Need help with java assignment dealing with for loops...
Hi there. I'm a beginner to java programming and I'm having a lot of difficulty.
I am trying to do a lab for class right now, and I really don't even know where to begin and to make things worse, someone in my class lost the copies of the class book so I'm extra confused.
I need to write a method to print a "line" of characters to the screen. The professor said that the method should consume both the character to print (this parameter can be of type char or of type String) and the number of the character to print. The method should use System.out.print().
e.g. if the method is called printLine, then
printLine(5,'*');
printLine(4,'j');
should print:
*****jjjj
I'd really appreciate any help possible! Thank you.
nevermind. i figured it out.
Similar Messages
-
I'm a beginner. I'm trying to get this output
Initial number of stars:
7
Here's my program. What's wrong with it? Please help
import java.io.*;
class starWedge
public static void main (String[] args ) throws IOException
int numStars; // the number of stars
int row ; // current row number
int star; // the number of stars in this row so far
BufferedReader userin = new BufferedReader (new InputStreamReader(System.in));
String inputData;
// collect input data from user
System.out.println( "Initial number of stars:" );
inputData = userin.readLine();
numStars = Integer.parseInt( inputData );
row = 1;
while ( row <= numStars )
star = 1;
star = numStars - star;
System.out.print("*");
star = star + 1;
System.out.println(); // end each line
row = row + 1;Okay the one thing that I see immediately is that your while loop never actully exits. Not once. Why? Well simple your exit condition is the row <= numStars, yet nither numStars nor row actually change their values within the loop. In short row always equals 1 and thus never is equal to greater than numStars and the while loop does not terminate.
Second thing is that your star drawing logic is not correct. Meaning you have not told to draw the specific number of stars in one given line. For starters the System.out.println() command should be in the loop not outside it. For your purposes a for-loop nested within a while-loop is much better.
If you think you know what's wrong your program than read no further and go try it on your own. But if you still have no clue below is my modification of your code that actually produces the pattern you want, it might provide you with more hints.
import java.io.*;
class starWedge{
public static void main (String[] args ) throws IOException{
int numStars; // the number of stars
int row ; // current row number
int star; // the number of stars in this row so far
BufferedReader userin = new BufferedReader (new InputStreamReader(System.in));
String inputData;
// collect input data from user
System.out.println( "Initial number of stars:" );
inputData = userin.readLine();
numStars = Integer.parseInt( inputData );
row = 1;
while (numStars > 0){
for(star = 1; star<=numStars; star++){
System.out.print("*");
numStars = numStars - 1;
System.out.println(); // end each line
} -
I need help with a loop within an hour
I need to make a loop that gives 100, 10, 1000, 100, 10000, 1000...
I can use a for loop, if loop, while loop, and do while loop.
Thankswarnerja wrote:
sharkura wrote:
warnerja wrote:
sharkura wrote:
Sorry warnerja. I know I should have done the same. I just couldn't help myself. I need to keep telling rubbish.
:D
¦ {ÞIt's not too late to edit your spoon-fed solution, though the OP may have seen and copied it by now.And you know this isn't going to make the OP a programmer, unless he/she/it changes his/her/its stripes.
¦ {ÞYes, but its laziness will continue to be encouraged more than it should.Nah. It'll crash and burn on the next assignment.
¦ {Þ -
Need help with while loop format
I'm building a form - everything works but I would like to change the way the data is output into the table.
In other scripting languages, like PHP, you had 2 different ways of dealing with a loop:
<?
do while xyz
do something here
?>
- OR -
<? do while xyz:?>
do something here
<?end while ?>
I would like to do something similar to the 2nd example in .jsp but I'm not sure of the format or how to stop the loop. From the tutorial, I'm using
<%
while(SQLResult.next())
UId = SQLResult.getString("uid");
FName = SQLResult.getString("fname");
LName = SQLResult.getString("lname");
out.println("<tr><td>" + UId + "</td><td>" + FName + "</td><td>" + LName
+ "</td></tr>");
%>
Could anyone point me in the right direction? I'd prefer it if I didn't have to build the table like this if I don't have to but haven't found anything anywhere telling me otherwise.
Thanks so much.
BobSorry - the answer was in JSP:Java Server Pages by Barry Burd. I had just gotten the output format wrong.
-
Help with for loop and remove-item command
Hi all here is the code so far
$a = Get-Content C:\Users\cody-horton\Desktop\test.txt
for($i=0;$i -lt $a.Length;$i++){
#$temp = [int32]::Parse($a[$i])
Remove-Item '\\ceit2551202x0'$a[$i]'\C$\Program Files\MATLAB\R2013a\*' -Force
I have a text file with a few number in it that i want to get. They are in the array $a but I'm getting an error that says a positional parameter cannot be found that accepts argument '53' (it does this for all the numbers in the array.) I know in java you
could have something like this string + int + string.
