Linking tables in Crystal with no relationship

I have three tables i need to link together. The first two have something in common where I it's no problem...but the problem is I require a third table where there is no common factor. I was told connecting a distribution table to this would work but not quite sure what that means...i'm new at this.

Hi,
Please advice all three table name to advice.
Thanks & Regards,
Nagarajan

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Linking table of contents with pages 5.0

I write some help-books for friends and the family.
I wrote down everything I need and I've created a table of contents with page numbers.
Now you can push the numbers behind the headings and you are automatically on the right page for reading the text. (In Pages document)
In pages 5.0 these things are still working fine, but....
When I export the document into a pdf, you can't push/touch the headings and the numbers behind there headings.
With the old pages, after exporting the document into a pdf, you could import it into iBooks on the iPad. In iBooks now you can touch a heading and you'll get on the right page.
That was realy helpfull, 1 click and you could read the text on which you're interested.
But with the new pages 5.0 this feature is deleted... or I do something wrong.
Could anyone of you help me for getting this feature back, if I do something wrong?

Well there is a standard body for EPUB - http://idpf.org/epub
And, Apple furnishes the TEMPLATE - the Pages 09 TEMPLATE - automatically (supposedily) makes the TOC links which - then - you can export to EPUB.
Again, the problem I'm daling with is that the Kindle for the iPad, does not see the TOC. It des see it in the Kindle Softward for the Mac - which is different - for some reason. I have authored two books on Pages but Amazon converts my EPUB file to fit the Kindle device itself.

Cannot link tables in Crystal Reports 2013

Hi Forum,
We upgraded to CR 2013 from old 8.5 and i cannot link tables anymore.
I disable Smart Linking and work ok now but i really don't want to keep it disable because some users are used to smart linking.
Is there a seeting or something in the registry that i can add or change to make the smart linking work?...
the error that i was getting is attached:
Fault bucket , type 0 Event Name: APPCRASH Response: Not available Cab Id: 0 Problem signature: P1: crw32.exe P2: 14.1.5.1501 P3: 54616206 P4: StackHash_ba3d P5: 6.1.7601.18247 P6: 521ea91c P7: c0000374 P8: 000c3873 P9: P10: Attached files: These files may be available here: C:\Users\TGHAZAL\AppData\Local\Microsoft\Windows\WER\ReportArchive\AppCrash_crw32.exe_9cb4f582e912c9a7d84acec8103b1fec3cc260e_121d946b Analysis symbol: Rechecking for solution: 0 Report Id: 9ca8bfab-e867-11e4-8ffc-904ce5e0a392 Report Status: 0
Regards,
Manuel Roman

Hi,
Rearrange links and then try.
Thanks.

Linking tables 'mara' , 'marc ' with 'konv'

hi, I have to link tables mara and marc to table konv.
i want to get the field kschl from konv and
i know the following fields : mara-werks, mara-matnr,mara-matkl, marc-ekgrp.
We can use the following tables for linking:
eina, a018,konh, konp,a005.
Pls. help
Rgds,
Ravindra

Hi Ravindra,
In order to retrieve KNUMH field, you can use table A018.
Based on the fields you have mara-werks, mara-matnr,mara-matkl, marc-ekgrp etc, fetch all relevant A018 records in an internal table and pick the record which has the latest validity end date(Field DATBI). you can use Read statment wth index 1 after sorting as per latest valid record and pick up the Condition record number(Field KNUMH).
Now you can use this condition record # to retrieve field KSCHL from Table KONH.
Cheers,
Vikram
Please reward for helpful replies!!

Link Tables in Crystal Report

Hi
I am using Crystal report2008 in SAP Business One.
I have made links between OCRD(BP Record) and ORCT(incoming payment). I want to display BP data Opening balance as well as Incoming payment document total. It displays nothing.
Can anyone help me how to display both in a report?
By
Kalai

Hi
Thanks for all who made efforts.
Yes these are the only tables. Account balance from OCRD.Balances
Invoice totals from OINV.DocTotal and Incoming payment total from ORCT.DocTotal.
Now the issue is am getting results, But it gives repetition of vlaues
Eg.
A customer has 1500, 2000, 4000 of Invoice total and 1500, 2000 of Incoming payments.
It gives results like
Cardname OINV.DocTotal ORCT.Total
      A            1500              1500
      A            2000
      A            4000
      A            1500              2000
      A            2000
      A            4000
What will be problem, Plaz give me a solution
By
Kalai

