Locate an occurrence of symbols at the very beginning of the string

Question

Hi all,
select 'jeklghje, s.Glkgje, u.slgjwek, 904869' as tt from dual union all
select 'Ueklghje, s.Glkgje, u.slgjwek, 904869' as tt from dual union all
select 'Uek88lghje, s.Glkgje, u.slgjwek, 904869' as tt from dual union all
select '397348, Ueklghje, s.Glkgje, u.slgjwek, 904869' as tt from dual union all
select 's.Tklgj, u.slgjwek, 23578, elslgjs' as tt from dual union all
select 's.klgj, u.ekgjes, 238573, dlsjkgj' as tt from dualMy need is to find word at the very beginning of the string, it starts with capital letter, consists of letters only and ends with ", " (comma and space), it's "Ueklghje, " in this test case.

Answer 1

If you see your previous post carefully, you yourself can get the answer.
Re: locate an occurrence of symbols combination
"^" This means the start of a line.
SQL>select regexp_substr('Udfdfdfdd 232dfdfdd','^[A-Z][[:alnum:]]* ') as test from dual;
TEST
Udfdfdfdd
1 row selected.
Elapsed: 00:00:00.00
SQL>Now apply the same logic with your statement.