Official example

Question

Any suggestions why this SUN's example doesn't work for me.
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Answer 1

Hello Satine,
Lets visit some concepts first:
String index starts with 0. Hence, for a expression "Satine __substringpos 't' ", result will be 2 and not 3. I guess that's where you probably made a mistake. So, lets see how __substringpos, __length, __trailingchars & __leadingchars are computed
_substringpos+: start counting with 0, till you reach the substring you are looking for
length+: start counting with 1, till you reach end of string (e.g., result of "_length Satine" will be 6)
+_trailingchars+: from end, start counting with 1 (e.g., result of "Satine _trailingchars 2" will be 'ne')
leadingchars+: from beginning, start counting with 1 (e.g., result of "Satine _leadingchars 2" will be 'Sa')
There are three ways of looking at the string. One "with return char", 2nd "with return char except for last item" and third "without return char". I am not sure what was the consideration of the author of the guide/DTD documentation, however, below examples will clarify how +__substringpos+, +__length+, +__trailingchars+ & +__leadingchars+ are computed
*Case 1: With Return char (return char at end too)*
parse_str=>#A1=10<new_line_char>#B1=20<new_line_char>#C1=30<new_line_char>#D1=40<new_line_char>#E1=50<new_line_char>#F1=60<new_line_char>
length of parse_str = 42
startpos = 21
num_trailing = 21
trim_str = #D1=40<new_line_char>#E1=50<new_line_char>#F1=60<new_line_char>
endpos = 7
result_str = #D1=40
*Case 2: With Return char (no return char at end)*
parse_str=>#A1=10<new_line_char>#B1=20<new_line_char>#C1=30<new_line_char>#D1=40<new_line_char>#E1=50<new_line_char>#F1=60
length of parse_str = 41
startpos = 21
num_trailing = 20
trim_str = #D1=40<new_line_char>#E1=50<new_line_char>#F1=60
endpos = 7
result_str = #D1=40
*Case 3: without return char*
parse_str=>#A1=10#B1=20#C1=30#D1=40#E1=50#F1=60
length of parse_str= 36
startpos = 18
num_trailing = 18
trim_str = #D1=40#E1=50#F1=60
endpos = 6
result_str = #D1=40
Regards
-Shant