Outer join two tables with two keys

Hi,
I have a question regard outer join,
I have table A (Aid, ADesc), Table B(Bid, Bdesc), and Table C (Aid, Bid, Cdesc)
There is data in Table A and B, but Table C is empty
I want to outer join C with A and B with below query
select ADesc,Bdesc, Cdest
from A, B, C
where A.Aid=C.Aid(+) and B.Bid(+)=C.Bid
and A.Aid='XXX' and B.Bid(+)='ZZZ'
The query result show only data in column Adesc , but column BDesc is empty even though there are some data in table B.
How should the query been modified to correctly show ADESC and Bdesc.
Thanks
Vincent

Guess the below should work:
Case when records are available in Table C:
with a as
(select 'XXX' aid, 'adesc' adesc from dual),
b as
(select 'ZZZ' bid, 'bdesc' bdesc from dual),
c as
(select 'XXX' aid, 'ZZZ' bid, 'cdest' cdest from dual where 1 = 1)
select ADesc,Bdesc, C1.Cdest
from
A LEFT OUTER JOIN C c1 ON (A.AID = C1.AID AND A.AID = 'XXX'),
B LEFT OUTER JOIN C C2 ON (B.BID = C2.BID AND B.BID = 'ZZZ');
Output:
"ADESC"     "BDESC"     "CDEST"
"adesc"     "bdesc"     "cdest"Case when table C is empty:
with a as
(select 'XXX' aid, 'adesc' adesc from dual),
b as
(select 'ZZZ' bid, 'bdesc' bdesc from dual),
c as
(select 'XXX' aid, 'ZZZ' bid, 'cdest' cdest from dual where 1 = 2)
select ADesc,Bdesc, C1.Cdest
from
A LEFT OUTER JOIN C c1 ON (A.AID = C1.AID AND A.AID = 'XXX'),
B LEFT OUTER JOIN C C2 ON (B.BID = C2.BID AND B.BID = 'ZZZ');
"ADESC"     "BDESC"     "CDEST"
"adesc"     "bdesc"     ""

Similar Messages

Left outer join 3 tables with where-statement

Hi folks,
I hope you can understand (and maybe solve) my problem.
Generally I try to left outer join three tables. The third table is used for a WHERE-statement.
The three table structures are the following:
table 1 (user)
user1 | key
table 2 (detail)
key | ID
table 3 (header)
ID | user2
...and I want to achieve the following structure (as example filled with data):
user | key | ID
|-----|----
xy    | a    | 001
xy    | b    | #
z     | b     | #
The clue ist the usage of the third table. I need the table to set user1 and user2 equal (WHERE) but there are two problems:
1) Obviously I can't left outer join two tables with each other. In this case I already used the 'key' of table 1 to join it with the 'key' of table 2. So I can't left outer join the 'ID' of table 2 with the 'ID' of table 3. Error message that I can only left outer join a table once. Any proposals?
2) I have to include a WHERE to equal user1 with user2. But I am not allowed to use the user2 from table 3 because of the left outer join.
I tried this coding:
SELECT auser1 akey b~id INTO TABLE itab FROM ( table1 AS a
LEFT OUTER JOIN table2 AS b ON akey = bkey )
LEFT OUTER JOIN table3 AS c ON bID = cID )
WHERE auser1 = cuser2.
I would really appreciate your help.
Regards
MrclSpdl

IF you want to join a DB table with an internal table, you need to use the 'FOR ALL ENTRIES' statement.
select dbfields
into table itab2
from dbtab
for all entries in itab
where dbfield1 = itab-field1.
This will get you a second internal table with all the corresponding data for the first selection. You can then join them with a loop through the first table and a read table on the second table (for 1 - 1 relation) or a nested loop statement on both tables (for 1 - N relation). Make itab a hashed table when using read table with key, use a sorted table if you need to loop without key access.
Regards,
Freek

