Listing classes name in known package

Hello!
Can you tell me how to get classes name in a package.
String package = "bla.bla.bla";
And the output is like this
Classes in bla.bla.bla :
- ClassA
- ClassB
- ClassCThank's

That misses any classes in a jar file.forgot about archived.. yeah..that would fail.
you can list files in a directory as shown inreply #1, but not in a java package,
since its contents can be distributed what do you mean? when you compile..the compiler
create a dicrectory structor of the package. the
java.class is a file..so you can list it. (I'm not
sure by what you mean distributed)..if you mean
RMI..then yeah..i missed that point too.not only that
it's common to have many source directories :
/Project
    /src
        /api
           /com/mycompany/myprogram
        /test
           /com/mycompany/myprogram
        /impl
           /com/mycompany/myprogramis something I do a lot
>
I guess you have to use reflection for that..even
with reflection..i don't think you can get all the
class name for RMI application (or those
server-client) application.

Similar Messages

How can i get all java class names from a package using reflection?

hi,
can i get all classes name from a package using reflection or any other way?
If possible plz give the code with example.

You can't, because the package doesn't have to be on the local machine. It could be ANYWHERE.
For example, via a URLClassLoader (ie from the internet) I could load a class called:
com.paperstack.NobodyExpectsTheSpanishInquisitionI haven't written it yet. But I might tomorrow. How are you going to determine if that class is in the package?
This subject comes up a lot. If you want to do something a bit like what you're asking for (but not quite) there are plenty of threads on the subject. Use google and/or the forum search facility to find them.
But the answer to your question, as you asked it, is "you can't do that".

[svn:fx-trunk] 5121: Fixing generated SymbolClass class names to take packages into account during FXG - SWF conversion.

Revision: 5121
Author: [email protected]
Date: 2009-03-01 19:08:01 -0800 (Sun, 01 Mar 2009)
Log Message:
Fixing generated SymbolClass class names to take packages into account during FXG -> SWF conversion.
QE: No
Doc: No
Checkintests: Pass
Reviewer: Discussed with Corey
Modified Paths:
flex/sdk/trunk/modules/compiler/src/java/flex2/compiler/fxg/TextFXGGraphics.java

How to get list of all class names in a package

hi,
how can i get all the names of classes in a specified package, for example, if i want to get all names of
classes in package java.util through java application.

hi,
if u read my question with open eyes , i wrote " with java application" not with java API .

How to get class names in a package ?

If I know a name of a package , is it possible for me to get all the classes in the package ?

YTes...
u can do so,,in SE80..
Give your package for the Dev Class.
Then check under Class Libraray...
Hope it helps.
Praveen

Conflit in class name and package name

I have a small doubt. If the class name and the package name are the same in a folder, is there will be any conflict between these while using it. That means suppose a folder named 'animator' contain a package 'a' and a class name 'a'. I got any error in the 'Eclipse' tool that "a collides with a package". Is this can be solved my any change of setting in Eclipse? If then where can i change.? Can anybody help me to solve this issue??

This works fine: just add an import to Test.java.
import PackageName.MyClass;
public class Test
    public static void main(String [] args)
        MyClass a = new MyClass();
public class PackageName {}
package PackageName;
public class MyClass {}It's a pretty wacky, useless example, but it works.
Plus I thought inner classes would have a dollar sign in their .class file names. When I compile this:
public class OuterClass
    public static void main(String [] args)
        OuterClass outer = new OuterClass();
        System.out.println(outer);
    public String toString() { return "I'm an OuterClass"; }
    class InnerClass
        public String toString() { return "I'm an InnerClass"; }
}I see two .class files: OuterClass.class and OuterClass$InnerClass.class
Why make up examples like this? It's hard enough writing code, and it's easy to disambiguate for the compiler.

Files with same name in different packages

I have a file with the same name defined in two different packages.
When I generate the javadoc, I get an error saying that
Class com.eg.toolkit.Email already defined in com.eg.common.Email.java
Does javadoc expect all files to be of different names acroos packages?
Thanks
Chintu

You can use the same class name in different packages.
The Java API does that (java.awt.List, java.util.List).
This is odd. What version of javadoc are you using,
and what command are you passing in, with what classpath setting?
-Doug Kramer
javadoc team

Non fully qualified class names in parameter list

Hi Folks,
When I generate my documentation the fully qualified class names (for each parameter) appear in the parameter list for methods. In looking at the documentation on this site, a hyperlink to the class using the only the class name appears. Can anyone provide thoughts on how this is achieved? Thanks.

