NodeList and getElementsByTagName

Question

Hi guys, I have a great problem, and I cannot solve them, therefor I like get some your help!!!!
I have a xml document:
<transformers>
    <transformer>
        <name>transformer1</names>
    </transformer>
        <transformer>
        <name>transformer2</names>
    </transformer>
        <transformer>
        <name>transformerN</names>
    </transformer>
</transformers>And I wanna create a function that remove a "transformer" based on the name value. Then I create the method:
public void delete(String tag, String name)
    ListNode list = xmlTree.getElementsByTagName(tag);
    System.out.pritln("SIZE LIST: " + list.getLength());
    for(int i = 0; i < list.getLength(); i++)
        System.out.println("NODE[" + i + "]: " + list.item(i));
        if(list.item(i).getNodeValue().equals(name))
            list.item(i).getParentNode().removeNode(list.item(i));
    }//End for
}//End delete() methodThen I call :
delete("name", "transformer2");And I get the result:
SIZE LIST: 3 //Thats OK, I just had three nodes
NOD[0]: null //Why I always get null, if the list had three nodes?!?!?
NOD[1]: null
NOD[2]: null
Someone can help me??!? Thanks
Giscard

Answer 1

The value of an element is not the text that is inside the node. You would need to call
getFirstChild, getNextSibling to collect the text, and then do the compare.