NUMBER AND INTEGER

HI, WHAT IS THE DIFFERENCE BETWEEN NUMBER AND INTEGER WHEN I CREATE A TABLE WITH SOME OF THESE ATRIBUTTES, AND TO CREATE SEQUENCES TO USING THE VARIABLE AUTOINCREMENT, THANKS FOR ANY HELP

Read this
http://download.oracle.com/docs/cd/B19306_01/olap.102/b14346/dml_datatypes002.htm#CJACDECG

Similar Messages

  • Counter KF with 1 & 0 and difference between data type NUMBER (DEC) and INTEGER (INT4)

    Hi,
    I need to create a counter kf which should populate 1 and 0 to this counter field. Please let me know is there any difference between data type
    NUMBER (DEC) and INTEGER (INT4).
    Please suggest.
    Thanks & Regards,
    Pavan kumar

    Hi Pavan,
    The basic difference between Number(DEC) and INT4 is its internal storage in system.
    For Number (DEC) - Value internally stored as packed number with 3 decimal places whereas INT 4 as 4 byte integer without decimal places.
    For counter KF, you can go for INT 4.
    Hope this helps.
    Thanks

  • Difference between Number(*,0) and Integer

    Hi,
    Is there any difference between Number(*,0) and Integer?
    And are there any documents i can download to describe such things.
    I user Oracle 10g
    Thanks,
    Yan

    There's an easy way to investigate this - using the SQL DUMP() function.
    For example:
    SQL> create table testtab( i integer, n number(5,2) );
    Table created.
    SQL> insert into testtab values( 100, 100.00);
    1 row created.
    SQL> insert into testtab values( 100, 100.01);
    1 row created.
    SQL> insert into testtab values( 99999, 999.99);
    1 row created.
    SQL> col i_dump format a30
    SQL> col n_dump format a30
    SQL>
    SQL> select i, n, dump(i) as i_dump, dump(n) as n_dump from testtab;
             I          N I_DUMP                         N_DUMP
           100        100 Typ=2 Len=2: 194,2             Typ=2 Len=2: 194,2
           100     100.01 Typ=2 Len=2: 194,2             Typ=2 Len=4: 194,2,1,2
         99999     999.99 Typ=2 Len=4: 195,10,100,100    Typ=2 Len=4: 194,10,100,100
    SQL>

  • String exponent number to integer and double conversion

    Anyone who can help please,
    I am receiving data back from an Agilent E4407B with the noise figure option in the following form:
    +1.00000000E+008,+1.52799997E+001,+1.00000000E+009,+1.52200003E+001,+2.00000000E+009,+1.51099997E+001,+3.00000000E+009,+1.50799999E+001,
    for up to 401 pairs of frequencies and amplitude figures.  This is all coming back in one long string.
    I want to read the pairs of figures into a 2 dimensional array, so that the first part of the array has the frequency in an double format, but NO exponent, and the second part of the array has the ENR value agan in a double format and also with NO exponent.
    I have been using:
    double ENR_Data[401][2];
    Scan(Databuf,"%s>%401f[x]",&ENR_Data);
    This reads the data into the array, but retains the exponent - please can someone show me the correct Scan formatting functions to use so that I keep just the number, and loose the scientific exponent format?
    Many thanks for any help,
    Allen Cherry

    Allen:
    It doesn't matter how you represent the doubles: the compiler represents them the same.
    double a = 2000000000.00;
    double b = 2e9;
    As far as the compiler is concerned (and as far as you should be concerned), a==b.
    In your last reply, your interpolated value of (say) 25000000000 = 2.5e10, which is greater than 2e9 and 3e9.  You said you may have the wrong number of zeros in the example, but please make sure you have the right number of zeros in your code.
    Are you sure you are handling the array correctly?  Remember that the array subscripts are [row][column].  From your sample data, the frequency values are in column 0.  The first frequency value would be ENR_Data[0][0].  The second frequency value would be ENR_Data[1][0], followed by ENR_Data[2][0], etc.
    Check the code I included below.  It's based on the numbers shown in your example.  It correctly determines if a number is greater than or less than a desired interpolated point.
    P.S. What algorithm are you using to do you interpolation?  I don't even know why you are searching for a number greater than some known value: you should be interpolating between points read from the array.
    #include <ansi_c.h>
    #include <utility.h>
    #include <formatio.h>
    main()
     char Databuf[] = "+1.00000000E+008,+1.52799997E+001,+1.00000000E+009,+1.52200003E+001,"
         "+2.00000000E+009,+1.51099997E+001,+3.00000000E+009,+1.50799999E+001";
     double ENR_Data[401][2];
     double interpValue = 2.5E9;
     // same as
     // double interpValue = 2500000000.00;
     int i;
     Scan(Databuf,"%s>%401f[x]",&ENR_Data);
     for (i=0; i<4; i++)
      if (ENR_Data[i][0] > interpValue)
       printf("%f (%e) > %f (%e)\n",
        ENR_Data[i][0], ENR_Data[i][0],
        interpValue, interpValue);
      else
       printf("%f (%e) <= %f (%e)\n",
        ENR_Data[i][0], ENR_Data[i][0],
        interpValue, interpValue);
     printf("Press any key to continue...\n");
     GetKey();

  • Difference between datatype NUMBER and NUMBER(38)

    Difference between datatype NUMBER and NUMBER(38)