I'm not sure what to do I also tried to parse it with no luck. Thanks any help is appreciated.Your issue is with the path for Remove-Item, it is not complete so try this
Remove-Item "\\ceit2551202x0$($a[$i])\C$\Program Files\MATLAB\R2013a\*" -Force
I am unable to test, so I would add the -WhatIf switch to make sure it outputs what you expect
If you find that my post has answered your question, please mark it as the answer. If you find my post to be helpful in anyway, please click vote as helpful.
Don't Retire Technet -
Need help with nested loop (c:forEach) tags. Can I break from inner loop?
Hi all, I have this annoying problem and I am looking for any suggestions.
I have 2 select boxes. One is for all available users, and second - for selected users (designated as admins). The list of all users is available in a collection (2 properties userId and userName displayed in the code below). The list of admins contains only userId (as strings).
I have no problem with populating selected users (admins) list, reusing pretty much the same logic below, but I cannot find a way to break out from the nested loop once the match is found, to avoid repetitions leading to incorrect display of results.
<select name=available>
<c:forEach items="${users}" var="user" varStatus="outer">
<c:forEach items="${adminIds}" var="adminId" varStatus="inner">
<c:if test="${user.userId!=adminId">
<option value="<c:out value="${user.userId}" />"><c:out value="${user.userFullName}"/></option>
</c:if>
</c:forEach>
</c:forEach>
</select>
<select name=selected>
<c:forEach items="${users}" var="user" varStatus="outer">
<c:forEach items="${adminIds}" var="adminId" varStatus="inner">
<c:if test="${user.userId==adminId">
<option value="<c:out value="${user.userId}" />"><c:out value="${user.userFullName}"/></option>
</c:if>
</c:forEach>
</c:forEach>
</select>Can anyone help, please? I am also restricted to JSP 1.2Double post: http://forum.java.sun.com/thread.jspa?threadID=707950&tstart=0
-
Hello let me first explain what im trying to achive:
I want a moving square that you control with the arrow keys on the keyboard. It has to be smooth ie able to move fast without looking like its jumping and it has to be able to move diagonaly aswell. Think of that arcade game Raiden ...you know the birds-eye view plane flying game...another thing! I'd prefer if it didnt use timers - i made one already using 4 timers and it works great but 4 timers is a little extreme - SO NO TIMERS !
I was thinking while loops, but i cant seem to get it working. I dont want to put in all the code so ill just say that I have 4 booleans: up, down, left right and the following code:
public void keyPressed(KeyEvent e) {
if (e.getKeyCode() == KeyEvent.VK_UP) {
up = true;
if (e.getKeyCode() == KeyEvent.VK_DOWN) {
down = true;
if (e.getKeyCode() == KeyEvent.VK_LEFT) {
left = true;
if (e.getKeyCode() == KeyEvent.VK_RIGHT) {
right = true;
repaint();
For the KeyReleased part i have the same as above exept it sets the booleans to false.
Soooo in theory if i set up a while loop like this (using the up direction as an example) :
while (up == true) {
[move square up]
So therefore when i press and hold the up arrow the loop will keep going untill i realease it right? WRONG ! it just keeps repeating indefinatly and it doesnt even do the " [move square up] " bit. I put a System.out.print in the loop to test and it kept printing out the message but it still didnt do the actual " [move square up] " bit.
Im not sure if im putting the while loop in the right place either....If anyone has any idea on how to use while loops in this way please heeeelp ! Its so annoying because it just doesnt work ive tried so many ways...
any help would be greatly apreciated !!!!Maybe you want something like this? You have to pause during the loop to allow for other events to happen, like if y ou release a key or whatever.
while( true )
if( up ) moveUp();
else if( down ) moveDown();
if( left ) moveLeft();
else if( right ) moveRight();
try
Thread.currentThread().sleep(10);
catch( InterruptedException e )
System.out.println( "Thread interrupted!");
} -
Need help with while loop and shift registers
I have a large data set and need to read in the data at maybe 200 samples at a time, process these samples through my VI, and have it append and concatenate a separate lvm file. The part where I am confused is the shift registers. How do I limit the number of samples read in an iteration? How do I get the while loop to stop when all the data are read in?
I've attached my diagram, maybe there is something wrong with my technique?
Solved!
Go to Solution.
Attachments:
shiftreg.JPG 56 KBThis will give you an idea. There are plenty of other (probably more efficient) methods. This is a basic, quick and dirty solution to help you grasp the overall concept.
Using LabVIEW: 7.1.1, 8.5.1 & 2013
Attachments:
ShiftRegLoop.JPG 54 KB -
Need help with infinite loop in recovery mode in Creative Zen 20
hi,
I'm having this problem with my Creative Zen 20 GB:
When I turned it on, it goes immediately to the rescue/recovery mode. Not sure why. Will do that even when I reset the device.
