OER REX query question

Can anyone help explain behavior in the OER Extensibility Framework/REX openapi that I am seeing. I may have misunderstood the documentation and I admit I'm looking at the 11g version of the api online and using it against 10.3
Anyway I'm trying to figure out how to query for only assets that are Registered on keywords, dates, and additional criteria.
I know it is possible because I can see the actual UI of the product does this but I'm having different behavior.
So from the api it led me to believe that if off of the AssetCriteria class I called setBrowsableOnly("true") it would only bring back browsable/registered assets (unless in progress flag is set). That was not filtering non-registered assets.
So I then attempted to set up a SearchTerm where I tried both the key of the SearchTerm to be both registered as well as assetstatus, on registered key I set the value to REGISTERED and on the assetstatus I set the value to 100.
But in all instances it is still bringing back more than registered assets.
There are other criteria I want to set as well but I'm missing some sort of basic here.
So example code is:
//Create Criteria
AssetCriteria criteria = new AssetCriteria();
//By default search browsable only assets
criteria.setBrowsableOnlyCriteria("true");
//By default do not do exact match search
//criteria.setExactMatchCriteria("false");
//Do general criteria search on provided keyword
criteria.setGeneralCriteria(keyword);
//Create SearchTerm to help get only registered assets
SearchTerm[] searchTermArray = new SearchTerm[1];
//TODO: Need to figure out what search term is needed if any for only registered
SearchTerm term = new SearchTerm();
term.setKey("/assetstatus");
term.setValue("100");
searchTermArray[0] = term;
criteria.setSearchTerms(searchTermArray);
//TODO: probably will need to remove the following code as final gets closer
//For testing purposes pull count right now
int count = repository.assetQueryCount(authToken, criteria);
logger.debug("Count is; " + count);
//Due to memory requirements pull back summary for now
//TODO: Figure out best approach for number of assets we will be pulling back
//assets = repository.assetQuery(authToken, criteria);
assetSummary = repository.assetQuerySummary(authToken, criteria);
I have looked at OER103-REX_Asset.pdf so unless it is clearly spelled out in there and I keep missing it, I already know it exists. Maybe I do keep missing it in there.
So likewise I need to understand how to query for assets that are active, retired, etc...which appears to be in the status field. But again I haven't gotten the SearchTerms to work correctly.
I have cross posted in SOA Governance.
Thanks,
Diane
Edited by: user10818227 on Jul 30, 2010 12:44 PM

Amy,
Take a look at this thread -
Re: ORA-01460: unimplemented or unreasonable conversion requested ORA-02063
and see if it addresses your problem.
John.

Similar Messages

Simple Query Question - How do I return the Last 3 records of a Table?

Question.
For example, I have a table that has 50 records.
How do I, specify in SQL to only return the last 3 records of the table.
Select a.* from table a where ????

I was just trying to show an example to a friend on
how something like this would work and if it was even possible. But it won't work. Here's a simple example:
SQL> create table emp
2 (id)
3 as
4 select object_id
5 from   all_objects
6 order by object_id;
Table created.
SQL> select *
2 from (select rownum rn
3               ,b.*
4         from   emp b)
5 where rn > ( select (max(rownum) - 3)
6                from    emp)
7 ;
        RN         ID
     40830      55891
     40831      55892
     40832      55893So far, so good. These are the "last 3" rows inserted. Now delete a bunch of rows and insert 3 new ones:
SQL> delete emp where id < 40000;
33423 rows deleted.
SQL> commit;
Commit complete.
SQL> insert into emp values (60000);
1 row created.
SQL> insert into emp values (60001);
1 row created.
SQL> insert into emp values (60002);
1 row created.
SQL> commit;
Commit complete.
SQL> select *
2 from (select rownum rn
3               ,b.*
4         from   emp b)
5 where rn > ( select (max(rownum) - 3)
6                from    emp)
7 ;
        RN         ID
      7410      55891
      7411      55892
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Oracle 10g and parallel query question

Hi Oracle on SAP Gurus!
We are currently thinking of activating parallel query for certain segments (large application tables and indexes). We searched in SAPNet and SDN and have also studied the SAP Note 651060. But we did not find a complete answer to the following question which is very important for us:
Which kinds of queries (despite from full table scan and index scan in partitioned indexes) support parallel queries and which ones do not support parallel queries?
This is important for us to find out whether we have candidates for parallel queries or not.
Thanx for any hint!
Regards,
Volker

