Numerical order (ORDER BY)`

Question

I'm working on building reports in Microsoft SSRS using an Oracle source database and query. I'm trying to figure how to order the following output into numerical order in Oracle.
'0 - 3 Days', '4 - 8 Days', '9 - 13 Days', '14 - 18 Days', '19 - 23 Days', '24 - 28 Days', '> 28 Days'.

Answer 1

Or with the CASE in ORDER BY
WITH mydata(txt)
AS
   SELECT '0 - 3 Days'   FROM DUAL UNION ALL
   SELECT '4 - 8 Days'   FROM DUAL UNION ALL
   SELECT '24 - 28 Days' FROM DUAL UNION ALL
   SELECT '> 28 Days'    FROM DUAL UNION ALL
   SELECT '9 - 13 Days'  FROM DUAL UNION ALL
   SELECT '14 - 18 Days' FROM DUAL UNION ALL
   SELECT '19 - 23 Days' FROM DUAL UNION ALL
   SELECT '24 - 28 Days' FROM DUAL UNION ALL
   SELECT '> 28 Days'    FROM DUAL UNION ALL
   SELECT 'dummy'        FROM DUAL UNION ALL
   SELECT '24 - 28 Days' FROM DUAL UNION ALL
   SELECT '> 28 Days'    FROM DUAL UNION ALL
   SELECT '0 - 3 Days'   FROM DUAL UNION ALL
   SELECT '19 - 23 Days' FROM DUAL
SELECT txt
  FROM mydata
ORDER BY CASE txt
           WHEN '0 - 3 Days'
              THEN 1
           WHEN '4 - 8 Days'
              THEN 2
           WHEN '9 - 13 Days'
              THEN 3
           WHEN '14 - 18 Days'
              THEN 4
           WHEN '19 - 23 Days'
              THEN 5
           WHEN '24 - 28 Days'
              THEN 6
           WHEN '> 28 Days'
              THEN 7
           ELSE 0
        END;
TXT        
dummy      
0 - 3 Days 
0 - 3 Days 
4 - 8 Days 
9 - 13 Days
14 - 18 Days
19 - 23 Days
19 - 23 Days
24 - 28 Days
24 - 28 Days
24 - 28 Days
28 Days
28 Days
28 Days Regards.
Al