So, I selected cleanup. After cleanup, it remained showing the menu of the recovery mode. I selected reboot. After reboot, it went back to the rescue/recovery mode. And it goes on and on like an infinite loop.
Finally, I decided to do a formatAll. Again, it remained in the recovery mode menu after the formatAll action. After reboot, it again went back to the rescue/recovery mode.
I have never updated the firmware. So, I thought maybe that will help. However, when I connected the device to my PC, the device went to rescue/recovery mode and the PC could not detect the device connected via USB. In short, I am currently not able to do anything at all with the device except charging it.
Would appreciate help/advise.
Tks in advance.huggiebear wrote:
I connected the device to the PC and after the PC tried to load the library, it said "Player is not connected".
What library are you loading? After you have run that reload os option, you need to connect the player to the computer and run the firmware update software. If you haven't download that, you can go to the download section and download it. If all else fail, the player is probably faulty and you would need to get in contact with Customer Support then.
Jason -
Hi,
I'm running a while loop to run through some results of a search. Anyway I know how to list the strings but my last item is a JComboBox (drop down box.) How do I go about changing that so its right for a drop down box. Its the one with questions marks in the code below.
while (srs.next())
//Get the values for each field in this row
String projectName = srs.getString("PROJECT_NAME");
System.out.println("Project Name = " + projectName );
String projectOfficier = srs.getString("PROJECT_OFFICER");
System.out.println("Project Officer = " + projectOfficier );
String projectDescription = srs.getString("PROJECT_OFFICER");
System.out.println("Project Description = " + projectDescription );
String paymentSchedule = srs.getString("PAYMENT_SCHEDULE");
System.out.println("Payment Schedule = " + paymentSchedule );
String banksInvestment = srs.getString("BANKS_INVESTMENT");
System.out.println("Banks Investment = " + banksInvestment );
? String paymentsMade = srs.getString("PAYMENTS_MADE");
? System.out.println("Payments Made = " + paymentsMade );Thanks.Yeah the Payments Made part is a JComboBox with 3 so called strings inside it. I wanna know instead of srs.getString what should I put in to replace String to get the results from a JComboBox?
-
Hi I am having a very very difficult time. for thos that have it I'm using the Intro to Java Programming 6th Edition by Y.Daniel Liang Book. I am on page 124 Ch 4 Problem 4.18
what it wants you to do is make and use nested loops that print
Pattern 1
1
12
123
1234
12345
123456
Pattern 2
123456
12345
1234
123
12
1
Patern 3
1
21
321
4321
54321
654321 ( I know this is crooked but you get the idea )
Pattern 4
123456
12345
1234
123
12
1 (once again crooked but you get the idea )
Ok so here is my code thus for and it includes pattern 1 and pattern 2...Keep in mind I'm just simply printing them out one right after the other..it doesnt have to look all pretty or nothing like that ok...thanks
public class Patterns
// Print Pattern I */
public static void main(String[] args)
for (int i = 1; i <= 6; i++)
for (int j = 1; j <= i; j++) ( NESTED FOR STATMENT)
System.out.print(j + " ");
System.out.println();
// Print Patter II
for ( int i = 6 ; i >=1; i--)
for ( int j = 1; j <= i; j++) (NESTED FOR STATMENT )
System.out.print ( j + " ") ;
System.out.println();
If yall could somehow give me hints as to how to get number 3 and number 4 thanks
-tim-package src;
public class Escada {
public Escada(){
System.out.println("Pattern1");
for (Integer i = 1; i <= 6; i++){
for (Integer j = 1; j <= i; j++){
System.out.print(j);
System.out.println("");
System.out.println("--------\nPattern2");
for (Integer i = 6; i >= 1; i--){
for (Integer j = 1; j <= i; j++){
System.out.print(j);
System.out.println("");
System.out.println("--------\nPattern3");
for (Integer i = 1; i <= 6; i++){
for (Integer j = i; j >=1; j--){
System.out.print(j);
System.out.println("");
System.out.println("--------\nPattern4");
for (Integer i = 6; i >= 1; i--){
for(Integer j = 1; j <= i; j++){
System.out.print(j);
System.out.println("");
public static void main(String[] args) {
new Escada(); -
do{
if((orderType != 'g') || (orderType != 'w')){
System.out.println("Please enter g or w only.");
}while((orderType == 'g') || (orderType == 'w'));
I need help with this loop... I have to make sure it will be able to pop the input back after the invalid input... i tried to fix it...wont stop and stay in same loop till it gets the valid before go to other loop... how? am i missing something?I know you've already been answered, but just a bit more...
if((orderType != 'g') || (orderType != 'w'))That would always be true. All characters are either not equal to 'g' or not equal to 'w'.
