Orderby jpa aritmetic exp in order by

Question

hello
i have aquestion i have this query in sql
select R.* from REOFFER R,.PROPERTY P where P.propertyId=R.propertyId order by (R.Precio/P.areaConstruction)
in mysql and run ok, but this equivalent query in jpa
select distinct object(o) from Table as o order by (o.precio/o.propertyId.areaConstruction)
BUT SAYS
Exception Description: Syntax error parsing the query [select distinct object(o) from Reoffer as o  where o.propertyId.suburbId.cityId=:city order by (o.precio/o.propertyId.areaConstruction)], line 1, column 96: syntax error at [(].
Internal Exception: line 1:96: expecting IDENT, found '('
at oracle.toplink.essentials.exceptions.EJBQLException.syntaxErrorAt(EJBQLException.java:379)
at oracle.toplink.essentials.internal.parsing.ejbql.EJBQLParser.handleANTLRException(EJBQLParser.java:335)
at oracle.toplink.essentials.internal.parsing.ejbql.EJBQLParser.addError(EJBQLParser.java:278)
is posible have a aritmethic exp in jpa in the order by?
thanks

Answer 1

Hi,
When you use a local variable in a cursor, it's as if you had hard-coded a literal in its place, so you can't use a variable for a column name.
If you know all the possible values of p_orderby, you can do something like this:
ORDER BY  TRIM ( CASE  p_orderby
               WHEN  'DESC'     THEN  plano.desc
               WHEN  'VALUE'     THEN  plano.value
           END
            ) ASC;If you don't know all the possible values, you could use dynamic SQL.
By the way,
TRIM (x)returns the same results as
LTRIM ( RTRIM (x))