Need help in the following query
Hi ,
I have the following query to pull out data for a particular timeperiod( campaign)
select
da.acct_nr,smas.mrkt_id,smas.fld_sls_cmpgn_perd_id,smas.acct_key,smas.upln_acct_key,smas.awrd_sls_amt,smas.fld_net_sls_amt
,smas.stf_ind,da1.acct_nr,
smas.fld_sls_cmpgn_perd_id,smas.acct_key,smas.upln_acct_key,smas.awrd_sls_amt,smas.fld_net_sls_amt
,smas.stf_ind,da1.acct_nr,prev.*
From cdw.sum_mrkt_acct_sls smas
join codi.dim_acct da
on (smas.mrkt_id = da.mrkt_id and smas.acct_key = da.acct_key)
join codi.dim_acct da1
on (smas.mrkt_id = da1.mrkt_id and smas.UPLN_acct_key = da1.ACCT_KEY)
where smas.acct_key in
select dwnln_acct_key from codi.dim_ldrshp_genlgy
where mrkt_id = 66 and fld_sls_cmpgn_perd_id = 20100304
and root_upln_acct_key = (select acct_key from codi.dim_acct where acct_nr = '0032622' and mrkt_id = 66)
and
smas.mrkt_id = 66
and smas.fld_sls_cmpgn_perd_id = 20100304
and smas.sls_org_key <> -100
order by 1
So this query will pull out data for campaign 20100304
No i want to modify the query to pull out data for 3 such campaigns.
for a smas.acct_key
so data will
smas.acct_key all the data for 1st campaign , all the data for 2nd campaign. all the data for 3rd campaign
Could you please help in modifying this query.
Thanks
How about this ??
select da.acct_nr,
smas.mrkt_id,
smas.fld_sls_cmpgn_perd_id,
smas.acct_key,
smas.upln_acct_key,
smas.awrd_sls_amt,
smas.fld_net_sls_amt,
smas.stf_ind,
da1.acct_nr,
smas.fld_sls_cmpgn_perd_id,
smas.acct_key,
smas.upln_acct_key,
smas.awrd_sls_amt,
smas.fld_net_sls_amt,
smas.stf_ind,
da1.acct_nr,
prev.*
From cdw.sum_mrkt_acct_sls smas
join codi.dim_acct da on (smas.mrkt_id = da.mrkt_id and
smas.acct_key = da.acct_key)
join codi.dim_acct da1 on (smas.mrkt_id = da1.mrkt_id and
smas.UPLN_acct_key = da1.ACCT_KEY)
where smas.acct_key in (select dwnln_acct_key
from codi.dim_ldrshp_genlgy
where mrkt_id = 66
and fld_sls_cmpgn_perd_id in( 20100304,20100305,20100306)
and root_upln_acct_key =
(select acct_key
from codi.dim_acct
where acct_nr = '0032622'
and mrkt_id = 66))
and smas.mrkt_id = 66
and smas.fld_sls_cmpgn_perd_id in( 20100304,20100305,20100306)
and smas.sls_org_key - 100
order by 1
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I have the following data
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Ok the data I want to grab the discount field is paid_amt = pymnt_gross_amt and discount <> 0. If however there is another invoice_id out there (same invoice ID except with a DC appended to it like 10151DC) then you want to select the differece between the discount field without the DC and the Invoice ID with the DC the paid_amt field.
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Hope this helps :
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This code solved my req.
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Hi everybody..,
can anyone plz check the following code and tell that how to end the exception after "raise form_trigger_failure and end if;"
thanks in advance.
DECLARE
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v_old_amount number(15,2);
f_number varchar2(10);
BEGIN
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where line_number = :line_number and
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EXCEPTION
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v_old_amount NUMBER (15, 2);
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BEGIN
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FROM pur_req
WHERE line_number = :line_number AND f_number = :f_number;
EXCEPTION
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IF :amount <= v_amount
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ELSE
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END;btw what if this
SELECT allocated_amount
INTO v_amount
FROM line_description
WHERE line_number = :line_number;also raises a no_data_found exception? you should close the first exception block and open another:
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INTO v_old_amount
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WHERE line_number = :line_number AND f_number = :f_number;
EXCEPTION
WHEN NO_DATA_FOUND
THEN
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WHEN NO_DATA_FOUND THEN
END;Edited by: jowal on 20.04.2011 14:32 -
Need help for the following select query-- illegal character
select product_group_id from product_group where description like '%%'
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This character is in the description field and I have to replace it with NULL..
Any suggestions..