'x' : neither 'g' nor 'w'. Evaluates to true.
'g' : not 'w', still evaluates to true.
'w': not 'g', still evaluates to true. -
Need help with calculator project for an assignment...
Hi all, I please need help with my calculator project that I have to do for an assignment.
Here is the project's specifications that I need to do"
"""Create a console calculator applicaion that:
* Takes one command line argument: your name and surname. When the
program starts, display the date and time with a welcome message for the
user.
* Display all the available options to the user. Your calculator must include
the arithmetic operations as well as at least five scientific operations of the
Math class.
-Your program must also have the ability to round a number and
truncate it.
-When you multiply by 2, you should not use the '*' operator to perform the
operation.
-Your program must also be able to reverse the sign of a number.
* Include sufficient error checking in your program to ensure that the user
only enters valid input. Make use of the String; Character, and other
wrapper classes to help you.
* Your program must be able to do conversions between decimal, octal and
hex numbers.
* Make use of a menu. You should give the user the option to end the
program when entering a certain option.
* When the program exits, display a message for the user, stating the
current time, and calculate and display how long the user used your
program.
* Make use of helper classes where possible.
* Use the SDK to run your program."""
When the program starts, it asks the user for his/her name and surname. I got the program to ask the user again and again for his/her name and surname
when he/she doesn't insert anything or just press 'enter', but if the user enters a number for the name and surname part, the program continues.
Now my question is this: How can I restrict the user to only enter 'letters' (and spaces of course) but allow NO numbers for his/her surname??
Here is the programs code that I've written so far:
{code}
import java.io.*;
import java.util.*;
import java.text.*;
public class Project {
private static String nameSurname = "";
private static String num1 = null;
private static String num2 = null;
private static String choice1 = null;
private static double answer = 0;
private static String more;
public double Add() {
answer = (Double.parseDouble(num1) + Double.parseDouble(num2));
return answer;
public double Subtract() {
answer = (Double.parseDouble(num1) - Double.parseDouble(num2));
return answer;
public double Multiply() {
answer = (Double.parseDouble(num1) * Double.parseDouble(num2));
return answer;
public double Divide() {
answer = (Double.parseDouble(num1) / Double.parseDouble(num2));
return answer;
public double Modulus() {
answer = (Double.parseDouble(num1) % Double.parseDouble(num2));
return answer;
public double maximumValue() {
answer = (Math.max(Double.parseDouble(num1), Double.parseDouble(num2)));
return answer;
public double minimumValue() {
answer = (Math.min(Double.parseDouble(num1), Double.parseDouble(num2)));
return answer;
public double absoluteNumber1() {
answer = (Math.abs(Double.parseDouble(num1)));
return answer;
public double absoluteNumber2() {
answer = (Math.abs(Double.parseDouble(num2)));
return answer;
public double Squareroot1() {
answer = (Math.sqrt(Double.parseDouble(num1)));
return answer;
public double Squareroot2() {
answer = (Math.sqrt(Double.parseDouble(num2)));
return answer;
public static String octalEquivalent1() {
int iNum1 = Integer.parseInt(num1);
String octal1 = Integer.toOctalString(iNum1);
return octal1;
public static String octalEquivalent2() {
int iNum2 = Integer.parseInt(num2);
String octal2 = Integer.toOctalString(iNum2);
return octal2;
public static String hexadecimalEquivalent1() {
int iNum1 = Integer.parseInt(num1);
String hex1 = Integer.toHexString(iNum1);
return hex1;
public static String hexadecimalEquivalent2() {
int iNum2 = Integer.parseInt(num2);
String hex2 = Integer.toHexString(iNum2);
return hex2;
public double Round1() {
answer = Math.round(Double.parseDouble(num1));
return answer;
public double Round2() {
answer = Math.round(Double.parseDouble(num2));
return answer;
SimpleDateFormat format1 = new SimpleDateFormat("EEEE, dd MMMM yyyy");
Date now = new Date();
SimpleDateFormat format2 = new SimpleDateFormat("hh:mm a");
static Date timeIn = new Date();
public static long programRuntime() {
Date timeInD = timeIn;
long timeOutD = System.currentTimeMillis();
long msec = timeOutD - timeInD.getTime();
float timeHours = msec / 1000;
return (long) timeHours;
DecimalFormat decimals = new DecimalFormat("#0.00");
public String insertNameAndSurname() throws IOException{
boolean inputCorrect = false;
while (inputCorrect == false) {
while (nameSurname == null || nameSurname.length() == 0) {
