OpenLDAP and Octet String.
Hi all, I had a new problem with my jsp's applications that must connect to a openLDAP server.
I resolve the connection and the search problems, as I said in other post.
Now the problem is that I must use the connection for authenticate the simple user.
I discovery that I can do that using the dn parameter.
The problem is that if I would do it I should do too much connections because I must do:
1)connect with the admin user;
2) search the dn value of the user that is trying to connect using the username's value that I receive withe login's form;
3) close the connection;
4) and finnally reconnect to the ldap server with thenew credentials!
I don't like this solution so I'm here because I would know if there are some thing to do for take the value of a octet string on a ldap server.
The alternative is "traslate" the string with the password write on my login's form in the same format of userPassword's field.
I know that the octet string is a byte's array and I try to cast my string in a bye's array and compare with the other with the method contains() but it retunes false.
I find this topic:
http://forums.sun.com/thread.jspa?threadID=721595&messageID=4162046
but there are two problems:
1) as I said I don't know how get the value of a octet string's field;
2) the code of for's cycle five me a compilers' error and I never seen a for's cycle withe the string so I don't know how I can traslate it in a classic for's cycle...
Some one can help me?
Thanks inadvance.
First I use the contaims() method.
Second i insert as value to control the string casts in byte's array with the method getBytes().
Than it returns true!
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Problem with OpenLDAP and JNDI
I'm having problem working with OpenLDAP and JNDI.
First I have changed LDAP's slapd.conf file:
suffix "dc=antipodes,dc=com"
rootdn cn=Manager,dc=antipodes,dc=com
directory "C:/Program Files/OpenLDAP/data"
rootpw secret
schemacheck offthan i used code below, to create root context:
package test;
import javax.naming.Context;
import javax.naming.InitialContext;
import javax.naming.NamingException;
import javax.naming.NameAlreadyBoundException;
import javax.naming.directory.*;
import java.util.*;
public class MakeRoot {
final static String ldapServerName = "localhost";
final static String rootdn = "cn=Manager,dc=antipodes,dc=com";
final static String rootpass = "secret";
final static String rootContext = "dc=antipodes,dc=com";
public static void main( String[] args ) {
// set up environment to access the server
Properties env = new Properties();
env.put( Context.INITIAL_CONTEXT_FACTORY,
"com.sun.jndi.ldap.LdapCtxFactory" );
env.put( Context.PROVIDER_URL, "ldap://" + ldapServerName + "/" );
env.put( Context.SECURITY_PRINCIPAL, rootdn );
env.put( Context.SECURITY_CREDENTIALS, rootpass );
try {
// obtain initial directory context using the environment
DirContext ctx = new InitialDirContext( env );
// now, create the root context, which is just a subcontext
// of this initial directory context.
ctx.createSubcontext( rootContext );
} catch ( NameAlreadyBoundException nabe ) {
System.err.println( rootContext + " has already been bound!" );
} catch ( Exception e ) {
System.err.println( e );
}this worked fine, I could see that by using "LDAP Browser/Editor".
and then I tried to create group with code:
package test;
import java.util.Hashtable;
import javax.naming.*;
import javax.naming.ldap.*;
import javax.naming.directory.*;
public class MakeGroup
public static void main (String[] args)
Hashtable env = new Hashtable();
String adminName = "cn=Manager,dc=antipodes,dc=com";
String adminPassword = "secret";
String ldapURL = "ldap://127.0.0.1:389";
String groupName = "CN=Evolution,OU=Research,DC=antipodes,DC=com";
env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory");
//set security credentials, note using simple cleartext authentication
env.put(Context.SECURITY_AUTHENTICATION,"simple");
env.put(Context.SECURITY_PRINCIPAL,adminName);
env.put(Context.SECURITY_CREDENTIALS,adminPassword);
//connect to my domain controller
env.put(Context.PROVIDER_URL,ldapURL);
try {
// Create the initial directory context
LdapContext ctx = new InitialLdapContext(env,null);
// Create attributes to be associated with the new group
Attributes attrs = new BasicAttributes(true);
attrs.put("objectClass","group");
attrs.put("samAccountName","Evolution");
attrs.put("cn","Evolution");
attrs.put("description","Evolutionary Theorists");
//group types from IAds.h
int ADS_GROUP_TYPE_GLOBAL_GROUP = 0x0002;
int ADS_GROUP_TYPE_DOMAIN_LOCAL_GROUP = 0x0004;
int ADS_GROUP_TYPE_LOCAL_GROUP = 0x0004;
int ADS_GROUP_TYPE_UNIVERSAL_GROUP = 0x0008;
int ADS_GROUP_TYPE_SECURITY_ENABLED = 0x80000000;
attrs.put("groupType",Integer.toString(ADS_GROUP_TYPE_UNIVERSAL_GROUP + ADS_GROUP_TYPE_SECURITY_ENABLED));
// Create the context
Context result = ctx.createSubcontext(groupName, attrs);
System.out.println("Created group: " + groupName);
ctx.close();
catch (NamingException e) {
System.err.println("Problem creating group: " + e);
}got the error code: Problem creating group: javax.naming.directory.InvalidAttributeIdentifierException: [LDAP: error code 17 - groupType: attribute type undefined]; remaining name 'CN=Evolution,OU=Research,DC=antipodes,DC=com'
I tried by creating organizational unit "ou=Research" from "LDAP Browser/Editor", and then running the same code -> same error.
