Link persons together to get the total Household value

Question

Version
Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit Production
Hi
i am trying to find all possible link and spouses to the persons and bring them together to find out the total sum for that household.
We have a person table which lists all the persons in out DB
a link table wich links identical persons
a spouse table which has spouse relation
Can some one please help me in building this logic.
Persons in our database = 100 / 200 / 300 / 400 / 500 / 600 / 700 / 800
Ids linked together that means they are the same people.
100 --> 200
200 --> 300
200 --> 800
300 --> 700
400 --> 500
Spouse
100 -- 600
200 -- 500
400 -- 500
Required Output
ID  ID2     VALUE   VIA_WEPID
100 100 --> 1000   100  ** Direct Link
100 200 --> 2000   200  ** Direct Link
100 800 --> 8000   200  ** In Direct Link
100 300 --> 3000   200  ** In Direct Link
100 300 --> 3000   300  ** In Direct Link
100 700 --> 7000   300  ** In Direct Link
100 600 --> 6000   600  ** Direct Link
100 500 --> 5000   200  ** In Direct Link
100 400 --> 4000   500  ** In Direct Link 
/* Formatted on 8/24/2012 8:28:39 AM (QP5 v5.115.810.9015) */
WITH PERSON AS (SELECT   100 ID, 1000 VALUE FROM DUAL
                UNION ALL
                SELECT   200 ID, 2000 VALUE FROM DUAL
                UNION ALL
                SELECT   300 ID, 3000 VALUE FROM DUAL
                UNION ALL
                SELECT   400 ID, 4000 VALUE FROM DUAL
                UNION ALL
                SELECT   500 ID, 5000 VALUE FROM DUAL
                UNION ALL
                SELECT   600 ID, 6000 VALUE FROM DUAL
                UNION ALL
                SELECT   700 ID, 7000 VALUE FROM DUAL
                UNION ALL
                SELECT   800 ID, 8000 VALUE FROM DUAL
    PERSON_LINK AS (SELECT   100 ID, 200 LINK_ID FROM DUAL
                    UNION ALL
                    SELECT   200 ID, 100 LINK_ID FROM DUAL
                    UNION ALL
                    SELECT   200 ID, 300 LINK_ID FROM DUAL
                    UNION ALL
                    SELECT   300 ID, 200 LINK_ID FROM DUAL
                    UNION ALL
                    SELECT   200 ID, 800 LINK_ID FROM DUAL
                    UNION ALL
                    SELECT   800 ID, 200 LINK_ID FROM DUAL
                    UNION ALL
                    SELECT   300 ID, 700 LINK_ID FROM DUAL
                    UNION ALL
                    SELECT   700 ID, 300 LINK_ID FROM DUAL
                    UNION ALL
                    SELECT   400 ID, 500 LINK_ID FROM DUAL
                    UNION ALL
                    SELECT   500 ID, 400 LINK_ID FROM DUAL
    SPOUSE AS (SELECT   400 ID, 500 SPOUSE_ID FROM DUAL
               UNION ALL
               SELECT   500 ID, 400 SPOUSE_ID FROM DUAL
               UNION ALL
               SELECT   200 ID, 500 SPOUSE_ID FROM DUAL
               UNION ALL
               SELECT   500 ID, 200 SPOUSE_ID FROM DUAL
               UNION ALL
               SELECT   100 ID, 600 SPOUSE_ID FROM DUAL
               UNION ALL
               SELECT   600 ID, 100 SPOUSE_ID FROM DUAL)
SELECT   *
  FROM   person, person_link, spousei am trying to implement this logic but i am no where near to the reqired output
SELECT   ID, ID ID2, VALUE FROM person
UNION
SELECT   a.ID, LINK_ID ID2, VALUE
  FROM   Person a, person_link b
WHERE   a.id = b.id
UNION
SELECT   a.ID, spouse_id ID2, VALUE
  FROM   Person a, spouse b
WHERE   a.id = b.idEdited by: new learner on Aug 24, 2012 6:05 AM
Edited by: new learner on Aug 24, 2012 7:56 AM

Answer 1

Does this make sense:
with
person(rid,the_value) as
(select 100,1000 from dual union all
select 200,2000 from dual union all
select 300,3000 from dual union all
select 400,4000 from dual union all
select 500,5000 from dual union all
select 600,6000 from dual union all
select 700,7000 from dual union all
select 800,8000 from dual
person_link(rid,link_id) as
(select 100,200 from dual union all
select 200,100 from dual union all
select 200,300 from dual union all
select 200,800 from dual union all
select 300,200 from dual union all
select 300,700 from dual union all
select 400,500 from dual union all
select 500,400 from dual union all
select 700,300 from dual union all
select 800,200 from dual
spouse(rid,spouse_id) as
(select 100,600 from dual union all
select 200,500 from dual union all
select 400,500 from dual union all
select 500,200 from dual union all
select 500,400 from dual union all
select 600,100 from dual
person_link_x(rid,link_id) as
(select 100,200 from dual union all
select 200,300 from dual union all
select 200,800 from dual union all
select 300,700 from dual union all
select 400,500 from dual
person_link_x as
(select rid,link_id
   from person_link
  where rid < link_id
spouse_x(rid,spouse_id) as
(select 100,600 from dual union all
select 200,500 from dual union all
select 400,500 from dual
spouse_x as
(select rid,spouse_id
   from spouse
  where rid < spouse_id
)the order of rows is changed for readability
the <tt> factors person_link_x </tt> and <tt> spouse_x </tt> are there to eliminate cycles
using <tt> factors person_link_x </tt> by following links (connect by ...) you can get the following trees (hierarchies) - No Database at hand to do it myself
1:   100     200   200   300   400
      |       |     |     |     |
2:   200     300   800   700   500
     / \      |
3: 300 800   700
    |
4: 700thus you discover there are just two individuals in the table denoting the same persons as the trees in the middle are all subtrees of the first tree.
taking the root values 100 and 400 as person ids and replacing all "alias" values with the corresponding root values in spouse_x you get
spouse_x(rid,spouse_id) as
(select 100,600 from dual union all
select 100,400 from dual union all
select 400,400 from dual
)the last row makes no sense (data entry error, ... ) and: either she has two husbands or he has two wives ;)
Regards
Etbin