Need help in creating RAID 5

Hi everyone,
i'm fairly new to RAID scene and i need help for creating RAID 5 with 8 disk's.
I have HP ProLiant DL380 G6 with 8 disk's, each 500 GB.
i'm trying to create RAID 5 and to have one spare disk. I have made array from 7 disk and then create logical drive.
the last disk (8-th) i used as spare.
up to now i think i'm ok???
what confuse me is:
7 HDD X 500GB= 3500GB
after creating array i get 3200 GB, where i lose 300 GB??
after creating logical drive i get 2700 GB, where i lose 500 GB???
from 2700GB i give 150GB for system partition and for data storage i have only 2550 GB.
Why i lose 800GB??
Can someone explain me how RAID 5 works, do i create it correctly and why i lose so much space???
Is there other way to create RAID 5 without losing so much space?
Thanks you in advnce.

The first 'loss' you encounter (300MB) is due to megabyte counting/rounding. A 500GB disk contains about 500.000.000 bytes. This quite a bit less than if counted properly using binary. you loose about 24288000 bytes per disk this way!
http://en.wikipedia.org/wiki/Mibibyte |
http://en.wikipedia.org/wiki/Megabyte
the second loss is due to how raid works.in raid 5 data is written to multiple disks to improve reliability. the simplies t form uses 3 disks: a write will cause half of the data to be written to disk 1, half to disk 2 and the XOR of both datahalfs to disk
3. In this scenario you will loose 33% of storage space and you can loose up to one of 3 disks.
By adding more disks, data can be spread more and the ratio available/raw will increase, or you can write aditionnal crc data and increase resliency for failures.
http://en.wikipedia.org/wiki/RAID
To check the exact algoritmes using on you RAID adapter, I would recommend contacting the vendor (or checking their support site) From your numbres, I do not think you will be able to configure RAID 5 on the same disks and having more available
space for your data.
MCP/MCSA/MCTS/MCITP

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