Need help with delivery address for iPhone 6
I am trying to change the delivery address for my iPhone but UPS says I need to talk to Apple and Apple says its up to UPS. UPS says there is a dedicated line for Apple to call UPS to change the address and Apple says no such line exists. Has anyone successfully changed a delivery address for an Apple product? If I don't figure it out in the next few days my phone is going back to China.
Minimize your iTunes, right click on your Desktop, click Properties, click the Settings tab. Increase your screen resolution to 1024 x 768. If it looks OK, click OK. You should be able to continue with your iPod.
CG
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i need help with a second hand iphone i purchased recently,i am having issues setting it up as it has is requesting for the icloud account that was used by the previous user
Sorry.
The iPhone is of no use until/unless the previous owner removes it from their account.
You will need to find the prior owner or return the iPhone. -
I still need help with the Dictionary for my Nokia...
I still need help with the Dictionary for my Nokia 6680...
Here's the error message I get when trying to open dictionary...
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DON'T HIT KIDS... THEY HAVE GUNS NOW. -
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Need help with calculator project for an assignment...
Hi all, I please need help with my calculator project that I have to do for an assignment.
Here is the project's specifications that I need to do"
"""Create a console calculator applicaion that:
* Takes one command line argument: your name and surname. When the
program starts, display the date and time with a welcome message for the
user.
* Display all the available options to the user. Your calculator must include
the arithmetic operations as well as at least five scientific operations of the
Math class.
-Your program must also have the ability to round a number and
truncate it.
-When you multiply by 2, you should not use the '*' operator to perform the
operation.
-Your program must also be able to reverse the sign of a number.
* Include sufficient error checking in your program to ensure that the user
only enters valid input. Make use of the String; Character, and other
wrapper classes to help you.
* Your program must be able to do conversions between decimal, octal and
hex numbers.
* Make use of a menu. You should give the user the option to end the
program when entering a certain option.
* When the program exits, display a message for the user, stating the
current time, and calculate and display how long the user used your
program.
* Make use of helper classes where possible.
* Use the SDK to run your program."""
When the program starts, it asks the user for his/her name and surname. I got the program to ask the user again and again for his/her name and surname
when he/she doesn't insert anything or just press 'enter', but if the user enters a number for the name and surname part, the program continues.
Now my question is this: How can I restrict the user to only enter 'letters' (and spaces of course) but allow NO numbers for his/her surname??
Here is the programs code that I've written so far:
{code}
import java.io.*;
import java.util.*;
import java.text.*;
public class Project {
private static String nameSurname = "";
private static String num1 = null;
private static String num2 = null;
private static String choice1 = null;
private static double answer = 0;
private static String more;
public double Add() {
answer = (Double.parseDouble(num1) + Double.parseDouble(num2));
return answer;
public double Subtract() {
answer = (Double.parseDouble(num1) - Double.parseDouble(num2));
return answer;
public double Multiply() {
answer = (Double.parseDouble(num1) * Double.parseDouble(num2));
return answer;
public double Divide() {
answer = (Double.parseDouble(num1) / Double.parseDouble(num2));
return answer;
public double Modulus() {
answer = (Double.parseDouble(num1) % Double.parseDouble(num2));
return answer;
public double maximumValue() {
answer = (Math.max(Double.parseDouble(num1), Double.parseDouble(num2)));
return answer;
public double minimumValue() {
answer = (Math.min(Double.parseDouble(num1), Double.parseDouble(num2)));
return answer;
public double absoluteNumber1() {
answer = (Math.abs(Double.parseDouble(num1)));
return answer;
public double absoluteNumber2() {
answer = (Math.abs(Double.parseDouble(num2)));
return answer;
