OBIEE RSUM() with partition by

Hi All,
Can anyone suggest me that how to get the below result in OBIEE:
Row Number Title Date
1 ABC 1/1/2012
1 ABC 1/2/2012
2 DEF 1/1/2012
3 GHI 4/1/2012
Currently I am using RSUM() and only able to get the below result which is not my expected result:
Row Number Title Date
1 ABC 1/1/2012
2 ABC 1/2/2012
3 DEF 1/1/2012
4 GHI 4/1/2012
I want to get the running distinct number of title instead of getting the running number of all records.
Any help would be appreciated. Many thanks.
Thanks & Regards,
Benard

Hi SVee,
Thanks for the reply. I have tried your suggestion but it is only partially working.
I have use suppress and use count(title) function and it shows below result:
Row Number Title Date
1 ABC 1/1/2012
ABC 1/2/2012
1 DEF 1/1/2012
1 GHI 4/1/2012
If I add in RCOUNT(title) function, it will still shows:
Row Number Title Date
1 ABC 1/1/2012
2 ABC 1/2/2012
3 DEF 1/1/2012
4 GHI 4/1/2012
I even set suppress to Title column as well, but it just didn't work well.
Thanks & Regards,
Benard

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Hi,
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'PORT OF NEWARK',
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I would recommend that you post this at the following OTN forum:
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General Database Discussions
and perhaps at:
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Warehouse Builder
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Hi
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Insert performance issue with Partitioned Table.....

Hi All,
I have a performance issue during with a table which is partitioned. without table being partitioned
it ran in less time but after partition it took more than double.
1) The table was created initially without any partition and the below insert took only 27 minuts.
Total Rec Inserted :- 2424233
PL/SQL procedure successfully completed.
Elapsed: 00:27:35.20
2) Now I re-created the table with partition(range yearly - below) and the same insert took 59 minuts.
Is there anyway i can achive the better performance during insert on this partitioned table?
[ similerly, I have another table with 50 Million records and the insert took 10 hrs without partition.
with partitioning the table, it took 18 hours... ]
SQL> select * from table(dbms_xplan.display);
PLAN_TABLE_OUTPUT
Plan hash value: 4195045590
| Id | Operation | Name | Rows | Bytes |TempSpc| Cost (%CPU)| Time |
| 0 | SELECT STATEMENT | | 643K| 34M| | 12917 (3)| 00:02:36 |
|* 1 | HASH JOIN | | 643K| 34M| 2112K| 12917 (3)| 00:02:36 |
| 2 | VIEW | index$_join$_001 | 69534 | 1290K| | 529 (3)| 00:00:07 |
|* 3 | HASH JOIN | | | | | | |
| 4 | INDEX FAST FULL SCAN| PK_ACCOUNT_MASTER_BASE | 69534 | 1290K| | 181 (3)| 00:00
| 5 | INDEX FAST FULL SCAN| ACCOUNT_MASTER_BASE_IDX2 | 69534 | 1290K| | 474 (2)| 00:00
PLAN_TABLE_OUTPUT
| 6 | TABLE ACCESS FULL | TB_SISADMIN_BALANCE | 2424K| 87M| | 6413 (4)| 00:01:17 |
Predicate Information (identified by operation id):
1 - access("A"."VENDOR_ACCT_NBR"=SUBSTR("B"."ACCOUNT_NO",1,8) AND
"A"."VENDOR_CD"="B"."COMPANY_NO")
3 - access(ROWID=ROWID)
Open C1;
Loop
Fetch C1 Bulk Collect Into C_Rectype Limit 10000;
Forall I In 1..C_Rectype.Count
Insert test
     col1,col2,col3)
Values
     val1, val2,val3);
V_Rec := V_Rec + Nvl(C_Rectype.Count,0);
Commit;
Exit When C_Rectype.Count = 0;
C_Rectype.delete;
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Total Rec Inserted :- 2424233
PL/SQL procedure successfully completed.
Elapsed: 00:51:01.22
Edited by: user520824 on Jul 16, 2010 9:16 AM

