Open link onto the current page in a region?

Was wondering how i would open a website onto my Apex page.
so for example...
i have a link linking to http://somewebsite.com in my apex page
when the link is click the page would populate within a region in apex which now let the user use that website within apex. (not redirecting to the url itself or popping up a new tab)
*I hope that make made sense...

Thanks!
Was wondering.. how do i make it so this error message is default to "no" if that's possible. if other people were to use it.
"Do you want to view only the webpage content that was delivered securely?"
Im using IE 8 at the moment
Edited by: PandaOracle on Feb 13, 2012 10:48 AM

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As I was searching in metalink I found somebody from Oracle had posted this :
### What were you trying to accomplish when the problem occurred? ###
Author : Jerry Silver Type : N/A
Date : Jun 6, 2001 11:22 PT
Here's a solution for Portal 3.0.8 or later that allows you to open a file in
a new browser window. It requires that you create a custom item type, and use a
procedure to display a link to the file.
1. Create the following procedure. You can create it in any schema, but the
schema has to have select privilege on the view 'WWSBR_ALL_ITEMS' in the portal
schema. In this example, the portal schema is PORTAL30. If you're running
version 3.0.8, you'll also need to apply the patch to bug 1724250.
Create or Replace PROCEDURE OPEN_FILE (p_itemid IN NUMBER) as
fileURL varchar2(1024);
baseURL varchar2(256) := '/pls/portal30/docs/';
begin
select baseURL | | filename into fileURL
from portal30.wwsbr_all_items
where id = p_ItemId;
htp.p ('Open File');
EXCEPTION
when NO_DATA_FOUND then
htp.p('Document not found or access denied');
when others then
htp.p(sqlerrm);
end;
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value with the correct Database Access Descriptor (DAD) and Document Access
Path ("/docs") for your site.
2. Grant execute on the procedure to the portal public schema. The name of this
schema is <portal schema>_PUBLIC. So if your portal schema is PORTAL30, grant
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that you create the type in the Shared Objects content area, so it can be used
in other content areas (from the Navigator, go to the Content Areas tab, select
Contents for Shared Objects, Custom Types, and Item Types - Create). Edit the
Text continued in next action...
new type and go to the Procedures tab.
4. In the Procedure Call Properties, enter:
Type: PL/SQL
Procedure Call: <your procedure schema>.OPEN_FILE
Link Text: Open File (it doesn't matter what you put here - it only displays if
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Attribute: Item Id
Pass As: p_itemid
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take advantage of this feature to write procedures that give you precise
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different item types for files.
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8. Now you can create items of the new item type. Each item's Display Name will
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file to open in a new browser window.
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But after doing this the issue with this still I am able to see this as link on the page but when I
click on it opens up in current window. But when I click on the header bar that
displays Content Area name then it takes to the content are manager. Here there is
a link that shows OPEN_FILE link and then it opens up in a new window.
But I don't want user to go inside the content manager to see the content to open up in a new window.
I want this same functionality to be there on the page rather then in the content area navigator
Thanks

fuscia wrote:
stonecrest wrote:sh -c "cd %f && urxvt"
can't help being ignorant: what is that?
A shell script for entering the working directory and launching urxvt.
Try it and see if it actually works.
I think I tried something like that but wasn't successful...
Last edited by moljac024 (2008-09-26 12:28:43)

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