Need help on the below query or Pl-SQL

Question

Hello Every one,
Please let me know if some one can help me out with the below scenario either in pl-sql or sql.
Source Data:
0000253800     0.25          0845A     0900A
0000253800     1          0900A     1000A
0000253800     1          1300P     1400P
0000253800     1          1500P     1600P
0000253800     1          1600P     1700P
Output needed:
0000253800     1.25          0845A     1000A
0000253800     1          1300P     1400P
0000253800     2          1500P     1700P
Thanks in Advance....
Edited by: user12564103 on Dec 11, 2011 5:54 PM

Answer 1

Hi,
Welcome to the forum!
Depending on your data and your requirements:
WITH     got_times     AS
     SELECT     column_1, column_2, column_3, column_4
     ,     TO_DATE ( substr (column_3, 1, 4)
               , 'HH24MI'
               )     AS time_3
     ,     TO_DATE ( SUBSTR (column_4, 1, 4)
               , 'HH24MI'
               )     AS time_4
     FROM     table_x
,     got_grp_id     AS
     SELECT     column_1, column_2, column_3, column_4
     ,     time_3, time_4
     ,     time_4 - SUM (time_4 - time_3) OVER ( PARTITION BY  column_1
                                    ORDER BY         time_3
                                  )     AS grp_id
     FROM     got_times
SELECT       column_1
,       SUM (column_2)     AS sum_2
,       MIN (column_3) KEEP (DENSE_RANK FIRST ORDER BY time_3)
                    AS min_3
,       MAX (column_4) KEEP (DENSE_RANK LAST  ORDER BY time_4)
                    AS max_4
FROM       got_grp_id
GROUP BY  column_1
,       grp_id
ORDER BY  column_1
,       grp_id
;Whenever you have a problem, please post CREATE TABLE and INSERT statements for your sample data, as well as the results you want from that data. Explain, with specific examples, how you get the results you want from that data.
Always say which version of Oracle you're using. The query above will work in Oracle 9.1 (and higher).
Since this is your first thread, I'll do this for you:
CREATE TABLE     table_x
(     column_1     NUMBER
,     column_2     NUMBER
,     column_3     VARCHAR2 (5)
,     column_4     VARCHAR2 (5)
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, .25, '0845A', '0900A');
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, 1,   '0900A', '1000A');
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, 1,   '1300P', '1400P');
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, 1,   '1500P', '1600P');
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, 1,   '1600P', '1700P');Column_1 identifes a day.
Column_2 is an amount that I need to total.
Column_3 and column_4 are starting and ending times. We can assume that they are all valid times (in 'HH24MI' format, plus a redundant 'A' or 'P') on the same day, column_3 is always less than column_4, and that the range of two rows for the same value of column_1 never overlap. Column_4 of one row may be equal to column_3 of another rows with the same column_1, but it will never be greater.
Each row of the output represent a contiguous group of rows (each ending exactly when the next one begins) with the same column_1, with the common column_1, the total of column_2, and the range of the group.
For example, the first two rows for a single group, because they have the same value for column_1, and one ends exactly when the other begins (at 9:00 AM). This group represents day 253800, from 8:45 AM to 10:00 AM. The totla of column_2 fro this group is .25 + 1 = 1.25.
The next row (from 1:00 PM to 2:00 PM) is a group all by itself, because there is a gap one either side of it separating it from its nearest neighbor on the same day."
Of course, I'm guessing at lots of things.
Edited by: Frank Kulash on Dec 11, 2011 9:44 PM
Changed TO_DATE calls.
Edited by: Frank Kulash on Dec 11, 2011 9:52 PM
Added sample question.