But why do you not propose to use parallel query in OLTP systems?
If the queries are accessed very frequently you will just run out of cpu and io ressources. OLTP systems are (historical) typically multi user systems. You can off course use PQ for 'single user' activities, like index rebuilds, some batchjobs, but you shouldn't do for frequent user queries.
If you have time look at this interesting Article [Suck It Dry - Tuning Parallel Execution|http://doug.burns.tripod.com/px.html]
It is quite old, and you don't have to read all tech details, but i recommend having a look at the conclusions at the end.
May it make sense to use partitioning of these tables in conjunction with parallel query?
I know some guys, who do partitioning on OLTP systems, even SAP systems. But they don't use PQ then. The use partitioning to work on a smaller set of data. In your case the range scans, would need to scan only one partition, saving buffer cache and effectively speeding up execution. So you don't need PQ to scan all partitions at all, this would be a typical OLAP approach.
Best regards
Michael

General JPA query question

Hello world,
I'm new to JPA 2.0 and there are few things I don't understand.
BTW: I can't figure out the keywords to search for this question, so please pardon me if it's one of the most asked.
Using the Preview, I've seen that alignment went straight to Hell, so I tried to make this as readable as I could using pipes in place of white spaces in the result sets.
I have a couple of tables:
CUST table (for customers):
CUST_ID (pk, integer)
CUST_NAME (varchar)
ORD table (for orders):
ORD_ID (pk, integer)
ORD_STATUS (char) can be: N for new, S for shipped, D for delivered
CUST_ID (fk, integer)
The relationship is, of course, a "one to many" (every customer can place many orders).
Content of the tables:
CUST_ID|CUST_NAME
1|elcaro
2|tfosorcim
3|elppa
ORD_ID|ORD_STATUS|CUST_ID
2|N|1
3|N|1
4|N|1
5|S|1
6|S|1
7|D|1
8|D|1
9|D|1
10|D|2
11|N|2
12|S|3
13|S|3
Here's how I annotated my classes:
Customer.java:
@Entity(name = "Customer")
@Table(name = "CUST")
public class Customer implements Serializable
private static final long serialVersionUID = 1L;
@Id
@Column(name = "CUST_ID")
private Integer id;
@Column(name = "CUST_NAME")
private String name;
@OneToMany(mappedBy = "customer")
private List<Order> orders;
// Default constructor, getters and setters (no annotations on these)
Order.java:
@Entity(name = "Order")
@Table(name = "ORD")
public class Order implements Serializable
private static final long serialVersionUID = 1L;
@Id
@Column(name = "ORD_ID")
private Integer id;
@Column(name = "ORD_STATUS")
private Character status;
@ManyToOne
@JoinColumns
@JoinColumn(name = "CUST_ID", referencedColumnName = "CUST_ID")
private Customer customer;
// Default constructor, getters and setters (no annotations on these)
Everything works just fine, the following JPQL query yields the results I expected:
select c from Customer c
it returns three objects of type Customer, each of which contains the orders that belong to that customer.
But now, I want to extract the list of customers that have orders in status 'N', along with the associated orders (only the status 'N' orders, of course).
Back in the good ol' days I would have written an SQL query like this:
select c.cust_id, c.cust_name, o.ord_id, o.ord_status
from cust c
inner join ord o on (o.cust_id = c.cust_id)
where o.ord_status = 'N'
and it would have returned the following result set:
CUST_ID|CUST_NAME|ORD_ID|ORD_STATUS
1|elcaro|2|N
1|elcaro|3|N
1|elcaro|4|N
2|tfosorcim|11|N
The following JPQL query, however, doesn't yield the expected results:
select distinct c from Customer c join c.orders o where o.status = 'N'
it returns the correct set of customers (customer 'elppa' doesn't have any status 'N' order and is correctly excluded), but each customer contains the full set of orders, regardless of the status.
It seems that the 'where' clause is only evaluated to determine which set of customers has to be extracted and then the persistence provider starts to navigate the relationship to extract the full set of orders.
Thinking a little about it, I must admit that it makes sense.
I then tried out another JPQL query:
select c, o from Customer c join c.orders o where o.status = 'N'
this JPA query yields results that are similar to the ones produced by the previous SQL query: each result (4 results as expected) is a 2-object array, the first object is of type Customer and the second object is of type Order. But, again, the objects of type Customer contain the full set of related orders (as I expected, this time). Not to mention the fact that now the orders are not contained in the Customer objects, but are returned separately, just as in an SQL result set.
Now the question is:
Is it possible to write a JPA query that filters out, not only the customers that don't have an order in status 'N', but the related orders (fetched during relationship navigation) that are not in status 'N' as well?
What I'd like to be able to get is a 2-customer result where each customer contains only its status 'N' orders.
I read the Java EE 6 Tutorial and one of the examples (the Order Application) has a schema that is similar to mine, but I couldn't find a query like this (in the downloaded source code).
Although I think the above is standard behavior, I use an Oracle Weblogic 12c server (through its Eclipse adapter) and the persistence provider appears to be EclipseLink.
Thanks in advance.
Best regards,
Stefano
Edited by: user11265230 on 17-apr-2012 14.11