for (int i = 0; i < nameSurname.length(); i++) {
if ((nameSurname.charAt(i) > 'a') && (nameSurname.charAt(i) < 'Z')){
inputCorrect = true;
else{
inputCorrect = false;
break;
try {
BufferedReader inStream = new BufferedReader (new InputStreamReader(System.in));
System.out.print("Please enter your name and surname: ");
nameSurname = inStream.readLine();
inputCorrect = true;
}catch (IOException ex) {
System.out.println("You did not enter your name and surname, " + nameSurname + " is not a name, please enter your name and surname :");
inputCorrect = false;
System.out.println("\nA warm welcome " + nameSurname + " ,todays date is: " + format1.format(now));
System.out.println("and the time is now exactly " + format2.format(timeIn) + ".");
return nameSurname;
public String inputNumber1() throws IOException {
boolean inputCorrect = false;
while (inputCorrect == false) {
try {
BufferedReader br = new BufferedReader (new InputStreamReader(System.in));
System.out.print("\nPlease enter a number you want to do a calculation with and hit <ENTER>: ");
num1 = br.readLine();
double number1 = Double.parseDouble(num1);
System.out.println("\nThe number you have entered is: " + number1);
inputCorrect = true;
} catch (NumberFormatException nfe) {
System.out.println("\nYou did not enter a valid number: " + "\""+ num1 + "\" is not a number!!");
inputCorrect = false;
return num1;
public String calculatorChoice() throws IOException {
System.out.println("Please select an option of what you would like to do with this number from the menu below and hit <ENTER>: ");
System.out.println("\n*********************************************");
System.out.println("---------------------------------------------");
System.out.println("Please select an option from the list below: ");
System.out.println("---------------------------------------------");
System.out.println("1 - Add");
System.out.println("2 - Subtract");
System.out.println("3 - Multiply");
System.out.println("4 - Divide (remainder included)");
System.out.println("5 - Maximum and minimum value of two numbers");
System.out.println("6 - Squareroot");
System.out.println("7 - Absolute value of numbers");
System.out.println("8 - Octal and Hexadecimal equivalent of numbers");
System.out.println("9 - Round numbers");
System.out.println("0 - Exit program");
System.out.println("**********************************************");
boolean inputCorrect = false;
while (inputCorrect == false) {
try {
BufferedReader inStream = new BufferedReader (new InputStreamReader(System.in));
System.out.print("Please enter your option and hit <ENTER>: ");
choice1 = inStream.readLine();
int c1 = Integer.parseInt(choice1);
System.out.println("\nYou have entered choice number: " + c1);
inputCorrect = true;
} catch (NumberFormatException nfe) {
System.out.println("You did not enter a valid choice number: " + "\""+ choice1 + "\" is not in the list!!");
inputCorrect = false;
return choice1;
public String inputNumber2() throws IOException {
boolean inputCorrect = false;
while (inputCorrect == false) {
try {
BufferedReader br2 = new BufferedReader (new InputStreamReader(System.in));
System.out.print("\nPlease enter another number you want to do the calculation with and hit <ENTER>: ");
num2 = br2.readLine();
double n2 = Double.parseDouble(num2);
System.out.println("\nThe second number you have entered is: " + n2);
System.out.println("\nYour numbers are: " + num1 + " and " + num2);
inputCorrect = true;
} catch (NumberFormatException nfe) {
System.out.println("You did not enter a valid number: " + "\""+ num2 + "\" is not a number!!");
inputCorrect = false;
return num2;
public int Calculator() {
int choice2 = (int) Double.parseDouble(choice1);
switch (choice2) {
case 1 :
Add();
System.out.print("The answer of " + num1 + " + " + num2 + " is: " + decimals.format(answer));
break;
case 2 :
Subtract();
System.out.print("The answer of " + num1 + " - " + num2 + " is: " + decimals.format(answer));
break;
case 3 :
Multiply();
System.out.print("The answer of " + num1 + " * " + num2 + " is: " + decimals.format(answer));
break;
case 4 :
Divide();
System.out.print("The answer of " + num1 + " / " + num2 + " is: " + decimals.format(answer));
Modulus();
System.out.print(" and the remainder is " + decimals.format(answer));
break;
case 5 :
maximumValue();
System.out.println("The maximum number between the numbers " + num1 + " and " + num2 + " is: " + decimals.format(answer));
minimumValue();
System.out.println("The minimum number between the numbers " + num1 + " and " + num2 + " is: " + decimals.format(answer));
break;
case 6 :
Squareroot1();
System.out.println("The squareroot of value " + num1 + " is: " + decimals.format(answer));
Squareroot2();
System.out.println("The squareroot of value " + num2 + " is: " + decimals.format(answer));
break;
case 7 :
absoluteNumber1();