public double Squareroot1() {
answer = (Math.sqrt(Double.parseDouble(num1)));
return answer;
public double Squareroot2() {
answer = (Math.sqrt(Double.parseDouble(num2)));
return answer;
public static String octalEquivalent1() {
int iNum1 = Integer.parseInt(num1);
String octal1 = Integer.toOctalString(iNum1);
return octal1;
public static String octalEquivalent2() {
int iNum2 = Integer.parseInt(num2);
String octal2 = Integer.toOctalString(iNum2);
return octal2;
public static String hexadecimalEquivalent1() {
int iNum1 = Integer.parseInt(num1);
String hex1 = Integer.toHexString(iNum1);
return hex1;
public static String hexadecimalEquivalent2() {
int iNum2 = Integer.parseInt(num2);
String hex2 = Integer.toHexString(iNum2);
return hex2;
public double Round1() {
answer = Math.round(Double.parseDouble(num1));
return answer;
public double Round2() {
answer = Math.round(Double.parseDouble(num2));
return answer;
SimpleDateFormat format1 = new SimpleDateFormat("EEEE, dd MMMM yyyy");
Date now = new Date();
SimpleDateFormat format2 = new SimpleDateFormat("hh:mm a");
static Date timeIn = new Date();
public static long programRuntime() {
Date timeInD = timeIn;
long timeOutD = System.currentTimeMillis();
long msec = timeOutD - timeInD.getTime();
float timeHours = msec / 1000;
return (long) timeHours;
DecimalFormat decimals = new DecimalFormat("#0.00");
public String insertNameAndSurname() throws IOException{
boolean inputCorrect = false;
while (inputCorrect == false) {
while (nameSurname == null || nameSurname.length() == 0) {
for (int i = 0; i < nameSurname.length(); i++) {
if ((nameSurname.charAt(i) > 'a') && (nameSurname.charAt(i) < 'Z')){
inputCorrect = true;
else{
inputCorrect = false;
break;
try {
BufferedReader inStream = new BufferedReader (new InputStreamReader(System.in));
System.out.print("Please enter your name and surname: ");
nameSurname = inStream.readLine();
inputCorrect = true;
}catch (IOException ex) {
System.out.println("You did not enter your name and surname, " + nameSurname + " is not a name, please enter your name and surname :");
inputCorrect = false;
System.out.println("\nA warm welcome " + nameSurname + " ,todays date is: " + format1.format(now));
System.out.println("and the time is now exactly " + format2.format(timeIn) + ".");
return nameSurname;
public String inputNumber1() throws IOException {
boolean inputCorrect = false;
while (inputCorrect == false) {
try {
BufferedReader br = new BufferedReader (new InputStreamReader(System.in));
System.out.print("\nPlease enter a number you want to do a calculation with and hit <ENTER>: ");
num1 = br.readLine();
double number1 = Double.parseDouble(num1);
System.out.println("\nThe number you have entered is: " + number1);
inputCorrect = true;
} catch (NumberFormatException nfe) {
System.out.println("\nYou did not enter a valid number: " + "\""+ num1 + "\" is not a number!!");
inputCorrect = false;
return num1;
public String calculatorChoice() throws IOException {
System.out.println("Please select an option of what you would like to do with this number from the menu below and hit <ENTER>: ");
System.out.println("\n*********************************************");
System.out.println("---------------------------------------------");
System.out.println("Please select an option from the list below: ");
System.out.println("---------------------------------------------");
System.out.println("1 - Add");
System.out.println("2 - Subtract");
System.out.println("3 - Multiply");
System.out.println("4 - Divide (remainder included)");
System.out.println("5 - Maximum and minimum value of two numbers");
System.out.println("6 - Squareroot");
System.out.println("7 - Absolute value of numbers");
System.out.println("8 - Octal and Hexadecimal equivalent of numbers");
System.out.println("9 - Round numbers");
System.out.println("0 - Exit program");
System.out.println("**********************************************");
boolean inputCorrect = false;
while (inputCorrect == false) {
try {
BufferedReader inStream = new BufferedReader (new InputStreamReader(System.in));
System.out.print("Please enter your option and hit <ENTER>: ");
choice1 = inStream.readLine();
int c1 = Integer.parseInt(choice1);
System.out.println("\nYou have entered choice number: " + c1);
inputCorrect = true;
} catch (NumberFormatException nfe) {
System.out.println("You did not enter a valid choice number: " + "\""+ choice1 + "\" is not in the list!!");
inputCorrect = false;
return choice1;
public String inputNumber2() throws IOException {
