Making a one to many relation it to columns per entry of the many relation

Question

CREATE TABLE main (id number, data varchar2(20));
INSERT INTO main values (1,'some data1');
INSERT INTO main values (2,'some data2');
CREATE TABLE sub(main_id number, data varchar2(20), value number);
INSERT INTO sub values (1,'data1', 10);
INSERT INTO sub values (1,'data2', 5);
INSERT INTO sub values (2,'data3', 10);
INSERT INTO sub values (2,'data4', 30);
INSERT INTO sub values (2,'data5', 20);
I want a result like this
id | data | sub1 | sub2 | sub3
1, some data1, data1, data2, NULL
2, some data2, data4, data5, data1
That is sub1 is the value sub.data that has the largest value, sub2 is the second largest and so on.
This is the closest I can get. Is there a way to make the where main_id = 1 dynamic so instead of 1 it refeers to the value of main.id? Or is there a different query that will give me the result I'm looking for?
SELECT main.id, main.data, sub1.data sub1, sub2.data sub2, sub3.data sub3
FROM main
full outer join
(SELECT main_id, data, value
FROM(SELECT main_id, data, value, rownum rn
FROM(SELECT *
FROM sub
WHERE main_id = 1
ORDER BY value desc))
WHERE rn = 1) sub1
on main.id = sub1.main_id
full outer join
(SELECT main_id, data, value
FROM(SELECT main_id, data, value, rownum rn
FROM(SELECT *
FROM sub
WHERE main_id = 1
ORDER BY value desc))
WHERE rn = 2) sub2
on main.id = sub2.main_id
full outer join
(SELECT main_id, data, value
FROM(SELECT main_id, data, value, rownum rn
FROM(SELECT *
FROM sub
WHERE main_id = 1
ORDER BY value desc))
WHERE rn = 3) sub3
on main.id = sub3.main_id
ID     DATA     SUB1     SUB2     SUB3
2     some data2     -      -      -
1     some data1     data1     data2     -

Answer 1

SQL> select main.id
  2       , main.data
  3       , max(decode(sub.rn,1,sub.data)) "sub1"
  4       , max(decode(sub.rn,2,sub.data)) "sub2"
  5       , max(decode(sub.rn,3,sub.data)) "sub3"
  6    from main
  7       , (select t.*, row_number() over (partition by main_id order by data) rn from sub t) sub
  8   where sub.main_id = main.id
  9   group by main.id
10       , main.data
11  /
        ID DATA                 sub1                 sub2                 sub3
         1 some data1           data1                data2
         2 some data2           data3                data4                data5
2 rijen zijn geselecteerd.Regards,
Rob.