More than one conequent in an association rule possible with SQL Developer?

Dear experts
Is it somehow possible to show more than one element in the consequence? According to the article http://docs.oracle.com/cd/B28359_01/datamine.111/b28129/algo_apriori.htm#autoId2 it seems not to be possible:
"Oracle Data Mining supports association rules that have one or more items in the antecedent and a single item in the consequent."
But is it somehow possible to (mathematically?) prove that e.g. xx, yy -> zz is the same as zz -> xx, yy? Or is there any other way to show more consequent items?
For example I have the rule a,b,c -> d, e. How can I find this rule with the limitation of a single element in the consequence?
Any help will be apreciated!
Thanks in advance.

Hi,
The Oracle AR model only has one consequent.
You can, however, write queries to extract out rules of interest that are filtered by both antecedent and consequent items along with other metrics.
See the GET_ASSOCIATION_RULES pl/sql api doc: http://docs.oracle.com/cd/E11882_01/appdev.112/e25788/d_datmin.htm#ARPLS65840
Here is an example of such a query:
SELECT t.rule_id rule_id,
  t.rule_support rule_support,
  t.rule_confidence rule_confidence,
  t.rule_lift rule_lift,
  t.antecedent,
  t.consequent,
  t.number_of_items rule_length,
  t.antecedent_support rule_antecedent_support,
  t.consequent_support rule_consequent_support
FROM TABLE(dbms_data_mining.get_association_rules('SALES62992_AS', 100, NULL, .10, .01, 5, 1, dmsys.ora_mining_varchar2_nt('RULE_CONFIDENCE DESC', 'RULE_SUPPORT DESC'), DM_ITEMS(DM_ITEM('PROD_ID','23',NULL,NULL)), DM_ITEMS(DM_ITEM('PROD_ID','25',NULL,NULL), DM_ITEM('PROD_ID','26',NULL,NULL)),.10)) t
ORDER BY rule_idThanks, Mark

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                                               name    = 'tableView'
                                               id      = 'tv1' ).
    IF table IS NOT INITIAL .
      tv_data = table->data .
      IF NOT tv_data IS INITIAL .
        CALL METHOD tv_data->get_row_filter_value
          EXPORTING
            column_index = 6
          RECEIVING
            value        = filter_value.
        IF NOT filter_value IS INITIAL .
          TRANSLATE filter_value TO UPPER CASE .
          REFRESH fil_val .
          SPLIT filter_value AT ',' INTO TABLE fil_val .
          CLEAR fil_val_wa .
          LOOP AT fil_val INTO fil_val_wa .
            filter_wa-sign = 'I' .
            filter_wa-option = 'EQ' .
            filter_wa-low = fil_val_wa .
            APPEND filter_wa TO filtertab .
          ENDLOOP .
        ELSE .
          REFRESH filtertab .
        ENDIF .
      ENDIF .
    ENDIF .
    Regards
    Raja

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