Join fact table with higher dimension level

how do i join fact tables with higher dimension levels with discoverer?
fact with detail at level C
measure X
dimension with
D->C->B->A
E->C
level
A B C
1------1------1
2------2------1
3------2------1
join between fact X and dimension level C
X=3*C because of sum(X) in discoverer and 3xC in dimension
is there a way to get correct values for X without creating a dimension like
D->C
E->

another way of asking this is whether you can create a summary table in Discoverer at a higher level than a dimension's fundamental grain. In other words - the summary examples in the documentation all describe leaving out one or more of your dimensions... they are either left in or completely taken out. But, some of the most effective summarization occurs when you summarize daily data to a monthly level. Assuming that I have a sales table (at a daily level, and a key value sales_date), and a table date_dim (primary key sales_date), I would like to create a summary sales_month_summary where the sales are grouped on month_year (which is a field in the sales_date table).
How is this done? I suspect that we can't use the date_dim table with the summary (due to the problems noted by the poster above). Do we have to create another table "month_dim"? Do we have to fold all of the desired date attributes (month, quarter, year) into the summary? Obviously we'd like to re-use all of the pertinent already existing date items (quarter, month, year, etc.), not recreate them over again, which would result in essentially two sets of items in the EUL. [One used for this month summary, and another used for the detail.]
I searched the forum - someone asked this same question back in 2000 - there was no answer provided.
The only other thought I have is to "snowflake" the date_dim into two tables and two folders, one at a date level, another at the month level. Then the detail tables can connect to date_dim (which is linked to month_dim), while the summary data can connect directly to month_dim.

How to insert record in child table with foreign key

Hi,
I am using Jdeveloper 11.1.2.0. I have two master table one child table.
How to insert and update a record in child table with foreign key ?
I have created VO based on three EO(one eo is updatable other two eo are references) by using joined query.
Thanks in Advance
Edited by: 890233 on Dec 24, 2011 10:40 PM

... And here is the example to insert using sequenceimpl by getting the primary key of the master record and insert master and detail together.
Re: Unable to insert a new row with a sequence generated column id
-Arun

Double outer join on table

Hi
Let's say I have three tables ORDERS, PRODUCT and CLIENT. I want a query that will give me all PRODUCT and CLIENT combinations and the total sum of orders if it has one. If I try to do this:
select P.NAME, C.NAME, SUM(O.AMOUNT)
from PRODUCT P, CLIENT C, ORDER O
where P.ID = O.PRODUCT_ID(+) and
C.ID = O.CLIENT_ID(+)
I get an error where I cannot double outer join a table.
Any ideas?