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i have a table
source table :
create table order(name_a varchar2(100),intid number);
insert into order values('a',1);
insert into order values('b',1);
insert into order values('c',1);
insert into order values('d',1);
insert into order values('e',2);
insert into order values('f',2);
insert into order values('g',2);
i need a query , which result in the below output :
if i look for intid=1 the query should give a,b,c,d
if i look for intid=2 the query should give f,g
ThanksHi,
781649 wrote:
i have a table
source table :
create table order(name_a varchar2(100),intid number);
insert into order values('a',1);
insert into order values('b',1);
insert into order values('c',1);
insert into order values('d',1);
insert into order values('e',2);
insert into order values('f',2);
insert into order values('g',2);Thanks for posting the CREATE TABLE and INSERT statements; it's very helpful.
i need a query , which result in the below output :
if i look for intid=1 the query should give a,b,c,d
if i look for intid=2 the query should give f,gDid you mean <b>e</b>,f,g ?
That's called String Aggregation , and how to do it depends on your version of Oracle, and your exact requirements.
See thie following page for several techniques:
http://www.oracle-base.com/articles/10g/StringAggregationTechniques.php
If you're using Oracle 10 (or higher), and it's important that the name_a's be in order in the output, then you can do this:
WITH got_r_num AS
SELECT name_a
, intid
, ROW_NUMBER () OVER ( PARTITION BY intid
ORDER BY name_a
) AS r_num
FROM order_table -- ORDER is not a good table name
WHERE intid IN (1) -- Optional
SELECT intid
, SUBSTR ( SYS_CONNECT_BY_PATH (name_a, ',')
, 2
) AS name_a_list
FROM got_r_num
WHERE CONNECT_BY_ISLEAF = 1
START WITH r_num = 1
CONNECT BY r_num = PRIOR r_num + 1
AND intid = PRIOR intid
;Starting in Oracle 11.2, LISTAGG is better.
This does not assume that you are getting the output only for a single intid at a time. You can get any number of them in a suingle query. Of course, that number can be 1 if that's what you want.
Edited by: Frank Kulash on Mar 24, 2011 12:19 PM -
Need help on the below query or Pl-SQL
Hello Every one,
Please let me know if some one can help me out with the below scenario either in pl-sql or sql.
Source Data:
0000253800 0.25 0845A 0900A
0000253800 1 0900A 1000A
0000253800 1 1300P 1400P
0000253800 1 1500P 1600P
0000253800 1 1600P 1700P
Output needed:
0000253800 1.25 0845A 1000A
0000253800 1 1300P 1400P
0000253800 2 1500P 1700P
Thanks in Advance....
Edited by: user12564103 on Dec 11, 2011 5:54 PMHi,
Welcome to the forum!
Depending on your data and your requirements:
WITH got_times AS
SELECT column_1, column_2, column_3, column_4
, TO_DATE ( substr (column_3, 1, 4)
, 'HH24MI'
) AS time_3
, TO_DATE ( SUBSTR (column_4, 1, 4)
, 'HH24MI'
) AS time_4
FROM table_x
, got_grp_id AS
SELECT column_1, column_2, column_3, column_4
, time_3, time_4
, time_4 - SUM (time_4 - time_3) OVER ( PARTITION BY column_1
ORDER BY time_3
) AS grp_id
FROM got_times
SELECT column_1
, SUM (column_2) AS sum_2
, MIN (column_3) KEEP (DENSE_RANK FIRST ORDER BY time_3)
AS min_3
, MAX (column_4) KEEP (DENSE_RANK LAST ORDER BY time_4)
AS max_4
FROM got_grp_id
GROUP BY column_1
, grp_id
ORDER BY column_1
, grp_id
;Whenever you have a problem, please post CREATE TABLE and INSERT statements for your sample data, as well as the results you want from that data. Explain, with specific examples, how you get the results you want from that data.
Always say which version of Oracle you're using. The query above will work in Oracle 9.1 (and higher).
Since this is your first thread, I'll do this for you:
CREATE TABLE table_x
( column_1 NUMBER
, column_2 NUMBER
, column_3 VARCHAR2 (5)
, column_4 VARCHAR2 (5)
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, .25, '0845A', '0900A');
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, 1, '0900A', '1000A');
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, 1, '1300P', '1400P');
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, 1, '1500P', '1600P');
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, 1, '1600P', '1700P');Column_1 identifes a day.
Column_2 is an amount that I need to total.
Column_3 and column_4 are starting and ending times. We can assume that they are all valid times (in 'HH24MI' format, plus a redundant 'A' or 'P') on the same day, column_3 is always less than column_4, and that the range of two rows for the same value of column_1 never overlap. Column_4 of one row may be equal to column_3 of another rows with the same column_1, but it will never be greater.
Each row of the output represent a contiguous group of rows (each ending exactly when the next one begins) with the same column_1, with the common column_1, the total of column_2, and the range of the group.
For example, the first two rows for a single group, because they have the same value for column_1, and one ends exactly when the other begins (at 9:00 AM). This group represents day 253800, from 8:45 AM to 10:00 AM. The totla of column_2 fro this group is .25 + 1 = 1.25.
The next row (from 1:00 PM to 2:00 PM) is a group all by itself, because there is a gap one either side of it separating it from its nearest neighbor on the same day."