Why data change in linked table in Access - link from Oracle DB

Can someone please help me to solve this situation? I try to find out why data is changed from Oracle to Access. I must come back to this thread because lot of data in my Oracle database is defined as NUMBER(22), and I am using Access heavily.
Here is the problem:
In Access, I created ODBC connection (System DSN) to Oracle 9.2 database by using Oracle driver (NOT Microsoft ODBC for Oracle). Then I linked tables from Access with the Oracle table. What happens is that the number in Access linked table is displayed as a scientific number. Is there a way that I can preserve whatever I have in Oracle database?
For example:
Comp_ID in Oralce is defined as NUMBER(22) = 40000000000324003; In Access it looks like this 4.0000000000324E+16.
What I have in my system:
1- Oracle 9.2 client
2- Oracle driver
3- Access 2003
4- Jet - SP 8

Can someone please help me to solve this situation? I try to find out why data is changed from Oracle to Access. I must come back to this thread because lot of data in my Oracle database is defined as NUMBER(22), and I am using Access heavily.
Here is the problem:
In Access, I created ODBC connection (System DSN) to Oracle 9.2 database by using Oracle driver (NOT Microsoft ODBC for Oracle). Then I linked tables from Access with the Oracle table. What happens is that the number in Access linked table is displayed as a scientific number. Is there a way that I can preserve whatever I have in Oracle database?
For example:
Comp_ID in Oralce is defined as NUMBER(22) = 40000000000324003; In Access it looks like this 4.0000000000324E+16.
What I have in my system:
1- Oracle 9.2 client
2- Oracle driver
3- Access 2003
4- Jet - SP 8

Crystal 2011 linking table with a String and a Number

Hello,
I am able to retrieve the data I want with the following SQL Query in SQL: If I try to create it in Crystal 2011 APPLRUNN is a string and CNTBTCH is a number. Is there a way I can link these two fields if one is a string and the other is a number ?
SELECT
ENADV.APPLRUNN, ENPBD.CNTBTCH,
ENPBD.DOCNBR
FROM
ENADV INNER JOIN
ENPBD ON ENADV.APPLRUNN = ENPBD.CNTBTCH
Thanks,
Debbie

Hi Debbie,
You cannot linking table with a string and a number. I have given a example query:
SELECT
ENADV.APPLRUNN, ENPBD.CNTBTCH,
ENPBD.DOCNBR
FROM
ENADV INNER JOIN
ENPBD ON
ENADV.APPLRUNN = ENPBD.APPLRUNN or ENADV.CNTBTCH = ENPBD.CNTBTCH
I modify last sentense because one table primary key is equal to another table Foreign key i.e
one table ID field = another table ID field or one table NAME field = another table Name field.
Please understand my intenction and check linking fields in tables.
Thanks,
DJ

How to Bind a Combo Box so that it retrieves and display content corresponding to the Id in a link table and populates itself with the data in the main table?

I am developing a desktop application in Wpf using MVVM and Entity Frameworks. I have the following tables:
1. Party (PartyId, Name)
2. Case (CaseId, CaseNo)
3. Petitioner (CaseId, PartyId) ............. Link Table
I am completely new to .Net and to begin with I download Microsoft's sample application and
following the pattern I have been successful in creating several tabs. The problem started only when I wanted to implement many-to-many relationship. The sample application has not covered the scenario where there can be a any-to-many relationship. However
with the help of MSDN forum I came to know about a link table and managed to solve entity framework issues pertaining to many-to-many relationship. Here is the screenshot of my application to show you what I have achieved so far.
And now the problem I want the forum to address is how to bind a combo box so that it retrieves Party.Name for the corresponding PartyId in the Link Table and also I want to populate it with Party.Name so that
users can choose one from the dropdown list to add or edit the petitioner.