also I have tried code for adding users:
package test;
import java.util.Hashtable;
import javax.naming.ldap.*;
import javax.naming.directory.*;
import javax.naming.*;
import javax.net.ssl.*;
import java.io.*;
public class MakeUser
public static void main (String[] args)
Hashtable env = new Hashtable();
String adminName = "cn=Manager,dc=antipodes,dc=com";
String adminPassword = "secret";
String userName = "cn=Albert Einstein,ou=Research,dc=antipodes,dc=com";
String groupName = "cn=All Research,ou=Research,dc=antipodes,dc=com";
env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory");
//set security credentials, note using simple cleartext authentication
env.put(Context.SECURITY_AUTHENTICATION,"simple");
env.put(Context.SECURITY_PRINCIPAL,adminName);
env.put(Context.SECURITY_CREDENTIALS,adminPassword);
//connect to my domain controller
env.put(Context.PROVIDER_URL, "ldap://127.0.0.1:389");
try {
// Create the initial directory context
LdapContext ctx = new InitialLdapContext(env,null);
// Create attributes to be associated with the new user
Attributes attrs = new BasicAttributes(true);
//These are the mandatory attributes for a user object
//Note that Win2K3 will automagically create a random
//samAccountName if it is not present. (Win2K does not)
attrs.put("objectClass","user");
attrs.put("samAccountName","AlbertE");
attrs.put("cn","Albert Einstein");
//These are some optional (but useful) attributes
attrs.put("giveName","Albert");
attrs.put("sn","Einstein");
attrs.put("displayName","Albert Einstein");
attrs.put("description","Research Scientist");
attrs.put("userPrincipalName","[email protected]");
attrs.put("mail","[email protected]");
attrs.put("telephoneNumber","999 123 4567");
//some useful constants from lmaccess.h
int UF_ACCOUNTDISABLE = 0x0002;
int UF_PASSWD_NOTREQD = 0x0020;
int UF_PASSWD_CANT_CHANGE = 0x0040;
int UF_NORMAL_ACCOUNT = 0x0200;
int UF_DONT_EXPIRE_PASSWD = 0x10000;
int UF_PASSWORD_EXPIRED = 0x800000;
//Note that you need to create the user object before you can
//set the password. Therefore as the user is created with no
//password, user AccountControl must be set to the following
//otherwise the Win2K3 password filter will return error 53
//unwilling to perform.
attrs.put("userAccountControl",Integer.toString(UF_NORMAL_ACCOUNT + UF_PASSWD_NOTREQD + UF_PASSWORD_EXPIRED+ UF_ACCOUNTDISABLE));
// Create the context
Context result = ctx.createSubcontext(userName, attrs);
System.out.println("Created disabled account for: " + userName);
//now that we've created the user object, we can set the
//password and change the userAccountControl
//and because password can only be set using SSL/TLS
//lets use StartTLS
StartTlsResponse tls = (StartTlsResponse)ctx.extendedOperation(new StartTlsRequest());
tls.negotiate();
//set password is a ldap modfy operation
//and we'll update the userAccountControl
//enabling the acount and force the user to update ther password
//the first time they login
ModificationItem[] mods = new ModificationItem[2];
//Replace the "unicdodePwd" attribute with a new value
//Password must be both Unicode and a quoted string
String newQuotedPassword = "\"Password2000\"";
byte[] newUnicodePassword = newQuotedPassword.getBytes("UTF-16LE");
mods[0] = new ModificationItem(DirContext.REPLACE_ATTRIBUTE, new BasicAttribute("unicodePwd", newUnicodePassword));
mods[1] = new ModificationItem(DirContext.REPLACE_ATTRIBUTE, new BasicAttribute("userAccountControl",Integer.toString(UF_NORMAL_ACCOUNT + UF_PASSWORD_EXPIRED)));
// Perform the update
ctx.modifyAttributes(userName, mods);
System.out.println("Set password & updated userccountControl");
//now add the user to a group.
