Cast number to integer

hopefully a simple question.
How do I cast a number to integer?
/Daniel

From Number you can go a getInt to get the integer. And then you can initialize this integer using a try/catch block to get the Integer data type. The code would look something like this:
Number n = <Number Value>.
int i = n.getInt();
try
Integer intn = new Integer(i);
catch(Exception e)
}

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Hql how to cast number to varchar2

Hello.
How to cast number to varchar2(to string)? I'm using hql toplink implementation and (don't know why) functions like cast(... as ...), to_char(...) and str(...) don't work. Please help me.
Kuba :).
Edited by: 854998 on 2011-04-27 03:12

Hello Chris.
First of all I'd like to thank you for answer. :)
1)I can't use native query.
2)What do you mean?
3)I can't upgrade.
I have something like this(it's only simple example, I have more complex query):
getManager().createQuery("SELECT obj FROM " + EntityClass.class.getSimpleName() + " obj "
+ " WHERE '14' = obj.number").getResultList();
r.number is Number in Oracle and Long in entity class.
I want to cast obj.number to String.
Here: http://docs.jboss.org/hibernate/core/3.3/reference/en/html/queryhql.html#queryhql-expressions expressions like cast is valid.
So, where's the problem? My toplink version is too old?
Thanks a lot
Kuba.

NUMBER AND INTEGER

HI, WHAT IS THE DIFFERENCE BETWEEN NUMBER AND INTEGER WHEN I CREATE A TABLE WITH SOME OF THESE ATRIBUTTES, AND TO CREATE SEQUENCES TO USING THE VARIABLE AUTOINCREMENT, THANKS FOR ANY HELP

Read this
http://download.oracle.com/docs/cd/B19306_01/olap.102/b14346/dml_datatypes002.htm#CJACDECG

Cast(NULL as INTEGER ) - Problem

Hello,
Can any body explain me why there is a sub Query here. c3 is suppose to be Count(T263127."ROW_WID")
select distinct D1.c1 as c1,
D1.c2 as c2,
cast(NULL as INTEGER ) as c3
from
(select distinct T31796."NAME" as c1,
T325219."X_OPPTY_NAME" as c2
from
"W_OPTY_DX" T325219,
"W_ORG_D" T31796 left outer join "W_ORG_DX" T262715 On T31796."ROW_WID" = T262715."ROW_WID",
"W_REVN_F" T32385,
"W_OPTY_DX" T263127
where ( T31796."ROW_WID" = T32385."PR_ACCNT_WID" and T32385."OPTY_WID" = T263127."ROW_WID" and T32385."OPTY_WID" = T325219."ROW_WID" and T263127."X_ACTIVE_FLG" <> 'D' )
) D1
order by c1, c2
Thanks

Thanks guys......i just missed a Complex join :(

Invalid casts - Object and Integer

OK, I have got myself confused with casts. I have written this code, which I have [bold]SUBMITTED[bold] to University (so if you change it you are not helping me cheat...) . It doesn't compile and I am out of ideas why. The problem is the last method returnEvenNumbers(). Please could someone help me learn how this should be used by turning this into running code.
* Filename: RandomNumberArray.java
* Author: Steven Lane
* Email: [email protected]
* Created on 17 February 2002, 17:53
* Course: KIT eLearning, MSc in IT, University of Liverpool, UK
*         MSC-JV0020110-03
* Purpose: This class creates an uncostrained array of length L passed as int on instantiation.
*          The array is populated with (pseudo) random numbers.
*          Methods contain a filter for even numbers, which is pushed onto a stack.
* Version: 0.2
//package com.thinkcorporation.week6;
// ------------------- Import Packages -------------------
import java.util.*;
// ------------------- Class Heading -------------------
public class RandomNumberArray extends java.lang.Object {
    // ------------------- Field Defintions -------------------
   private Stack stkEvenNumbers = new Stack();
    private int [] rndNoArray;
    //private int [] evenNoArray;
    private Integer evenNoArray[];
    // ------------------- Constructors -----------------------
    public RandomNumberArray(int length) {
        rndNoArray = new int [length];
        populateRndNoArray();
    //------------------- Methods -----------------------------
    private void populateRndNoArray() {
        Random rnd = new Random();
        for(int counter = 0; counter < rndNoArray.length; counter++) {
            rndNoArray[counter] = rnd.nextInt();
    public void evenNumberFilter() {
        for(int counter = 0; counter < rndNoArray.length; counter++) {
            if (rndNoArray[counter]%2 == 0)
                stkEvenNumbers.push(new Integer(rndNoArray[counter]));
    public int [] returnEvenNumbers() {
        if (!stkEvenNumbers.empty()) {
            evenNoArray = new Integer [stkEvenNumbers.size()];
            evenNoArray = (Integer)stkEvenNumbers.toArray();
        return evenNoArray;
}You help is much appreciated.

