Open a text file and show it in JList

hi!
Can somebody give me a example!!
Tnx

public class FileChooser extends JFileChooser
protected FileStreams fileStreams;
public FileChooser()
//Set Text Filter
setFileFilter(new TextFilter());
//Show Files
int result = showOpenDialog(this);
//Grab Selected file
if (result == JFileChooser.APPROVE_OPTION)
getSelectedFile();
System.out.println("File:" + getSelectedFile).getPath());
if (getSelectedFile() != null)
try
fileStreams = new FileStreams(getSelectedFile());
catch (Exception e)
System.err.println("Error:FileChooser:Stream:" + e);
if (result == JFileChooser.CANCEL_OPTION){System.exit(0); }
}//End Class
You would need to create a class such as fileStreams that would take in:
BufferedReader buffReader = new BufferedReader(new FileReader(file));
and then do something.

Similar Messages

I want to open a text file and display it within Lookout 5.0

How do you read and display a text file within Lookout 5.0?

Hi Kenneth,
This should have been trivial, but isn't. Well, it isn't that difficult either. Here's the trick:
Create a DataSocket Object. For the URL, type: file:c:\ni\lookout5\test.txt[text]
Leave the Update mode as Automatic for now. Connect a Switch to the Connect member of the DataSocket object.
On the panel, drag-and-drop the DataSocket.data.txt. Toggle the Switch and voila you have the text in Lookout! I have attached an example (detach the txt file to your C drive; or change the path in the DataSocket object).
For the curious, DataSocket is a NI networking technology which supports ftp, http, file, and other protocols. See this
>FAQ f
or general info' on DataSockets.
Hope this helps,
Khalid
Attachments:
test.txt ‏1 KB
readtext.lks ‏2 KB

Recommended way to open a text file included in a jar?

Forgive me if this seems like an ignorant question, but I keep reading two different things about loading resources in the javadocs and forums, and can't seem to connect them...
Say you want to open a text file and read the contents into a String or a List. Apparently, the preferred way to do this is something like:
fileName = "myFile.txt";
BufferedReader br = new BufferedReader(new FileReader(new File(fileName)));
String line;
while ((line = reader.readLine()) != null) {...}
Now say you want to distribute your app in a jar file, with the text file included in the jar file. The above method won't work, because a FileReader operates on a File, and as I understand it, once myFile.txt is packed into the jar file, it's no longer a "file".
So what do you do? I keep reading that the best way to open the jarred text file is to use something like this:
InputStream is = getClass().getResourceAsStream(fileName);
Here's where I get confused: InputStream, and all of its subclasses, are now supposedly dispreferred for reading character data (in preference to Reader, as above). But no subclass of Reader can wrap around an InputStream, which would facilitate the reading of character data greatly, with methods like readLine().
So my question is: What's the best way to read a text file from within a .jar?
Thanks,
Gregory

great! glad it's working
here is a statement from the javadoc
http://java.sun.com/j2se/1.4.2/docs/api/java/io/InputStreamReader.html
For top efficiency, consider wrapping an InputStreamReader within a BufferedReader. For example:
BufferedReader in
= new BufferedReader(new InputStreamReader(System.in));
kind regards
Waken16

How do I open a text file to sort using bubble sort?

Hi,
I have a text file, which is a list of #'s.. ex)
0.001121
0.313313
0.001334
how do you open a text file and read a list? I have the bubble sort code which sorts.. thanks

I wrote this, but am getting a couple errors:
import java.util.*;
import java.io.*;
public class sort
     public static void main(String[] args)
          String fileName = "numsRandom1024.txt";
          Scanner fromFile = null;
          int index = 0;
          double[] a = new double[1024];Don't use double. You should use something that implements Comparable, like java.lang.Double.
          try
               fromFile = new Scanner(new File(fileName));
          catch (FileNotFoundException e)
System.out.println("Error opening the file " +
" + fileName);
               System.exit(0);
          while (fromFile.hasNextLine())
               String line = fromFile.nextLine();
               a[index] = Double.parseDouble(line);Don't parse to a double, create a java.lang.Double instead.
               System.out.println(a[index]);
               index++;
          fromFile.close();
          bubbleSort( a, 0, a.length-1 );No. Don't use a.length-1: from index to a.length-1 all values will be null (if you use Double's). Call it like this:bubbleSort(a, 0, index);
public static <T extends Comparable<? super T>> void
d bubbleSort( T[] a, int first, int last )
          for(int counter = 0 ; counter < 1024 ; counter++)
for(int counter2 = 1 ; counter2 < (1024-counter) ;
) ; counter2++)Don't let those counter loop to 1024. The max should be last .
                    if(a[counter2-1] > a[counter2])No. Use the compareTo(...) method:if(a[counter2-1].compareTo(a[counter2]) > 0) {
                         double temp = a[counter2];No, your array contains Comparable's of type T, use that type then:T temp = a[counter2];
// ...Good luck.

