Multiple input on one line

Question

Originally had a program to input 5 numbers then put into an array and sort in order. I used seperate lines for each inputted number but want to get the user to put all five numbers on the same line therefore reducing the amount of code. For this I've used args[0] to args[4] as the five different numbers but I now get an arrayindexoutofbounds exception. I can't see where the difference is from the first program to this new one. It's probably an oversight somewhere. Any ideas?
Thanks,
Chris
//The purpose of this is to take 5 numbers from the user and puts numbers into order and also calculates average
import java.io.BufferedReader;
import java.io.InputStreamReader;
class Statistics1
     static BufferedReader b;
     public static void main(String[]args)
     throws java.io.IOException
          //Define variables
          b=new BufferedReader(new InputStreamReader(System.in));
          double input_number[]; //creates array called input_number which will be a double
          input_number=new double[5]; //5 elements in array
          double one,two,three,four,five;
          String str; //5 numbers inputted by user
          //This part of the program takes the five inputs from the user and converts them into an integer and puts into array.
          System.out.println("Input 5 numbers and press [Enter]");
          str=b.readLine();
          one=Integer.parseInt(args[0]);
          input_number[0]=one;
          two=Integer.parseInt(args[1]);
          input_number[1]=two;
          three=Integer.parseInt(args[2]);
          input_number[2]=three;
          four=Integer.parseInt(args[3]);
          input_number[3]=four;
          five=Integer.parseInt(args[4]);
          input_number[4]=five;
          //This loop is designed to use the bubblesort method to arrange numbers in order and print them to screen
          double tmp; //has to be double as array is a double
          for(int x=0;x<input_number.length-1;x++)
               for (int y=x+1;y<input_number.length;y++)
                    if (input_number[x]>input_number[y])
                         tmp=input_number[x];
                         input_number[x]=input_number[y];
                         input_number[y]=tmp;
          for (int x=0;x<input_number.length;x++)
          System.out.println(input_number[x]);
     System.out.println("These are your numbers in order");
          //This loop is to calculate the average and prints to screen
          int e; //representing the individual elements of the array
          double sum=0;
          for(e=0;e<5;e++) //e<5 as arrays are numbered from 0
          sum=sum + input_number[e];
          System.out.println("The average is " + sum/5);
}

Answer 1

Sorry about late reply. To explain I'm a complete biff at java and have scoured a few reference books on how to implement the string tokenizer. My effort is below but str1 to str5 don't initialise. Could you please point me in the right direction.
Thanks again,
Chris
//The purpose of this is to take 5 numbers from the user and puts numbers into order and also calculates average
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
class Statistics1
     static BufferedReader b;
     public static void main(String[]args)
     throws java.io.IOException
          //Define variables
          StringTokenizer st=new StringTokenizer(" ");
          b=new BufferedReader(new InputStreamReader(System.in));
          double input_number[]; //creates array called input_number which will be a double
          input_number=new double[5]; //5 elements in array
          double one,two,three,four,five;
          String str; //5 numbers inputted by user
          String str1,str2,str3,str4,str5;
          //This part of the program takes the five inputs from the user and converts them into an integer and puts into array.
          System.out.println("Input 5 numbers and press [Enter]");
          str=b.readLine();
          while(st.hasMoreTokens())
               str1=st.nextToken();
               str2=st.nextToken();
               str3=st.nextToken();
               str4=st.nextToken();
               str5=st.nextToken();
          one=Integer.parseInt(str1);
          two=Integer.parseInt(str2);
          three=Integer.parseInt(str3);
          four=Integer.parseInt(str4);
          five=Integer.parseInt(str5);
          input_number[0]=one;
          input_number[1]=two;
          input_number[3]=three;
          input_number[4]=four;
          input_number[5]=five;
          //This loop is designed to use the bubblesort method to arrange numbers in order and print them to screen
          double tmp; //has to be double as array is a double
          for(int x=0;x<input_number.length-1;x++)
               for (int y=x+1;y<input_number.length;y++)
                    if (input_number[x]>input_number[y])
                         tmp=input_number[x];
                         input_number[x]=input_number[y];
                         input_number[y]=tmp;
          for (int x=0;x<input_number.length;x++)
          System.out.println(input_number[x]);
     System.out.println("These are your numbers in order");
          //This loop is to calculate the average and prints to screen
          int e; //representing the individual elements of the array
          double sum=0;
          for(e=0;e<5;e++) //e<5 as arrays are numbered from 0
          sum=sum + input_number[e];
          System.out.println("The average is " + sum/5);
}