Need help compiling an EJB with Apache Tomcat 5.5

Hi everyone, I need some help. I�m writing an EJB that has to run on Apache Tomcat 5.5.
I�m importing the javax.ejb.* library, but Eclipse can�t find the JAR it needs. Where can I find this JAR? Do I have to download or what?
Thanks a lot.

Thanks, I�ve already downloaded the javaee.jar from the Sun webpage. As you can see I�m quite new to EJB developing. I want to create an EJB that will get some information from a database and send it back to a servlet, and then a web page. I've been browsing the JBoss page, and I see there are LOTS of versions. Any suggestion, regarding which version I shoud use for this? Thanks a lot again.

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Servlet mapping with Apache + Tomcat

I'm trying to set up my servlet with apache + Tomcat(3.2.3), and i'm using mod_jk as the Tomcat-Apache plug-in.
The HelloWorld servlet that comes with the examples app worked fine at: http://localhost/examples/servlet/HelloWorldExample,
but how do I change the configurations, so that it can be invoked at:
http://localhost/examples/HelloWorldExample ?
It appears to me that '/servlet/' is the default prefix for Tomcat's RequestInterceptor, there is no way to get around that.
Any insights will be greatly appreciated, thanks!
Elaine

hi
Try this:
add below code in web.xml file in examples/WEB-INF
F directory
<servlet-mapping>
<servlet-name>
HelloWorldExample
</servlet-name>
<url-pattern>
/HelloWorldExample
</url-pattern>
</servlet-mapping>
Thanks for the reply, the web.xml is already set up this way, in fact, I'm able to invoke the servlet through tomcat(running on port 8080): http://localhost:8080/examples/HelloWorldExample,
tomcat reads the web.xml without any problems.
The problem comes from Apache(port 80), http://localhost:80/examples/HelloWorldExample wouldn't work, only http://localhost:80/examples/servlet/HelloWorldExample works.
It appears to me that when requests are relayed from Apache to tomcat, you need to tell tomcat that you intend to invoke a servlet by prefixing '/servlet/', if you look in the server.xml, it has
<RequestInterceptor
className="org.apache.tomcat.request.InvokerInterceptor"
debug="0" prefix="/servlet/" />
I've tried to change this to something else, it didn't seem to make any difference.

Need help on struts configuration with ColdFusion 10 using IIS

We need help on struts configuration with ColdFusion 10 using IIS.
Earlier we were using ColdFusion 8 with IIS 6 for one of our application. This application internally calls struts. After upgrading to ColdFusion 10 struts calls are not loading. We get 404 error.
In ColdFusion 8 struts were configured using actions extension .do in IIS from this file-
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Duane wrote:
doctormirabilis, Welcome to the discussion area!
1) how can i configure the time capsule in order to operate as a remote base station synchronizing with the relay using the ethernet port?
Configure the Time Capsule to act as a bridge (not distributing IP addresses). Also configure the Time Capsule to create an 802.11n wireless network with a unique network name (SSID). That's it.
2) how can i avoid that my powerbook while accessing my wireless network does connect through the relay station instead of using the time capsule?
Configure the Time Capsule to use a different network name than the WDS link between the 2 AirPort Express (AX). Configure the PowerBook to use the Time Capsule network.
There are 2 pieces of information that you should be aware of...
(1) None of the PowerBooks are capable of 802.11n.
(2) The WDS link cuts your available bandwidth in half. So the wireless link to your neighbor's has a maximum potential of 27 Mbps.
Let's for a minute assume that you have a Mac compatible with 802.11n. In your configuration the time you could take advantage of the 802.11n speed is when the Mac is sending/recieving data directly from/to the Time Capsule.
There would be NO speed increase in Internet access. The speed of Internet access is going to be controlled by the slowest link in the path to the Internet. That is probably the connection to the ISP. The next slowest path is the WDS link to your neighbor's.
Duane,
I am in a similar situation, sharing internet with my neighbor. Do you think it would be plausible to hook up a vonage phone adapter to time capsule's ethernet port if time capsule is bridging from my neighbor's router in the configuration you have described? A check of my upload speed shows 1.67Mbps (powerbookG4 w/ airport extreme). Vonage reccommends 90kbps minimum upload speed. Am I going to lose some speed putting the Vonag adapter behind time capsule?
Thank you

I have misplaced my iPod Touch 4th Generation. According to Find my iPhone, it should show up in offline mode. I need help on locating it with a software or some other way. Help?