3360 wrote:
BluShadow wrote:
and ANSI allows a little more in those terms than regular oracle syntax.It is different, but it cannot do anything that regular equi-joins cannot do. In most cases the optimizer converts ANSI joins to regular joins for execution, and this additional conversion has been subject to numerous bugs.ANSI does allow for doing things that regular Oracle syntax cannot do.
Here's an ANSI way to do it if you only want to see those client/product combinations that exist in orders table:
SQL> with product as (
2     select 101 id, 'Product 1' name from dual union all
3     select 102 id, 'Product 2' name from dual union all
4     select 103 id, 'Product 3' name from dual
5 ), client as (
6     select 11 id, 'Client 1' name from dual union all
7     select 12 id, 'Client 2' name from dual
8 ), orders as (
9     select 11 client_id, 101 product_id, 10 amount from dual union all
10     select 11 client_id, 103 product_id, 30 amount from dual union all
11     select 12 client_id, 102 product_id, 20 amount from dual union all
12     select 12 client_id, 102 product_id, 20 amount from dual
13 )
14 --
15 -- end-of-test-data
16 --
17 select p.name
18       , c.name
19       , sum(o.amount)
20    from orders o
21    left outer join product p
22         on p.id = o.product_id
23    left outer join client c
24         on c.id = o.client_id
25   group by
26         p.name
27       , c.name
28   order by
29         p.name
30       , c.name
31 /
NAME      NAME     SUM(O.AMOUNT)
Product 1 Client 1            10
Product 2 Client 2            40
Product 3 Client 1            30(If the datamodel is good with product_id being a foreign key of product.id and the same with client, then outer join is not really necessary, I know. But for the sake of argument assume bad datamodel that needs outer join ;-) )
The above ANSI can be written in regular Oracle syntax as well:
SQL> with product as (
2     select 101 id, 'Product 1' name from dual union all
3     select 102 id, 'Product 2' name from dual union all
4     select 103 id, 'Product 3' name from dual
5 ), client as (
6     select 11 id, 'Client 1' name from dual union all
7     select 12 id, 'Client 2' name from dual
8 ), orders as (
9     select 11 client_id, 101 product_id, 10 amount from dual union all
10     select 11 client_id, 103 product_id, 30 amount from dual union all
11     select 12 client_id, 102 product_id, 20 amount from dual union all
12     select 12 client_id, 102 product_id, 20 amount from dual
13 )
14 --
15 -- end-of-test-data
16 --
17 select p.name
18       , c.name
19       , sum(o.amount)
20    from orders o, product p, client c
21   where p.id(+) = o.product_id
22     and c.id(+) = o.client_id
23   group by
24         p.name
25       , c.name
26   order by
27         p.name
28       , c.name
29 /
NAME      NAME     SUM(O.AMOUNT)
Product 1 Client 1            10
Product 2 Client 2            40
Product 3 Client 1            30Many old Oracle coders will probably state that this syntax is much easier. For a simple case like this I find both ways easy. But I have complex cases where I much prefer ANSI where I can easily distinguish join predicates from filter predicates. It is a matter of opinion, I know ;-)
But if we then take the original post as a literal specification, that we want all combinations of products and clients and then the sum of order amount if it exists, null otherwise.
This can be written easily in ANSI notation:
SQL> with product as (
2     select 101 id, 'Product 1' name from dual union all
3     select 102 id, 'Product 2' name from dual union all
4     select 103 id, 'Product 3' name from dual
5 ), client as (
6     select 11 id, 'Client 1' name from dual union all
7     select 12 id, 'Client 2' name from dual
8 ), orders as (
9     select 11 client_id, 101 product_id, 10 amount from dual union all
10     select 11 client_id, 103 product_id, 30 amount from dual union all
11     select 12 client_id, 102 product_id, 20 amount from dual union all
12     select 12 client_id, 102 product_id, 20 amount from dual
13 )
14 --
15 -- end-of-test-data
16 --
17 select p.name
18       , c.name
19       , sum(o.amount)
20    from product p
21   cross join client c
22    left outer join orders o
23         on o.product_id = p.id
24        and o.client_id = c.id
25   group by
26         p.name
27       , c.name
28   order by
29         p.name
30       , c.name
31 /
NAME      NAME     SUM(O.AMOUNT)
Product 1 Client 1            10
Product 1 Client 2
Product 2 Client 1
Product 2 Client 2            40
Product 3 Client 1            30
Product 3 Client 2
6 rows selected.ANSI notation allows outer join with more than one table.
Regular Oracle syntax could only do this by creating an inline view of the cartesian join and then outer joining orders with the inline view. Doable, but not as nice (IMHO) as the ANSI method for a case like this ;-)

Best way to outer join a table that is doing a sub query

RDBMS : 11.1.0.7.0
Hello,
What is the best way to outer join a table that is doing a sub query? This is a common scenario in EBS for the date tracked tables.
SELECT papf.full_name, fu.description
FROM fnd_user fu
      ,per_all_people_f papf
WHERE fu.user_id = 1772
   AND fu.employee_id = papf.person_id(+)
   AND papf.effective_start_date = (SELECT MAX( per1.effective_start_date )
                                      FROM per_all_people_f per1
                                     WHERE per1.person_id = papf.person_id)Output:
No output produced because the outer join cannot be done on the sub queryIn this case I did a query in the FROM clause. Is this my best option?
SELECT papf.full_name, fu.description
FROM fnd_user fu
      ,(SELECT full_name, person_id
          FROM per_all_people_f papf
         WHERE papf.effective_start_date = (SELECT MAX( per1.effective_start_date )
                                              FROM per_all_people_f per1
                                             WHERE per1.person_id = papf.person_id)) papf
WHERE fu.user_id = 1772
   AND fu.employee_id = papf.person_id(+)Output:
FULL_NAME     DESCRIPTION
{null}            John DoeThanks,
--Johnnie

