Missing something obvious (batch process with ffmpeg)

Question

I have a number of video clips in .mov format. I want to trim the first four seconds from each, and save with a new name. This script works fine:
#!/bin/sh
ffmpeg -i clip1.mov -vcodec copy -acodec copy -ss 00:00:04 clip1trim.mov
ffmpeg -i clip2.mov -vcodec copy -acodec copy -ss 00:00:04 clip2trim.mov
ffmpeg -i clip3.mov -vcodec copy -acodec copy -ss 00:00:04 clip3trim.mov
and etc. I have quite a number of these.
Being 'typing lazy' I figured something like this would work:
#!/bin/sh
for f in *.mov;
do
echo "Procesing $f"
ffmpeg -i "$f"  -vcodec copy -acodec copy -ss 00:00:04  "${f%.mov}trim.mov"
done
I know only enough shell scripting to be dangerous, but I figured the problem had to do with quoting or shell substitution -- two topics I am weak on.
Instead it tries to run each file and throws this error:
"Unable to find a suitable output format for ' -vcodec'"
Anyway, I appreciate any help.
Andy

Answer 1

#!/bin/sh
for f in *.mov
do
echo "Procesing $f"
ffmpeg -i "$f" -vcodec copy -acodec copy -ss 00:00:04 "${f%.mov}trim.mov"
done
Your script actually looks rather good.
I can not see anything wrong with it from a scripting point of view.
You might try running the script using
sh -x your.script
which should show you want the actually ffmpeg command looks like after the substitution has occurred.