System.out.println("The absolute number of " + num1 + " is: " + decimals.format(answer));
absoluteNumber2();
System.out.println("The absolute number of " + num2 + " is: " + decimals.format(answer));
break;
case 8 :
octalEquivalent1();
System.out.println("The octal equivalent of " + num1 + " is: " + octalEquivalent1());
octalEquivalent2();
System.out.println("The octal equivalent of " + num2 + " is: " + octalEquivalent2());
hexadecimalEquivalent1();
System.out.println("\nThe hexadecimal equivalent of " + num1 + " is: " + hexadecimalEquivalent1());
hexadecimalEquivalent2();
System.out.println("The hexadecimal equivalent of " + num2 + " is: " + hexadecimalEquivalent2());
break;
case 9 :
Round1();
System.out.println("The rounded number of " + num1 + " is: " + decimals.format(answer));
Round2();
System.out.println("The rounded number of " + num2 + " is: " + decimals.format(answer));
break;
case 0 :
if (choice2 == 0) {
System.exit(1);
break;
return choice2;
public String anotherCalculation() throws IOException {
boolean inputCorrect = false;
while (inputCorrect == false) {
try {
BufferedReader br3 = new BufferedReader (new InputStreamReader(System.in));
System.out.print("\nWould you like to do another calculation? Y/N ");
more = br3.readLine();
String s1 = "y";
String s2 = "Y";
if (more.equals(s1) || more.equals(s2)) {
inputCorrect = true;
while (inputCorrect = true){
inputNumber1();
System.out.println("");
calculatorChoice();
System.out.println("");
inputNumber2();
System.out.println("");
Calculator();
System.out.println("");
anotherCalculation();
System.out.println("");
inputCorrect = true;
} else {
System.out.println("\n" + nameSurname + " thank you for using this program, you have used this program for: " + decimals.format(programRuntime()) + " seconds");
System.out.println("the program will now exit, Goodbye.");
System.exit(0);
} catch (IOException ex){
System.out.println("You did not enter a valid answer: " + "\""+ more + "\" is not in the list!!");
inputCorrect = false;
return more;
public static void main(String[] args) throws IOException {
Project p1 = new Project();
p1.insertNameAndSurname();
System.out.println("");
p1.inputNumber1();
System.out.println("");
p1.calculatorChoice();
System.out.println("");
p1.inputNumber2();
System.out.println("");
p1.Calculator();
System.out.println("");
p1.anotherCalculation();
System.out.println("");
{code}
*Can you please run my code for yourself and have a look at how this program is constructed*
*and give me ANY feedback on how I can better this code(program) or if I've done anything wrong from your point of view.*
Your help will be much appreciated.
Thanks in advanceSmirre wrote:
Now my question is this: How can I restrict the user to only enter 'letters' (and spaces of course) but allow NO numbers for his/her surname??You cannot restrict the user. It is a sad fact in programming that the worst bug always sits in front of the Computer.
What you could do is checking the input string for numbers. If it contains numbers, just reprompt for the Name.
AND you might want to ask yourself why the heck a calculator needs to know the users Name. -
Im DROWNING! need help with a simple java assignment! plz someone help me!
i need help with my java assignment, with validating a sin number. easy for must who know java. im drowning... please help!
You will need to store each digit of the social insurance number in a field of its own. To validate the entry you will:
1. Multiply the 2nd, 4th, 6th and 8th digit by 2.
2. If the product of any of the four multiplications result in a value greater than 9, add the two resulting digits together to yield a single-digit response. For example 6 * 2 = 12, so you would add the 1 and the 2 to get a result of 3.
3. Add these four calculated values together, along with the 1st, 3rd, 5th, and 7th digits of the original number.
4. Subtract this sum from the next highest multiple of 10.
5. The difference should be equal to the 9th digit, which is considered the check digit.
Example of validating S.I.N. 765932546
1st digit 7
2nd digit (6*2 =12 1+2=) 3
3rd digit 5
4th digit (9*2 = 18 1+8 =) 9
5th digit 3
6th digit (2*2 = 4) 4
7th digit 5
8th digit (4*2 = 8) 8
Total 44 next multiple of 10 is 50
50-44 = 6 which is the 9th digit
Therefore the S.I.N. 765932546 is Valid
********* SIN Validation *********
Welcome - Please enter the first number: 120406780
Second digit value multiplied by 2 4
Fourth digit value multiplied by 2 8
Sixth digit value multiplied by 2 12
Eighth digit value multiplied by 2 16
Value derived from 6th digit 3
Value derived from 8th digit 7
The total is 30
Calculated digit is 10
Check digit must be zero because calculated value is 10
The SIN 120406780 is Valid
this is my assignemtn this is what i have! i dont know where to start! please help me!
