Merging data in table rows into single page form to be printed?

Hello all,
I've been trying to make this work but after much hair pulling have had no luck with it.
I have a three page pdf. On the first page are two tabls of employee names. Each row in the tables includes a cell for the employee name and also one that holds a checkbox. 
The second and third pages are time sheets appropriate for the department that each employee is in. These two pages are hidden.
So the idea is that if a particular employee is selected by the check mark, a time sheet with his name, dates and other info would be printed. One department is straightforward in that there is one sheet per employee.
The trouble is with the other department, in that for that department, each time sheet has four columns, at the top of each goes one employee's name. So the logic for this department is as follows:
1. count how many names are selected
2. if four or less are selected, enter first selected name into the first row of the first column, the second into the first rown of the second column, the third into the first row of the third colum etc.  
3. if more than four are selected, enter the first four names into the first page, print the page, and enter the remaining into the second page and print, and so on until all selected names are processed.
1. works fine
2. works fine
3. works but not correctly.
So if I have say six names selected, for example, aaa, ,bbb, ccc, ddd, eee, and fff what end at the top of the columns on first page is:
eee, fff, ccc, ddd  and on the second page its the same thing
The actual bit of formcalc script to do this is below, obviously it is incorrect or else missing something.
Any pointers and suggestions (in formcalc if possible) would be very welcome and appreciated.
Thanks.
// use a for loop to count number of names selected. tabel has 15 employee names
for i = 0 upto 14 do
      if ((not (form1.main.front.Table2.Row[i].dbmname.isNull | form1.main.front.Table2.Row[i].dbmname == "")) and (form1.main.front.Table2.Row[i].Checkbox == 1)) then    
               ns = ns + 1    // ns = number of names selected
      endif
endfor
for i = 0 upto 14 do                         //if any names are selected then process and print desk and maintenance sheet
                                                       //check to see if selected rows are not empty     
               if ((not (form1.main.front.Table2.Row[i].dbmname.isNull | form1.main.front.Table2.Row[i].dbmname == "")) and (form1.main.front.Table2.Row[i].Checkbox == 1)) then
                                                      //enter first selected name into column 1 and second into colum 2 etc... 
             form1.dbm_sheet.Table3.header2.dbm_name[np] = form1.main.front.Table2.Row[i].dbmname.rawValue 
                                                       //np = name position to select next column that the next name will go into
              np = np + 1
                                                       //ok - check if number of names selected was 4 or more and if first four names have been entered, lets print the first timesheet
              if ((ns >= 4) and (np == 4)) then
                        xfa.host.print(1, "2", "2", 1, 1, 0, 0, 0)          //print sheet
                                                       //first sheet with 4 names is printed, therefore reduce ns by 4
                        ns = ns - 4
                                                       //first sheet printed, reset np to zero
                        np = 0
                                                      //if less than 4 names were selected OR are left after printing first 4 then process remaining names
            elseif ((ns  < 4) and (np == ns)) then
                                             xfa.host.print(1, "2", "2", 1, 1, 0, 0, 0)
                                                    // blank remaining columns that are supposed to be empty : if there are less than four names to be printed on the sheet
                for i = (np) upto 3 do
                                                                      form1.dbm_sheet.Table3.header2.dbm_name[np] = ""
             endfor        
        endif
                    endfor
  endif
  endfor

helo DV,
to insert a new node element in the resulting model node following code can he used.
wdContext.node<Node name>().validate();
IPublic<controller>.I<node>Element ele = wdContext.create<node>Element(new <model structure type>());
ele.set<attribute name>("<value>");
wdContext.node<node name>().addElement(ele);
now to traverse the model node and change a column value following code can be used.
for(int i=0;i<wdContext.node<node name>().size();i++
IPublic<controller>.I<node>Element ele = wdContext.node<node name>().get<node name>ElementAt(i);
ele.set<attribute name>("");
Regards,
Piyush.

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        <ZipCode>51012</ZipCode>
        <Name>Processors</Name>
      </Row>
    </Data>

    Hi there,
    Your discussion was moved to the Acrobat Forms forum: the folks here should be well suited to answer your question.
    Best,
    Sara

  • Combining Multiple Rows into single row with multple columns

    Hi Experts,
    I have the following requirement, kindly help me.
    I have data in my table like below.
    ID NAME DEPT
    1 Sam 10
    1 Sam 20
    2 alex     30
    2 alex 40
    2 alex 50
    3 vinod 60
    3 vinod 70
    I want to show the same data into single row with dynamically generating columns for DEPT. I want show like below.
    ID NAME DEPT1 DEPT2 DEPT3
    1 Sam 10 20
    2 alex 30 40 50
    3 vinod 60 70
    It's urgent requirement, kindly help me.
    Thanks in advance.

