Operator precedence query ( && ,||)

Question

Hi,
Please take a look at the following simple program.
public class C {
static boolean a,b,c;
public static void main(String[] args){
     boolean x= (a=true) || (b=true) && (c=true);
     System.out.print(a+","+b+","+ c);
The output of this program is true,false,false. Now this has got me all confused.
The result I expected was true,true,true. This is the order of operation that I expected
1) All operations within brackets are executed first .So this should set a=true,b=true and c=true.
2) Next the && operation is executed .
3)Lastly the || is executed
Could someone please give explain why (a=true) is executed and the remaining parts are not executed?
Appreciate your help. Thanks!

Answer 1

To amplify on why:
You initialized the variables as false: static boolean a,b,c;
Then, as previously noted, the || operator did not evaluate the last 2 conditions.
To get what you expected, use the non-short-circuiting versions:
Opr     Use                Returns true if
&&      op1 && op2      op1 and op2 are both true, conditionally evaluates op2
||      op1 || op2      either op1 or op2 is true, conditionally evaluates op2
&      op1 & op2      op1 and op2 are both true, always evaluates op1 and op2
|      op1 | op2      either op1 or op2 is true, always evaluates op1 and op2