I have misplaced my iPod Touch 4th Generation. According to Find my iPhone, it should show up in offline mode. I need help on locating it with a software or some other way. Help?

There is no other way.
Sorry

Need help re-synching iPods with new computer and getting iTunes to...

Need help re-synching iPods with new computer and getting iTunes to recognize our iPods (it doesn't even recognize them when they're plugged in).
Hubby wiped my harddrive for me, so now I need to get everything back in proper places. I'm using windows XP and installed iTunes once again (I believe it's version 8). I also installed all of my iTunes songs. Now I need to know where to go from here. We have 3 iPods and I need to get them all synched once again. I know how to create different libraries for each of us, but I can't figure out how to get our songs back into our iTunes libraries. When I open iTunes and plug in an iPod, iTunes doesn't even show that an iPod is plugged in.
What do I do now to get each of our iPods synched with our own libraries?
TIA
Brandy

Thanks Zevoneer. The "Restart ipod service" worked and itunes is now recognizing my ipod! Hooray!
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Unable to compile class for JSP. apache-tomcat-6. What could be wrong?

Hello, I am new to JSP and I am trying a very basic jsp and class file on Windows XP. I get the Unable to compile class for JSP.
Steps that I have done:
javac ch06_01.java , placed the ch06_01.class under
C:\Apps\apache-tomcat-6.0.16\webapps\ch06\WEB-INF\classes
Then grabbed the ch06_02.jsp and placed it under
C:\Apps\apache-tomcat-6.0.16\webapps\ch06\
When I run it (by placing this into Explorer or Firefox URL
http://localhost:8080/ch06/ch06_02.jsp) I get the error further
below. Things I have done and made sure they are in place are:
set up JAVA_HOME to C:\Apps\jdk1.6.0_06
Using CATALINA_BASE: C:\Apps\apache-tomcat-6.0.16
Using CATALINA_HOME: C:\Apps\apache-tomcat-6.0.16
Using CATALINA_TMPDIR: C:\Apps\apache-tomcat-6.0.16\temp
Using JRE_HOME: C:\Apps\jre1.6.0_06
I did a google on the error and I found people saying to place the
tools.jar from the jsk into the lib directory under CATALINA_HOME. But
the examples still don't work. What step could I be missing? Your help is greatly
appreciated.
This is the simple jsp file:
<%@ page import="ch06_01" %>
<HTML>
<HEAD>
<TITLE>Using a JavaBean</TITLE>
</HEAD>
<BODY>
<H1>Using a JavaBean</H1>
<% ch06_01 messager = new ch06_01(); %>
The message is: <%= messager.msg() %>
</BODY>
</HTML>
this is the simple ch6_01 java file:
public class ch06_01
public ch06_01()
public String msg()
return "Hello from JSP!";
HTTP Status 500 -
type Exception report
message
description The server encountered an internal error () that prevented
it from fulfilling this request.
exception
org.apache.jasper.JasperException: Unable to compile class for JSP:
An error occurred at line: 6 in the generated java file
The import ch06_01 cannot be resolved
An error occurred at line: 9 in the jsp file: /ch06_02.jsp
ch06_01 cannot be resolved to a type
6: <BODY>
7: <H1>Using a JavaBean</H1>
8:
9: <% ch06_01 messager = new ch06_01(); %>
10:
11: The message is: <%= messager.msg() %>
12:
An error occurred at line: 9 in the jsp file: /ch06_02.jsp
ch06_01 cannot be resolved to a type
6: <BODY>
7: <H1>Using a JavaBean</H1>
8:
9: <% ch06_01 messager = new ch06_01(); %>
10:
11: The message is: <%= messager.msg() %>
12:
Stacktrace:
org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:92)
org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:330)
org.apache.jasper.compiler.JDTCompiler.generateClass(JDTCompiler.java:423)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:316)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:294)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:281)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:566)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:317)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:337)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
Edited by: indikon1 on Jun 12, 2008 1:18 PM
I just updated the directories of the variables to reflect the current status of my system.