Hi,
BrendanP wrote:
... See the adjacent thread for the other with Row_Number().Do you mean {message:id=10564772} ? Which threads are adjacent is always changing. Post a link.
I think RANK suits the requirements better than ROW_NUMBER:
WITH    all_matches     AS
     SELECT papf.full_name
     ,      fu.description
     ,     RANK () OVER ( PARTITION BY papf.person_id
                           ORDER BY          papf.effective_start_date     DESC
                    )           AS r_num
     FROM             fnd_user             fu
     LEFT OUTER JOIN      per_all_people_f papf ON fu.employee_id = papf.person_id
     WHERE   fu.user_id = 1772
SELECT     full_name
,     description
FROM     all_matches
WHERE     r_num     = 1
Johnnie: I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) for all tables involved, and also post the results you want from that data.
See the forum FAQ {message:id=9360002}

Join 2 tables with 2 criteria

hello
i'm trying to join 2 tables with 2 criteria
one criteria is "numero de matricule" and the other is "date"
in one table i have many times the same "matricule" it depends of "date de validité" validity date
ex table 1
n°mat - periode - montant
1 -31-12-2013 - 100
table2
n°mat -periode - nom - adresse
1 -
31-12-2013 - gerard - 12 RUE X
1- 31/12/2012-GERARD - 2AVENUE Z
how can i join those tow table
thak you for your help, i'm a french beginner

select *
from table1 as a
join table2 as b
on a.n°mat = b.n°mat
and a.periode = b.periode
sqldevelop.wordpress.com
Saeid, check this out and reply there if you're interested:
http://social.technet.microsoft.com/Forums/en-US/a2e22d61-7c32-43f2-900e-d9d6325fa26d/needed-more-power-pivot-answerers?forum=sqlkjpowerpivotforexcel
Thank you for all your contributions!
Ed Price, Azure & Power BI Customer Program Manager (Blog,
Small Basic,
Wiki Ninjas,
Wiki)
Answer an interesting question?
Create a wiki article about it!

Outer join OJ syntax with JDBC drivers

Hello,
I'm facing a problem with CrystalReports 2008 and jdbc connection.
Crystal genrates OJ syntax (as below) which cannot be interpreted by the Database.
SELECT "T1"."T1D", "T2"."T2D", "T3"."T3D"
FROM   {oj ("PUBLIC"."PUBLIC"."T3" "T3" LEFT OUTER JOIN "PUBLIC"."PUBLIC"."T2" "T2" ON "T3"."T2K"="T2"."T2K") LEFT OUTER JOIN "PUBLIC"."PUBLIC"."T1" "T1" ON "T2"."T1K"="T1"."T1K"}
Prensently my database is HSQLDB.
After browsing several post about ODBC, I tried to change the registry, introducing a new key
HKEY_CURRENT_USER\Software\Business Objects\Suite 12.0\Crystal Reports\DatabaseOptions\NoOuterJoinEscSeq=myodbc3,hsqldb
It did not change anything.
Now, I suppose Crystal queries the database driver for its capabilities.
This is done by a DatabaseMetaData object which implements several methods.
In case of hsqldb, here is what the driver answers:
     public boolean supportsMinimumSQLGrammar() throws SQLException {
          return false;
     public boolean supportsCoreSQLGrammar() throws SQLException {
          return true;
     public boolean supportsExtendedSQLGrammar() throws SQLException {
          return false;
     public boolean supportsANSI92EntryLevelSQL() throws SQLException {
          return false;
     public boolean supportsANSI92IntermediateSQL() throws SQLException {
          return false;
     public boolean supportsANSI92FullSQL() throws SQLException {
          return false;
     public boolean supportsIntegrityEnhancementFacility() throws SQLException {
          return true;
     public boolean supportsOuterJoins() throws SQLException {
          return true;
     public boolean supportsFullOuterJoins() throws SQLException {
          return false;
     public boolean supportsLimitedOuterJoins() throws SQLException {
          return true;
How can I tell Crystal to stop using the OJ syntax ?
Thank you and kind regards.
Alain