    Right I've had my drink, so what was this "urgent" question then?
    798616 wrote:
    I have data in my table like below.
    ID NAME DEPT
    1 Sam 10
    1 Sam 20
    2 alex     30
    2 alex 40
    2 alex 50
    3 vinod 60
    3 vinod 70
    I want to show the same data into single row with dynamically generating columns for DEPT. I want show like below.Dynamic numbers of columns eh! Tricky.
    If you understand how SQL statements are executed it's along these lines...
    1. Open Cursor
    2. Parse SQL statement and determine columns
    3. Bind in any input values
    4. Fetch data
    5. Bind out values to columns
    6. Repeat step 3 until no more data
    7. Close cursor
    Now, you're expecting that you can determine the columns (step 2) from the fetched data (step 4 onwards). You can't. The SQL engine needs to know the expected columns before any data is fetched so, it can't base the number of columns on the data itself.
    If you need that requirement, you would need to query the data first and build up a dynamic query based on the data and then execute that dynamically built query to fetch the data and pivot it into those columns, which means that you have queried the data twice. Not good practice and not good (or simple) coding.
    What you're talking of doing is something that should be handled at the presentation/interface layer, not as part of the data fetch.
    Typically these sorts of things are handled most easily in report generation/writer tools such as Oracle Reports, Business Objects etc. where they fetch the data from the database and then process it to format it on the display, pivoting the results as required.
    It's not something that lends itself to be easily achieved in SQL. Yes, SQL can do pivoting of data quite easily, but NOT with a dynamic number of columns.
    If you were to specify that there is a maximum number of columns that you could get (rather than wanting it dynamic), then you can do it simply in SQL with the max-decode method...
    SQL> ed
    Wrote file afiedt.buf
      1  with t as (select deptno, ename, row_number() over (partition by deptno order by ename) as rn from emp)
      2  --
      3  select deptno
      4        ,max(decode(rn,1,ename)) as ename1
      5        ,max(decode(rn,2,ename)) as ename2
      6        ,max(decode(rn,3,ename)) as ename3
      7        ,max(decode(rn,4,ename)) as ename4
      8        ,max(decode(rn,5,ename)) as ename5
      9        ,max(decode(rn,6,ename)) as ename6
    10        ,max(decode(rn,7,ename)) as ename7
    11        ,max(decode(rn,8,ename)) as ename8
    12        ,max(decode(rn,9,ename)) as ename9
    13        ,max(decode(rn,10,ename)) as ename10
    14  from t
    15  group by deptno
    16* order by deptno
    SQL> /
        DEPTNO ENAME1     ENAME2     ENAME3     ENAME4     ENAME5     ENAME6     ENAME7     ENAME8     ENAME9     ENAME10
            10 CLARK      KING       MILLER
            20 ADAMS      FORD       JONES      SCOTT      SMITH
            30 ALLEN      BLAKE      JAMES      MARTIN     TURNER     WARD
    SQL>

  • Need to split data from one row into a new row redux

    Hi folks,
    I asked this question about eight months ago (see thread https://discussions.apple.com/message/23961353#23961353) and got an excellent response from forum regular Wayne Contello.  However, I need to perform this operation again and when I attempted it recently, I am now greeted with a yellow warning triangle.  Clicking it shows "This formula can’t reference its own cell, or depend on another formula that references this cell."
    What I'm trying to do is the following:
    I have an excel file that keeps track of members of a social group.  The file places each member "unit" on a single row.  The unit can be a single person or a couple.  Columns are labeled "First1" "Last1" "Hometown1" "B-day1" while the second member of the unit is identified in columns like "First2" "Last2" etc.
    What I'd like to do is duplicate those rows with two people (which I'll do by hand) but have a way of deleting the "xxxx2" data from one row and the "xxxx1" data from the duplicate row.
    Wayne's illustrated solution was to create a blank sheet and enter the following formula in cell A2:
    =OFFSET(Input Data::$A$2, INT((ROW()−2)÷2), COLUMN()−1+IF(MOD(ROW()−2, 2)=0, 0, 4)), which apparently worked fine for me last year but now is sending up an error flag.  When I look at the formula, there is no clue except that which I quoted above.
    Can anyone (or hopefully Wayne) take a second look at this and help me out?  I can't imagine that it's a problem with using the newer version of Numbers, but who knows?  I'm using version 3.2 (1861), which is the "new" Numbers.
    Any help would really be appreciated.
    Thanks!
    -Tod

    Hi Tod,
    The error message "This formula can’t reference its own cell, or depend on another formula that references this cell." may be because your table may be different from the one you were using for Wayne's solution. Numbers has Header Rows, Footer Rows and Header Columns. Such Headers in tables exclude themselves from formulas. Excel does not recognise them as headers. What table are you using now?
    A screen shot of (the top left portion of) your table or a description of what you see under Menu > Table will help.
    Regards,
    Ian.

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