Material code line repeats with same values in a Query

Hi Experts,
I have created a small query (SQVI) to fetch the material master details of a plant. I see a lot a material codes repeating with the same data in each report I extract. So everytime I have to download the report to an excel, filter and then submit to users.
Please advise your thoughts
Tables used (in order) MARC > MBEW > MARA > MAKT
Primary input fields are Plant & Material code
other input fields are Material group and Material type
Output fields are
Plant
Material code
UOM
Mat Type
Description
Old Material number
Mat group
MAP
Std Price
Val class
Proc type
Special Proc type
Please help with your valuable inputs
Thanks,
Rajoo

if a material has descriptions in sveal languages, then you get one record per language.
if your material have split valuation active, then you get one record per valuation type.
Add teh language to your selection to select only the description of a certain language (do the same for valuation type if your material is split valuated)

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In this scenario no further payment should be made.
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Hi Ahmed
Thanx for your response...............
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>> would like to understand how sql server 2008 deals with cascade updates <<
Your posting has a number of conceptual errors.
1. The terms “parent” and “child” are not RDBMS; they are used in network databases. We have “referenced” and “referencing” tables; they can be the same table.
2. A table models a SET of things, so there is no “Employee” table unless you truly have a one-man company. We want a collective or plural name for the SET/table. A better name is “Personnel” for this table.
3. Her is no such thing as a generic “id” in RDBMS; it has to be “<something in particular>_id” to be valid. Identifiers are usually fixed length
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5. The ISO standard uses “<property>_<attribute property>” syntax, no the old PascalCase.
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CREATE TABLE Personnel
(emp_id CHAR(20) NOT NULL PRIMARY KEY,
emp_name VARCHAR(25) NOT NULL,
CREATE TABLE Health_Plan
(health_plan_acct CHAR(20) NOT NULL PRIMARY KEY,
emp_id CHAR(20) NOT NULL
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ON DELETE CASCADE,
Scenario 1:
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Scenario 2:
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WHERE emp_id = 'ABC';
This time, I am doing something different. I am beside UPDATE of column emp_name with new value, also UPDATE PRIMARY KEY but
with SAME value.
>> Question is: what is going to happen to child [sic: referencing] rows? Are they ALL going to UPDATE due to CASCADE UPDATE. <<
SQL uses a set-oriented model, so the whole table is updated as a unit of work in theory.
So far, what I did in order to find solution is:
>> I put an timestamp column in child [sic: referencing] table that should UPDATE each time row gets updated <<
Why? It is not in the SET clause list; it cannot change. As an aside, The T-SQL TIMESTAMP is not the ANSI/ISO TIMESTAMP; it is DATETIME2(n) in T-SQL. The old TIMESTAMP is being deprecated because it stinks both in concept and implementation.
>> I put a trigger for UPDATE event on child [sic: referencing] table that will write something to some log table.<<
TRIGGERs are fired by what is called a “database event” shown in the ON [DELETE | UPDATE] clause. T-SQL adds INSERT as an event. An update to any value or to no value at all is still an update. Depending on the collation, case may or may not matter in the final
outcome.
--CELKO-- Books in Celko Series for Morgan-Kaufmann Publishing: Analytics and OLAP in SQL / Data and Databases: Concepts in Practice Data / Measurements and Standards in SQL SQL for Smarties / SQL Programming Style / SQL Puzzles and Answers / Thinking
in Sets / Trees and Hierarchies in SQL

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select 1,      'SHOP_C' from dual union all
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select 3,      'SHOP_C' from dual union all
select 4,      'SHOP_C' from dual union all
select 5,      'SHOP_A' from dual union all
select 6,      'SHOP_A' from dual union all
select 7,      'SHOP_C' from dual union all
select 8,      'SHOP_B' from dual union all
select 9,      'SHOP_B' from dual union all
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select 11,     'SHOP_A' from dual union all
select 12,     'SHOP_D' from dual union all
select 13,     'SHOP_D' from dual union all
select 14,     'SHOP_F' from dual union all
select 15,     'SHOP_G' from dual union all
select 16,     'SHOP_F' from dual union all
select 17,     'SHOP_C' from dual union all
select 18,     'SHOP_C' from dual union all
select 19,     'SHOP_C' from dual union all
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     4 SHOP_C    3
     5 SHOP_A    4
     6 SHOP_A    4
     7 SHOP_C    5
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     9 SHOP_B    6
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    11 SHOP_A    8
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    13 SHOP_D    9
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