boolean inputCorrect = false;
while (inputCorrect == false) {
try {
BufferedReader br2 = new BufferedReader (new InputStreamReader(System.in));
System.out.print("\nPlease enter another number you want to do the calculation with and hit <ENTER>: ");
num2 = br2.readLine();
double n2 = Double.parseDouble(num2);
System.out.println("\nThe second number you have entered is: " + n2);
System.out.println("\nYour numbers are: " + num1 + " and " + num2);
inputCorrect = true;
} catch (NumberFormatException nfe) {
System.out.println("You did not enter a valid number: " + "\""+ num2 + "\" is not a number!!");
inputCorrect = false;
return num2;
public int Calculator() {
int choice2 = (int) Double.parseDouble(choice1);
switch (choice2) {
case 1 :
Add();
System.out.print("The answer of " + num1 + " + " + num2 + " is: " + decimals.format(answer));
break;
case 2 :
Subtract();
System.out.print("The answer of " + num1 + " - " + num2 + " is: " + decimals.format(answer));
break;
case 3 :
Multiply();
System.out.print("The answer of " + num1 + " * " + num2 + " is: " + decimals.format(answer));
break;
case 4 :
Divide();
System.out.print("The answer of " + num1 + " / " + num2 + " is: " + decimals.format(answer));
Modulus();
System.out.print(" and the remainder is " + decimals.format(answer));
break;
case 5 :
maximumValue();
System.out.println("The maximum number between the numbers " + num1 + " and " + num2 + " is: " + decimals.format(answer));
minimumValue();
System.out.println("The minimum number between the numbers " + num1 + " and " + num2 + " is: " + decimals.format(answer));
break;
case 6 :
Squareroot1();
System.out.println("The squareroot of value " + num1 + " is: " + decimals.format(answer));
Squareroot2();
System.out.println("The squareroot of value " + num2 + " is: " + decimals.format(answer));
break;
case 7 :
absoluteNumber1();
System.out.println("The absolute number of " + num1 + " is: " + decimals.format(answer));
absoluteNumber2();
System.out.println("The absolute number of " + num2 + " is: " + decimals.format(answer));
break;
case 8 :
octalEquivalent1();
System.out.println("The octal equivalent of " + num1 + " is: " + octalEquivalent1());
octalEquivalent2();
System.out.println("The octal equivalent of " + num2 + " is: " + octalEquivalent2());
hexadecimalEquivalent1();
System.out.println("\nThe hexadecimal equivalent of " + num1 + " is: " + hexadecimalEquivalent1());
hexadecimalEquivalent2();
System.out.println("The hexadecimal equivalent of " + num2 + " is: " + hexadecimalEquivalent2());
break;
case 9 :
Round1();
System.out.println("The rounded number of " + num1 + " is: " + decimals.format(answer));
Round2();
System.out.println("The rounded number of " + num2 + " is: " + decimals.format(answer));
break;
case 0 :
if (choice2 == 0) {
System.exit(1);
break;
return choice2;
public String anotherCalculation() throws IOException {
boolean inputCorrect = false;
while (inputCorrect == false) {
try {
BufferedReader br3 = new BufferedReader (new InputStreamReader(System.in));
System.out.print("\nWould you like to do another calculation? Y/N ");
more = br3.readLine();
String s1 = "y";
String s2 = "Y";
if (more.equals(s1) || more.equals(s2)) {
inputCorrect = true;
while (inputCorrect = true){
inputNumber1();
System.out.println("");
calculatorChoice();
System.out.println("");
inputNumber2();
System.out.println("");
Calculator();
System.out.println("");
anotherCalculation();
System.out.println("");
inputCorrect = true;
} else {
System.out.println("\n" + nameSurname + " thank you for using this program, you have used this program for: " + decimals.format(programRuntime()) + " seconds");
System.out.println("the program will now exit, Goodbye.");
System.exit(0);
} catch (IOException ex){
System.out.println("You did not enter a valid answer: " + "\""+ more + "\" is not in the list!!");
inputCorrect = false;
return more;
public static void main(String[] args) throws IOException {
Project p1 = new Project();
p1.insertNameAndSurname();
System.out.println("");
p1.inputNumber1();
System.out.println("");
p1.calculatorChoice();
System.out.println("");
p1.inputNumber2();
System.out.println("");
p1.Calculator();
System.out.println("");
p1.anotherCalculation();
System.out.println("");
{code}
*Can you please run my code for yourself and have a look at how this program is constructed*
*and give me ANY feedback on how I can better this code(program) or if I've done anything wrong from your point of view.*
Your help will be much appreciated.
