One to many to return only one row

Question

hi guys,
i have an urgent problem here. i have a sql statement like below;
SELECT ALM_SWAP2_REP.M_TP_RTMFRP0, ALM_SWAP2_REP.M_TP_RTMFRP1,
ALM_SWAP2_REP.M_TP_RTMFRF0, ALM_SWAP2_REP.M_TP_RTMFRF1,
To_Char(TRN_HDR_DBF.M_OPT_FLWFST,'YYYYMMDD') AS VALDATE, ALM_SWAP2_REP.M_TP_RTFXC02,
ALM_SWAP2_REP.M_TP_RTFXC12, TRN_HDR_DBF.M_BRW_NOMU1, TRN_HDR_DBF.M_BRW_NOMU2,
ALM_SWAP2_REP.M_TP_RTAMC02, ALM_SWAP2_REP.M_TP_RTAMC12,
(CASE WHEN PAY_FLOW_DBF.M_LEG = 0 AND '20100831' BETWEEN To_Char(PAY_FLOW_DBF.M_CALC_DATE0,'YYYYMMDD') AND To_Char(PAY_FLOW_DBF.M_CALC_DATE1,'YYYYMMDD') THEN To_Char(PAY_FLOW_DBF.M_CALC_DATE1,'YYYYMMDD') END) AS RCV_DATE,
(CASE WHEN PAY_FLOW_DBF.M_LEG = 1 AND '20100831' BETWEEN To_Char(PAY_FLOW_DBF.M_CALC_DATE0,'YYYYMMDD') AND To_Char(PAY_FLOW_DBF.M_CALC_DATE1,'YYYYMMDD') THEN To_Char(PAY_FLOW_DBF.M_CALC_DATE1,'YYYYMMDD') END) AS PAY_DATE
FROM ALM_SWAP2_REP, TRN_HDR_DBF, PAY_FLOW_DBF WHERE ALM_SWAP2_REP.M_REF_DATA = 456576
AND ALM_SWAP2_REP.M_NB = TRN_HDR_DBF.M_NB
AND ALM_SWAP2_REP.M_NB = PAY_FLOW_DBF.M_TRN_ID
AND ALM_SWAP2_REP.M_NB = 228128
AND '20100831' BETWEEN To_Char(PAY_FLOW_DBF.M_CALC_DATE0,'YYYYMMDD') AND To_Char(PAY_FLOW_DBF.M_CALC_DATE1,'YYYYMMDD')
ORDER BY ALM_SWAP2_REP.M_TRN_GRP, ALM_SWAP2_REP.M_NB
When I join few tables, the results are returned in two rows because I have two records that in table PAY_FLOW_DBF that matches one row in table ALM_SWAP2_REP. I need these two matches but I want it to be returned in only one row without using group by. Pls help me. Thankls

Answer 1

user9274041 wrote:
i have an urgent problem here.http://www.oracle.com/html/terms.html
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Could you explain how something that is for your personal, informational, noncommercial purposes can be urgent?
Or is this a violation of the terms of use and abuse of these forums?