Need to create a button to open an URL

Hi, everyone:
I want to create a button that response opening a webpage. How? someone can help me?
Thanx
Khriz

Hey ! Go for this , this is very easy !!
public void actionPerformed(ActionEvent ae)
    // showContent is a button
   if( ae.getSource()==showContent)
      try
        Process process = Runtime.getRuntime().exec("start www.yahoo.com");
      catch(Exception e)
}

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hi
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Message was edited by: Yellowbox. Oops, had to revise Table names.

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Thanks

Hi,
First of all I would advice you to post this question in the new CRM 2007 forum.
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CONCATENATE 'javascript:window.open'
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ls_button-type     = cl_thtmlb_util=>gc_icon_print.
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ls_button-page_id = me->component_id.
ls_button-enabled = abap_true.
APPEND ls_button TO rt_buttons.
CLEAR ls_button.
ls_button-text     = cl_wd_utilities=>get_otr_text_by_alias( 'CRM_UIU_BT_SALES_QUOT/SORDER_CREATEFOLLOW-UP' )."#EC NOTEXT
ls_button-tooltip = cl_wd_utilities=>get_otr_text_by_alias( 'CRM_UIU_BT_SALES_QUOT/SORDER_CREATEFOLLOW-UP' )."#EC NOTEXT
ls_button-on_click = 'FOLLOWUP'.                          "#EC NOTEXT
ls_button-page_id = me->component_id.
ls_button-enabled = lv_persistent.
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CLEAR ls_button.
/Anders

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Hi Milinda,
you have to define your own form and dropdownboxes for this. To fill your dropdownboxes you can use the web item dropdowns with the parameter ONLY_VALUES = X.
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<META NAME="GENERATOR" Content="Microsoft DHTML Editing Control">
<TITLE>BW Web Application</TITLE>
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regards
Alex

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Thanx,
Gulsah.

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//this is the variable you want to pass from one form to the other
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htp.p('<script language="JavaScript1.3">
< !--
function getField(form,fieldName)
var objName = "";
var tmp = "";
var dAction = "";
var sel_idx = 0;
var cnt = 0;
var instance = 0;
var slicedName;
var fillData = new Array();
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instance = parseInt(slicedName[3],10);
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//-->
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I hope this helps.
null

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Please next time consider using a line break or two when you post. Thank you for your consideration.

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