Thanks in advanceSmirre wrote:
Now my question is this: How can I restrict the user to only enter 'letters' (and spaces of course) but allow NO numbers for his/her surname??You cannot restrict the user. It is a sad fact in programming that the worst bug always sits in front of the Computer.
What you could do is checking the input string for numbers. If it contains numbers, just reprompt for the Name.
AND you might want to ask yourself why the heck a calculator needs to know the users Name. -
Need Help making a Screencast for IPHONE
Hello there
I need some serious help making a screencast for a client - for it's Iphone Apps -
something similare to this
http://www.newsluxe.com/chaumet-et-iphone.php
but more sexy, with a animated background and a different type of cursor.
Anyideas ?
I really don't know where to start - I found leads however :
Camtasia Studio , screenflow, ,
Maybe you could help me filling the gaps.
Thanks for your help !does anyone know how apple made these forums?
I think they use Jive:
http://www.jivesoftware.com/products/forums/
The Apple way for users to add photos is the .Mac web gallery:
http://www.apple.com/ilife/iphoto/#webgallery -
Need help with SQL retrieval for previous month till current date
Hi ,
Need help generating statistics from previous month from date of enquiry till current date of enquiry.
and have to display it according to date.
Date of enquiry : 03/02/2012
Application Type| 01/01/2012 | 02/01/2012 | 03/01/2012 |...... | 31/01/2012 | 01/02/2012 | 02/02/2012 | 03/02/2012 |
sample1 20 30 40
sample 2 40 40 50
sample 3 50 30 30
Hope you guys can help me with this.
RegardsHi,
932472 wrote:
Scenario
1)If i run the query at 12 pm on 03/2/2012. the result i will have to display till the current day.
2)displaying the count of the application made based on the date.
Application type 01012012 | 02012012 | 03012012 | ..... 01022012| 02022012|03022012
sample 1 30 40 50 44 30
sample 2 35 45 55
sample 3 36 45 55Explain how you get those results from the sample data you posted.
It would help a lot if you posted the results in \ tags, as described in the forum FAQ. {message{id=9360002}
SELECT application_type as Application_type
, COUNT (CASE WHEN created_dt = sysdate-3 THEN 1 END) AS 01012012 (should be getting dynamically)
, COUNT (CASE WHEN created_dt = sysdate-4 THEN 1 END) AS 02022012
, COUNT (CASE WHEN created_dt = sysdate-5 THEN 1 END) AS 03022012
, COUNT (CASE WHEN created_dt = sysdate-6 THEN 1 END) AS 04022012
FROM table_1
GROUP BY application_type
ORDER BY application_typeThat's the bais idea.
You can simplify it a little by factoring out the date differences:WITH got_d AS
SELECT qty
, TRUNC ( dt
- ADD_MONTHS ( TRUNC (SYSDATE, 'MON')
, -1
) AS d
FROM table1
WHERE dt >= ADD_MONTHS ( TRUNC (SYSDATE, 'MON')
, -1
AND dt < TRUNC (SYSDATE) + 1
SELECT SUM (CASE WHEN d = 1 THEN qty END) AS day_1
, SUM (CASE WHEN d = 2 THEN qty END) AS day_2
, SUM (CASE WHEN d = 62 THEN qty END) AS day_62
FROM got_d
See the links I mentioned earlier for getting exactly the right number of columns, and dynamic column aliases. -
Need help with correction inscript for duplication on regular basis
Hi,
I am using Oracle 10.2.0.4 on Win 2008 R2. We have Archive mode enabled and no rman catalog is used. I have a requirement where i have to duplicate prod sevrer on regular basis to development server.