Of course, I'm guessing at lots of things.
Edited by: Frank Kulash on Dec 11, 2011 9:44 PM
Changed TO_DATE calls.
Edited by: Frank Kulash on Dec 11, 2011 9:52 PM
Added sample question. -
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1/13/12 12:06:33.325 AM sandboxd: ([108]) DumpGPURestart(108) deny file-read-data /private/etc/hosts
1/13/12 12:06:33.343 AM sandboxd: ([108]) DumpGPURestart(108) deny ipc-posix-shm apple.shm.notification_center
1/13/12 12:06:33.345 AM sandboxd: ([108]) DumpGPURestart(108) deny ipc-posix-shm apple.shm.notification_center
1/15/12 8:34:16.596 PM sandboxd: ([128]) DumpGPURestart(128) deny file-write-create /Library/Application Support/SubmitDiagInfo
1/15/12 8:34:16.638 PM sandboxd: ([128]) DumpGPURestart(128) deny ipc-posix-shm apple.shm.notification_center
1/15/12 8:34:16.645 PM sandboxd: ([128]) DumpGPURestart(128) deny ipc-posix-shm apple.shm.notification_center
1/15/12 8:34:16.647 PM sandboxd: ([128]) DumpGPURestart(128) deny ipc-posix-shm apple.shm.notification_center
1/15/12 8:34:16.648 PM sandboxd: ([128]) DumpGPURestart(128) deny ipc-posix-shm apple.shm.notification_center
1/15/12 8:34:16.649 PM sandboxd: ([128]) DumpGPURestart(128) deny ipc-posix-shm apple.shm.notification_center
1/15/12 8:34:16.665 PM sandboxd: ([128]) DumpGPURestart(128) deny ipc-posix-shm apple.shm.notification_center
1/15/12 8:34:16.667 PM sandboxd: ([128]) DumpGPURestart(128) deny network-outbound /private/var/run/mDNSResponder
1/15/12 8:34:16.667 PM sandboxd: ([128]) DumpGPURestart(128) deny file-read-data /private/etc/hosts
1/15/12 8:34:16.668 PM sandboxd: ([128]) DumpGPURestart(128) deny file-read-data /private/etc/hosts
1/15/12 8:34:16.685 PM sandboxd: ([128]) DumpGPURestart(128) deny ipc-posix-shm apple.shm.notification_center
1/15/12 8:34:16.686 PM sandboxd: ([128]) DumpGPURestart(128) deny ipc-posix-shm apple.shm.notification_center
1/15/12 9:09:26.511 PM sandboxd: ([333]) DumpGPURestart(333) deny file-write-create /Library/Application Support/SubmitDiagInfo
1/15/12 9:09:26.534 PM sandboxd: ([333]) DumpGPURestart(333) deny ipc-posix-shm apple.shm.notification_center
1/15/12 9:09:26.536 PM sandboxd: ([333]) DumpGPURestart(333) deny ipc-posix-shm apple.shm.notification_center
1/15/12 9:09:26.537 PM sandboxd: ([333]) DumpGPURestart(333) deny ipc-posix-shm apple.shm.notification_center
1/15/12 9:09:26.539 PM sandboxd: ([333]) DumpGPURestart(333) deny ipc-posix-shm apple.shm.notification_center
1/15/12 9:09:26.541 PM sandboxd: ([333]) DumpGPURestart(333) deny ipc-posix-shm apple.shm.notification_center
1/15/12 9:11:30.625 PM com.apple.stackshot: Running fs_usage, spindump and top
I know that my MacBook Pro is the one that has the 330m GPU that has given some problems under Mac OS X Lion. Would like to know if this can be related to the OSX Lion graphics issues in the 2010 MacBook Pros.Bump. Any suggestions or ideas? I really need them.
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Help! I have an imac m6498 question(s) need help on the following ASAP thanx
i found an imac m6498 at my grandmas's, its working smooth and great. However, i have these problems:
idont have admin (she doesnt remember the password nor how to remove it)
i dont have the cd repair and backup etc, nor does she
cd drive works well (i need info on how i could reset this so i could use the pc like it was new)
i was thinking of transferring mac os 9 [or leopeord, cuz i saw a forum that its possible] into a usb ext hard drive and installing it there
the main problem is, i dont have admin. It says "you do not have access privileges"
other questions:
is there a way / combo buttons/commands that i could do to reset, change, redeem the password.
thank you, sorry for the woording, i rushed it. heehheJames,
That machine is over 10 years old and is not an Intel based iMac, Apple began using Intel microprocessors in 2006 a full 5 years after your machine was made. It is a PPC (Power PC) based machine which cannot run Leopard. In other words you are in the wrong forum. You can reset the password per Resetting an account password however you need the original Install discs. If you don't have those your last option is to contact Apple and see if you can get a duplicate of the originals, you need these because they are machine specific. I suspect that due to the age of the machine you won't be able to get them.
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