What is wrong is that you are using an "old" jsp tutorial :-)
Since Java 1.4, JSPs have been unable to access classes in the "default" package.
What you need to do:
Put the java class ch06_01 in a package.
Steps to do this
- Edit ch06_01 and add the following to the very top of the file (without the quotes): "package mypackage;"
- create a folder "mypackage"
- move ch06_01.java into that folder
- compile that class (now in the mypackage package)
- place ch06_01.class under C:\Apps\apache-tomcat-6.0.16\webapps\ch06\WEB-INF\classes\mypackage
In your jsp:
<%@ page import="mypackage.ch06_01" %>
I would suggest using a more up-to-date tutorial that uses JSTL.
Take a look at this [Apache Tomcat tutorial|http://www.coreservlets.com/Apache-Tomcat-Tutorial/index.html]

Need help finding whats wrong with my servlet

I've been trying to create a simple login page following the tutorial found http://www.roseindia.net/mysql/loginauthentication.shtml
There is a single JSP (AuthenticateLogin.jsp) and a servlet (LoginAuthentication.java). Basically what has to happen is the user enters the login information in the JSP which sends these info to the servlet. The servlet checks whether the username and password exist in the table and if they do it displays the user if not it says to that the username and/or password is invalid. I'm using IntelliJ IDEA as the IDE, Tomcat as the application server and MySQL 5.0.18 for the database. I'm also using Ant as a build tool.
The following are my code:
AuthenticateLogin.jsp
<head>
     <title>Login Page</title>
     <script type="text/javascript">
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               var user = document.frm.user
               var pass = document.frm.pass
               if ((user == null) || (user == "")) {
                    alert("Please enter a username")
                    user.focus()
                    return false
               if ((pass == null) || (pass == "")) {
                    alert("Please enter a password")
                    pass.focus()
                    return false
     </script>
</head>
<body>
<form name="frm" action="LoginAuthentication" method="post" onsubmit="return validate()">
     Name:       <input type="text" name="user"/>
     <br/>
     Password:   <input type="text" name="pass" />
     <br />
     <input type="submit" value="Sign in"/>
     <input type="reset" value="Reset"/>
</form>
</body>
</html>{code}
LoginAuthentication.java
{code:java}import java.io.*;*
*import java.sql.*;
import javax.servlet.*;*
*import javax.servlet.http.*;
public class LoginAuthentication extends HttpServlet {
     private ServletConfig config;
     public void init (ServletConfig config) throws ServletException {
          this.config = config;
     public void doPost (HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException{
          PrintWriter out = response.getWriter();
          String connectionUrl = "jdbc:mysql://192.168.0.95:3306/loginTester";
          Connection connection = null;
          ResultSet rs;
          String userName = new String("");
          String passwrd = new String("");
          response.setContentType("text/html");
          try {
               Class.forName("com.mysql.jdbc.Driver");
               connection = DriverManager.getConnection(connectionUrl, "root", "");
               String sql = "select user, password from user";
               Statement s = connection.createStatement();
               s.executeQuery(sql);
               rs = s.getResultSet();
               while (rs.next()) {
                    userName = rs.getString("user");
                    passwrd = rs.getString("password");
               rs.close();
               s.close();
          } catch (Exception e){
               System.out.println("Exception thrown: ["+e+"}");
          if (userName.equals(request.getParameter("user")) && passwrd.equals(request.getParameter("pass"))) {
//               response.sendRedirect("http://localhost:8080/xplanner_reports/");
               out.println("Hello"+userName);
          } else {
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               out.println("<a href='AuthenticateLogin.jsp'><br/>Login again</a>");
}{code}
web.xml
{code:java}<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee"
             xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
             xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
            http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
             version="2.5">
     <welcome-file-list>
          <welcome-file>AuthenticateLogin.jsp</welcome-file>
     </welcome-file-list>
     <servlet>
          <servlet-name>LoginAuthentication</servlet-name>
          <servlet-class>LoginAuthentication</servlet-class>
     </servlet>
     <servlet-mapping>
          <servlet-name>LoginAuthentication</servlet-name>
          <url-pattern>/LoginAuthentication</url-pattern>
     </servlet-mapping>
</web-app>
</web-app>{code}
The problem I'm facing is the validation (checking whether the username and password match to those in the database) isn't working properly. No matter what I enter as the username and password (even if it is the correct pair) it always shows as my username and/or password is invalid. When I check the tomcat (catalina) log the following entry was found:
{code:java}Exception thrown: [java.lang.ClassNotFoundException: com.mysql.jdbc.Driver}{code}
Could someone please show me what I could be doing wrong here? It would be a great help. Spent a day trying to figure this out :no:

How could I add it to my classpath from Idea?
By the way the following is my build.xml (ant build file)
<project name="LoginForm" basedir=".">
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</project>and my directory structure could be found here http://img407.imageshack.us/img407/1594/tempf.png
I think I"ve added it to the classpath.

