could have an array as big (using the class java.nio.ByteBuffer and the like). Try and see.

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    Attachments:
    split number.PNG ‏2 KB

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