The root of the problem is a difference between primitive types and objects. The Stack.toArray() method returns an array of Objects (Object[]), which you can cast to an array of Integer objects (Integer[]):
evenNoArray = (Integer[])stkEvenNumbers.toArray();However, your return type for that method is int[] - a primitive types, not objects. Meaning that you either have to step through the array and build an array of ints (using Integer.intValue()), or you have to change the return type of your method.

Why the data type has changed to number from integer?

SQL> create table t3(id integer);
Table created.
SQL> desc t3;
Name Null? Type
ID NUMBER(38)

Yes you are right, but obviousely Oracle represents INTEGER as NUMBER(38) internally, which meens that you do not have decimal digits.
see my demo:
1 create table test_i
2* (col1 integer)
SYS @10gR2 SQL > /
Table created.
SYS @10gR2 SQL > desc test_i
Name Null? Type
----------------------------------------- -------- ---------------------------- COL1 NUMBER(38)
SYS @10gR2 SQL > insert into test_i values(10.2);
1 row created.
SYS @10gR2 SQL > select * from test_i;
COL1
10
SYS @10gR2 SQL > insert into test_i values(10.6);
1 row created.
SYS @10gR2 SQL > select * from test_i;
COL1
10
11
=;-)
Lutz

Casting Number as Char - how to hide decimal places?

I am casting a number as a Char because I am concatenating it with other things. The problem is that when I cast to char, it displays two decimal places of just 0's. I really don't want to show the decimal place or anything after it. Is there a way to remove them?
Thanks

Hi,
You can have two approaches for the same.
1> cast( cast(column as int) as char)
2> Go to the column properties(i.e the finger mark on the coulmn heading). Then select the data format tab and check the override the default data format tab. Then you can set the decimal places.

Copy command change type number to integer.

Hi, when i do a copy table from one database to another using 'copy from to...create ...using select * from..', the datatype 'number' had been changed to 'integer' in the target database...
Pls advise.

MultipleInvoicesPayListVOImpl MultipleInv = (MultipleInvoicesPayListVOImpl)paymentAM.findViewObject("MultipleInvoicesPayListVO");
Row row[] = MultipleInv.getAllRowsInRange();
Integer modifiedTotal = new Integer("0");
for (int i = 0;i<row.length;i++)
MultipleInvoicesPayListVORowImpl currentRow = (MultipleInvoicesPayListVORowImpl)row;
//modifiedTotal=modifiedTotal+(int)currentRow.getPaymentAmt();
//modifiedTotal=currentRow.getPaymentAmt();
modifiedTotal = new Integer(currentRow.getPaymentAmt().toString());
Haroon.

How to find whether a given number is integer?

hello,
How can i find out whether a given number ( a variable after simplification holds a value) is an integer or not.?
I thought i could use isinteger( ) function in mathscript, but it does not exist- is giving error
can i do it without mathscript?
Thanks,
Solved!
Go to Solution.

I assume you want m/N to be a (possibly rounded up) integer. Is this correct.
In this case, you could do something like the following?
Message Edited by altenbach on 01-25-2009 04:47 PM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
DivideAndRoundUp.png ‏5 KB

String exponent number to integer and double conversion

Anyone who can help please,
I am receiving data back from an Agilent E4407B with the noise figure option in the following form:
+1.00000000E+008,+1.52799997E+001,+1.00000000E+009,+1.52200003E+001,+2.00000000E+009,+1.51099997E+001,+3.00000000E+009,+1.50799999E+001,
for up to 401 pairs of frequencies and amplitude figures. This is all coming back in one long string.
I want to read the pairs of figures into a 2 dimensional array, so that the first part of the array has the frequency in an double format, but NO exponent, and the second part of the array has the ENR value agan in a double format and also with NO exponent.
I have been using:
double ENR_Data[401][2];
Scan(Databuf,"%s>%401f[x]",&ENR_Data);
This reads the data into the array, but retains the exponent - please can someone show me the correct Scan formatting functions to use so that I keep just the number, and loose the scientific exponent format?
Many thanks for any help,
Allen Cherry

