Nio Question - get() method in ByteBuffer

Question

I m working on the telnet client program, in the negotiation phase of telnet
connection, my telnet server returns me FF FB 03 FF FB 01 (WILL SUPPRESS-GO-AHEAD
WILL ECHO), I read those bytes into a ByteBuffer, and trying to print them out
to the screen.
static ByteBuffer bb = ByteBuffer.allocateDirect(1024);
public static void main(String args[]) throws IOException{
InetSocketAddress isa = new InetSocketAddress("192.168.1.1", 23);
SocketChannel sc = null;
try {
sc = SocketChannel.open();
sc.connect(isa);
bb.clear();
sc.read(bb);
bb.flip();
System.out.println(bb.get());
For byte FF FB 03 FF FB 01, I got result like -1 -5 3 -1 -5 1
it seems to me that "print" can't print byte to screen, I therefore tried
this "new Byte(bb.get()).intValue()", however it gives me the same result
03 01 are properly displayed, does it mean java interprets 1111 1111 as negative?
how do I display them as integer value?

Answer 1

Integer.toHexString(int) will return a string containing the hexadecimal representation of the value of the int.