NetStream.publish for P2P NetGroup fails in the FMS 4.0 AS

Question

Hi,
I recently tried to modify the system-provided codes in the "multicast" folder, and could not get it work. I pinned down the issue to be the function call NetStream.publish("p2p_pindao1", "live") always failed for me. The proof the function call failed including:
1. The returned value is false.
2. I got no further events beyond NetStream.Connect.Success, i.e. I did not get the expected NetStream.Publish.Start
The following are the testing codes
application.onAppStart = function()
var nc = new NetConnection();
nc.onStatus = testNetStatus;
nc.connect("rtmfp://localhost/TVLive");
trace("to connect");
function testNetStatus(info)
trace("TestNetStatus:" + info.code);
var gs = new GroupSpecifier("net.lysk.pindao1");
gs.serverChannelEnabled = true;
gs.postingEnabled = true;
gs.peerToPeerDisabled = false;
// Multicast address over which to exchange peer discovery.
//var p2pm = "224.0.0.255:30000"; // BUGBUG
// Must be enabled for LAN peer discovery to work
//gs.ipMulticastMemberUpdatesEnabled = true; 
var ng = new NetGroup(this, gs);
ng.objNc = this;
ng.objGs = gs;
ng.onStatus = testNetGroupStatus;
function testNetGroupStatus(info)
trace("testNetGroupStatus:" + info.code);
var ns = new NetStream(this.objNc, this.objGs);
ns.onStatus = testNetStreamStatus;
function testNetStreamStatus(info)
trace("testNetStreamStatus:" + info.code);
if (info.code == "NetStream.Connect.Success")
  if(!this.attach(Stream.get("mp4:sample1_1000kbps.f4v")))
   trace("can not attach");
  if (!this.publish("testpublish", "live"))
   trace ("can not publish");
tracing outputs are the following:
to connect
TestNetStatus:NetConnection.Connect.Success
testNetGroupStatus:NetGroup.Connect.Success
testNetStreamStatus:NetStream.Connect.Success
can not publish
Your help in solving the problem will be highly appreciated.
Thanks.

Answer 1

em, it appears I was wrong in believing peerToPeerDisabled=true sufficed for P2P publishing, while multicastEnabled was for IP multicast. I will try out the answer. Thanks for the help.