Allen:
It doesn't matter how you represent the doubles: the compiler represents them the same.
double a = 2000000000.00;
double b = 2e9;
As far as the compiler is concerned (and as far as you should be concerned), a==b.
In your last reply, your interpolated value of (say) 25000000000 = 2.5e10, which is greater than 2e9 and 3e9. You said you may have the wrong number of zeros in the example, but please make sure you have the right number of zeros in your code.
Are you sure you are handling the array correctly? Remember that the array subscripts are [row][column]. From your sample data, the frequency values are in column 0. The first frequency value would be ENR_Data[0][0]. The second frequency value would be ENR_Data[1][0], followed by ENR_Data[2][0], etc.
Check the code I included below. It's based on the numbers shown in your example. It correctly determines if a number is greater than or less than a desired interpolated point.
P.S. What algorithm are you using to do you interpolation? I don't even know why you are searching for a number greater than some known value: you should be interpolating between points read from the array.
#include <ansi_c.h>
#include <utility.h>
#include <formatio.h>
main()
char Databuf[] = "+1.00000000E+008,+1.52799997E+001,+1.00000000E+009,+1.52200003E+001,"
     "+2.00000000E+009,+1.51099997E+001,+3.00000000E+009,+1.50799999E+001";
double ENR_Data[401][2];
double interpValue = 2.5E9;
// same as
// double interpValue = 2500000000.00;
int i;
Scan(Databuf,"%s>%401f[x]",&ENR_Data);
for (i=0; i<4; i++)
  if (ENR_Data[i][0] > interpValue)
   printf("%f (%e) > %f (%e)\n",
    ENR_Data[i][0], ENR_Data[i][0],
    interpValue, interpValue);
  else
   printf("%f (%e) <= %f (%e)\n",
    ENR_Data[i][0], ENR_Data[i][0],
    interpValue, interpValue);
printf("Press any key to continue...\n");
GetKey();

Validate text filed - phone number or integer?

I am trying to validate a field that requires a phone number but I want to make sure that the user enters only numbers and cannot enter a (1) before the number.
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Thanks.

Have you seen this page?
http://labs.adobe.com/technologies/spry/samples/validationwidgets/TextfieldValidationSampl e.html

How to cast an Object into a specific type (Integer/String) at runtime

Problem:
How to cast an Object into a specific type (Integer/String) at runtime, where type is not known at compile time.
Example:
public class TestCode {
     public static Object func1()
Integer i = new Integer(10); //or String str = new String("abc");
Object temp= i; //or Object temp= str;
return temp;
     public static void func2(Integer param1)
          //Performing some stuff
     public static void main(String args[])
     Object obj = func1();
//cast obj into Integer at run time
     func2(Integer);
Description:
In example, func1() will be called first which will return an object. Returned object refer to an Integer object or an String object. Now at run time, I want to cast this object to the class its referring to (Integer or String).
For e.g., if returned object is referring to Integer then cast that object into Integer and call func2() by passing Integer object.

GDS123 wrote:
Problem:
How to cast an Object into a specific type (Integer/String) at runtime, where type is not known at compile time.
There is only one way to have an object of an unknown type at compile time. That is to create the object's class at runtime using a classloader. Typically a URLClassloader.
Look into
Class.ForName(String)

Reg : Number v/s Integer -

Hi Experts,
I have a confusion regarding the usage of data types - Number & Integer.
I'm into Pl/Sql development and generally use Number.
Below text is from the docs -
>
Analytic workspace calculations on NUMBER variables is slower than other numerical data types because NUMBER values are calculated in software (for accuracy) rather than in hardware (for speed).
When data is fetched from an analytic workspace to a relational column that has the NUMBER data type, performance is best when the data already has the NUMBER data type in the analytic workspace because a conversion step is not required.
>
Can any body please explain me this difference and what exactly is this Analytic workspace mentioned here?
Taken from -- http://docs.oracle.com/cd/B19306_01/olap.102/b14346/dml_datatypes002.htm
Thanks,
Ranit B.