try {
ModificationItem member[] = new ModificationItem[1];
member[0]= new ModificationItem(DirContext.ADD_ATTRIBUTE, new BasicAttribute("member", userName));
ctx.modifyAttributes(groupName,member);
System.out.println("Added user to group: " + groupName);
catch (NamingException e) {
System.err.println("Problem adding user to group: " + e);
//Could have put tls.close() prior to the group modification
//but it seems to screw up the connection or context ?
tls.close();
ctx.close();
System.out.println("Successfully created User: " + userName);
catch (NamingException e) {
System.err.println("Problem creating object: " + e);
catch (IOException e) {
System.err.println("Problem creating object: " + e); }
}same error.
I haven't done any chages to any schema manually.
I know I'm missing something crucial but have no idea what. I have tried many other code from tutorials from net, but they are all very similar and throwing the same error I showed above.
thanks in advance for help.I've solved this.
The problem was that all codes were using classes from Microsoft Active Directory, and they are not supported in OpenLDAP (microsoft.schema in OpenLDAP is just for info). Due to this some fields are not the same in equivalent classes ("user" and "person").
so partial code for creating user in root would be:
import java.util.Hashtable;
import javax.naming.ldap.*;
import javax.naming.directory.*;
import javax.naming.*;
import javax.net.ssl.*;
import java.io.*;
public class MakeUser
public static void main (String[] args)
Hashtable env = new Hashtable();
String adminName = "cn=Manager,dc=antipodes,dc=com";
String adminPassword = "secret";
String userName = "cn=Albert Einstein,ou=newgroup,dc=antipodes,dc=com";
env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory");
//set security credentials, note using simple cleartext authentication
env.put(Context.SECURITY_AUTHENTICATION,"simple");
env.put(Context.SECURITY_PRINCIPAL,adminName);
env.put(Context.SECURITY_CREDENTIALS,adminPassword);
//connect to my domain controller
env.put(Context.PROVIDER_URL, "ldap://127.0.0.1:389");
try {
// Create the initial directory context
LdapContext ctx = new InitialLdapContext(env,null);
// Create attributes to be associated with the new user
Attributes attrs = new BasicAttributes(true);
attrs.put("objectClass","user");
attrs.put("cn","Albert Einstein");
attrs.put("userPassword","Nale");
attrs.put("sn","Einstein");
attrs.put("description","Research Scientist");
attrs.put("telephoneNumber","999 123 4567");
// Create the context
Context result = ctx.createSubcontext(userName, attrs);
System.out.println("Successfully created User: " + userName);
catch (NamingException e) {
System.err.println("Problem creating object: " + e);
}hope this will help anyone. -
Null and empty string not being the same in object?
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create or replace
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declare
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obj object;
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dbms_output.put_line(xml.getStringVal());
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Difference in Null and Empty String
Hi,
I have been wondering about the difference between Null and Empty String in Java. So I wrote a small program like this:
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try {
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Saish,
Whether you do any of the following code, the JUnit Test always passes: I mean he NOT Sign doesnt make a difference ...
assert (! "".equals(null));
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Just i have little confusion that the difference bet'n NULL String and Empty String ..
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ThankxFor the same reason I think it's okay to say "null
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Please Reply
prabhakant
Regards
Prabhakant PatilReadability.
Functionally, they are the same. From a coding standpoint, the Empty String Constant is unambiguous.
It is empty and will always be; good for initialization. Also, because you can not type a value into and Empty String Constant, someone would need to conciously replace it to set a 'default' value that is something other than NULL.
Now is the right time to use %^<%Y-%m-%dT%H:%M:%S%3uZ>T
If you don't hate time zones, you're not a real programmer.
"You are what you don't automate"
Inplaceness is synonymous with insidiousness -
Difference between String and final String
Hi friends,
This is Ramana. Can u suggest me in this Question
What is the difference between String and final String? Means
String str="hai";
final String str="hai";
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Ramana.*******REPEAT POST***********
We already answered your question why post in a different section?
http://forum.java.sun.com/thread.jspa?threadID=5201549 -
On-Screen Keyboard and a String Control
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Solved!
Go to Solution.Since you marked Jarle's message as the solution, I hope it means your happy and he's helped you solve your problem.