The -link and -linkoffline options enable the documents to link to other API documentation
generated in separate runs of javadoc. Linkoffline is usually the one you want.
http://java.sun.com/j2se/1.4/docs/tooldocs/win32/javadoc.html#linkoffline
With 1.4.0, you can also choose to omit the package name even if -link or -linkoffline
is not used by using -noqualifier.
-Doug Kramer
Javadoc team

Class name and package names

I read a passage from some Java Book (sorry don't have the reference handy) that
"It is illegal for a package and a class to have the same name, so there can be no ambiguity."
Yet I have created a class named pkgclass within a package with the very same name.
i.e.
package pkgclass;
public class pkgclass {
This compiles just fine. Have I misinterpreted the statement from the book? What is it trying to say?
Thanks in advance.

Here's a quote from the Java language spec:
"The hierarchical naming structure for packages is intended to be convenient for organizing related packages in a conventional manner, but has no significance in itself other than the prohibition against a package having a subpackage with the same simple name as a top level type (�7.6) declared in that package."
So your book was not quite correct, or maybe you just misremembered it (clearly you are typing from memory there). It isn't illegal for a package to have the same name as a class, as in your example. But it is illegal for a package to contain a subpackage and a class with the same name.

Class name and package name clashing

When i have a class and a package with the same name, I cannot access classes in the package. For example I have 3 classes and 1 package as below
- Test.java
- PackageName.java
+ PackageName // this is a directory
- MyClass.java
Below are the codes of .java files
Test.java
=======
public class Test { PackageName.MyClass a = new PackageName.MyClass ();}
PackageName.java
===============
public class PackageName{ }
MyClass.java
==========
package PackageName; public class MyClass { }
I can compile PackageName.java and MyClass.java but not Test.java. It says
cannot resolve symbol
symbol : class MyClass
location: class PackageName
PackageName.MyClass a = new PackageName.MyClass ();
But if I remove the PackageName.java, I can compile Test.java perfectly. I think when I use PackageName.MyClass, java thinks that I try to access an inner class MyClass of PackageName class, and that does not exists. Is there any way to solve this ambiguation, other than making the package name and class name different? Thank you very much.

This works fine: just add an import to Test.java.
import PackageName.MyClass;
public class Test
    public static void main(String [] args)
        MyClass a = new MyClass();
public class PackageName {}
package PackageName;
public class MyClass {}It's a pretty wacky, useless example, but it works.
Plus I thought inner classes would have a dollar sign in their .class file names. When I compile this:
public class OuterClass
    public static void main(String [] args)
        OuterClass outer = new OuterClass();
        System.out.println(outer);
    public String toString() { return "I'm an OuterClass"; }
    class InnerClass
        public String toString() { return "I'm an InnerClass"; }
}I see two .class files: OuterClass.class and OuterClass$InnerClass.class
Why make up examples like this? It's hard enough writing code, and it's easy to disambiguate for the compiler.

Getting 'binary name' of the package of a given class

I needed this for a kind of dynamic class loader, where the binary name of the package of an object was required. What made it more complex is that the classpath of the object is not the local filesystem path, where the java executable was invoked (such as 'bin' in an eclipse project)
I searched the forum, and didn't find a solution that addresses all of these problems. Finally I came up with my own solution, and I'll share it with you (also because there might be some bright minds who can tell me it can be done much simpler (which I hope))
@SuppressWarnings("null")
public static String getPathFromClass(Class< ? > rootClass) throws FileNotFoundException
     String rootPath;
          // These are all the possible directories where the package root
          // exists (relative to where the java executable might be invoked).
          String systemPaths[] = {"bin", "."};
          File root = null;
          for (String systemPath : systemPaths)
               root = new File(systemPath);
               if (root.exists())
                    break;
          if (!root.exists() || !root.isDirectory())
               throw new FileNotFoundException("No package root found");
          rootPath = root.getAbsolutePath();
     String localPath;
     try
          localPath = new File(rootClass.getResource(".").toURI()).getPath();
     catch (URISyntaxException e)
          // Should never happen; Hack to prevent unjust error.
          localPath = "";
     if (!localPath.startsWith(rootPath))
          // What's going on ??
          throw new FileNotFoundException("Class' local path not inside package root");
     return localPath.substring(rootPath.length() + 1).replace(File.separatorChar, '.');
}Example:
main class is in c:\projects\test\bin\test\mj\foo\Main.class (package declaration sais "test.mj.foo".)
java.exe is executed from c:\projects\test\
calling this method with an instance of the Main class returns: "test.mj.foo".