I'm concerned about the view in step 2 and the index join in step 3. A composite index with both columns might eliminate the index join and result in fewer read operations.
If you know which partition the data is going into beforehand you can save a little bit of processing by specifying the partition (which may not be a scalable long-term solution) in the insert - I'm not 100% sure you can do this on inserts but I know you can on selects.
The APPEND hint won't help the way you are using it - the VALUES clause in an insert makes it be ignored. Where it is effective and should help you is if you can do the insert in one query - insert into/select from. If you are using the loop to avoid filling up undo/rollback you can use a bulk collect to batch the selects and commit accordingly - but don't commit more often than you have to because more frequent commits slow transactions down.
I don't think there is a nologging hint :)
So, try something like
insert /*+ hints */ into ...
Select
     A.Ing_Acct_Nbr, currency_Symbol,
     Balance_Date,     Company_No,
     Substr(Account_No,1,8) Account_No,
     Substr(Account_No,9,1) Typ_Cd ,
     Substr(Account_No,10,1) Chk_Cd,
     Td_Balance,     Sd_Balance,
     Sysdate,     'Sisadmin'
From Ideaal_Cons.Tb_Account_Master_Base A,
     Ideaal_Staging.Tb_Sisadmin_Balance B
Where A.Vendor_Acct_Nbr = Substr(B.Account_No,1,8)
   And A.Vendor_Cd = b.company_no
      ;Edited by: riedelme on Jul 16, 2010 7:42 AM

Problems with partition tables

Hi all,
I've got some problems with partition tables. The script at the bottom run but when I wanna insert some values it returns me an error
(ORA-06550: line 1, column 30: PL/SQL: ORA-06552: PL/SQL: Compilation unit analysis terminated
ORA-06553: PLS-320: the declaration of the type of this expression is incomplete or malformed
ORA-06550: line 1, column 7: PL/SQL: SQL Statement ignored)
and I can't understand why!
There's something incorrect in the script or not?
Please help me
Thanks in advance
Steve
CREATE TABLE TW_E_CUSTOMER_UNIFIED
ID_CUSTOMER_UNIFIED VARCHAR2 (27) NOT NULL ,
START_VALIDITY_DATE DATE NOT NULL ,
END_VALIDITY_DATE DATE ,
CUSTOMER_STATUS VARCHAR2 (255)
PARTITION BY RANGE (START_VALIDITY_DATE)
SUBPARTITION BY LIST (END_VALIDITY_DATE)
PARTITION M200909 VALUES LESS THAN (TO_DATE('20091001','YYYYMMDD'))
(SUBPARTITION M200909_N VALUES (NULL), SUBPARTITION M200909_NN VALUES (DEFAULT)),
PARTITION M200910 VALUES LESS THAN (TO_DATE('20091101','YYYYMMDD'))
(SUBPARTITION M200910_N VALUES (NULL), SUBPARTITION M200910_NN VALUES (DEFAULT)),
PARTITION M200911 VALUES LESS THAN (TO_DATE('20091201','YYYYMMDD'))
(SUBPARTITION M200911_N VALUES (NULL), SUBPARTITION M200911_NN VALUES (DEFAULT)),
PARTITION M200912 VALUES LESS THAN (TO_DATE('20100101','YYYYMMDD'))
(SUBPARTITION M200912_N VALUES (NULL), SUBPARTITION M200912_NN VALUES (DEFAULT)),
PARTITION M201001 VALUES LESS THAN (TO_DATE('20100201','YYYYMMDD'))
(SUBPARTITION M201001_N VALUES (NULL), SUBPARTITION M201001_NN VALUES (DEFAULT)),
PARTITION M201002 VALUES LESS THAN (TO_DATE('20100301','YYYYMMDD'))
(SUBPARTITION M201002_N VALUES (NULL), SUBPARTITION M201002_NN VALUES (DEFAULT)),
PARTITION M210001 VALUES LESS THAN (MAXVALUE))
(SUBPARTITION M210001_N VALUES (NULL), SUBPARTITION M210001_NN VALUES (DEFAULT))
;