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Traceback B0;//the starting point of Traceback
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abstract class Traceback {
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I would like to do a program that have one string control and one string indicator, any character that I type in the string control in the same time it will be appear in another string (indicator). How can help me?
Why not use an event
Add a While Loop, inside the loop add the Event Sructure.
Now in the event structure selecd the String Controls.value change event to
react
and the new value inside the event that you get,( connect to the String
indicator box.
On Sun, 10 Aug 2003 15:58:47 -0500 (CDT), WiltonFilho wrote:
> I would like to do a program that have one string control and one
> string indicator, any character that I type in the string control in
> the same time it will be appear in another string (indicator). How can
> help me?
>
> I would like to do a program that have one string control and one
> string indicator, any character that I type in the string control in
> the same time it will be appear in another string (indicator). How can
> help me?
>
Using M2, Opera's revolutionary e-mail client: http://www.opera.com/m2/ -
Search and replace strings in a file while ignoring substrings
Hi:
I have a java program that searches and replaces strings in a file. It makes a new copy of the file, searches for a string in the copy, replaces the string and renames the new copy to the original file, thereafter deleting the copy.
Now searching for "abcd", for eg works fine, but searching for "Topabcd" and replacing it doesnot work because there is a match for "abcd" in a different search scenario. How can I modify the code such that if "abcd" is already searched and replaced then it should not be searched for again or rather search for "abcd" as entire string and not if its a substring of another string.
In the below code output, all instances of "abcd" and the ones of "Topabcd" are replaced by ABCDEFG and TopABCDEF respectively, whereas according to the desired output, "abcd" should be replaced by ABCDEFG and "Topabcd" should be replaced by REPLACEMEFIRST.
try
String find_productstring = "abcd";
String replacement_productstring = "ABCDEFG";
compsXml = new FileReader(compsLoc);
compsConfigFile = new BufferedReader(compsXml);
File compsFile =new File("file.xml");
File compsNewFile =new File("file1.xml");
BufferedWriter out =new BufferedWriter(new FileWriter("file1.xml"));
while ((compsLine = compsConfigFile.readLine()) != null)
new_compsLine =compsLine.replaceFirst(find_productstring, replacement_productstring);
out.write(new_compsLine);
out.write("\n");
out.close();
compsConfigFile.close();
compsFile.delete();
compsNewFile.renameTo(compsFile);
catch (IOException e)
//since "Topabcd" contains "abcd", which is the search above and hence the string "Topabcd" is not replaced correctly
try
String find_producttopstring = "Topabcd";
String replacement_producttopstring = "REPLACEMEFIRST";
compsXml = new FileReader(compsLoc);
compsConfigFile = new BufferedReader(compsXml);
File compsFile =new File("file.xml");
File compsNewFile =new File("file1.xml");
BufferedWriter out =new BufferedWriter(new FileWriter("file1.xml"));
while ((compsLine = compsConfigFile.readLine()) != null)
new_compsLine =compsLine.replaceFirst(find_producttopstring, replacement_producttopstring);
out.write(new_compsLine);
out.write("\n");
out.close();
compsConfigFile.close();
compsFile.delete();
compsNewFile.renameTo(compsFile);
catch (IOException e)
}Thanks a lot!Hi:
I have a java program that searches and replaces
strings in a file. It makes a new copy of the file,
searches for a string in the copy, replaces the
string and renames the new copy to the original file,
thereafter deleting the copy.
Now searching for "abcd", for eg works fine, but
searching for "Topabcd" and replacing it doesnot work
because there is a match for "abcd" in a different
search scenario. How can I modify the code such that
if "abcd" is already searched and replaced then it
should not be searched for again or rather search for
"abcd" as entire string and not if its a substring of
another string.
In the below code output, all instances of "abcd" and
the ones of "Topabcd" are replaced by ABCDEFG and
TopABCDEF respectively, whereas according to the
desired output, "abcd" should be replaced by ABCDEFG
and "Topabcd" should be replaced by REPLACEMEFIRST.
