Need help in bursting
Hi All,
Greetings!!!!!!!!!!!
I am working on converting Remittance report to XML.In this i have a case where the mail should have a different content based on the org id.
For ex: IF org_id = 1 it will have the following content
+"Please find attached Remittance Advice for payment ${C_CHECK_NUM}."+
Org_id = 2 it should will have following content
+"Please find attached Remittance Advice for payment ${C_CHECK_NUM}.+
+Vous trouverez ci-attaché un avis de dépôt au sujet d'un paiement direct effectué par Sélection du Reader's Digest, portant le numéro de référence: 13440"+
Please let us know whether we can write any if condition or something similar to filter which we will use for selecting the template.
Below is the sample bursting file for reference.
<?xml version="1.0" encoding="UTF-8"?>
<xapi:requestset xmlns:xapi="http://xmlns.oracle.com/oxp/xapi">
<xapi:request select="/XXRMTADV/LIST_G_SEL_CHECKS/G_SEL_CHECKS">
<xapi:delivery>
<xapi:email server="xxxx.xxx.xx.com" port="587" from="test.com" reply-to ="">
<xapi:message id="${C_CHECK_ID}" to=="${C_EMAIL_ADDR}" cc=""
attachment="true"
subject="Remittance ${C_CHECK_NUM}">
Please find attached Remittance Advice for payment ${C_CHECK_NUM}.
Regards,
The Payables Team
</xapi:message>
</xapi:email>
</xapi:delivery>
<xapi:document output="Remit_Advice_${C_CHECK_NUM}" output-type="pdf" delivery="${C_CHECK_ID}">
<xapi:template type="rtf" location="xdo://XX.XXXXXX.fr.CA/?getSource=true" filter=".//G_SEL_CHECKS[C_ORG_ID = 161]"></xapi:template>
<xapi:template type="rtf" location="xdo://XX.XXXXX.en.US/?getSource=true" filter=".//G_SEL_CHECKS[C_ORG_ID = 54 or C_ORG_ID = 56 or C_ORG_ID = 247]"></xapi:template>
</xapi:document>
</xapi:request>
</xapi:requestset>
Please help to resolve this issue.
Thanks
Rajesh
Hi Rajesh,
Here is an idea. Hopefully it applies to your scenario. In your main RTF template, you could define two templates and call them this way; ofcourse within the individual templates you can add whatever other functionality that needs to be included.
<?choose:?>
<?when: . /org_id=1?><?call@inlines:Template_1?><?end call?><?end when?>
<?when: ./org_id =2?> <?call@inlines:Template_2?><?end call?> <?end when?>
<?end choose?>
<?template:Template_1?>
"Please find attached Remittance Advice for payment ${C_CHECK_NUM}."
<?end template?>
<?template:Template_2?>
"Please find attached Remittance Advice for payment ${C_CHECK_NUM}.
Vous trouverez ci-attaché un avis de dépôt au sujet d'un paiement direct effectué par Sélection du Reader's Digest, portant le numéro de référence: 13440"
<?end template?>
Hope this helps. If it does, then please award points.
Thanks!
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I have attempted to configure rdp access but it does not seem to be working for me Could I please ask someone to help me modify my current configuration to allow this? Please do step by step as I could use all the help I could get.
I need to allow the following IP addresses to have RDP access to my server:
66.237.238.193-66.237.238.222
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I already added one server for Static route and RDP but when I try to put in same commands it doesnt allow me to for this new one. Please take a look at my configuration file and give me the commands i need in order to put this through. Also please tell me if there are any bad/conflicting entries.