Hi Hoek,
the DB version is 10.2 (italian version, then SET is correct).
...there's something strange: now I can INSERT rows but I can't update them!
I'm using this command string:
UPDATE TW_E_CUSTOMER_UNIFIED SET END_VALIDITY_DATE = TO_DATE('09-SET-09', 'DD-MON-RR') WHERE
id_customer_unified = '123' and start_validity_date = TO_DATE('09-SET-09', 'DD-MON-RR');
And this is the error:
Error SQL: ORA-14402: updating partition key column would cause a partition change
14402. 00000 - "updating partition key column would cause a partition change"
*Cause: An UPDATE statement attempted to change the value of a partition
key column causing migration of the row to another partition
*Action: Do not attempt to update a partition key column or make sure that
the new partition key is within the range containing the old
partition key.
I think that is impossible to use a PARTITION/SUBPARTITION like that: in fact the update of "END_VALIDITY_DATE" cause a partition change.
Do u agree or it's possible an update on a field that implies a partition change?
Regards Steve

Problems Faced with Partitions in Oracle 9i.

I have a doubt regarding the partitions in Oracle 9i can you please help me regarding this?
Create table t1
( x number,
y number,
z number);
insert into t1 values (1,1,1);
insert into t1 values (2,2,2);
insert into t1 values (3,3,3);
Create table t2
x number,
y number,
z number
partition by range(x)
partition p1 values less than(2),
partition p2 values less than(3),
partition p3 values less than(4),
partition p4 values less than(maxvalue)
alter table t2 exchange partition p1 with table t1;
SQL> alter table t2 exchange partition p1 with table t1;
alter table t2 exchange partition p1 with table t1
ERROR at line 1:
ORA-14099: all rows in table do not qualify for specified partition
WHAT DOES THIS ERROR MESSAGE MEAN? I AM NOT ABLE TO UNDERSTAND THIS? WHAT NEED's TO BE DONE TO RESOLVE THIS?
alter table t2 exchange partition p1 with table t1 WITHOUT VALIDATION;
SQL> SELECT * FROM T2;
X Y Z
1 1 1
2 2 2
3 3 3
SQL> SELECT * FROM T2 PARTITION(P1);
X Y Z
1 1 1
2 2 2
3 3 3
SQL> SELECT * FROM T2 PARTITION(P2);
no rows selected
SQL> SELECT * FROM T2 PARTITION(P3);
no rows selected
(i) Why i am facing this error ORA-14099: while partitioning? Can you please brief me about this ?
(ii) why there is not data's in the PARTITIONS p2 &p3 after the partitions is exchanged WITHOUT VALIDATION options?
what is going with this method?
(iii) Also can you please explain me with an example how to partitions a table having milliion of records with EXCHANGE PARTITION Options with MULITPLE partition segment's (say partition based on status id column with 6 differnt values i am thinking to use list partitions using status_id as partition key) ?
Also i have tried the below approch is this a right approch? please correct me if i am wrong.
Create table t1
( x number,
y number,
z number);
insert into t1 values (1,1,1);
insert into t1 values (2,2,2);
insert into t1 values (3,3,3);
commit;
Create table t2
x number,
y number,
z number
partition by range(x)
partition p1 values less than(2),
partition p2 values less than(3),
partition p3 values less than(4),
partition p4 values less than(maxvalue)
SQL> insert into t2 select * from t1;
3 rows created.
SQL> commit;
Commit complete.
SQL> SELECT * FROM T2 PARTITION(P1);
X Y Z
1 1 1
SQL> SELECT * FROM T2 PARTITION(P2);
X Y Z
2 2 2
SQL> SELECT * FROM T2 PARTITION(P3);
X Y Z
3 3 3
SQL> SELECT * FROM T2 PARTITION(P4);
no rows selected
EXPLAIN PLAN
FOR SELECT * FROM T2 WHERE X = 1
| Id | Operation | Name | Rows | Bytes | Cost | Pstart| Pstop |
| 0 | SELECT STATEMENT | | 1 | 9 | 2 | | |
| 1 | TABLE ACCESS FULL | T2 | 1 | 9 | 2 | 1 | 1 |
Now my question is what is problem instead of using EXCHANGE PARTITION why caun't we follow this above approch?
to partition a non-partitioned table?
Thanks,
Rajesh.