I have created few batch files so that the entire process in automated. Stored all the scripts in c:\script\clone\ directory.+
I have taken the backup copy of password and spfile from prod server and copied to the development server in same location.
These are the scripts i run in order:
*1_clone.bat*
set ORACLE_SID=orcl
sqlplus / as sysdba @c:\script\clone\2_test.bat
*2_test.bat*
shutdown immediate
startup nomount
host rman target sys/oracle@live nocatalog auxiliary / @c:\script\clone\3_rman.rcv
*3_rman.rcv*
run {
allocate auxiliary channel d1 type disk;
duplicate target database to ORCL NOFILENAMECHECK;
exit
When the duplication process in about to finish, i get below error:
contents of memory script:
shutdown clone;
startup clone nomount;
executing Memory Script
RMAN-03002: failure of duplicate DB command at 07/31/2012 08:02:21
RMAN-03015: error occured in stored script memory script
RMAN-06136: Oracle error from auxiliary database: ORA-01013: user requested cancel of current operation
Recovery Manager complete
SQL>
When i press exit, this window closes and i can run the alter database open resetlogs;+ command from a new sql prompt. I check online and some suggest there might be a window open with system user connected. Please suggest any changes in the script.
Best Regards,Hello;
Having another session with system user will cause rman to throw this error. For example another session used to start up database in nomount mode still being active.
Duriing the cloning process the rman session needs to be exclusively connected to the auxiliary instance (no other session are allowed).
Duplicate post
request for help with rman cloning script
Best Regards
mseberg
Edited by: mseberg on Jul 31, 2012 5:02 AM -
Not exactly iweb - need help with a graphic for my site
This doesn't fit anywhere so dumping it here. I drew by hand a graphic I want to use with iweb to put on my site as my site's logo. Main problem is that getting the background transparent isn't working well as when it was scanned the scanner didn't back the background "pure" white. I have tried adjusting the whitepoint and setting the color depth down, but still no good. I don't know a ton about graphic program use. I have an older copy of graphic converter that came on this powerbook when i got it. I would be fine having the graphic loose the marker look and have solid fill colors - just I am not good enough with computer drawing tools to do it on the computer! So I either need to get a volunteer to help me out, or some help with some detailed instructions to get this to work out... (also I am broke so no cost/shareware is only option here)
many thanks!!!!
I can get you a scanned jpg of the pic if needed.THANK YOU/___sbsstatic___/migration-images/migration-img-not-avail.png so the tolerance makes it not care so much about the gradations in color? what else is tolerence good for?
I have a cleaner copy now after someone suggested GIMP, so played with it last night - though couldn't figure out transparency - that was clear on converter- just not cooperative till these wonderful directions.
So now I know how to do it without messing with the pic, and with messing with it - both good lessons and got a bit brighter color out of the deal.
many thanks for the straightforward and clear directions, they worked perfectly/___sbsstatic___/migration-images/migration-img-not-avail.png extra strars for you/___sbsstatic___/migration-images/migration-img-not-avail.png -
Need performance! - Need help with Server Architecture for SSAS on Azure VM
I would like to build 100% Azure VM base solution. We can install as many as needed.
I have large amount data in DW. (100GB-1000GB)
I would like to provide PowerView reports in SharePoints.
I would like to have report data be as real time as possible. (Min data is updated once in 2 hours)
These are requirements:
-SharePoint 2013
-PowerView
-SSAS OLAP Cube
-SQL Server DW&Staging DB (Currently DW&Staging on same server)
I need help specially what can be done with SSAS to meet requirements? Should be installed to own application server? Possible to install multiple SSAS? SSRS needs own server?