Hi Alaine,
You are correct, CR does query the driver to get what it requires to use for outer join syntax. The registry key will not work for this driver. It's the driver meta layer telling CR to use the oj syntax and is dependent on the driver being configured.
Not sure if you can but start by trying to alter these settings if you can:
public boolean supportsOuterJoins() throws SQLException {
return true;
public boolean supportsFullOuterJoins() throws SQLException {
return false;
I would think both should be reversed, true to false and false to true.
Before you do that though go to our download page and install Service Pack 2, it may by a CR issue and the patch may have fixed the problem.
If it doesn't I suggest asking this on the HSQLDB forum to see how to alter those option. CR follows the JDBC Type 4 Standards. You may want to see if Sun has a HSQLDB JDBC driver also.
Thank you
Don

Maintenance View for custom table with foreign key relationship

Hi Folks,
I have created a custom table with foreign key relationship with other check tables. I want to create a maintenance view / tablemaintenance generator. What all things I need to take care for the foreign keys related fields while creating the maintenance view / tablemaintenance generator.
Regards,
santosh

Hi,
You do not have to do anything explicitely for the foreign key relationships in the table maintainance generator.
Create the table maintainance generator via SE11 and it will take care of all teh foreign key checks by itself.
Regards,
Ankur Parab

Joining a table with all_tab_columns

How is it possible to join a table with the tab_columns?
The query im trying to establish is that in my table they are 12 columns with months names. So under an input variable im trying to return the required values with the selected months. The only way i could think of to get the months to connect with the tab_columns table.
Any suggestion is really appreciated
SELECT bust,
Sum(jan) JAN,
Sum(feb) FEB,
Sum(mar) MAR,
Sum(apr) APR,
Sum(may) MAY,
Sum(jun) JUN,
Sum(jul) JUL,
Sum(aug) AUG,
Sum(sep) SEP,
Sum(oct) OCT,
Sum(nov) NOV,
Sum(DEC) DECC
FROM budget a,all_tab_columns b
WHERE vsl_code = 4602
AND code = 1
AND year=2013
AND account_code='30'
AND b.table_name='BUDGET'
AND b.column_name IN
                     (SELECT column_name
                      FROM (SELECT Column_name, ROWNUM r
                                    FROM all_tab_columns b
                                    WHERE table_name = 'BUDGET'
                                    AND Column_id BETWEEN 3 AND 14
                                    ORDER BY column_id)
                      WHERE r BETWEEN 2 AND 3 ) --Returns February,March
group by bust;

Sorry, I don't understand what you're trying to do or why you think you need to join to all_tab_columns. Perhaps you could post the definition of the budget table, some sample data, and the results you're hoping to see.
Without that, I don't see why you can't just do this:
SELECT bust,
Sum(jan) JAN,
Sum(feb) FEB,
Sum(mar) MAR,
Sum(apr) APR,
Sum(may) MAY,
Sum(jun) JUN,
Sum(jul) JUL,
Sum(aug) AUG,
Sum(sep) SEP,
Sum(oct) OCT,
Sum(nov) NOV,
Sum(DEC) DECC
FROM budget a
WHERE vsl_code = 4602
AND code = 1
AND year=2013
AND account_code='30'
group by bust;

