Oracle 10g - To find the corresponding record for a certain row

Question

Hi all,
The scenario is like this - Suppose I've got a table with 100+ columns. For a certain row inside, I need to find its corresponding record which is in the same table. The way how I define "corresponding" here is - these two rows should be identical in all attributes but only different in one column, say "id" (primary key).
So how could I achieve this? What I can think of is to fetch all columns of the first row into some pre-defined variables, then use a cursor to loop the table and match the values of the columns of each row to those variables. But given that we've got 100+ rows in the table, this solution doesn't look practical?
Any advises are greatly appreciated. Thanks.

Answer 1

something to play with as Solomon suggested (use some other string aggregation technique if you're not 11g yet)
you'll have to adjust the column_list accordingly
select 'select ' || column_list ||
       ' from ' || :table_name ||
       ' group by ' || column_list ||
       ' having count(*) > 1' the_sql
  from (select listagg(column_name,',') within group (order by column_id) column_list
          from user_tab_cols
         where table_name = :table_name
       )Regards
Etbin
Edited by: Etbin on 25.12.2011 16:53
Sorry, I'd better leave the forum: the title says you're 10g :(
Providing a link for replacing listagg: http://www.sqlsnippets.com/en/topic-11787.html