I appreciate also links to server topology diagrams.
Kenny_II assume you mean 100GB-1000GB (not 1000TB) right?
For Sharepoint I would refer to the sizing guide for diagrams and sizing:
http://technet.microsoft.com/en-us/library/ff758647(v=office.15).aspx
SSRS (and Power View) will run in the SharePoint farm on a SharePoint app server potentially with other SharePoint services.
I would definitely put SSAS on a dedicated server for a cube that size. Depending on how well your data compresses, there may not be a VM in Azure with enough RAM to put your model into a Tabular SSAS model. I would prototype it with a subset of data to see
how well it compresses. You can always use a Multidimensional model as a fallback.
Depending on how much processing the SSAS model impacts user queries (since it is happening during the day) you could build an SSAS processing server and a separate SSAS query server and run the XMLA Synchronize command to copy the cube incrementally from processing
to query servers.
Does that help?
http://artisconsulting.com/Blogs/GregGalloway -
Need help with XI certif for technical consultant
Hi XI experts ,
I am trying for certif for Development Consultant SAP NetWeaver u201904 - Exchange Infrastructure & Integration Technology - C_TBIT44_04 .
Can somebody please give me some sample questions and answers?
I really will appreciate such help since I donu2019t have any idea what kind of questions are at the exam!
I only have heard it is not an easy exam to take.?Is this true?
Also any shared experienced will be appreciate it. If you have, please give me more hands on information , not just course numbers and syllabus.
Looking forward to receive info from you. Please use emal contcts in my Business Card.
Thanks in advance all!
JimHI,
Yes its true ...any SAP certification is never ever be the easy stuff...that could be easily achievable....
You need to be well prepare for the Certification. There are many SDN links available for sample questions. you can just search on SDN as well as on Internet.
https://www.sdn.sap.com/irj/sdn/developerareas/xi?rid=/webcontent/uuid/a680445e-0501-0010-1c94-a8c4a60619f8
1. SAP XI Certification - Important Topics
2. Regarding XI Certification Material.
3. Xi sample Certification questions
XI certification passing used to be normally 65%. It may vary based on the runtime exam rules.
There are marks as well as no of questions allocated for every section, so you may refer below link
you can go to the following site and check the information.
https://service.sap.com/%7Esapidp/011000358700005902252004E
https://service.sap.com/~sapidp/011000358700003595762004E
SAP XI Certification - Important Topics All about XI certification
Thanks
Swarup -
Need help with installing Windows for the bar exam
I need to retake the bar exam in Feb 2011 and I've decided to switch to typing. I am trying to figure out what Windows I need (the software says XP is fine but is that even available anymore)- so can someone walk me through this process? I've partioned my hard drive with the default 5GB but should it be more?
I'm looking at buying Windows- is XP okay or should I shell out for 7-i.e. is one more compatible with Macs?
And then finally, in the installation instructions they mention that I need my Mac OS disc for the process- is that the snow leopard disc or something else? My discs are in storage right now so should I wait until I get them before starting this process or can I get replacements if I accidentally threw them out in moving?
Sorry for all the questions, but well, I'm racing to get everything done and I want to make sure I don't crash my system halfway through the exam!You don't need Boot Camp, but even XP will have a lot of stuff to update from after the install, and that takes temp space. Just as your Mac shows 5-10GB there is add'l hidden space used.
Apple's 'requirements' has gotten others in trouble and I was pretty sure it was more like 10GB. Plus a lot of XP discs are now SP3.
XP out of the box but connected to the net is just waiting for malware, average is 15 minutes to be infected. 7 is better and just in case you need it again.
System Builder can come in 32 or 64-bit but XP is 32-bit only.
VirtualBox by Oracle is a free VM.