    From
    http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/sql_elements001.htm#i54330
    NUMBER Datatype
    The NUMBER datatype stores zero as well as positive and negative fixed numbers with absolute values from 1.0 x 10-130 to (but not including) 1.0 x 10126. If you specify an arithmetic expression whose value has an absolute value greater than or equal to 1.0 x 10126, then Oracle returns an error. Each NUMBER value requires from 1 to 22 bytes.
    Specify a fixed-point number using the following form:
    NUMBER(p,s)
    where:
    p is the precision, or the total number of significant decimal digits, where the most significant digit is the left-most nonzero digit, and the least significant digit is the right-most known digit. Oracle guarantees the portability of numbers with precision of up to 20 base-100 digits, which is equivalent to 39 or 40 decimal digits depending on the position of the decimal point.
    s is the scale, or the number of digits from the decimal point to the least significant digit. The scale can range from -84 to 127.
    Positive scale is the number of significant digits to the right of the decimal point to and including the least significant digit.
    Negative scale is the number of significant digits to the left of the decimal point, to but not including the least significant digit. For negative scale the least significant digit is on the left side of the decimal point, because the actual data is rounded to the specified number of places to the left of the decimal point. For example, a specification of (10,-2) means to round to hundreds.
    Scale can be greater than precision, most commonly when e notation is used. When scale is greater than precision, the precision specifies the maximum number of significant digits to the right of the decimal point. For example, a column defined as NUMBER(4,5) requires a zero for the first digit after the decimal point and rounds all values past the fifth digit after the decimal point.
    It is good practice to specify the scale and precision of a fixed-point number column for extra integrity checking on input. Specifying scale and precision does not force all values to a fixed length. If a value exceeds the precision, then Oracle returns an error. If a value exceeds the scale, then Oracle rounds it.
    Specify an integer using the following form:
    NUMBER(p)
    This represents a fixed-point number with precision p and scale 0 and is equivalent to NUMBER(p,0).
    Specify a floating-point number using the following form:
    NUMBER
    The absence of precision and scale designators specifies the maximum range and precision for an Oracle number.
    And
    2
    NUMBER[(precision [, scale]])
    Number having precision p and scale s. The precision p can range from 1 to 38. The scale s can range from -84 to 127
    Sybrand Bakker
    Senior Oracle DBA

  • How to find the largest odd number and smallest even number from an array

    Hello All
    I want to find out largest odd number and the smallest even number from an arry numbers? What is the best method to achieve this.
    Thanks
    Sravz

    You need to sit down and figure out an algo on how you would do it if you had to do the same thing from a blind container perspective:
    1 - collect all the items you want to look at
    2 - look at an item
    3 - is it odd?
    4 - if it is odd then check if it is larger than previously largest number
    5 - save it if it is larger
    6 - return back to 2 unless no more items
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    9 - return back to 2 unless no more items
    Now you just need to know how to check if something is even or odd: to do this you will need the modulous operator--integer division.
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  • Lockbox Customer Number and Bank Account Validation

    When attempting to run lockbox, we are populating both customer number and bank account number. My understanding is that when providing bank account only, Oracle requires this be the pirmary bank account for the customer. It uses this information to identify the customer.
    When we provide the customer number in our file, it should use that value.
    We do not have the primary flag set for any bank accounts, as we have multiple per customer in many cases, any of which can receive payment.
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    thanks
    Bill

    That's what I thought as well, but it isn't. It's set as text and still drops it as if it were an integer
    If I enter 0123456 into this field, when I go into 'Cases' to retrieve this information, it is displayed as 123456

  • Convert time to number and number to time

    I'm using SAP 4.0b
    I'm looking for function that converts time to number and number to time.
    Any suggestion?

    Hi,
    Can you give an example of what number you want to give to get what time and vice-versa?
    There can be a direct conversion between an integer and a time variable in ABAP.
    For example -
    data: number type i,
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    write time.
    The time will be output as "01:00:00". That is because 3600 seconds make up one hour.
    Regards,
    Anand Mandalika.

  • Number and name of rows

    Is there any way to know the total number and the names of the rows in a table?

    Sample:
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    try {
    metaData = rs.getMetaData();
    int singleHtColumnType;
    columnCount = metaData.getColumnCount();
    for (i = 1; i <= columnCount; i++) {
    columnNames[i-1] = new String(metaData.getColumnName(i));
    // System.out.println("meta-look " + columnNames[i-1]);
    // System.out.println(metaData.getColumnLabel(i)); // on AS/400 == columnName :-((
    // System.out.println("ColumnDisplaySize: " + metaData.getColumnDisplaySize(i));
    singleHtColumnType = metaData.getColumnType(i);
    if (readBigDecimalAsInt & singleHtColumnType == 8) singleHtColumnType = 4;
    columnType[i-1] = singleHtColumnType;
    if (singleHtColumnType == 8
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    htColumnType.put(columnNames[i-1], new Integer(singleHtColumnType));
    if (singleHtColumnType == 1 | singleHtColumnType == 12) maxFieldSize.put(columnNames[i-1], new Integer(getColumnDisplaySize(i)));
    catch (SQLException e2) {
    System.out.println("loadMetaData caught " + e2);
    System.out.println("Index was " + i);
    catch (Exception e) {
    System.out.println("loadMetaData caught " + e);
    System.out.println("Index was " + i);

  • Cast number to integer

    hopefully a simple question.
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    /Daniel

    From Number you can go a getInt to get the integer. And then you can initialize this integer using a try/catch block to get the Integer data type. The code would look something like this:
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    int i = n.getInt();
    try
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    }

  • Excise Invoice number and Internal Number

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  • HT201328 I have been given permission for unlocking my iphone 3 GS from Orange. I want to set up the phone for my wife to use with a new number and carrier. Do I unlock under my itunes account first or set one up for her and then unlock the phone.

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