>
But then y not lets always use INTEGER? It'll always be fast... right?
>
Pull back on the reins, there, cowboy, and let that horse catch his breath.
Don't confuse SQL datatypes with PL/SQL datatypes. NUMBER is an Oracle SQL datatype. See the doc reference I gave you above. INTEGER is an ANSI SQL datatype and Oracle supports it but used NUMBER(38) instead.
Both wind up being NUMBER which is processed using 'software' and not hardware.
If you want to talk about PL/SQL datatypes see the PL/SQL Language doc
http://docs.oracle.com/cd/E11882_01/appdev.112/e10472/tuning.htm#BABEJFDG
In particular see 3 PL/SQL Data Types. There you will find PLS_INTEGER and BINARY_INTEGER which DO use hardware and so are faster than the software versions.
Also see 'Tune Computation-Intensive PL/SQL Code' which has a section 'Use Data Types that Use Hardware Arithmetic'. That sections discusses how hardware is used. But those datatypes are PL/SQL and do not include NUMBER or INTEGER which are SQL types.
However, to make things more confusing the OLAP module uses PL/SQL code and does define additional PL/SQL datatypes. And one of them is INTEGER (not to be confused with the SQL datatype INTEGER). And that PL/SQL datatype IS a subset of PLS_INTEGER (just like BINARY_INTEGER is) and so DOES use hardware for implementation.
See Numeric Data Types in the OLAP DML Reference
http://docs.oracle.com/cd/B19306_01/olap.102/b14346/dml_datatypes002.htm#g1022512
Are you confused yet? In summary, yes OLAP DML does define an INTEGER datatype that, internally, gets processed treated like the PLS_INTEGER PL/SQL datatype and can use hardware implementation. But that is NOT the same INTEGER datatype that the SQL engine supports.
So when talking about INTEGER it is important to include which engine you are talking about; the SQL engine or the OLAP engine. If you are talking about SQL then use NUMBER rather than INTEGER since INTEGER just uses NUMBER(38) anyway.
If you are talking about OLAP the use INTEGER instead of number so that Oracle can use hardware instead of software to perform the calculations. The OLAP DML doc cited above provides the guidance you need in the section 'Using NUMBER Values'
>
Using NUMBER Values
When you define a NUMBER variable, you can specify its precision (p) and scale (s) so that it is sufficiently, but not unnecessarily, large. Precision is the number of significant digits. Scale can be positive or negative. Positive scale identifies the number of digits to the right of the decimal point; negative scale identifies the number of digits to the left of the decimal point that can be rounded up or down.
The NUMBER data type is supported by Oracle Database standard libraries and operates the same way as it does in SQL. It is used for dimensions and surrogates when a text or INTEGER data type is not appropriate. It is typically assigned to variables that are not used for calculations (like forecasts and aggregations), and it is used for variables that must match the rounding behavior of the database or require a high degree of precision. When deciding whether to assign the NUMBER data type to a variable, keep the following facts in mind in order to maximize performance:
•Analytic workspace calculations on NUMBER variables is slower than other numerical data types because NUMBER values are calculated in software (for accuracy) rather than in hardware (for speed).
•When data is fetched from an analytic workspace to a relational column that has the NUMBER data type, performance is best when the data already has the NUMBER data type in the analytic workspace because a conversion step is not required.
>
Workspace calculations are faster using INTEGER but the fetching of data to/from relational tables is faster if the workspace datatype is NUMBER.
So as with many things Oracle there is a tradeoff. If the bulk of your process is moving data between the workspace and relational tables use NUMBER. If the bulk of your process involves mostly calculations use INTEGER.
My suggestion would be start simple. Use NUMBER everywhere until you have a workspace performance issue and then you can do the testing and consider converting the workspace datatypes to INTEGER.

Account Number( Integer)

Hi All,
I am working on MDM 5.5
I facing error while adding Bank Account Number which has 16 digits.
I have designed the Bank Account Number type Integer . while adding the account number in Data Manager more than 10 digits automatically in conevrting into another value ( i..e 2147483647) what will b the cause of error Or I need to change the type of the Field to Text or Large Text
Suggest me some links to study this , why it is causing error. This there any SAP Note for this .
Thanks in Advance.
Regards,
Pr
Edited by: Praveen Reddy Bachupally kolanu on Mar 22, 2010 3:17 PM

Hi Praveen,
There are several solutions to your problem as follows:
1) Define the field as Text , and restrict entry of non-numeric characters using validation. Validation expression to use will be :
HAS_ALL_CHARS(XXXX,"0","9")
here, XXXX is your field. this will restrict entry of non numeric chars.
2) Define the field as type Currency and set the 'Currency's thousand
separator' to 'None' so that the value will not have any commas in it if this could cause an issue.
Check Note 1367237 - Integer type field of over 10 characters is converted wrong for more details.
REgards,
Shiv

About CAST function in oracle

Hi ,
Now iam migrating my system from SQL to ORACLE 9i.
Here USERID is of NUMBER(38) type
and DATA is of LONG type in SQL.
I have table named :
PEOPLE and DBATABLE and i run the following code in oracle but found the following error...
ORA-00932: inconsistent datatypes:
SELECT P.USERID FROM PEOPLE P LEFT OUTER JOIN (SELECT DATA FROM DBATABLE WHERE NAME='USER' ) R ON CAST(DATA AS VARCHAR(50))= CAST(P.USERID AS VARCHAR(50)) WHERE P.USERLOGID= 1000 AND R.DATA IS NULL;
So help me for finding my error.
I have missed somewhere but could not find what i missed .
Plz help me out.
With regards,
Namus

I messed up with the type conversion of :
USERID -> NUMBER(38)
and DATA -> LONG type in SQL.
I have the checked in the database and found the value of the Column DATA with 31 and when i try to run as :
SELECT DATA FROM DBATABLE WHERE NAME='USER' AND DATA = '31'.
it gives error : Illegal use of the Long datatype and then i tried to cast as :
SELECT CAST<DATA AS INTEGER> FROM DBATABLE WHERE NAME='USER' AND DATA = '31'.
it also give error as:
FROM keyword not found where expected
So plz help me out with this conversion.

Cast number to integer

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