try
String find_productstring = "abcd";
String replacement_productstring = "ABCDEFG";
compsXml = new FileReader(compsLoc);
compsConfigFile = new
BufferedReader(compsXml);
File compsFile =new File("file.xml");
File compsNewFile =new File("file1.xml");
BufferedWriter out =new BufferedWriter(new
FileWriter("file1.xml"));
while ((compsLine =
compsConfigFile.readLine()) != null)
new_compsLine
=compsLine.replaceFirst(find_productstring,
replacement_productstring);
out.write(new_compsLine);
out.write("\n");
out.close();
compsConfigFile.close();
compsFile.delete();
compsNewFile.renameTo(compsFile);
catch (IOException e)
//since "Topabcd" contains "abcd", which is
the search above and hence the string "Topabcd" is
not replaced correctly
try
String find_producttopstring = "Topabcd";
String replacement_producttopstring =
topstring = "REPLACEMEFIRST";
compsXml = new FileReader(compsLoc);
compsConfigFile = new
gFile = new BufferedReader(compsXml);
File compsFile =new File("file.xml");
File compsNewFile =new File("file1.xml");
BufferedWriter out =new BufferedWriter(new
dWriter(new FileWriter("file1.xml"));
while ((compsLine =
compsLine = compsConfigFile.readLine()) != null)
new_compsLine
new_compsLine
=compsLine.replaceFirst(find_producttopstring,
replacement_producttopstring);
out.write(new_compsLine);
out.write("\n");
out.close();
compsConfigFile.close();
compsFile.delete();
compsNewFile.renameTo(compsFile);
catch (IOException e)
Thanks a lot!I tried the matches(...) method but it doesnt seem to work.
while ((compsLine = compsConfigFile.readLine()) != null)
if(compsLine.matches(find_productstring))
System.out.println("Exact match is found for abcd");
new_compsLine =compsLine.replaceFirst(find_productstring, replacement_productstring);
out.write(new_compsLine);
out.write("\n");
else
System.out.println("Exact match is not found for abcd");
out.write(compsLine);
out.write("\n"); -
Search and replace string formatting
Hi,
I am trying to do a search and replace formatting of a string.
In the example I am looking for string "PASSED" but it must also start with usbflash and some number + PASSED.
I can't get the format to have a number from 1-99. The number of replacements should add up to 6 in this case. I have tried with \d for any number, and I also tried [1-99].
Solved!
Go to Solution.Right click on the Search And Replace String function. There is an option to use Regular Expressions. Then give this a try.
EDIT: You will need to set the Replace All input to TRUE.
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Attachments:
Match Pattern.png 12 KB -
Search and replace string problems
Hi to all,
I have problem with Search and replace string function. It shows me a wrong Value (Number) from 15 to 100 is everything OK (15=0, 30=1, 45=2, 100=3), but after 100 ........
Take look in VI and if you have any ideas post them please
THX
Igor
Attachments:
indexing.vi 10 KBthere will be no 15115 string, but 15 or 115 and 15 is 0, 115 is 4. Anyway, i have changed string input format and now its working THX for your help
Attachments:
indexing.vi 10 KB -
Search and Replace String throwing the wrong error message with regexp?
This came up in a LAVA thread, and I'm not sure if there's a bug here or not. When using Search and Replace string, and using a regular expression of [(G[b|i])], LabVIEW throws error -4622, "There is an unmatched parenthesis in a regular expression." There are obviously no unmatched parenthesis in that expression, so it seems to me that the wrong error is being thrown. I'm just not sure if that's a syntactically valid regexp. The problem seems to be with nesting [ ]'s inside ( )'s inside [ ]'s. I've tried a couple of regexp resources on the Web, and one suggests it's valid, while the other seems to think it isn't.
Message Edited by eaolson on 03-13-2007 10:33 AM
Attachments:
ATML_StandardUnit2.vi 10 KB
regexp.png 5 KBadambrewster wrote:
I think your regexp is invalid.
In regexps, brackets are not the same as parentheses. Parens are for grouping, while brackets are for matching one of a class of characters. Brackets can not be nested.
If the regexp is replaced with [G[bi]], there is no error, so it's not a matter of nested brackets. I couldn't find anything on the PCRE man page that forbids nested brackets specifically, but it makes sense.
Your expression "[(G[bi])]", therefore parses as a character class which matches '(', 'G', '[', 'b', or 'i' followed by an unmatched paren, and an unmatched bracket.
I don't believe that's the case. Replace the regexp with [(Gbi)], and the error goes away. So it's not a matter of the '(' being literal, and then encountering a ')' without a matching '('.
daveTW wrote:
what string exactly you want to replace? I think the round braces are not right in this case, since they mark partial matches which are given back by "match regular expression". But you don't want to extract parts of the string, you want to replace them (or delete, with empty <replace string>). So if you leave the outer [( ... )] then your RegEx means all strings with either "Gb" or "Gi".
It's not my regular expression. A poster at LAVA was having problems with one of his (a truly frightening one), and this seemed to be the element that was causing the problem. I'm pretty sure that the originator of the regexp meant to use G(b|i), which seems like a complicated way of matching "Gb" or "Gi", if you ask me.
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