Hello Barry,
Thanks a lot for responding to my query. As I am completely new to .Net and following the pattern of Microsoft's Employee Tracker sample it seems difficult to clearly understand the concept and implement it in a scenario which is different than what is in
the sample available at the link you supplied.
To get the idea of the thing here is my code behind of a view vBoxPetitioner:
<UserControl x:Class="CCIS.View.Case.vBoxPetitioner"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:v="clr-namespace:CCIS.View.Case"
xmlns:vm="clr-namespace:CCIS.ViewModel.Case"
mc:Ignorable="d"
d:DesignWidth="300"
d:DesignHeight="200">
<UserControl.Resources>
<DataTemplate DataType="{x:Type vm:vmPetitioner}">
<v:vPetitioner Margin="0,2,0,0" />
</DataTemplate>
</UserControl.Resources>
<Grid>
<HeaderedContentControl>
<HeaderedContentControl.Header>
<StackPanel Orientation="Horizontal" HorizontalAlignment="Right">
<TextBlock Margin="2">
<Hyperlink Command="{Binding Path=AddPetitionerCommand}">Add Petitioner</Hyperlink>
| <Hyperlink Command="{Binding Path=DeletePetitionerCommand}">Delete</Hyperlink>
</TextBlock>
</StackPanel>
</HeaderedContentControl.Header>
<ListBox BorderThickness="0" SelectedItem="{Binding Path=CurrentPetitioner, Mode=TwoWay}" ItemsSource="{Binding Path=tblParties}" />
</HeaderedContentControl>
</Grid>
</UserControl>
This part is working fine as it loads another view that is vPetioner perfectly in the manner I want it to be.
Here is the code of vmPetitioner, a ViewModel:
Imports Microsoft.VisualBasic
Imports System.Collections.ObjectModel
Imports System
Imports CCIS.Model.Party
Namespace CCIS.ViewModel.Case
''' <summary>
''' ViewModel of an individual Email
''' </summary>
Public Class vmPetitioner
Inherits vmParty
''' <summary>
''' The Email object backing this ViewModel
''' </summary>
Private petitioner As tblParty
''' <summary>
''' Initializes a new instance of the EmailViewModel class.
''' </summary>
''' <param name="detail">The underlying Email this ViewModel is to be based on</param>
Public Sub New(ByVal detail As tblParty)
If detail Is Nothing Then
Throw New ArgumentNullException("detail")
End If
Me.petitioner = detail
End Sub
''' <summary>
''' Gets the underlying Email this ViewModel is based on
''' </summary>
Public Overrides ReadOnly Property Model() As tblParty
Get
Return Me.petitioner
End Get
End Property
''' <summary>
''' Gets or sets the actual email address
''' </summary>
Public Property fldPartyId() As String
Get
Return Me.petitioner.fldPartyId
End Get
Set(ByVal value As String)
Me.petitioner.fldPartyId = value
Me.OnPropertyChanged("fldPartyId")
End Set
End Property
End Class
End Namespace
And below is the ViewMode vmParty which vmPetitioner Inherits:
Imports Microsoft.VisualBasic
Imports System
Imports System.Collections.Generic
Imports CCIS.Model.Case
Imports CCIS.Model.Party
Imports CCIS.ViewModel.Helpers
Namespace CCIS.ViewModel.Case
''' <summary>
''' Common functionality for ViewModels of an individual ContactDetail
''' </summary>
Public MustInherit Class vmParty
Inherits ViewModelBase
''' <summary>
''' Gets the underlying ContactDetail this ViewModel is based on
''' </summary>
Public MustOverride ReadOnly Property Model() As tblParty
'''' <summary>
'''' Gets the underlying ContactDetail this ViewModel is based on
'''' </summary>
'Public MustOverride ReadOnly Property Model() As tblAdvocate
''' <summary>
''' Gets or sets the name of this department
''' </summary>
Public Property fldName() As String
Get
Return Me.Model.fldName
End Get
Set(ByVal value As String)
Me.Model.fldName = value
Me.OnPropertyChanged("fldName")
End Set
End Property
''' <summary>
''' Constructs a view model to represent the supplied ContactDetail
''' </summary>
''' <param name="detail">The detail to build a ViewModel for</param>
''' <returns>The constructed ViewModel, null if one can't be built</returns>
Public Shared Function BuildViewModel(ByVal detail As tblParty) As vmParty
If detail Is Nothing Then
Throw New ArgumentNullException("detail")
End If
Dim e As tblParty = TryCast(detail, tblParty)
If e IsNot Nothing Then
Return New vmPetitioner(e)
End If
Return Nothing
End Function
End Class
End Namespace
And final the code behind of the view vPetitioner:
<UserControl x:Class="CCIS.View.Case.vPetitioner"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:vm="clr-namespace:CCIS.ViewModel.Case"
mc:Ignorable="d"
Width="300">
<UserControl.Resources>
<ResourceDictionary Source=".\CompactFormStyles.xaml" />
</UserControl.Resources>
<Grid>
<Border Style="{StaticResource DetailBorder}">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="Auto" />
<ColumnDefinition Width="*" />
</Grid.ColumnDefinitions>
<TextBlock Grid.Column="0" Text="Petitioner:" />
<ComboBox Grid.Column="1" Width="240" SelectedValuePath="." SelectedItem="{Binding Path=tblParty}" ItemsSource="{Binding Path=PetitionerLookup}" DisplayMemberPath="fldName" />
</Grid>
</Border>
</Grid>
</UserControl>
The problem, presumably, seems to be is that the binding path "PetitionerLookup" of the ItemSource of the Combo box in the view vPetitioner exists in a different ViewModel vmCase which serves as an ObservableCollection for MainViewModel. Therefore,
what I need to Know is how to route the binding path if it exists in a different ViewModel?
Sir, I look forward to your early reply bringing a workable solution to the problem I face.
Warm Regards,
Arun