THE FOLLOWING IS MY CONFIGURATION FILE
Also I have modified IP information so that its not the ACTUAL ip info for my server/network etc... lol for security reasons of course
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ASA Version 7.2(4)
hostname ciscoasa
domain-name default.domain.invalid
enable password DowJbZ7jrm5Nkm5B encrypted
passwd 2KFQnbNIdI.2KYOU encrypted
names
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switchport access vlan 2
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interface Ethernet0/2
interface Ethernet0/3
interface Ethernet0/4
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object-group service MarsFTP tcp
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description NM1503
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access-list outside_access_in extended permit tcp 69.16.158.128 255.255.255.128 192.168.6.0 255.255.255.0 eq www
access-list outside_access_in extended permit tcp 69.16.158.128 255.255.255.128 host 99.89.69.334 object-group SSL
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access-list outside_access_in extended permit tcp 69.16.158.128 255.255.255.128 192.168.6.0 255.255.255.0 object-group NM1731
access-list outside_access_in extended permit tcp 173.197.144.48 255.255.255.248 host 99.89.69.334 object-group RDP
access-list outside_access_in extended permit tcp any interface outside eq 3389
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access-list outside_access_in extended permit tcp host 66.237.238.194 host 99.89.69.333 object-group rdp
access-list outside_access_in extended permit tcp any host 99.89.69.333 object-group rdp
access-list out_in extended permit tcp any host 192.168.6.2 eq 3389
pager lines 24
logging enable
logging asdm informational
mtu inside 1500
mtu outside 1500
icmp unreachable rate-limit 1 burst-size 1
asdm image disk0:/asdm-524.bin
no asdm history enable
arp timeout 14400
global (outside) 1 interface
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static (inside,outside) tcp interface 3389 192.168.6.2 3389 netmask 255.255.255.255
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crypto isakmp policy 10
authentication pre-share
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lifetime 86400
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Hi i need help to develop proofs 2,3,4
of pythagoras theorems in java as demonstrations
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the site is the following
http://www.uni-koeln.de/ew-fak/Mathe/Projekte/VisuPro/pythagoras/pythagoras.html
then double click on the screen to make it startPardon my ASCII art, but I've always liked the following, simple, geometric proof:
a b
---------------------------------------+
| | |
a| I | II |
| | |
---------------------------------------+
| | |
| | |
| | |
| | |
| | |
b| IV | III |
| | |
| | |
| | |
| | |
| | |
| | |
---------------------------------------+It almost goes without saying that I+II+III+IV == (a+b)^2, and II == IV == a*b,
I == a*a and III == b*b, showing that (a+b)^2 == a^2+a*b+a*b+b^2.
I hope the following sketch makes sense, stand back, ASCII art alert again: a b
---------------------------------------+
| . VI |
| . . |a
| V . |
| +
| |
| . |
b| . |
| |
| IX |
| . |
| . |b
| |
+ |
| . |
a| . . VII |
| VIII . |
---------------------------------------+
a bThe total area equals (a+b)^2 again and equals the sum of the smaller areas:
(a+b)^2 == V+VI+VII+VIII+IX. Let area IX be c^2 for whatever c may be.
V+VII == VI+VIII == a*b, so a^2+b^2+2*ab= c^2+2*a*b; IOW a^2+b^2 == c^2
Given this fundamental result, the others can easily be derived from this one,
or did I answer a question you didn't ask?
kind regards,
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as i see theres some people here that theires ipod touch are recongnzed as a digitl camra, mine is reconzied as nothing, some help plz.
Message was edited by: B0OmB0Om wrote:
ok but i still dont understed, only my itnes recongnize my ipod, when i go to " my cumputer, it dosent show up there, not even as a digital camra
Your Touch is working correctly. Currently, without unsupported third party hacks, the Touch has NO disc mode. It will only show up in iTunes.
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Weird error message need help..
SO.. i havent updated my itunes in a while because i keep getting this weird message.. it comes up when im almost done installing the newest/newer versions of itunes. it says
"the feature you are trying to use is on a network resource that is unavailable" "click ok to try again or enter an alternate path to a folder containing the installation package 'iTunes.msi' in the box below"
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no idea need help thanks
~~~lake
Message was edited by: DarkxFlamexCaster
Message was edited by: DarkxFlamexCaster+it comes up when im almost done installing the newest/newer versions of itunes. it says+ +"the feature you are trying to use is on a network resource that is unavailable" "click ok to try again or enter an alternate path to a folder containing the installation package 'iTunes.msi' in the box below"+
With that one, let's try the following procedure.