/* File: sinnumber.java
Author: Ashley
Date: October 2006
Purpose: Lab1
import java.util.Scanner;
public class Lab1
public static void main(String[] args)
Scanner input = new Scanner(System.in);
int sin = 0;
int number0, number1, number2, number3, number4, number5, number6, number7, number8;
int count = 0;
int second, fourth, sixth, eighth;
System.out.print("\t\n**********************************");
System.out.print("\t\n**********SIN Validation**********");
System.out.print("\t\n**********************************");
System.out.println("\t\nPlease enter the First sin number: ");
sin = input.nextInt();
count = int.length(sin);
if (count > 8 || count < 8)
System.out.print("Valid: ");
} -
HOW DO YOU GUYS DEAL WITH APPLE.. SO CONFUSING...NEED HELP WITH SPECS FOR PURCHASE OF IMAC 21.5
Hi guys, been reading your forums, blogposts, etc and am getting more confused. I'm just a video girl trying to produce meaningful content through web videos for small to mid sized businesses and want to come over from the dark side.
Good news,, I dont need a super giant system, I do simple editing for web videos, minimal graphics, no motion graphics, no animation etc. currently using CS4, will probably end up with 5.5.
I want to get imac 21.5 or 27 if i have to.. So here's the question we all have,,, what do I really need besides an Apple fairy godmother to figure this crazy stuff out?????
I want to be able to have firewire add on, but the rest is what I need help with. So i've been looking at cs6 specs, even though im not there yet, eventually will be,, so just need to run cs4 now and build from there. I also want to eventually move to final cut down the road so I want imac able to upgrade to final cut.
WHAT DO I REALLY NEED MINIMALLY FOR NOW? WHAT CAN I GET LATER IF i CHOOSE TO DO MORE AND NEED MORE POWER?
cs6:
Multicore Intel processor with 64-bit support
Mac OS X v10.6.8, v10.7, or v10.8**
4GB of RAM (8GB recommended)
4GB of available hard-disk space for installation; additional free space required during installation (cannot install on a volume that uses a case-sensitive file system or on removable flash storage devices)
Additional disk space required for preview files and other working files (10GB recommended)
1280x900 display
7200 RPM hard drive (multiple fast disk drives, preferably RAID 0 configured, recommended)
OpenGL 2.0–capable system
DVD-ROM drive compatible with dual-layer DVDs (SuperDrive for burning DVDs; Blu-ray burner for creating Blu-ray Disc media)
QuickTime 7.6.6 software required for QuickTime features
Optional: Adobe-certified GPU card for GPU-accelerated performance
Any responses would be great. I know you guys are busy answering the really high end tech questionsAll the current iMac models (both 21.5" and 27" with OS X Mt. Lion 10.8) will run CS4, 5.5 and 6 just fine. They will also run Final Cut Pro X just fine. Ditto for most any application you may want to use.
Below are some notes (specific to your apparent requirements) that may help you with your purchase decision:
Notes on purchasing a 21.5" iMac
All 21.5" iMacs come with 8GB RAM but you cannot add more later. I strongly suggest getting the maximum RAM (16GB) when you order the iMac.
The basic hard drive is a 1TB 5400rpm drive. It will work fine with Adobe CS but you will probably want the added speed of the optional 1TB Fusion drive for better performance. Some people will recommend/argue for one of the optional SSD drives instead, but they are very expensive and still only come in relatively small capacities - I don't recommend the SSD drives. Get the Fusion drive and spend any extra money on a good external hard drive for backup and/or extra storage instead of an SSD.
Notes on purchasing a 27" iMac
All 27" iMacs come with 8GB RAM and you can add more later, up to 32GB
The basic hard drive is a 1TB 7200rpm drive - it will be fine with Adobe CS. There are upgrade options to a 3TB 7200rpm drive or a 1TB or 3TB fusion drive - these will be fine also. There are also SSD drive options, but I do not recommend them. (Same comments as above.)
Notes on all the current iMacs
iMacs no longer come with built-in CD/DVD drives. If you need one, you will need to purchase the Apple Superdrive accessory drive ($79)
All of the iMac graphic processors (GPU's) are compatible with Adobe CS 4, 5.5, 6
It is very difficult to impossible to change or upgrade the hard drive later on, so don't buy low-end thinking you can add a better internal hard drive later.
Be aware that Macs always come with the latest (most recent) version of OS X. And OS X Mavericks (10.9) is due to be released soon (in the next month or two). There is no guarantee that the older Adobe CS 4 or 5.5 versions will run on OS X Mavericks. If you cannot upgrade to CS 6 in the near future, you may want to purchase now rather than after OS X Mavericks is released.