As far as I can tell it just returns the package root (such as "c:\projects\test\bin"), but because of that, it does greatly simplify the first part of my function. Thanks.
String rootPath = new File(rootClass.getProtectionDomain().getCodeSource().getLocation().toURI()).getPath();
String localPath;
...A binary name (as mentioned in the Java Language Specification) is a representation of a fully qualified java class, such as "java.lang.String". A "binary name of a package" as I mentioned is just my way of meaning anything like "java.lang".

Need class name to display ALV list (not Grid) in objects..

hi,
i need to display ALV list ( not ALV Grid ) in objects.. i dont the class name for tat.. so plz can anyone help me out for the same..
thanks in advance..

With cl_salv_table you can have both grid or list, depending what you want.
      cl_salv_table=>factory(
         EXPORTING
           list_display   = 'X' "when space then GRID, when 'X' then LIST
         IMPORTING
           r_salv_table = ref_table
         CHANGING
           t_table       = gt_sflight ).
Regards
Marcin

"Name not known" error in all PCR of the MSS Package

Hi,
I'm getting an error in the PCR workset of the MSS package.
When I submit any form the error which I get is
"Name not known.Check your entries" .
Is this due to some problem in R/3 settings?
Also when I submit a PCR "Request for separation(enhanced)" I get an exception.
The log entry for this exception is as follows:
_27##0#0#Error#1#com.sap.sup.admin.connector.AbapConnectorLauncher#Plain###Cannot start ABAP Connector Listener. Please try to configure the connection in ABAP Systems Management (Setup Local Connectivity).

Hi Justin,
With other words, you are using the BP for MSS 60.1.5 or later.
Can you connect to the backend via a Java Connection?
Also this link will guide you much further. It helped me a lot for the new MSS forms (ECC 50).
The ISR Cookbook can be found here!
http://www.service.sap.com/isr
regards,
Noel

Getting class name without it's package.

Hi.
How can I get only class name of an object?
obj.getClass().getName() returns the full package hierarchy.
Any simple ideas?

Is there any method that do it automatically?What do you mean automatically? You mean a single method so that you don't have to write any code? That's a very small amount of code to write, and you can put it inside a method you create yourself.
Or you could use regex, though some may find that to be overkill. String classOnly = theClass.getName().replaceAll(".*\\.(.*)", "$1");

Deploy java stored proc. publishes java class names without package name

Hi to All,
Using JDevStudio 10132 I've created a 'Loadjava and Java Stored Procedure' deployment profile for my project. I've added my static method to the deplyment profile, but it generates script without java packege name, only pure class name.
For example it executes: ...
CREATE OR REPLACE PROCEDURE Procedure1(p1 IN VARCHAR2) AUTHID CURRENT_USER AS LANGUAGE JAVA NAME 'CryptoHelper.Procedure1(java.lang.String)';
instead of
CREATE OR REPLACE PROCEDURE Procedure1(p1 IN VARCHAR2) AUTHID CURRENT_USER AS LANGUAGE JAVA NAME 'mypackege.xxx.yyy.CryptoHelper.Procedure1(java.lang.String)';
The CryproHelper class is definitely in mypackage.xxx.yyy package and JDeveloper Application Navigator shows correctly it.
Any ideas?
thx fo answers

Hi,
I've just been doing this on 10133 and found exactly the same thing. It's an easy fix to edit the package body - but it's rather annoying to have to manually do something that should just work.
Steve
*Hand editing the .deploy file to add in the package name works.
Message was edited by:
spilgrim

Listing classes name in known package

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