Layout: multiple rows of different lengths
Ok for one im kinda new to java so all this swing stuff is still in a limited understanding for me. I am doing quite well with it, but i am trying to have a set of buttons, 50 in fact. There are like 10 rows. Now the problem is that the first 3 rows are different lengths such as:
x is a button
x x x x x
x x x x x x x
x x x x
x x x x x x x x x
x x x x x x x x x
x x x x x x x x x
x x x x x x x x x
x x x x x x x x x
x x x x x x x x x
sorry about the horrible illustration, what im trying to say is that the first row has lets say 5 buttons, then the second row has 6 then the 3rd has 4 and then the remaining ones have 5. How would i come about this. I have tried using multiple jpanels like in the code below, but only the last one is being displayed, how would i do this?
If you need more info post that you need it.
Thanks
CODE:
JPanel pane1 = new JPanel(new GridLayout(0, 1));
pane1.setBorder(BorderFactory.createEmptyBorder(30, 30, 10, 30));
JPanel pane2 = new JPanel(new GridLayout(0, 5));
pane2.setBorder(BorderFactory.createEmptyBorder(30, 30, 10, 30));
JPanel pane3 = new JPanel(new GridLayout(0, 6));
pane3.setBorder(BorderFactory.createEmptyBorder(30, 30, 10, 30));
JPanel pane4 = new JPanel(new GridLayout(0, 4));
pane4.setBorder(BorderFactory.createEmptyBorder(30, 30, 10, 30));
JPanel pane5 = new JPanel(new GridLayout(0, 5));
pane5.setBorder(BorderFactory.createEmptyBorder(30, 30, 10, 30));
JTextArea displayBox = new JTextArea("Hello");
pane1.add(displayBox);
JButton[] buttons = new JButton[50];
for (int x=0; x < 50; x++)
buttons[x] = new JButton(normKeys[x]);
if (x <= 4)
pane2.add(buttons[x]);
else if (x <= 10)
pane3.add(buttons[x]);
else if (x <= 14)
pane4.add(buttons[x]);
else
pane5.add(buttons[x]);
frame.getContentPane().add(pane1, BorderLayout.CENTER);
frame.getContentPane().add(pane2, BorderLayout.CENTER);
frame.getContentPane().add(pane3, BorderLayout.CENTER);
frame.getContentPane().add(pane4, BorderLayout.CENTER);
frame.getContentPane().add(pane5, BorderLayout.CENTER);
frame.pack();
frame.setVisible(true);
The GridBagLayout class is a flexible layout manager that aligns components vertically and horizontally, without requiring that the components be of the same size. Each GridBagLayout object maintains a dynamic, rectangular grid of cells, with each component occupying one or more cells, called its display area.
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Hi All,
I am using oracle database 11g
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table_1 having columns
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email
and table_2 having columns
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emp_no phone_type phone_number
1001 MOB 9451421452
1001 WEMG 235153654
1001 EMG 652341536
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1003 WEMG 5332621456
1004 EMG 59612356
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1004 donald finn sian [email protected] null null
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$sidFrank Kulash wrote:
sonething like this:Frank, you missed aggregate function (pivot requires one). However main thing is it will cause ORA-01748:
with table_1 as (
select 1001 emp_no,'mark' first_name,null middle_name,'k'last_name,'[email protected]' email from dual union all
select 1002,'john','cena','gary','[email protected]' from dual union all
select 1003,'dany',null,'craig','[email protected] null' from dual union all
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table_2 as (
select 1001 emp_no,'MOB' phone_type,9451421452 phone_number from dual union all
select 1001,'WEMG',235153654 from dual union all
select 1001,'EMG',652341536 from dual union all
select 1002,'MOB',9987526312 from dual union all
select 1003,'WEMG',5332621456 from dual union all
select 1004,'EMG',59612356 from dual
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PIVOT ( max(t2.phone_number)
FOR t2.phone_type IN ( 'MOB' AS mob
, 'WEMG' AS wemg
FOR t2.phone_type IN ( 'MOB' AS mob
ERROR at line 19:
ORA-01748: only simple column names allowed hereYou need to:
with table_1 as (
select 1001 emp_no,'mark' first_name,null middle_name,'k' last_name,'[email protected]' email from dual union all
select 1002,'john','cena','gary','[email protected]' from dual union all
select 1003,'dany',null,'craig','[email protected] null' from dual union all
select 1004,'donald','finn','sian','[email protected]' from dual
table_2 as (
select 1001 emp_no,'MOB' phone_type,9451421452 phone_number from dual union all
select 1001,'WEMG',235153654 from dual union all
select 1001,'EMG',652341536 from dual union all
select 1002,'MOB',9987526312 from dual union all
select 1003,'WEMG',5332621456 from dual union all
select 1004,'EMG',59612356 from dual
table_3 as (
select t1.emp_no,first_name,middle_name,last_name,email,
phone_type,phone_number
FROM table_1 t1
LEFT JOIN table_2 t2 ON t1.emp_no = t2.emp_no
SELECT *
FROM table_3
PIVOT ( max(phone_number)
FOR phone_type IN ( 'MOB' AS mob
, 'WEMG' AS wemg
EMP_NO FIRST_ MIDD LAST_ EMAIL MOB WEMG
1004 donald finn sian [email protected]
1003 dany craig [email protected] null 5332621456
1001 mark k [email protected] 9451421452 235153654
1002 john cena gary [email protected] 9987526312
SQL>SY. -
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ID
1
2
3
4
5
6
7
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SQL>create table t_csv
2 (TPNUMBER varchar2(20),
3 ROUTE_1 VARCHAR2(5),
4 ROUTE_2 VARCHAR2(5),
5 ROUTE_3 VARCHAR2(5),
6 ROUTE_4 VARCHAR2(5),
7 ROUTE_5 VARCHAR2(5),
8 ROUTE_6 VARCHAR2(5) );
Table created.
