Number that is a multiple of 9 and all digits are even?

Question

I've writen this short program to find a number that is a multiple of 9 yet all its digits are even. Here is the code. I'm sure its not very compact and am doing this the hard way.
public class alldigitseven
    public static void main(String[] args)
        int number = 0;
        String numberString, tempString;
        char tempChar;
        int tempInt, matches = 0, stringLength;
        double tempRemainder;
        boolean answer = false;
        while (answer != true)
            // add 9 to the number
            if (number < 1000000)
                number += 9;
            // convert the int to a string
            numberString = "" + number;
            stringLength = numberString.length();
            for (int i = 0; i <= stringLength; i++)
                tempChar = numberString.charAt(i);
                tempString = "" + tempChar;
                tempInt = Integer.parseInt(tempString);
                tempRemainder = tempInt%2;
                if (tempRemainder == 0)
                    matches++;
                if (matches == stringLength - 1)
                    System.out.println (numberString);
                    answer = true;
}anways the code complies fine however when I run it, I get the error
"StringIndexOutOfBoundsException:
String index out of range: 1 (in Java.lang.String)"
What do I need to do to fix this?

Answer 1

here was the final code if anyone was curious...
public class alldigitseven
    public static void main(String[] args)
        int number = 0;
        String numberString, tempString;
        char tempChar;
        int tempInt, matches = 0, stringLength;
        int tempRemainder;
        boolean answer = false;
        while (answer != true)
            // reset matches
            matches = 0;
            // add 9 to the number
            if (number < 1000)
                number += 9;
            else
                answer = true;
            // convert the int to a string
            numberString = "" + number;
            stringLength = numberString.length();
            for (int i = 0; i < stringLength; i++)
                tempChar = numberString.charAt(i);
                tempString = "" + tempChar;
                tempInt = Integer.parseInt(tempString);
                tempRemainder = tempInt%2;
                if (tempRemainder == 0)
                    matches++;
                if (matches == stringLength)
                    System.out.println (numberString);
        answer = true;
}