The value of 3 should obviously should go into the partition P3.Then why are you putting it into p1?
Your command,
<tt> alter table t2 exchange partition <b>p1</b> with table t1;</tt>
will swap partition p1 with the contents of table t1, leaving you with partition p1 containing the three values that were in t1. At first it told you there were rows in t1 that did not belong in that partition, but you used FORCE so it put them in anyway.
btw there are notes in the FAQ about how to use ** tags to format your posts.
~Edited by: William Robertson on Oct 15, 2008 6:49 AM~

OBIEE SSO with authorization

Hi Gurus,
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Is it possible to create table with partition in compress mode

Hi All,
I want to create a table in compress option, with partitions. When i create with partitions the compression isnt enabled, but with noramal table creation the compression option is enables.
My question is:
cant we create a table with partition/subpartition in compress mode..? Please help.
Below is the code that i have used for table creation.
CREATE TABLE temp
TRADE_ID                    NUMBER,
SRC_SYSTEM_ID               VARCHAR2(60 BYTE),
SRC_TRADE_ID                VARCHAR2(60 BYTE),
SRC_TRADE_VERSION           VARCHAR2(60 BYTE),
ORIG_SRC_SYSTEM_ID          VARCHAR2(30 BYTE),
TRADE_STATUS                VARCHAR2(60 BYTE),
TRADE_TYPE                  VARCHAR2(60 BYTE),
SECURITY_TYPE               VARCHAR2(60 BYTE),
VOLUME                      NUMBER,
ENTRY_DATE                  DATE,
    REASON                      VARCHAR2(255 BYTE),
TABLESPACE data
PCTUSED    0
PCTFREE    10
INITRANS   1
MAXTRANS   255
NOLOGGING
COMPRESS
NOCACHE
PARALLEL (DEGREE 6 INSTANCES 1)
MONITORING
PARTITION BY RANGE (TRADE_DATE)
SUBPARTITION BY LIST (SRC_SYSTEM_ID)
SUBPARTITION TEMPLATE
(SUBPARTITION SALES VALUES ('sales'),
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PARTITION RMS_TRADE_DLY_MAX VALUES LESS THAN (MAXVALUE)
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    SUBPARTITION TS_MAX_BLR VALUES ('BLR')      TABLESPACE data,
    SUBPARTITION TS_MAX_SUT VALUES ('SUT')      TABLESPACE data,
    SUBPARTITION TS_MAX_RM VALUES ('RM')      TABLESPACE data,
    SUBPARTITION TS_MAX_DEFAULT VALUES (default)      TABLESPACE data)); Edited by: user11942774 on 8 Dec, 2011 5:17 AM