Compare two .txt files and show result

HI
Could anybody show me how to compare two text files and show the result.
i.e.
textfile1.txt
harry.denmark
karry.sweden
textfile2.txt
harry.denmark
karry.sweden
marry.usa
Compare
result=
marry.usa
The text files I want to compare are how ever much larger than this example. (up to 2-3.000 words)
anybody ??
Sincerly
Peder

HI & thanks for reply
I know almost nothing about java so could you or anybody please show me the code to do this? Or is it perhaps too large or difficult a code?
I know how to compile a .java file and run it in prompt :-) and thats about it (almost)
I offcourse understand if its too much to ask for :-)

Please help! I defragged my hard drive and now Illustrator CS6 is trying to open all of my complex Illustrator files with a "Text Import Options" box as if they are text files, and they are not opening!

Please help! Illustrator CS6 started trying to open all of my complex.ai files with a "Text Import Options" box as if they were text files, and they are not opening! Help!

Hi Monika,
I have spent the last two or three days trying to do what you suggested. I uninstalled Adobe 6 from Windows. Some files that CS6 placed on my system during installation remained, including fonts and .dll files.
I had to abandon the Cleaner Tool you suggested because in one screen it allowed me to specify removing CS6 only, but on the following screen it only gave on option to remove ALL Adobe programs. I could not do that because I didn't have the serial number handy for CS3 in case I want to reinstall it at some point.
I tried to get technical help with the Cleaner Tool problem but no definitive help was available, so I reinstalled CS6 again without having the benefit of the Cleaner Tool. I tried to get the serial number for CS3 so I could use the Cleaner Tool but spent 2 wasted hours in chat. Even though I had a customer number, order number, order date, place of purchase, the email address used AND 16 digits of the serial number, in two hours the agent couldn't give me the serial number. After two hours I had nothing but instructions to wait another 20 minutes for a case number.
Illustrator CS6 is still trying to open some backups as Text and otherNone of the problems have been fixed. I have tried to open/use the .ai files in CS6 installed on another system and am getting the same result, so I don't think the software was damaged by the cleaner. The hard drive cleaner is well-known and I've run it many times without any problem to previous versions of Illustrator or any other programs.
When I ordered, the sale rep promised good technical support and gave me an 800 number, but after I paid the $2000, I learned that the 800 number she gave me doesn't support CS6 and hangs up on me. Adobe doesn't call it a current product even though they just sold it to me about 3 weeks ago.
Would appreciate any help you experts can offer. If I can't solve this, the last backup I can use was from June and I will have lost HUNDREDS of hours of work and assets that I cannot replace.
Exhausted and still desperately in need of help...

How do i add a download action for dxf files. firefox assumes its a text file and just opens it with no download action dialog box

I want to add a download action for dxf files so they open in Autodesk trueview. The steps described here (http://support.mozilla.com/en-US/kb/Managing%20file%20types#w_adding-download-actions) say to click on a link for the filetype you want to add an action to but firefox thinks the dxf is a text file and just opens it in a new tab with no download action dialog box.

Use the right-click context menu and choose "Save Link As" or hold down the alt key and left-click the link.