Crystal Report - Linking tables

Hi all,
I had a look around for this subject matter but cannot find anything to answer my question. If you know where I can find the answer, please let me know.
I have 2 tables on Crystal Report and am trying to link the Primary table to the secondary one with a 'NOT EQUAL' link. ie. I want all the records in the Primary table (about 4000) which Do Not have an entry in the secondary one (about 3500) so I am expecting to get about 500 records.
I have tried with all the various link and Enforce Join options but cannot get the correct results.
I have also tried to link them with an Inner Joint of Equal Type then created a formula of Primary.key.field <> to Secondary.key.field but this is not working either as it returns no records.
Any idea?

Hi All,
This is to let you know that I have now found an answer to my questions (yiha!). So thanks to James Gust who answered a note from Joey041 on March 2nd.
Thanks a lot for being there.
Cheers, Sylvie
Edited by: SylvieWolpert on May 12, 2009 7:31 AM

Link to a crystal report with prompt from xcelsius dashboard

Hi
How can we make a link to a crystal reports with a country promt?
If I named the prompt ContryParam in Crystal.
And I want to open this crystal report by sending f.eks UK as countryname to this report.
What will the link be seeing as in xcelsius?
How will the connection be made from xcelsius to this spesific crystal report`?
BR
Sadaf

Hey Sadaf,
This example uses prompt# to pass "CA" as a value to the first parameter:
http://<servername>:<port>/CrystalRe
ports/viewrpt.cwr?id=1152&prompt0=CA
search for follwing document title for further reading
Viewing Reports and Documents using URLs

Crystal report XI error while Linking tables

We have just purchased Crystal Report XI license copy but as we going to create new report there is problem in linking tables
i.e while pressing LINK tab after selecting ODBC databse name application going shut down.Please suggest.Thanks in advance

I would make verify the database within Crystal report and then re publish it again. It seems it doesn't get the connection to the db.
Have you refreshed the database within Crystal Reports?
As Graham said, does it open in Crystal Viewer?
another thing would be to add the DSN (System DSN) onto your client machine as well. Maybe it is not getting a right connection.
Try it and let us know.
Kind Regards
Jehanzeb

Help with linking tables

Hello,
I am not really sure if this is a site that this question should be asked but I have done alot of searching and can't seem to find an answer so....
I work for a large company that uses Oracle for its databases.
In my department we use access link tables to look at the Oracle data.
In one such database I need to link to the oracle tables but only see certain data when I open the link (like a fliter).
I have no idea how to do this...I just know it can be done.. I have heard that you can use Oracle views to do the filtering on the server side and it would only return the filtered data. I think I have to do this with SQL.
But I really dont know how to go about it.
So I am posting here hoping that you guys could help me or point me in the right direction as I don't even know what questions to ask in google :)
I will be glad to give any information you may need to help me out.
Thanks a Million.

user12063135 wrote:
Hello,
I have heard that you can use Oracle views to do the filtering on the server side and it would only return the filtered data. I think I have to do this with SQL.
Thanks a Million.You heard it right and your thouts are are floating in the right direction.
Use views and you will be fine.