user11942774 wrote:
I want to create a table in compress option, with partitions. When i create with partitions the compression isnt enabled, but with noramal table creation the compression option is enables. First of all your CREATE TABLE statement is full of syntax errors. Next time test it before posting - we don't want to spend time on fixing things not related to your question.
Now, I bet you check COMPRESSION value of partitioned table same way you do it for a non-partitioned table - in USER_TABLES - and therefore get wrong results. Since compreesion can be enabled on individual partition level you need to check COMPRESSION in USER_TAB_PARTITIONS:
SQL> CREATE TABLE temp
2 (
3    TRADE_ID                    NUMBER,
4    SRC_SYSTEM_ID               VARCHAR2(60 BYTE),
5    SRC_TRADE_ID                VARCHAR2(60 BYTE),
6    SRC_TRADE_VERSION           VARCHAR2(60 BYTE),
7    ORIG_SRC_SYSTEM_ID          VARCHAR2(30 BYTE),
8    TRADE_STATUS                VARCHAR2(60 BYTE),
9    TRADE_TYPE                  VARCHAR2(60 BYTE),
10    SECURITY_TYPE               VARCHAR2(60 BYTE),
11    VOLUME                      NUMBER,
12    ENTRY_DATE                  DATE,
13      REASON                      VARCHAR2(255 BYTE),
14    TRADE_DATE                  DATE
15 )
16 TABLESPACE users
17 PCTUSED    0
18 PCTFREE    10
19 INITRANS   1
20 MAXTRANS   255
21 NOLOGGING
22 COMPRESS
23 NOCACHE
24 PARALLEL (DEGREE 6 INSTANCES 1)
25 MONITORING
26 PARTITION BY RANGE (TRADE_DATE)
27 SUBPARTITION BY LIST (SRC_SYSTEM_ID)
28 SUBPARTITION TEMPLATE
29    (SUBPARTITION SALES VALUES ('sales'),
30     SUBPARTITION MAG VALUES ('MAG'),
31     SUBPARTITION SPI VALUES ('SPI', 'SPIM', 'SPIIA'),
32     SUBPARTITION FIS VALUES ('FIS'),
33     SUBPARTITION GD VALUES ('GS'),
34     SUBPARTITION ST VALUES ('ST'),
35     SUBPARTITION KOR VALUES ('KOR'),
36     SUBPARTITION BLR VALUES ('BLR'),
37     SUBPARTITION SUT VALUES ('SUT'),
38     SUBPARTITION RM VALUES ('RM'),
39     SUBPARTITION DEFAULT_SUB VALUES (default)
40    )
41 (
42   PARTITION RMS_TRADE_DLY_MAX VALUES LESS THAN (MAXVALUE)
43      LOGGING
44          TABLESPACE users
45       ( SUBPARTITION TS_MAX_SALES VALUES ('SALES')      TABLESPACE users,
46      SUBPARTITION TS_MAX_MAG VALUES ('MAG')      TABLESPACE users,
47      SUBPARTITION TS_MAX_SPI VALUES ('SPI', 'SPIM', 'SPIIA')      TABLESPACE users,
48      SUBPARTITION TS_MAX_FIS VALUES ('FIS')      TABLESPACE users,
49      SUBPARTITION TS_MAX_GS VALUES ('GS')      TABLESPACE users,
50      SUBPARTITION TS_MAX_ST VALUES ('ST')      TABLESPACE users,
51      SUBPARTITION TS_MAX_KOR VALUES ('KOR')      TABLESPACE users,
52      SUBPARTITION TS_MAX_BLR VALUES ('BLR')      TABLESPACE users,
53      SUBPARTITION TS_MAX_SUT VALUES ('SUT')      TABLESPACE users,
54      SUBPARTITION TS_MAX_RM VALUES ('RM')      TABLESPACE users,
55      SUBPARTITION TS_MAX_DEFAULT VALUES (default)      TABLESPACE users));
Table created.
SQL>
SQL>
SQL> SELECT PARTITION_NAME,
2          COMPRESSION
3    FROM USER_TAB_PARTITIONS
4    WHERE TABLE_NAME = 'TEMP'
5 /
PARTITION_NAME                 COMPRESS
RMS_TRADE_DLY_MAX              ENABLED
SQL> SELECT COMPRESSION
2    FROM USER_TABLES
3    WHERE TABLE_NAME = 'TEMP'
4 /
COMPRESS
SQL> SY.

OBIEE RSUM() with partition by

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