Urgent Help:read from text file and write to table

Hi,
I'm a super beginner looking for a vi to read this data from a text file and insert it into a table:
   #19
Date: 05-01-2015
ID= 12345678
Sample_Rate= 01:00:00
Total_Records= 2
Unit: F
   1 03-23-2015 10:45:46   70.1   3.6
   2 03-23-2015 11:45:46   67.7   2.7
Output table
#     date                 time                 x          y        Sample rate    Total Records
1          03-23-2015     10:45:46        76.8     2.8      01:00:00           2
2          03-23-2015     10:45:46        48.7 2.1      01:00:00           2
Thanks for your help in advance.
Attachments:
sample.txt ‏1 KB

jcarmody wrote:
Will there always be the same number of rows of noise header information?
Show us how you've read the data and what you've tried to do to parse it. Once you've got the last rows, you can loop over them using Spreadsheet String to Array (after cleaning up a few messy spaces).
Jim,
I didn't know you're that active on here.
Yes, There will always be the same number of noise header information.
I'll show you in person
Regards,

How to open a text file without using dialog box

I can open a file using dialog box but I want to open a file without using any dialog box for writing.
With the following commands a new file is created.
File outputFile = new File("outagain.txt");
FileWriter out = new FileWriter(outputFile);
I want to open an existing file and put some more text in it using FileWriter or any other object
rgds,
Arsalan

import java.io.*;
class UReader
    BufferedReader in;
    BufferedReader input;
    String fileName;
    public UReader(String fileName)
        this.fileName = null;
        this.fileName = fileName;
        try
            in = new BufferedReader(new FileReader(fileName));
            input = new BufferedReader(new FileReader("A.b"));
        catch(IOException _ex) { }
    public final String getContent()
        String txt = "";
        try
            while(in.ready())
                txt = txt + in.readLine();
                txt = txt + "\n";
            in.close();
            txt.trim();
        catch(IOException _ex) { }
        return txt;
    public final String getLine(int row)
        try
            input = new BufferedReader(new FileReader(fileName));
        catch(IOException _ex) { }
        String txt = null;
        if(row <= getRows()) {
            try
                for(int i = 0; i < row; i++)
                    txt = input.readLine();
                input.close();
            catch(IOException _ex) { }
        } else {
            txt = "Index out of Bounds";
        return txt;
    public final int getRows()
        try
            input = new BufferedReader(new FileReader(fileName));
        catch(IOException _ex) { }
        String txt = null;
        int rows = 0;
        try
            while(input.ready())
                txt = input.readLine();
                rows++;
            input.close();
        catch(IOException _ex) { }
        return rows;
import java.io.*;
import java.util.*;
class UWriter
    PrintWriter out;
    String fileName;
    String[] txt;
    static int NEW_LINE = 1;
    static int APPEND = 0;
    public UWriter(String s)
        fileName = null;
        txt = null;
        fileName = s;
        try
            out = new PrintWriter(new BufferedWriter(new FileWriter(s, true)));
        catch(IOException ioexception) { }
    public final void addContent(String s, int i)
        int l = 0;
        StringBuffer sb = new StringBuffer(s);
        s.replaceAll("\n\n", "\n###\n");
        StringTokenizer str = new StringTokenizer(s, "\n");
        String token = null;
        while (str.hasMoreTokens()) {
            ++l;
            token = str.nextToken();
        str = new StringTokenizer(s, "\n");
        txt = new String[l];
        int k = 0;
        String test;
        while (str.hasMoreTokens()) {
            test = str.nextToken();
            if (test.equals("###")) test = "";
            txt[k++] = test;
        if(i == 0) {
            try
                for (int j = 0; j < txt.length; ++j) {
                    out.println(txt[j]);
                out.close();
            catch(Exception ioexception) { }
        } else {
            try
                out.println();
                for (int j = 0; j < txt.length; ++j) {
                    out.println(txt[j]);
                out.close();
            catch(Exception ioexception1) { }
    public final void writeContent(String s)
        int l = 0;
        s.replaceAll("\n\n", "###");
        StringTokenizer str = new StringTokenizer(s, "\n");
        String token = null;
        while (str.hasMoreTokens()) {
            ++l;
            token = str.nextToken();
        str = new StringTokenizer(s, "\n");
        txt = new String[l];
        int k = 0;
        String test;
        while (str.hasMoreTokens()) {
            test = str.nextToken();
            if (test.equals("###")) test = "";
            txt[k++] = test;
        try
            PrintWriter bufferedwriter = new PrintWriter(new BufferedWriter(new FileWriter(fileName, false)));
            for (int j = 0; j < txt.length; ++j) {
                bufferedwriter.println(txt[j]);
            bufferedwriter.close();
        catch(IOException ioexception) { }
}Maybe they are not the best codes, i wrote them a long time ago, so dont ask why i did anything wierd. :D
But anyway it works.