1GB for one program actually seems like a lot, or is that RAM requirement? -
MOVED: need help with finding gpu for win 7
This topic has been moved to MSI Notebook.
https://forum-en.msi.com/index.php?topic=128552.0Mike,
I'm not going to be much help with Boot Camp however I can direct you to the Boot Camp forum where there are more people that know how to troubleshoot it and Windoze 7. You can find it at:
https://discussions.apple.com/community/windows_software/boot_camp
Roger -
Need help with user ID for this forum
I have problem that I can't seem to get resolved online which involves my Apple Support user ID... Sorry to post this here, but I don't know where to go for help.
I have been a member of the apple community for a long time (since 2002) but my login ID and user ID seem to have been disconnected. Happened when I tried to sign in once and had all kinds of problems. Now I've created a new user ID but would like my old one back. I've tried several times to get my original user ID back, but there seems to be no way to get it back... If I sign up for the user ID, it tells me that it is taken (because its mine).
Can you help me? Is there a real person I can contact who can help me?
Thanks for any support.try calling Apple suport
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1941w - Need help with IP address assigning, and relay wireless to a DHCP server.
Hope someone can point me in the right direction -
Basically have a Win08 R2 DHCP server, and a 1941w router.
I've got the internet, got the lan clients getting DHCP ok (with ip helper-address set on the 0/0 internal interface).
Also have the SSID, and wireless clients can connect - but no IPs are being handed out, also not sure if I understand or did the bridging correctly or assigned IPs to the vlan or bvi1 correctly.
for ex:
DHCP server IP:
10.10.2.4
Router Ethernet internal interface 0/0 IP:
10.10.2.1
with helper-address 10.10.2.4 (lan clients are resolving IPs correctly from the DHCP server)
Vlan1 IP address:
10.10.3.1
Does this interface need the helper-address as well? (10.10.2.4)?
wlan-ap 0 IP address:
unnumbered
interface BVI1 IP address (static):
10.10.2.2
am i totally off? not even sure if i have the vlan bridged to the 0/0 adapter or not correctly - but as I said, i can get a wireless client to connect with the SSID.
would appreciate any advice/pointers, thanksof course - here is the router config:
=======================================================
Using 5591 out of 262136 bytes
version 15.1
no service pad
service tcp-keepalives-in
service tcp-keepalives-out
service timestamps debug datetime msec localtime show-timezone
service timestamps log datetime msec localtime show-timezone
service password-encryption
service sequence-numbers
hostname router
boot-start-marker
boot-end-marker
security authentication failure rate 3 log
security passwords min-length 6
logging buffered 51200
logging console critical
enable secret 5 $1$JWwK$.04.NFg7tQ82UTy68/hyv.
no aaa new-model
service-module wlan-ap 0 bootimage autonomous
no ipv6 cef
no ip source-route
ip cef
no ip bootp server
ip name-server 10.10.2.4
multilink bundle-name authenticated
crypto pki token default removal timeout 0
crypto pki trustpoint TP-self-signed-975501586
enrollment selfsigned
subject-name cn=IOS-Self-Signed-Certificate-975501586
revocation-check none
rsakeypair TP-self-signed-975501586
crypto pki certificate chain TP-self-signed-975501586
certificate self-signed 01 nvram:IOS-Self-Sig#3.cer
license udi pid CISCO1941W-A/K9 sn FTX155085QG
hw-module ism 0
ip tcp synwait-time 10
ip ssh time-out 60
ip ssh authentication-retries 2
interface Embedded-Service-Engine0/0
no ip address
no ip redirects
no ip unreachables
no ip proxy-arp
ip flow ingress
shutdown
interface GigabitEthernet0/0
description $ETH-LAN$$ETH-SW-LAUNCH$$INTF-INFO-GE 0/0$$ES_LAN$$FW_INSIDE$
ip address 10.10.2.1 255.255.255.0
ip helper-address 10.10.2.4
no ip redirects