First, head into your Add/Remove programs and uninstall your QuickTime. If it goes, good. If it doesn't, we'll just attend to it when we attend to iTunes.
Next, download and install the Windows Installer CleanUp utility:
Description of the Windows Installer CleanUp Utility
Now launch Windows Installer CleanUp ("Start > All Programs > Windows Install Clean Up"), find any iTunes and/or QuickTime entries in the list of programs in CleanUp, select those entries, and click “remove”.
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(1) Open Local Disk (C:) in Computer or whichever disk programs are installed on.
(2) Open the Program Files folder.
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(4) Right-click the QuickTime folder and select Delete and choose Yes when asked to confirm the deletion. (Note: This folder may have already been deleted if QuickTime was successfully removed using Add/Remove Programs earlier.)
(5) Delete the QuickTime and QuicktimeVR files located in the C:\Windows\system32\ folder. Click Continue if Windows needs confirmation or permission to continue. (Note: These files may have already been deleted if QuickTime was successfully removed using Add/Remove Programs earlier.)
(6) Right-click on the Recycle Bin and on the shortcut menu, click Empty Recycle Bin.
(7) Restart your computer.
Now try another iTunes install. Does it go through properly now? -
I got new hard driver for my MacBook I don't have the cd but I do have flash drive that has the software I need help because when I turn on my laptop it shows me a file with question mark how can I install the software from the flash driver?
Hold down the Option key while you boot your Mac. Then, it should show you a selection of devices. Click your flash drive and it will boot from that.
-
Need help adobe bridge cc output module
I need help. I have an assignment I'm held up on completing because the adobe cc bridge does not have the output modue I need. I followed the adobe instructions page to the letter. I copied and pasted the output module folder to the adobe bridge cc extensions folder in programs/commonfiles/adobe. The only thing is the instructions then say to paste the workspace file into the workspace folder located below the bridge extensions folder. I don't have a workspaces folder there or anywhere. I even tried must making one and adding the file to it, but no go. can someone PLEASE help me with this? I have an assignment due like now that requires the use of the output modue.thanks!
oh,my system is windows 8.1. sorry, lol.
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Trying to create a Invoice based on Order need help Error -5002
the dreaded -5002 error is haunting me too! and I could not find a matching solution for this in the forum....
I need help quickly on this. I am trying to create invoices for some orders so the Base - Target relationship is retained. The orders I pick are all Open (DocStatus = O and the lines are all Open LineStatus = O)
here is my code
oInvoice.Lines.BaseEntry = 48
oInvoice.Lines.BaseLine = 0
oInvoice.Lines.BaseType = SAPbobsCOM.BoObjectTypes.oOrders
oInvoice.Lines.ItemCode = "A00001"
oInvoice.Lines.ItemDescription = "IBM Infoprint 1312"
'adding Line
oInvoice.Lines.Add
oInvoice.Lines.BaseEntry = 48
oInvoice.Lines.BaseLine = 1
oInvoice.Lines.BaseType = SAPbobsCOM.BoObjectTypes.oOrders
oInvoice.Lines.ItemCode = "A00002"
oInvoice.Lines.ItemDescription = "IBM Inforprint 1222"
'adding Line
oInvoice.Lines.Add
lRetCode = oInvoice.Add
If lRetCode <> 0 Then
gObjCompany.GetLastError lErrCode, sErrMsg
MsgBox (lErrCode & " " & sErrMsg)
End IfIndika,
Only set your base types...