Join the Table with View

Hi,
My doubt is can I join the table with view in the below where clause condition in the query. If yes, the below query will take 4 hrs to execute it. Can I do the below query to write as simplest?
SELECT *
FROM uabpymt p, uavlsum l
WHERE uabpymt_appl_ind = 'N'
   AND uabpymt_amount > 5
   AND l.uavlsum_balance < 0
   AND l.uavlsum_cust_code = p.uabpymt_cust_code
   AND l.uavlsum_prem_code = p.uabpymt_prem_codeuavlsum ---view
uabpymt ---table
The view script below:
CREATE OR REPLACE VIEW UAVLSUM
(UAVLSUM_CUST_CODE, UAVLSUM_PREM_CODE, UAVLSUM_AMOUNT, UAVLSUM_BALANCE)
AS
SELECT cust_code,
       prem_code,
       SUM(amount),
       SUM(balance)
FROM (
SELECT uabopen_cust_code cust_code,
       uabopen_prem_code prem_code,
       uabopen_billed_chg amount,
       uabopen_balance balance
FROM   uimsmgr.uabopen
UNION ALL
SELECT uabpymt_cust_code,
       uabpymt_prem_code,
       uabpymt_amount * -1,
       uabpymt_balance * -1
FROM   uimsmgr.uabpymt
UNION ALL
SELECT uabadje_cust_code,
       uabadje_prem_code,
       uabadje_balance,
       to_number(0)
FROM   uimsmgr.uabadje
WHERE uabadje_balance <> 0)
GROUP BY cust_code,
         prem_code

Find the below explain plan output which we get from the execute the query
STATEMENT_ID            TIMESTAMP     REMARKS        OPERATION     OPTIONS          OBJECT_NODE OBJECT_OWNER            OBJECT_NAME            OBJECT_INSTANCE      OBJECT_TYPE OPTIMIZER
            16/01/2009 05:57:24                   SELECT STATEMENT                                                                                                                           RULE
            16/01/2009 05:57:24                   FILTER
            16/01/2009 05:57:24                   SORT           GROUP BY
            16/01/2009 05:57:24                   TABLE ACCESS           BY INDEX ROWID                     UIMSMGR                     UABPYMT                                1
            16/01/2009 05:57:24                   NESTED LOOPS
            16/01/2009 05:57:24                   VIEW                                                   UIMSMGR                                                         3
            16/01/2009 05:57:24                   UNION-ALL
            16/01/2009 05:57:24                   TABLE ACCESS           FULL                            UIMSMGR                     UABOPEN                                    4
            16/01/2009 05:57:24                   TABLE ACCESS           FULL                            UIMSMGR                     UABPYMT                                    5
            16/01/2009 05:57:24                   TABLE ACCESS           FULL                            UIMSMGR                     UABADJE                                    6
            16/01/2009 05:57:24                   INDEX       RANGE SCAN                                   UIMSMGR                     UABPYMT_CUST_PREM_INDEX                        NON-UNIQUE
Index column:
Table name :UABPYMT
Column Name
UABPYMT_APPL_IND
UABPYMT_APPROVED_IND
UABPYMT_PYMT_DATE
UABPYMT_SOURCE
UABPYMT_ORIGIN
UABPYMT_CUST_CODE
UABPYMT_PREM_CODE
UABPYMT_PYMT_DATE
UABPYMT_AR_TRANS
UABPYMT_GL_IND
UABPYMT_GL_POST_DATE
UABPYMT_AR_TRANS

Join Istore table with AR tables

Hi Gurus,
How to join ibe_msites_b table with AR table. I am trying to get list of all customers from different mini sites. These are the AR tables i am using
HZ_Cust_Accounts
HZ_Parties
Regards,

The following query should give you resullts for B2C. Change the query based on your requirement incase if you want it for B2B. Please note that I haven't added alll the conditions. This should be your starting point.
Hope this helps,
RK
SELECT imt.msite_name,
hp.party_name
FROM jtf_um_subscription_reg jusr,
jtf_um_subscription_resp jure,
fnd_responsibility fr,
ibe_msite_resps_b imrb,
ibe_msites_tl imt,
fnd_user fu,
hz_parties hp
WHERE jusr.subscription_id = jure.subscription_id
AND jure.responsibility_key = fr.responsibility_key
AND fr.responsibility_id = imrb.responsibility_id
AND imrb.msite_id = imt.msite_id
AND imt.language = USERENV('LANG')
AND fu.user_id =jusr.user_id
AND fu.person_party_id = hp.party_id

Joining 3 tables with null values

Hi,
I have three tables that have varying data in. I want to write a query which will list all three in the result set, but when one of the tables doesn't have a row, write in No Value.
I will be intending on joining the tables with account numbers. What will be the syntax of a join with three tables where I am not sure which table will have null values?
Thanks...