Hello,
When returning an entity from JPQL, it gives you the entity as it is in the database. Your "select distinct c from Customer c join c.orders o where o.status = 'N'" is asking for all customers that have an order with a status of 'N', so that is what it gives you. There is no condition to filter anything on the relationship when building the Customer object in JPA - doing so would mean returning a managed entity that does not reflect what is in the database. This would affect other queries, since JPA requires that queries return the same instance of an entity regardless of the query that is used to bring it back. So a query using your "where o.status = 'N'" would cause conflicting results when used with a query using "where o.status = 'Y'". And these queries would make the EntityManager unable to determine what has changed on the returned objects.
EclipseLink does have the ability to filter over relationships, it is just not available through standard JPA and I would strongly discourage it. Instead of querying for Customers, why not change the query to get Orders instead -
"select o from Customer c join c.orders o where o.status = 'N'". Assuming Orders have a ManyToOne back reference to their Customer, this will mean you do not need to travers the Customer-> order relationship. If using
"select c, o from Customer c join c.orders o where o.status = 'N'"
I am not sure why you would use the orders from the returned customers instead of the orders returned in the results though.
You could also return "select c.id, c.name, o.id, o.status from Customer c join c.orders o where o.status = 'N'" which is the equivalent of what you would get from the SQL you initially posted.
Regards,
Chris

Left Join Query Question

Version 10.2.0.4.0
I have a question on the expected behavior of the query below.
When I run the query below with the constraint on t1.partid = 789, I get the query result t2.Indicator showing "SPECIAL" as expected.
However, if I remove the constraint, and return all orders and parts, for the "789" part, the Indicator column is null.
select t1.orderid, t1.partid, t2.Indicator
from Orders a left outer join
select partid, 'SPECIAL' as Indicator
from vendors
where vendorname like '%ABC%'
) t2
on t1.partid = t2.partid
where t1.partid = '789'
I can address the issue with a case statement (below) or likely restructuring into a better statement.
But I'm just curious if this is expected or if there is some SQL rule being violated in the first example.
I tried to search for this to see if it was already addressed but didn't have much luck.
This works:
select t1.orderid, t1.partid,
case when t1.partid is not null then "SPECIAL" else null end as Indicator
from Orders a left outer join
select partid, 'SPECIAL' as Indicator
from vendors
where vendorname like '%ABC%'
) t2
on t1.partid = t2.partid

Sorry, it's been a while since I posted and should have read the rules. And I didn't properly reference the alias. So Post #1 was bad.
When I mockup a small set of data (shown below), I don't get the error. The original query actually joins to a few other (seemingly) irrelevant tables and I tried to simplify it here So I guess if I can't replicate it, then there might not be much assistance that can be provided.
This was more of a curiousity than anything else to see if perhaps someone came across this before.
For what it's worth:
create table t1 (orderid number,
             partid varchar2(20)
create table t2
        (vendorid varchar2(20),
         partid varchar2(20)
insert into t1 values(1, '123');
insert into t1 values(2, '456');
insert into t1 values(3, '789');
insert into t2 values ('ABC','789');
insert into t2 values ('DEF','123');
insert into t2 values ('EFG','456');
insert into t2 values ('ABC','7891');
insert into t2 values ('DEF','1231');
insert into t2 values ('EFG','4561');
select t1.orderid, t1.partid, t2.Indicator
from t1 left outer join
select partid, 'SPECIAL' as Indicator
from t2
where vendorid like '%ABC%'
) t2
on t1.partid = t2.partid
the query that gives unexpected behavior is (although I can't replicate on this simplified version):
select t1.orderid, t1.partid, t2.Indicator
from t1 left outer join
select partid, 'SPECIAL' as Indicator
from t2
where vendorid like '%ABC%'
) t2
on t1.partid = t2.partid