no ip unreachables
no ip proxy-arp
ip flow ingress
ip nat inside
ip virtual-reassembly in
duplex auto
speed auto
no mop enabled
interface wlan-ap0
description Service module interface to manage the embedded AP
ip unnumbered GigabitEthernet0/0
no ip redirects
no ip unreachables
no ip proxy-arp
ip flow ingress
arp timeout 0
no mop enabled
no mop sysid
interface GigabitEthernet0/1
description $ES_WAN$$FW_OUTSIDE$
ip address dhcp client-id GigabitEthernet0/1
no ip redirects
no ip unreachables
no ip proxy-arp
ip flow ingress
ip nat outside
ip virtual-reassembly in
duplex auto
speed auto
no mop enabled
interface Wlan-GigabitEthernet0/0
description Internal switch interface connecting to the embedded AP
no ip address
interface Vlan1
ip address 10.10.3.1 255.255.255.0
ip helper-address 10.10.2.4
no ip redirects
no ip unreachables
no ip proxy-arp
ip flow ingress
ip forward-protocol nd
ip http server
ip http authentication local
ip http secure-server
ip http timeout-policy idle 60 life 86400 requests 10000
ip nat inside source list 1 interface GigabitEthernet0/1 overload
logging trap debugging
access-list 1 remark INSIDE_IF=GigabitEthernet0/0
access-list 1 remark CCP_ACL Category=2
access-list 1 permit 10.10.2.0 0.0.0.255
no cdp run
control-plane
line con 0
login local
transport output telnet
line aux 0
login local
transport output telnet
line 2
no activation-character
no exec
transport preferred none
transport input all
transport output pad telnet rlogin lapb-ta mop udptn v120 ssh
stopbits 1
line 67
no activation-character
no exec
transport preferred none
transport input all
transport output pad telnet rlogin lapb-ta mop udptn v120 ssh
line vty 0 4
privilege level 15
login local
transport input telnet ssh
line vty 5 15
privilege level 15
login local
transport input telnet ssh
scheduler allocate 20000 1000
end
=======================================================
and the ap config:
=======================================================
Using 2067 out of 32768 bytes
version 12.4
no service pad
service timestamps debug datetime msec
service timestamps log datetime msec
service password-encryption
hostname ap
enable secret 5 $1$xKDT$GdLGeA6h.H9LKL9l3dPmj.
no aaa new-model
dot11 syslog
dot11 ssid WIFI1
vlan 1
authentication open
authentication key-management wpa
mbssid guest-mode
wpa-psk ascii 7 044B1E030D2D43632A
bridge irb
interface Dot11Radio0
no ip address
no ip route-cache
encryption vlan 1 mode ciphers aes-ccm
broadcast-key vlan 1 change 30
ssid WIFI1
antenna gain 0
station-role root
interface Dot11Radio0.1
encapsulation dot1Q 1 native
no ip route-cache
bridge-group 2
bridge-group 2 subscriber-loop-control
bridge-group 2 block-unknown-source
no bridge-group 2 source-learning
no bridge-group 2 unicast-flooding
bridge-group 2 spanning-disabled
interface Dot11Radio1
no ip address
no ip route-cache
encryption vlan 1 mode ciphers aes-ccm
broadcast-key vlan 1 change 30
ssid WIFI1
antenna gain 0
dfs band 3 block
channel dfs
station-role root
interface Dot11Radio1.1
encapsulation dot1Q 1 native
no ip route-cache
bridge-group 2
bridge-group 2 subscriber-loop-control
bridge-group 2 block-unknown-source
no bridge-group 2 source-learning
no bridge-group 2 unicast-flooding
bridge-group 2 spanning-disabled
interface GigabitEthernet0
description the embedded AP GigabitEthernet 0 is an internal interface connecting AP with the host router
no ip address
no ip route-cache
interface GigabitEthernet0.1
encapsulation dot1Q 1 native
no ip route-cache
bridge-group 1
no bridge-group 1 source-learning
bridge-group 1 spanning-disabled
interface BVI1
ip address 10.10.2.2 255.255.255.0
no ip route-cache
ip http server
no ip http secure-server
ip http help-path http://www.cisco.com/warp/public/779/smbiz/prodconfig/help/eag
bridge 1 route ip
line con 0
no activation-character
line vty 0 4
login local
end
============================================
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