Need help on EJB deubugging

Question

Could you do me a faviour to post the example REMOTEDEBUGGING.JWS which can be seen on "Online Walkthrough Demo 'Remote Debugging EJBs in WebLogic'".
I was frustrated with debugging EJB on weblogic under JDevelopper.
Thanks
CHENLW

Answer 1

Here is the procedure I follow
1. configure weblogic startWebLogic.cmd file according to the instruction and start it
2. create a EJB project contains HelloWorld.java, HelloWorldBean.java, HelloWorldHome.java and Client.java, Bean has one method hello(), just return a String
3. in JDeveloper, configure project properties, set RUN/DEBUG to Remote Debugging as the instruction provided by Oracle
4. Then how should I do next?
select Client.java --> Debug --> attach it to the target weblogic
select HelloWorldxxx.java --> Debug --> attach it to the target weblogic
I tried the above and it attached to weblogic, after that, the program suspend there, nothing happen, no debug message, no outcome...
I have a question, the project have no EJB Descripter, How Client.java test program find EJB interface through JNDI?
Thanks
-- CHENLW --
Client.java
==// Copyright (c) 2000 qingniao
==package com.chemuser.ejb.HelloWorld;
==import javax.ejb.*;
==import javax.naming.*;
==import java.rmi.*;
==import java.util.Properties;
==
==/**
== * A Class class.
== * <P>
== * @author chenlw
== */
==public class Client {
==
== public static void main(String[] args) {
== try {
== Properties props = System.getProperties();
==
== Context ctx = new InitialContext(props);
== HelloWorldEJBHome home = (HelloWorldEJBHome)ctx.lookup("HelloHome");
== HelloWorldEJB hello = home.create();
==
== System.out.println(hello.hello());
==
== hello.remove();
== } catch (Exception ex)
== {
== ex.printStackTrace();
== }
==
== }
==}
==
==