SQL Query Question

Hi,
I am trying to filter my output from the query based on some conditions but not able to figure out how. May be I am just overlooking at the issue or is it something tricky.
So, I have a query returning 4 rows of output out of which I need to filter the rows. I have created a table from the result of the query that I need to filter to make it simple. So below is my create table script and values that are obtained from my original query.
CREATE TABLE TEMPACCT
SOURCEKEY           NUMBER,
FLAG                VARCHAR2(1),
ITEMID              NUMBER(9)                 ,
ITEMNAME            VARCHAR2(10)               ,
ITEMKEY             NUMBER(9)
Insert into tempacct values (0, 'N', 100, 'ITEM1' , 9647);
Insert into tempacct values (0, 'N', 200, 'ITEM2' , 9648);
Insert into tempacct values (9648, 'N', 100, 'ITEM3' , 9813);
Insert into tempacct values (9647, 'Y', 100, 'ITEM4' , 9812);
SQL> select * from tempacct;
SOURCEKEY F     ITEMID ITEMNAME      ITEMKEY
         0 N        100 ITEM1            9647
         0 N        200 ITEM2            9648
      9648 N        100 ITEM3            9813
      9647 Y        100 ITEM4            9812
SQL> Tempacct table is the table created from the resultset of my original query.
So from the above output, what I need is 3 rows. The logic to filter out the row is - If any of the row thathas sourcekey that is same as Itemkey in any of the 4 rows and flag is Y then remove the row which have flag =N and only display the one with Falg = Y.
Ok, so, in this case the desired output would be
SOURCEKEY F     ITEMID ITEMNAME      ITEMKEY
         0 N        200 ITEM2            9648
      9648 N        100 ITEM3            9813
      9647 Y        100 ITEM4            9812So here we compared between the first row and the fourth row, and since the sourcekey in fourth row is same as itemkey in first row and Flag is 'Y' for fourth row, we keep 4th row and remove the first row since the flag is 'N'. (and sourcekey is 0. the row that gets removed will always have sourcekey =0) .
SQL> select * from v$version;
BANNER
Oracle Database 10g Release 10.2.0.4.0 - 64bit Production
PL/SQL Release 10.2.0.4.0 - Production
CORE    10.2.0.4.0      Production
TNS for Linux: Version 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - ProductionAppreciate your help.