(not items & description)
oInvoice.Lines.BaseEntry = 48
oInvoice.Lines.BaseLine = 0
oInvoice.Lines.BaseType = SAPbobsCOM.BoObjectTypes.oOrders
oInvoice.Lines.ItemCode = "A00001"
oInvoice.Lines.ItemDescription = "IBM Infoprint 1312"
'adding Line (to fill the second item line)
' the 1st line item is there by default
oInvoice.Lines.Add
oInvoice.Lines.BaseEntry = 48
oInvoice.Lines.BaseLine = 1
oInvoice.Lines.BaseType = SAPbobsCOM.BoObjectTypes.oOrders
oInvoice.Lines.ItemCode = "A00002"
oInvoice.Lines.ItemDescription = "IBM Inforprint 1222"
'DO NOT Add THIS line
' (only if you want to add a 3rd line item)
'''oInvoice.Lines.Add -> Don't add this
lRetCode = oInvoice.Add
If lRetCode <> 0 Then
gObjCompany.GetLastError lErrCode, sErrMsg
MsgBox (lErrCode & " " & sErrMsg)
End If
remember to add :
oInvoice.CardCode = "your BP"
oInvoice.DocDueDate = Now
oInvoiceDoc.CardCode = txtDOCBPCode.Text -
I need help installing update 13.1.2 for Photoshop creative cloud, installation fails with error code: U44M1P7. Could someone please help?
Sorry to bother you.
I could find the answer after searching previous posts about this language problem.
Had to change my language in AAM profile and then download PS CS6 again ( english version ).
Then open the actual Photoshop and in preferences > interface you can besides the Dutch also option for English.
restart application and Voila.
Greetz, Jeroen -
Stored DB Procedure - Need help
Hi. I have a stored database package containing 2 functions. I need help with the function named ret_columns.
If you look at the code below you will see this function has two different FOR loops. The Select statement in FOR loop that is commented out works just fine, but when I try to use the uncommented select statement in it's place the Function returns NULL (or no records). However, if I run the Select statement in plain old SQL Plus it returns the rows I need. I don't get it.
Can anyone help me? I'm really stuck on this one.
-- PACKAGE BODY
CREATE OR REPLACE package body audit_table_info
as
function ret_tables return table_type is
t_t table_type;
i integer;
begin
i := 1;
for rec in (select distinct table_name
from all_triggers
where substr(trigger_name,1,9) = upper('tr_audit#')) loop
t_t(i).tableA := rec.table_name;
i := i+1;
end loop;
return t_t;
end;
function ret_columns return column_type is
c_t column_type;
i integer;
begin
i := 1;
-- for rec in (select distinct table_name column_name
-- from all_triggers
-- where substr(trigger_name,1,9) = upper('tr_audit#')) loop
for rec in (select distinct b.column_name column_name
from all_triggers a, all_tab_columns b
where a.table_owner = b.owner
and a.table_name = b.table_name
and substr(a.trigger_name,1,9) = upper('tr_audit#') and rownum < 5) loop
c_t(i).tableB := rec.column_name;
i := i+1;
end loop;
return c_t;
end;
end audit_table_info;
-- PACKAGE DEFINITION
CREATE OR REPLACE package Audit_Table_Info as
type table_rec is record( tableA all_tab_columns.TABLE_NAME%type);
type table_type is table of table_rec index by binary_integer;
function ret_tables return table_type;
type column_rec is record( tableB all_tables.TABLE_NAME%type);
type column_type is table of column_rec index by binary_integer;
function ret_columns return column_type;
end Audit_Table_Info;
/It works when I do this!!! I'm so confused.
Ok...so I did this:
1 create table test_columns as
2 (select b.column_name
3 from all_triggers a,
4 all_tab_columns b
5 where a.table_owner = b.owner
6 and a.table_name = b.table_name
7 and substr(a.trigger_name,1,9) = upper('tr_audit#')
8* and rownum < 5)
SQL> /
Table created.
Then altered the Function so the Select statement refers to this table:
function ret_columns return column_type is
c_t column_type;
i integer;
begin
i := 1;
for rec in (select distinct column_name
from test_columns) loop
c_t(i).tableB := rec.column_name;
i := i+1;
end loop;
return c_t;
end;
Again, any help would be greatly greatly appreciated!
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