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Hello,
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Hi,
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themagooshow,
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TCS3414_Datasheet_EN_v1.pdf ‏1806 KB

Hi Aaron,
Here you go, this is made with a USB-8452.
When you run the code tick the power en dac enable box on.
Maybe you can help me with my problem, I want to use a fiber to sense light from a led.
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gr,
Attachments:
TCS3414.vi ‏63 KB

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Hi,
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Hello,
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[source]
HTTP Status 500 - No Context configured to process this request
type Status report
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description The server encountered an internal error (No Context configured to process this request) that prevented it from fulfilling this request.
Apache Tomcat/4.1.24-LE-jdk14
[source]
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In the log:
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This code are not complated
import java.applet.*;
import java.awt.*;
import java.awt.event.*;
//declaring class
public class test3 extends Applet implements ActionListener
{ //declaring the TextField
private TextField fromField ,toField;
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int N; // Set of Nodes
int d; // distance
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int j; // destition Node
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setBackground(Color.white);
setForeground(Color.red);
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Label TITLE2,TITLE1;
TITLE1 = new Label("from:");
add(TITLE1);
fromField = new TextField(5);
add(fromField);
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TITLE2 = new Label("to");
add(TITLE2);
toField = new TextField(5);
add(toField);
// register listener using void add actionListener
toField.addActionListener(this);
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public void actionPerformed(ActionEvent event) {
//declaring textfield
from=Integer.parseInt(fromField.getText());
to=Integer.parseInt(toField.getText());
weight =new int[7][7];
weight[1][1] = 0; weight[2][1]= 2;
weight[1][2]= 2; weight[2][2]= 0;
weight[1][3]= 5; weight[2][3]= 3;
weight[1][4]= 1; weight[2][4]= 2;
weight[1][5]= 99; weight[2][5]= 99;
weight[1][6]= 99; weight[2][6]= 99;
weight[3][1]= 5;
weight[3][2]= 3;
weight[3][3]= 0;
weight[3][4]= 3;
weight[3][5]= 1;
weight[3][6]= 5;
for (int i=1; i<7; ++i) {
for (int j=1; j<7; ++j)

all your base are belong to us

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So i based myself on some tutorial so theres some code in there that had dynamic text, but not exactly what i wanted
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This is my code:
var counter:Number = 0;
var startX:Number;
var startY:Number;
six_mc.addEventListener(MouseEvent.MOUSE_DOWN, pickUp);
six_mc.addEventListener(MouseEvent.MOUSE_UP, dropIt);
five_mc.addEventListener(MouseEvent.MOUSE_DOWN, pickUp);
five_mc.addEventListener(MouseEvent.MOUSE_UP, dropIt);
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four_mc.addEventListener(MouseEvent.MOUSE_UP, dropIt);
three_mc.addEventListener(MouseEvent.MOUSE_DOWN, pickUp);
three_mc.addEventListener(MouseEvent.MOUSE_UP, dropIt);
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two_mc.addEventListener(MouseEvent.MOUSE_UP, dropIt);
one_mc.addEventListener(MouseEvent.MOUSE_DOWN, pickUp);
one_mc.addEventListener(MouseEvent.MOUSE_UP, dropIt);
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event.target.x = myTarget.x;
event.target.y = myTarget.y;
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event.target.x = startX;
event.target.y = startY;
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six_mc.buttonMode = true;
five_mc.buttonMode = true;
four_mc.buttonMode = true;
three_mc.buttonMode = true;
two_mc.buttonMode = true;
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where you have
xxx.text = ....
is where you're assigning text.

Need help on ammount formating with num{$z,zzz,zz9.99}

Hi All
Need help in formating the amount fields.
Currently I am using num{$z,zzz,zz9.99} Its working fine for positive ammount value.
But for negative amount its giving output as $-18,970.50
Expected out is -$18,970.50
need '-' sign before $
Thanks,
Abhijit

issue resolved by setting pattern as = num{z$z,zzz,zz9.99}

Need help compiling an EJB with Apache Tomcat 5.5

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