Hi,
ARIZ wrote:
Although the original question is already been answered, I had another small modification to the same question and also seeking some clarification. I do not want to open a new thread just for a similar question.I think you'll get better replies faster if you do start a new thread.
Not counting this one, there have been 13 replies to this thread. Not many people who havn't already been participating in this thread are going to start reading a thread with 13 replies. Those who do are going to waste a lot of time reading about issues that have already been resolved, and the are likely to understand the remaining issues incorrectly.
I have been following the thread from the beginnning, and I'm starting to get confused about what the unresolved issues are.
I believe there are two things you still need:
(1) An explanation of the solution I posted yesterday, involving the analytic COUNT function.
(2) A solution for a new problem involving the same tables
If I got that wrong, start a new thread, asking just what you need to know. Copy any relevant parts (like the CREATE TABLE and INSERT statements) from this thread. You can include a link to this thread, but do your best to make sure people don't have to use it.
I realize that's more work for you, but getting the best results, and getting them quickly, sometimes does require more work.
<h2>(1) An explanation of the solution I posted yesterday, involving the analytic COUNT function.</h2>
ARIZ wrote:
Hi Frank,
Just out of curiosity, I was trying to understand the Count analytical function that you have used in the solution.
                COUNT ( CASE
                             WHEN ac.flag = 'Y'
                       THEN 1
                         END
                    ) OVER ( PARTITION BY CASE
                                               WHEN sourcekey = 0
                                   THEN acctkey
                                   ELSE sourcekey
                                           END
                              )     AS y_cntSo what I am thinking is, this would first partition the row with acctkey ( where sourcekey =0) and sourcekey and then within that partition, it will check whether ac.flag = Y or not, if it is 'Y' then it would return count as 1 else 0. Am I correct? In the mean time I am also reading the tutorials on Count() analytical query. I'm not sure I understand your explanation.
This is not partitioning first by x, and then by y. There is only one expression in the PARTITION BY clause. Most often, a PARTITION BY clause refers to some column in the table, for example:
SELECT ename
,       job
,       sal
,       AVG (sal) OVER (PARTITION BY job) AS avg_sal_for_job
FROM    scott.emp;This divides the result set into mutually exclusive parts; there will be as many such parts as there are distinct values for the PARTITION BY column. In the simple query above, if there happen to be 5 different values for job, you will get 5 independent averages.
In your problem, there is no one column that defines a partition. That is, these two rows belong to the same partition:
. SOURCEKEY F   ACCTKEY
         0 N       9647
      9647 Y       9812even though none of the 3 columns are the same. We could create a view that had a single column, telling to which partition each row belonged, like this:
. SOURCEKEY F   ACCTKEY PART_NUM
         0 N       9648     9648
         0 N       9647         9647
      9648 N       9813         9648
      9647 Y       9812         9647where part_num is the result of a CASE expression:
CASE
    WHEN sourcekey = 0
    THEN acctkey
    ELSE sourcekey
ENDWe could then use that new column, part_num, in a (very simple) PARTITION BY clause. But there is no need to create a view, even an in-line view, for that: we can (and I did) use the CASE expression directly in a (not so simple) PARTITION BY clause.
Why did I use COUNT? The important thing about each partition is whether or not it includes any rows with flag='Y'. I don;t know of any function that directly answers that question. There are lots of ways to get the correct answer, but I think the one that corresponds most closely to the question we really want to ask:
"Do any rows have flag='Y'?" is
"How many rows have flag='Y'?"
The analytic function COUNT (x) returns a number (possibly 0) of rows in the partition where x is not NULL. So, as the argument to COUNT, I used
CASE
    WHEN ac.flag = 'Y'
    THEN 1
-- ELSE NULL          -- I did not explicitly say this, but it is the default
ENDwhich returns either
(a) the literal number 1 or
(b) NULL
Instead of the literanl number 1, I could have used any literal or expression, of any data type, that is not NULL). all that matters is we produce something non-NULL for COUNT to count.
<h2>(2) A solution for a new problem involving the same tables</h2>
Also, I was trying to modify this query to fit my other similar requirement where I would need following output
Original output:
SOURCEKEY F    ACCTKEY
0 N       9648
0   N      9647
9648 N       9813
9647 Y       9812
So, the query should be smart enough to return only the last two rows where sourcekey >0 which is
SOURCEKEY F    ACCTKEY
9648 N       9813
9647 Y       9812
And In case there are only first two 2 rows in the table then , it should return only those two row and not check for sourcekey > 0 which would be .
SOURCEKEY F    ACCTKEY
0 N       9648
0   N      9647 Is it something that I should be using analytical function to solve this requirement. I am trying to accomplish this new requirement.If I understand this problem correctly, it does indeed involve mutually exclusive divisions, but in this problem, the divisions correspond more closely to a single column in the table. We want to divide the table into two mutually exclusive groups:
(A) rows where soucekey > 0, and
(B) rows where sourcekey = 0
We could do that with a CASE expression, but there happens to be a built-in function that works very nicely.
SIGN (sourcekey) returns
(A) 1 if sourcekey > 0, and
(B) 0 if sourcekey = 0
But what do we want to do with those divisions? We want to display rows only from the "best" of those divisions, where division (A) is coinsidered "better" than division (B). That is, if there are any rows in division (A), then we want to display only rows in division (A), but if there are no rows in division (A), then (and only then) we want to display rows in divison (B).
This is an example of a Top-N Query , where we want to display N items from the top of an ordered list. A typical top-N query uses an analytic function (either ROW_NUMBER, RANK or DENSE_RANK, depending on how we want to handle ties) to assign numbers to each row (lower numbers for the "better" rows), and then uses "WHERE f <= n" to display only the n "best" ones. (A special case, though a very common one, is where N=1, that is, we're only interested in the row (or rows, if there happens to be a tie) with the "best" value. In this case, most people find it cleare to say "WHERE f = 1" ratehr than "WHERE f <= 1". Your problem is an exmple ot that special case.)
SELECT sourcekey
,     flag
,     acctkey
FROM     (
         SELECT ac.sourcekey
         ,         NVL (ac.flag, 'N')     AS flag
         ,         ac.acctkey
         ,         DENSE_RANK () OVER (ORDER BY SIGN (sourcekey)     DESC)     AS division_num
            FROM    itemtable     i
         ,         finance     f
         ,         acct     ac
         WHERE   i.itemtableid1      = f.parentid1
         AND         i.itemtableid2      = f.parentid2
         AND         f.financekey      = ac.financekey
         AND         i.parenttableid      = 19063
WHERE     division_num     = 1
;Notice I talked about "mutually exclusiive *divisions* " above, not "mutually exclusive *partitions* ".
There is no PARTITION BY in the analytic clause above. PARTITION BY means we want a separate, independent caluclation for each partition. Here, we want one single numbering for the entire result set.
We want all rows that tie for the "best" to be numbered 1, so we have to use DENSE_RANK (or RANK) rather than ROW_NUMBER.

Urgent , Two Query questions ...