Opening a text file in server from an applet running in the client

Friends,
I want to open a text file in the server(The server machine uses tomcat 4.1.12 server)from an applet running in the client machine;
The applet invokes a servlet that opens the text file;this text file is opened in the server machine; but I want it to be opened in the client machine where the applet is running.
Plese help me to get around this.

You can open the textfile on the servlet and then send the information to the client (applet) as stirngs. The must then applet convert the stirngs into some object or simply display the information in someway. But then the text file that you are opening must be stored in some relevant tomcat directory e.g. on the server. If you want to open a file on the clients computer, you get into signed applets.

Reading multiple text files and writing them to one text file

Hi,
I'm trying to read a number of text files and write them to a single master file. My program reads all the files but only writes the last one to the master file.
import java.awt.event.ActionListener;
import java.awt.event.ActionEvent;
// Input/Output Classes
import java.util.Scanner;
import java.io.PrintWriter;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.FileNotFoundException;
import javax.swing.JFrame;
import javax.swing.JTextField;
import javax.swing.JTextArea;
import java.awt.GridLayout;
public class Actor implements ActionListener
public static String DataRoot = "I:\\JAVA\\UBP\\DAT
public static JFrame SW = new JFrame();
public static JTextField txtSPath;
public static JTextArea txtTable;
public void actionPerformed( ActionEvent e )
String Command = e.getActionCommand();
if (Command.equals("Process") )
SetupWin();
ProcessAll();
public void SetupWin()
SW.setTitle("void");
SW.setSize(300,400);
SW.setLayout(new GridLayout(6,1));
txtSPath = new JTextField(40);    SW.add(txtSPath);
txtTable = new JTextArea(10, 40); SW.add(txtTable);
SW.setVisible(true);
public void ProcessAll()
Process("Dunstable","Finance");
Process("Dunstable","Production");
Process("Dunstable","Sales");
public void Process(String Town, String Dept)
String SPath = DataRoot + Town + "
" + Dept + ".txt";
String MPath = DataRoot + "masterFile" + ".txt";
txtSPath.setText(SPath);
String message = "Trying " + SPath;
System.out.println(message);
String SlaveTable=message;
try// if following fails an exception is thrown
Scanner Slave = new Scanner(new FileInputStream(SPath)); // reads slave file
PrintWriter outputStream = null;
outputStream = new PrintWriter(new FileOutputStream(MPath));
while ( Slave.hasNextLine() ) // reads text line by line
//Read and output next record
String PartRecord = Slave.nextLine();
String FullRecord = Town + " " + PartRecord;
System.out.println(FullRecord);
outputStream.println(FullRecord);
Slave.close();
outputStream.close();
txtTable.setText(SlaveTable);
//An Exception Error would be THROWN by above & CAUGHT below
catch(FileNotFoundException e)
message = "Could Not Find " + SPath;
System.out.println(message);     //console
txtSPath.setText(message);     //window
catch(IOException e)
System.out.println("Slave I/O Problem " + SPath);
}Edited by: Ardour on Mar 4, 2008 1:53 PM

I haven't looked closely, but my spidey sense tingles at this:
new FileOutputStream(MPath)This will clobber (erase) the previous contents of the file. Open in append mode:
new FileOutputStream(MPath, true)Of course, if the file exists before you run this code, you will end up append to the original contents. If that is not wanted, consider using File's delete method first.

Opening a Text File?

I am having no luck opening a text file that contains comma delimited data. I have tried some different ways and am having no luck at all. I can't even get a open file dialog to appear when I click a button.
I did not see any example of this in the sdk sample plugins.
Anyone able to help me out.
The file I am trying to load is "D:\Test\TestFile.txt".

