Open URL in new window from page process

Question

I have a Page process that returns a URL (stored in 'l_val' field). Within this process, what is the best way to open that URL (stored in l_val) in a new window?
thanks
DECLARE l_clob clob;
l_xml xmltype;
l_val clob;
BEGIN
for c1 in (select clob001
from apex_collections
where collection_name = 'CENTRIS_IEP_VIEWER') loop
l_clob := c1.clob001;
exit;
end loop;
l_xml := xmltype.createxml(l_clob);
l_val := dbms_xmlgen.convert(
l_xml.extract(
'//GetIEPUrlWithAuditResult/text()'
, 'xmlns="http://www.iepdirect.com/CentrisWebServices/IEPViwer"'
).getstringval()
, 1
END;

Answer 1

Hello,
You can create a application process using this code and call that process from a javascript function and return that URL to the javascript function there you can open a popup easily.
If you want you can open a popup from process, you can do that using htp.p() function, I had tried this once but what it does was, it opens a popup but it clears out my parent page, I was not be able to see anything on my parent page.
Thanks
Tauceef