Hello everybody ,
      i have created a query in our production system . but i found some people can change my query setting (ex : my local fileds & selection fields ) , has any one can tell me how can i disable the 'Change' function in 'SQ01' ? many thanks !
(i also use 'su24' to check the authorzation object in 'SQ01' , but i don't know which one can help me to solved this case)
      another question that is when i execute the query i found one of the field's sequence was wrong . but this query is used everyday & nobody has changed it . but when i use sort this function to make it & it seems ok . therefore i think the problem is in the table index , right ? Has anyone can tell me how to check it ?
Best Regards,
Carlos

hi Ramki
     the query is made by ourselves . the data is only fetched from the billing table (vbrk & vbak) . but today i found some filed's sequence was wrong & i don't know what cause this .
another problem is that could you tell me how to disable 'Change' function in 'SQ01' ?
many thanks ~
Best Regards,
Carlos

Named query question

Hi Guys,
I have the following problem - I know I did something wrong, but I cannot figure out how to correct it. Here is my question:
I have a table tableA, with composite key (col1, col2, col3, col4). I mapped the table, and create a Toplink named query (findCol3List)as such:
select distinct col3
from tableA
where col1=#col1 and col2=#col2
I created an EJB session method getCol3List(col1, col2) -
now when I run the application to call this EJB method, I got the following error at line:
List results = (List)session.executeQuery("findCol3List", String.class, params);
Exception Description: Missing descriptor for [java.lang.String] for query named [findCol3List].
I know there are multiple mistakes in my approach, but with my limited Toklink knowledge, I could not figure out.
Any help with be appreciated!

hello,
The executeQuery method is trying to look up the "findCol3List" in the descriptor for the class passed in. It is complaining because you passed in String.class which does not have a valid descriptor.
How/where did you define the named query? Chances are you defined it in the class used for TableA, and so should specify it in the executeQuery method:
session.executeQuery("findCol3List", tableA.class, params);
Best Regards,
Chris

Creating SAP QUERY - question about tables in buisness transactions.

Hello.
I am pretty new to SAP.
I want to create a query, as i so far have successfully done by creating a join in transaction SQVI.
I am useing several tables;
CRMD_ORDERADM_H
CRMD_ORDERADM_I
CRMD_ORDER_INDEX
I have two questions.
1: I try to join CRMD_ORDER_INDEX-PARTNER_NO with BUT000-PARTNER, but it won't do the trick. After a join like this i would like to join BUT000 with ADRC . Can someone explain how i could do this?
2: I want join CRMD_ORDERADM_I with all the partners for the specific Item. (sold-to-party, shipping-party and so on). Can anyone tell me which table(s) i can find this in, and what fields to join.
I will appreciate any answer to this

Hi,
For the second question, enter your transaction number ( Object ID ) into <b>CRMD_ORDERADM_H</b> table. Pass the guid to table <b>CRMD_LINK.</b>
Take set guid from CRMD_LINK and pass it to <b>CRMD_PARTNER</b>.
You will get all the partners in that transaction
regards,
Prashant
<b>Kindly Reward the points if helpful !</b>

Web Service Query Question

I have a process that is going through each account record and doing some processing on it.
This is a time consuming process. It takes close to 20 minutes to complete.
I would like to provide a better status message to my customer to let them know how much longer the process should take.
My question is:
Can I retrieve the count of the number of records that would be returned based on the query criteria I am using?
I would use this to provide a status message like
"Processing account 50 of 120,000"

Hi All,
Recently we also had the same requirement, count the number of records and we achieved it by reports.
1. create a report which generates the simply total count of records.
2. on your custom page / application access that report and get the count.
Dinesh
CRMIT

Complex Query Question

I am doing a 9-1-1 reporting system. I am selecting calls by
Agency and type of call for a given month. That works fine, but I
need them printed in desending sequence by number call far a call
type. Don't see anyway to accomplish that with one query.
Is that a way? If not, the second part of this question is
that I have not created a table using SQL. I need 3 fields, Field_A
is Text (9 positions); Field_B is Text (40 Positions) and the last
is my summarized count from the query. How do I create a Table to
support this function?
Query
<cfquery name="GetEventCount"
datasource="JasperCountyDB">
select count(AG_ID) as EventCount, TYCOD, TYP_ENG, CURENT
from aeven
where ((AG_ID = '#Session.InquiryAgencyCode#')
AND (CURENT = 'T') AND (CDTS LIKE '#EventReportDate#'))
group by AG_ID, TYCOD, TYP_ENG, CURENT
</cfquery>
Thanks for any guideance that you can provide.
Ron

Your question wasn't very clear, but if you only want to sort
them by the count in descending order, just ORDER BY 1 DESC.
<cfquery name="GetEventCount"
datasource="JasperCountyDB">
SELECT COUNT(AG_ID) as EventCount, TYCOD, TYP_ENG, CURENT
FROM aeven
WHERE AG_ID = '#Session.InquiryAgencyCode#'
AND CURENT = 'T'
AND CDTS LIKE '#EventReportDate#'
GROUP BY AG_ID, TYCOD, TYP_ENG, CURENT
ORDER BY 1 DESC
</cfquery>
Phil

SQL Query question : how to add data to two tables connected by third Junction-table.