For what it's worth, I'd recommend the 27" iMac if your budget can afford it. You will appreciate the larger screen size and added capabilities over the years you will use the computer. -
I think I need help with driver (software) settings for D110a
I think I need help with driver (software) settings for D110a all-in-one
Product: D110a all-in-one
OS: Windows XP Professional
Error messages: None
Changes before problem appeared: None--new installation
The quality of photo images (mostly JPG files) in printouts is awful even though the files display beautifully on the PC screen. I am using
IrfanView software for displaying/printing. As far as I can tell, IrfanView is not the problem.
When I print the same images on a Deskjet 5150 attached to a different PC also running XP Pro and IrfanView, the quality of the printouts is at
least acceptable, Some would probably say good or very good.
It's dificult to explain in words the problem with the printouts. A picture of really pretty vegetables (squashes, tomatoes, watermelon, etc) comes
out much too red. Moreover, the red, which appears shaded on the screen, seems to be all one shade in the D110a printouts.
Something similar happens to a view of a huge tree in full leaf. On screen, there are subtle variations in the "greenness" of the leaves. In the
printout, all green is the same shade. In the same printout, the trunk of the tree is all a single shade of grey. It isn;t even obvious that the
trunk is a round, solid object.
I liken the effect to audio that disappears entirely when you lower the volume and gets clipped into square waves in even moderately loud passages.
I don't know whether the D110a driver software permits adjusting the parameters that appear to be set incorrectly, and if adjustments are possible,
how I would identify which parameters to adjust, how I would access them, or how I would adjust them. I'm hoping that someone can help. Thanks.
I forgot to mention that I have used the diagnostic application and it tells me that there are no problems.
e-mail me at [email protected]brazzmonkey wrote:
Hi everyone,
I noticed the following message when network starts on my gateway
Warning: This functionality is deprecated.
Please refer to /etc/rc.conf on how to define a single wired
connection, or use a utility such as netcfg.
Then I realized the way network settings should be written in rc.conf has changed. But I can't figure out how this should be done.
Currently, my set up is the following (old way):
INTERFACES=(eth0 eth1)
eth0="dhcp"
eth1="eth1 192.168.0.10 netmask 255.255.255.0 broadcast 192.168.0.255"
ROUTES=(!gateway)
eth0 is on DHCP because the IP is dynamically assigned my ISP.
eth1 has a fix IP because it's on the LAN side.
No problem to use DHCP on eth0 with the new settings.
But for eth1, I don't know what I am supposed to write for gateway.
Wiki isn't clear on that one either, and it looks like many articles still refer to the old way.
Any guidance appreciated, thanks.
brazzmonkey,
you can't define 2 interfaces the old way (even though I saw some tricky workaround somewhere in the forums).
Use, f.e., netcfg:
Comment your old lines.
In /etc/rc.conf insert:
NETWORKS=(Eth0-dhcp Eth1-static)
DAEMONS=(..... !network @net-profiles ....)
In /etc/network.d create 2 files:
First one is named Eth0-dhcp.
Contents:
CONNECTION="ethernet"
DESCRIPTION="Whatever text"
INTERFACE=eth0
HOSTNAME="your hostname"
IP="dhcp"
DHCP_TIMEOUT=15
Second one is named Eth1-static.
Contents:
CONNECTION='ethernet'
DESCRIPTION='whatver'
INTERFACE='eth1'
HOSTNAME='hname'
IP='static'
ADDR='192.168.0.10'
GATEWAY='192.168.0.1' # your gateway IP
DNS=('192.168.0.1') # your DNS server
The names Eth0-dhcp and Eth1-static are not magic. They just must be the same in rc.conf and in /etc/network.d.
Hope it helps.
mektub
PS: netcfg must be installed.
Last edited by Mektub (2011-07-20 14:07:05)
Maybe you are looking for
-
My iPhoto won't open. It says "Your photo library is either in use by another application or no longer readable." Please tell me I haven't lost all my pics?! I do not have them backed up. I have tried restarting my mac. Please Help!
-
Why can I not receive iMessages on my iPod touch 4g after updating my iPhone 5 to iOS 7?
Yes, you read correctly. I updated my iPhone to iOS 7, and poof!!! Now iMessages are not being sent to my iPod touch. What happened?!
-
Getting list of tables the user has access to across different schemas.
Hi, I have to get the list of tables that an User has access to. I tried the below code. It takes a very long time. Is there any way in which I can specify the user name and get all the tables that he has access to? I know that we can use dbMetadata.
-
***Urgent Need of resolution***X220 driver not installed Intel Management Engine AMT 7.1
I have a laptop refresh project strating soon and i can not deploy any X220 machines. After the installation of Windows 7 there is an "Unknown device" shown in device manager. If I uninstall the unknown device then "Scan hardware changes" the device
-
Ok, I recently submitted crash information to bugzilla for an epiphany issue I am seeing. My bug was determined to be related to another issue pending additional information (Bug 362609). The devs are requesting additional information as the stack