Numbers bigger then 10 to a array of integers

Okay I want to do the following...
I have a number (bigger then 10). Assume I got the number 4327 now I want to change this number to a numeric array with the values [4,3,2,7] as fast as possible.
I only thought of one solutions (which is possible also the fastest), but I want to know if anyone has maybe a better idea.
My solution is just to cast that number to a string using the NumberToString VI, "4327", then split into a array of strings ["4","3","2","7"], and cast it back using the StringToNumber VI.
Anyone got a better faster idea?
Solved!
Go to Solution.

Jeff Bohrer wrote:
Absolutely not!
Although Nathand's solution could be expanded to work with any base as well. This may be a bit faster
the use of native recursion vs the buffer expansion should show in favor of the recusive technique up to a considerable number of digits.
Nowhere close, unfortunately. Here's the benchmarking VI updated with your code, which is 4-5x slower than both my approach and Matt W's. The recursive implementation is a good idea but LabVIEW's recursion is not terribly efficient. Each recursive copy requires allocating an entirely new copy of the VI.
EDIT: uploaded recursive subVI, needed as well.
Attachments:
benchmark to individual digits.vi ‏15 KB
Recurse.vi ‏9 KB

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pleace can someone help me? i am new in java . i want
to create an array integers? Here i hava my codes that
creates an array of strings? can anybody convert that
so can accept integer and modified my method to add
Integers instead of strings?Thanks for your time[snip]
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Numbers bigger then 10 to a array of integers

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