Hello specialists.
Maybe this is the wrong formum but I've got a question for which you probably have the answer, i hope.
Situation
John is member of Group_A and Group_B
Bill is member of Group_B and Group_C
Allison is member of Group_A and Group_E
How can I create a query to input Allisons username into table 1 and groupmembership into table 2. Also updating the relationship within junction-table3 must be done automaticaly. I want to avoid duplicate records.
The final situation I want is given in red text.
The relationships between the tables are as follows
Table1 (PK)ID-Userinfo    [ONE]    <------------> [MANY] Table3 ID-Userinfo
Table3 (PK)ID-GroupInfo [MANY] <------------> [ONE]   Table2 (PK)ID-GroupInfo
Table1: UserInfo
(PK)ID-Userinfo   UserName
1                        John
2                        Bill
3                      Allison
Table2: GroupInfo
(PK)ID-GroupInfo  GroupName
1                          Group_A
2                         Group_B
3                          Group_C
4                          Group_E
Table3: MemberOf
(PK)ID-MemberOf  ID-UserInfo ID-GroupInfo
1                           1                 1
2                           1                 2
3                           2                 2
4                           2                 3
5                           3                 1
6                           3                 4
I hope you can help me cracking this nut.
Thx in advance. Greetings Fred

Hi RSingh
May i comment something very small?
Anyone who writes a response, done it on the assumption that he is writing the answer. Writing response is the statement of "I think that's correct". Each one that write a response see it as the answer. It makes no sense immediately mark your own
answer too (double actions). Marking a response as "Propose as answer" is explicitly designed to
allow others to announce that they think this is the best right answer in the thread, after the discussion :-)
In my personal opinion, we should not mark our own answers. There are enough users with permissions, which would be glad to mark your answers as correct / recommended.
Give us the opportunity, I will love to mark your answers :-). Moreover, by marking "Proposed as answer" you actually close the thread, other users which see that the question got an answer, may not check
the thread at all, and maybe they could provide a different answer.
* Exceptions are very specific cases. For example a case where the message has already become very old and no one marked anything. in this case marking "Proposed as answer" can help others and especially the person who ask the question, to focus
on thread and the answer (more on the subject is in the Moderators forum and the Moderators Guide by the way).
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Record group query question

Just wondering if we need to check :system.mode = query or normal in the query for record groups or oracle forms handles it automatically
Thanks

No, you should not check System.Mode in a record group query. But then, Forms does not do that either.
Your question makes me wonder what you are doing... Record groups are usually populated only when you need to see a list of values, or use an LOV to perform an edit.

Complex Query Question(s)

I have two tables; one where I am defining questions and
possible answers and another where you insert the answers. The
table of questions is called 'public_survey', and SURVEY_ID is the
primary key.
The table of answers is called 'public_surveydata', where
SURVEYDATA_ID is the primary key, SURVEYDATA_QUESTIONID is what
links the primary key to public_survey and SURVEYDATA_CONTENTID is
what is needed for output; the other columns are the answers.
I need to:
(a) output public_survey so it displays in a searchable
manner;
(b) using variables from the search I need to search
public_surveydata and pull SURVEYDATA_CONTENTID.
Now comes the part I cannot figure out; I search and I can
pull up all the contentids that are related to each question; but I
cannot figure out to only pull results that are shared over all
returns. My query is a mess; somehow I need to either combine the
query or run another query after the fact that only pulls common
ids.
How do I output only common contentid that are shared in all
the queries?
To see all the code and cfdumps in regards to this post go to
this page:
http://208.106.208.43/data/query.cfm
To see the page in action sans cfdump and code go to this
page:
http://208.106.208.43/data/
Thanks!

Thanks Phil; I'm beginning to think I need to redesign it as
well. Basically my reasoning for the tables was that I wanted a
table where I could dynamically add questions that would display a
y/n, dropdown or checkbox answer - this in turn is linked to
another table (posts) by the contentid (see
http://208.106.208.43/data/query.cfm
The idea is to have a dynamic database feature that I could
change on the fly; for example -- if another question is to be
added to the post (i.e. Region) then I can quickly add it to all
data using a query without having to actually touch the database.
This is the form that creates these questions:
http://208.106.208.43/data/survey.cfm
However... that said - I know the easiest way to fix it would
be to just pull these columns out and stick them in the content
table; however that doesn't allow me to set up a dynamic table
where I can quickly change the questions.
How would you write a dynamic databases where you can quickly
insert fields and link them to other tables?