SQL>INSERT INTO t_csv (TPNUMBER,ROUTE_1,ROUTE_2) values( '1001 1', '56W', '18' );
1 row created.
SQL>INSERT INTO t_csv (TPNUMBER,ROUTE_1,ROUTE_2,ROUTE_3) values( '1002 2', '16', '186', '28');
1 row created.
SQL>create table t_quotes(
2 tpnumber NUMBER,
3 routes VARCHAR2(5));
Table created.
SQL>DECLARE
2 L_tpnumber NUMBER;
3 L_route VARCHAR2(5);
4 begin
5 for rec in (select * from t_csv) loop
6 L_tpnumber := SUBSTR(rec.tpnumber,1,INSTR(rec.tpnumber,' ')-1);
7 L_route := SUBSTR(rec.tpnumber,INSTR(rec.tpnumber,' ')+1);
8 insert into t_quotes values( L_tpnumber, l_route );
9 if rec.route_1 is not null then
10 insert into t_quotes values( L_tpnumber, rec.route_1 );
11 end if;
12 if rec.route_2 is not null then
13 insert into t_quotes values( L_tpnumber, rec.route_2 );
14 end if;
15 if rec.route_3 is not null then
16 insert into t_quotes values( L_tpnumber, rec.route_3 );
17 end if;
18 if rec.route_4 is not null then
19 insert into t_quotes values( L_tpnumber, rec.route_4 );
20 end if;
21 if rec.route_5 is not null then
22 insert into t_quotes values( L_tpnumber, rec.route_5 );
23 end if;
24 end loop;
25 end;
26 /
PL/SQL procedure successfully completed.
SQL> select tpnumber, routes from t_quotes;
TPNUMBER ROUTE
1001 1
1001 56W
1001 18
1002 2
1002 16
1002 186
1002 28
7 rows selected. -
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select manager_id mg_id, employee_id emp_id, last_name name from employees
where manager_id = '100'
and DEPARTMENT_ID = '80'if i run the following query, then o/p comes row wise; like below:
mg_id emp_id name
100 145 Russell
100 146 Partners
100 147 Errazuriz
100 148 Cambrault
100 149 Zlotkeybut if i want the o/p like below; i.e; under manager # 100, all employees' emp_id and name should come in only ONE row NOT in multiple rows:
mg_id emp_id name emp_id name emp_id name emp_id name emp_id name
100 145 Russell 146 Partners 147 Errazuriz 148 Cambrault 149 Zlotkeypls. help me to sort out the above sought o/p.
kindly tell me if there is any posting guidelines (except "Plain Text Help" on the right side) in this forum. i tried a lot to post above two o/p in easily readable format, but couldn't do that.
Edited by: Shariful on Sep 20, 2009 4:28 AM
Edited by: Shariful on Sep 20, 2009 4:29 AMHi,
Shariful wrote:
Hi All,
Pls. check the below query:
select manager_id mg_id, employee_id emp_id, last_name name from employees
where manager_id = '100'
and DEPARTMENT_ID = '80'
if i run the following query, then o/p comes row wise; like below:
mg_id emp_id name
100 145 Russell
100 146 Partners
100 147 Errazuriz
100 148 Cambrault
100 149 Zlotkey
but if i want the o/p like below; i.e; under manager # 100, all employees' emp_id and name should come in only ONE row NOT in multiple rows:
mg_id emp_id name emp_id name emp_id name emp_id name emp_id name
100 145 Russell 146 Partners 147 Errazuriz 148 Cambrault 149 ZlotkeyIf you want all the emp_ids and names concatenated into one big VARCHAR2 column, that's called String Aggregation
[AskTom.oracle.com|http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:2196162600402] shows several different ways to do it.
You can format that one big column so that it looks like separate columns.
If you want each emp_id and name in its own column, that's called Pivoting .
Look up "pivot" for various techniques. If you do not know exactly how many rows were in the original query (and therefore how many columns you'll need in the output), then it will require Dynamic SQL , which can be complicated.
Unfortunately, when you do search for "pivot", mlost of the hits will be things like "Search for pivot and you'll get lots of examples".
Re: Help for a query to add columns is one that actually has some information. It was a question very much like yours.
kindly tell me if there is any posting guidelines (except "Plain Text Help" on the right side) in this forum. i tried a lot to post above two o/p and query in easily readable format, but couldn't do that.Type these 6 characters:
(small letters only, inside curly brackets) before and after formatted text, to preserve spacing.
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