How can I link table KONV with table VBRP and VBRK using KSCHL field?

Hi experts,
How can I link table KONV with table VBRP/VBRK using KSCHL field so that items are fully filtered?
Thanks,

Hi,
If you do not want to specify it as hard code, then define a variable for it if you want to pass the value for it from the selection screen so that it will be dynamic. Code will be as follows.
select-options: x_KSCHL for T685l-KSCHL.
select kwert
           kbetr
           knumv
           kposn
           kschl
      from konv
      into CORRESPONDING FIELDS OF TABLE it_konv
      FOR ALL ENTRIES IN it_all
      where knumv = it_all-knumv
      and   kposn = it_all-b_posnr
      and   kschl in x_KSCHL. "Dynamic Selection as per the selection screen input
endif.
Hope this helps.
Regards,
Chandravadan

SQL query - 2 tables with no relationship

I'm fairly new to SQL, but I'm trying to put together a query using 2 tables. They have no relationship. I'm using this information in a C# app and I'm trying to pull it as clean as possible to use in a class.
For example, I have a table called Server where I am selecting 2 columns,
ServerID and Type. The second table called
App I am selecting the AppVersion column.
Question is how can output the data without duplicate AppVersion values? I would rather see null or empty.
I have tried below along with a CROSS JOIN and I get duplicates in the AppVersion.
SELECT ServerID, Type, AppVersion
FROM Server, App;
I know that is wrong as it outputs duplicates for AppVersion in the results.
Thanks in advance.
A

I didn't get your question. When you cross join two different tables the output is a Cartesian product of the two tables.
The Record (A, 1, 1.1) is different from (B, 1, 1,1).
You can use a distinct to eliminate if you have duplicates in data and you don't want to see them.
SELECT DISTINCT ServerID, Type, AppVersion
FROM Server, App;
Please mark as answer, if this has helped you solve the issue.
Good Luck :) .. visit www.sqlsaga.com for more t-sql code snippets and BI related how to articles.

Migrating 3 access2000 DB's with linked tables to each other

I am trying to migrate 3 access2000 DB's to oracle. The main DB's has linked tables to the other 2 DB's. I have been trying to migrate these seperately. When I try and migrate the main DB, it brings along the other 2 with it. Is this sufficient??

Thx for the post Hilary. I still have some issues with getting this accomplished. I am having trouble moving all 3 access DB's into a single one. I can actually do this, but the app's step all over each other. Two of the DB's have applications and the coding errors out b/c of stepping all over each other. This is a customers DB's and I don't have permissions to change the code at this time, even if its the best way to do this.
So, is it sufficient to do it this way. I got this post earlier last week.
For the description purposes i'm going to migrate tables access1.mdb, access2.mdb, access3.mdb to "access_user" schema in oracle
1. export access1.mdb to c:\test1\access_user.xml [repeat the same for the other 2 mdb's keeping the same export name but in different directories]
2. export access2.mdb to c:\test2\access_user.xml
3. export access3.mdb to c:\test3\access_user.xml
4. Capture the c:\test1\access_user.xml and complete the migration i.e., at the end of this step, you must be able to log into oracle as "access_user" and should be able to see all your tables in it.
5. Now capture c:\test2\access_user.xml and repeat the same steps, this time workbench will fire up an alert saying that access_user tablespace already create --> ignore this error. similarly ignore the "access_user" and "omwb_emulation" creation errors. Note: if you select re-create, this may over ride your previous tables, so I think its safer to ignore this error.
6.Repeat the step #5 for the c:\test3\access_user.xml
7. Now log into the oracle model as "access_user" user and password as "oracle", you must be able to see all your access tables and data.
After doing this, I should have all my tables in the "access_user". The process also created other oracle users at each migration b/c the DB's are linked to each other and as Hilary said before, workbench migrates the linked tables also. This is not a problem if after all 3 have been done, each app now points to the "access_user" and not to any of the other created oracle users. I would need to delete the bogus oracle users and still expect my access applications to correctly point to the "access_user".
Is this the correct way to do this??
Thx for the help
Marty

Linking tables in Crystal with no relationship

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