Advanced? Query question

Advanced for me anyway. Okay, running on an Oracle 11g database, I have a table that consists of the following fields:
acad_yr (academic year)
gender
ssno (social security number)
age
and many other fields not relevant to this question. The academic years run from 2006 through 2013, and the same people can appear multiple times in the table, but only once per academic year.
I want to write a query (or rather one of you kind folks write a query since I obviously can't) that will display the following output:
                                   2006                              2007                              2008                              2009                              2010                              2011                              2012                              2013
AGE                    M               F                  M               F                M                    F               M               F               M                    F               M                   F               M                 F               M                   F
20-24                 xxx             xxx               xxx             xxx             xxx                  xxx           xxx             xxx            xxx                 xxx            xxx                 xxx           xxx               xxx            xxx                xxx
25-29                 xxx             xxx               xxx             xxx             xxx                  xxx           xxx             xxx            xxx                 xxx            xxx                 xxx           xxx               xxx            xxx                xxx
30-34                 xxx             xxx               xxx             xxx             xxx                  xxx           xxx             xxx            xxx                 xxx            xxx                 xxx           xxx               xxx            xxx                xxx
35-39                 xxx             xxx               xxx             xxx             xxx                  xxx           xxx             xxx            xxx                 xxx            xxx                 xxx           xxx               xxx            xxx                xxx
40-44                 xxx             xxx               xxx             xxx             xxx                  xxx           xxx             xxx            xxx                 xxx            xxx                 xxx           xxx               xxx            xxx                xxx
45-49                 xxx             xxx               xxx             xxx             xxx                  xxx           xxx             xxx            xxx                 xxx            xxx                 xxx           xxx               xxx            xxx                xxx
50-59                 xxx             xxx               xxx             xxx             xxx                  xxx           xxx             xxx            xxx                 xxx            xxx                 xxx           xxx               xxx            xxx                xxx
60-99                 xxx             xxx               xxx             xxx             xxx                  xxx           xxx             xxx            xxx                 xxx            xxx                 xxx           xxx               xxx            xxx                xxx
Where xxx is a count of the number of people in the table that meet the academic year, gender and age criteria.
Thoughts?
Bob

with
test_data as
(select floor(dbms_random.value(2009,2014)) acad_yr,
        case when dbms_random.random > 0 then 'F' else 'M' end gender,
        floor(20 + abs(20 * dbms_random.normal)) age
   from dual
connect by level <= 1000
select *
from (select acad_yr,gender, case when age between 20 and 24 then 'g_20_24'
                                    when age between 25 and 29 then 'g_25_29'
                                    when age between 30 and 34 then 'g_30_34'
                                    when age between 35 and 39 then 'g_35_39'
                                    when age between 40 and 44 then 'g_40_44'
                                    when age between 45 and 49 then 'g_45_49'
                                    when age between 50 and 59 then 'g_50_59'
                                    when age between 60 and 99 then 'g_60_99'
                               end age_group,
               count(*) cnt
          from test_data
         group by acad_yr,gender, case when age between 20 and 24 then 'g_20_24'
                                       when age between 25 and 29 then 'g_25_29'
                                       when age between 30 and 34 then 'g_30_34'
                                       when age between 35 and 39 then 'g_35_39'
                                       when age between 40 and 44 then 'g_40_44'
                                       when age between 45 and 49 then 'g_45_49'
                                       when age between 50 and 59 then 'g_50_59'
                                       when age between 60 and 99 then 'g_60_99'
                                  end
pivot (max(cnt) for (gender,acad_yr) in (('F',2009) as F_2009,
                                         ('M',2009) as M_2009,
                                         ('F',2010) as F_2010,
                                         ('M',2010) as M_2010,
                                         ('F',2011) as F_2011,
                                         ('M',2011) as M_2011,
                                         ('F',2012) as F_2012,
                                         ('M',2012) as M_2012,
                                         ('F',2013) as F_2013,
                                         ('M',2013) as M_2013
order by 1
AGE_GROUP
F_2009
M_2009
F_2010
M_2010
F_2011
M_2011
F_2012
M_2012
F_2013
M_2013
g_20_24
16
19
18
25
20
27
15
19
26
18
g_25_29
24
19
16
19
15
19
17
18
22
23
g_30_34
16
16
11
13
14
14
16
16
17
15
g_35_39
15
12
11
17
13
15
16
13
16
12
g_40_44
10
12
14
8
11
8
8
11
13
12
g_45_49
10
7
10
4
15
6
10
4
9
14
g_50_59
10
10
7
5
6
7
9
8
8
9
g_60_99
4
4
2
7
4
8
3
1
5
4
Regards
Etbin

OER REX query question

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