If you did not escape the path's backslashes that may be part of the problem.
Some example code:
local LrDialogs = import 'LrDialogs'
local LrFileUtils = import 'LrFileUtils'
local LrPathUtils = import 'LrPathUtils'
local file = 'C:\\temp\\Testfile1.txt'
if not LrFileUtils.isReadable(file) then
local dialogresult = LrDialogs.runOpenPanel {
title = 'Select input text file',
allowsMultipleSelection = false,
initialDirectory = LrPathUtils.parent(file)
file = dialogresult and dialogresult[1] or nil
end
if file and LrFileUtils.isReadable(file) then
local collectedLines = {}
for line in io.lines(file) do table.insert(collectedLines, line) end
LrDialogs.message(table.concat(collectedLines, '\n'))
end
Herb

Opening a text file in a bundle with C++

Hi folks! I'm working with bundles for the first time, and I'd like to know how to open a text file inside one with C++. What I have now is this:
ifstream file = new ifstream(fileName.c_str());
if (!file->is_open())
return false;
Where fileName is a std::string. This is the way I'm accustomed to opening files (I'm from a Windows development background -- don't hate me! ). Unfortunately, the is_open() test always fails.
I know how to get the path of the bundle. Once I add on my data subdirectory and file name, the fileName variable ends up as this:
/Users/sb/...project location.../Debug/MyProg.app/data/Dev Options.ini
Should the path be different somehow? Thanks for any help!

Your data folder most likely isn't directly inside the .app bundle. The first directory inside an .app bundle is named Contents. The article at the following URL should help you:
http://www.meandmark.com/bundlespart1.html
If you're going to use C++ streams to open files, you'll want to ignore the section on opening the file in Part 3 of the article. You'll want to read up on the Core Foundation CFURL functions. You'll want to use one of the functions that gives you a path to the text file that you can pass to a C++ file stream.

How to open a text file using button click event

hi, How can i open a text file in a textpad or notepad on the click event of a button.?
Thanks
Jay

Pnt,
this will not work LV 8.0.1 and LV 8.6 will give back error 193.
Attached is a VI to use the ShellExecute WinAPI. The VI is LV 7.1.1.
Message Edited by waldemar.hersacher on 10-09-2008 10:48 PM
Waldemar
Using 7.1.1, 8.5.1, 8.6.1, 2009 on XP and RT
Don't forget to give Kudos to good answers and/or questions
Attachments:
ShellExecute.zip ‏27 KB

Copy one text file to another text file and delete last line

Hi all wonder if someone can help, i want to be able to copy one text file to another text file and remove the last line of the first text file. So currently i have this method:
Writer output = null;
         File file = new File("playerData.xml");
         try {
               output = new BufferedWriter(new FileWriter(file, true));
               output.write("\t" + "<player>" + "\n");
               output.write("\t" + "\t" + "<playerName>" + playerName + "</playerName>" + "\n");
               output.write("\t" + "\t" + "<playerScore>" + pointCount + "</playerScore>" + "\n");
               output.write("\t" + "\t" + "<playerTime>" + minutes + " minutes " + seconds + " seconds" + "</playerTime>" + "\n");
               output.write("\t" + "</player>" + "\n");
               output.write("</indianaTuxPlayer>" + "\n");
              output.close();
              System.out.println("Player data saved!");
         catch (IOException e) {
               e.printStackTrace();
          }However each time the method is run i get the "</indianaTuxPlayer>" line repeated, now when i come to read this in as a java file i get errors becuase its not well formed. So my idea is to copy the original file, remove the last line of that file, so the </indianaTuxPlayer> line and then add this to a new file with the next data saved in it. So i would end up with something like this:
<?xml version="1.0" encoding="UTF-8"?>
<indianaTuxPlayers>
     <player>
          <playerName>Default Player</playerName>
          <playerScore>0</playerScore>
          <playerTime>null minutes null seconds</playerTime>
     </player>
     <player>
          <playerName>Default Player</playerName>
          <playerScore>0</playerScore>
          <playerTime>null minutes null seconds</playerTime>
     </player>
     <player>
          <playerName>Default Player</playerName>
          <playerScore>0</playerScore>
          <playerTime>null minutes null seconds</playerTime>
     </player>
</indianaTuxPlayers>
However after all day searching the internet and trying ways, i have been unable to get anything working, could anyone give me a hand please?

I would go the XML route too, but for fun, open a file as a BufferedWriter and do this:
void copyAllButLastLine(File src, BufferedWriter tgt) throws IOException {
    BufferedReader in = new BufferedReader(new FileReader(src));
    try {
        String previous= in.readLine();
        for (String current = null; (current = in.readLine()) != null; previous=current) {
            tgt.write(previous);
            tgt.newLine();
    } finally {
        in.close();
}

Open a text file and show it in JList

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