Need Help for getting today's records from sysdate with current time.

Question

Here is the procedure which gives me the below mentioned output.
Create or Replace Procedure pt(rdate date default sysdate) is
sdate date;
edate date;
begin
sdate:=trunc(NVL(rdate,sysdate));
edate:=NVL(trunc(rdate)+23/24/+59/24/60+59/24/60/60,sysdate);
dbms_output.put_line(sdate || ' ' || edate);
end;
Scenerio 1 (This is ok and is giving the desired output)
In the above procedure if i give any date as parameter then it will take the input date as the parameter and execute accordingly and gives the result like SQL> EXEC PT('02-JAN-07');
SQL> 02-02-07 00:00:00 02-02-07 23:59:59
Scenerio 2 (This is giving problem it is not giving the desired output).
In the above procedure if i dont give any date as parameter then it will take the sysdate as the parameter and execute accordingly and gives the result like SQL> EXEC PT();
SQL> 25-10-07 00:00:00 25-10-07 23:59:59
INSTEAD OF THIS OUTPUT FOR NOT GIVING ANY DATE PARAMETER I SHOULD GET BELOW O/P
SQL> 25-10-07 00:00:00 25-10-07 12:28:43 THE CURRENT DATE AND TIME
AND NOT 25-10-07 23:59:59.
Here i think the NVL function is not working properly or i am doing something incorrect, Cna anyone guide me.
Thnx

Answer 1

Scenerio 1 (This is ok and is giving the desired output)
... and gives the result like SQL> EXEC PT('02-JAN-07');
SQL> 02-02-07 00:00:00 02-02-07 23:59:59
02-JAN should be 02-01
This?
SQL> declare
   rdate date := sysdate-5;
   sdate date;
   edate date;
begin
   select trunc(nvl(rdate, sysdate)),
      trunc(nvl(rdate, sysdate))+1-(1/24/60/60)
   into sdate, edate
   from dual;
   dbms_output.put_line(to_char(sdate,'YYYY/MM/DD HH24:MI:SS') || ' ' || to_char(edate,'YYYY/MM/DD HH24:MI:SS'));
end;
2007/10/20 00:00:00 2007/10/20 23:59:59
PL/SQL procedure successfully completed.