Something like
select nvl(a.id,'No Value'), nvl(b.id, 'No Value'), nvl(C.id, 'No Value')
   from (select id from t1) a,
              (select id from t2) b,
              (select id from t3) c
where a.id = b.id(+)
      and a.id = c.id(+)
Hi,
I have three tables that have varying data in. I want to write a query which will list all three in the result set, but when one of the tables doesn't have a row, write in No Value.
I will be intending on joining the tables with account numbers. What will be the syntax of a join with three tables where I am not sure which table will have null values?
Thanks...

Outer join two tables with query search record attached to both tables

When I create a query with two tables that have query search records attached with outer join, PS seems to do a natural join (cartesian). We are on PT8.48.
Is there a workaround for this issue. I do not want to remove query search record on either of the tables.
I am trying to create an Emergency contact report. I am using two tables PS_EMPLOYEES and PS_EMERGENCY_CNTCT. Here is the sql PeopleSoft query generated when I did Left outer Join.
Query SQL:
SELECT A.EMPLID, A.NAME, A.ADDRESS1, A.CITY, B.PRIMARY_CONTACT, B.ADDRESS1, B.CITY, B.STATE, B.POSTAL, B.RELATIONSHIP, A.DEPTID, A.JOBCODE, A.COMPANY, A.EMPL_TYPE
FROM (PS_EMPLOYEES A LEFT OUTER JOIN PS_EMERGENCY_CNTCT B ON A.EMPLID = B.EMPLID ), PS_EMPLMT_SRCH_QRY A1, PS_PERS_SRCH_QRY B1
WHERE A.EMPLID = A1.EMPLID
AND A.EMPL_RCD = A1.EMPL_RCD
AND A1.OPRID = 'SREESR'
AND (B.EMPLID = B1.EMPLID OR B.EMPLID IS NULL )
AND B1.OPRID = 'PS'
Appreciate any help.

I think there are fixes for this issue in later tools releases (Report ID 1544345000). I'm not sure about 8.48, but you might try the workaround documented in
E-QR: Left Outer Joins with Security Records are returning unexpected results [ID 651252.1]
on Oracle Support.
Regards,
Bob

Outer Join Two tables

I got two Tables.APPROVAL_ROUTING_TAB and doc_issue_tab where APPROVAL_ROUTING_TAB has more rows. I need to do the join two tables such that All the rows in APPROVAL_ROUTING_TAB should be displayed ( more rows) but still connect with the doc_issue_tab. I did an outer join syntax failed.
What is the correct syntax for this.
Key_ref takes the following pattern "DOC_CLASS=PR_CLASS_1^DOC_NO=1000007^DOC_REV=A3^DOC_SHEET=1^"
SELECT
ar.line_no LINE_NO,
ar.step_no STEP_NO,
ar.lu_name LU_NAME,
ar.key_ref KEY_REF,
ar.description DESCRIPTION,
di.status STATUS
FROM APPROVAL_ROUTING_TAB ar, doc_issue_tab di
WHERE
ar.key_ref = 'DOC_CLASS='||di.doc_class||'^DOC_NO='||di.doc_no||'^DOC_REV='||di.doc_rev||'^DOC_SHEET='||di.doc_sheet||'^') (+)
Thansk in advance
Prash

Other options include:
with t1 as (select 1 id, 'd1=fred^d2=john^d3=bob^' col2 from dual union all
            select 1 id, 'd1=fred^d2=john^d3=george' col2 from dual),
     t2 as (select 'fred' d1, 'john' d2, 'bob' d3 from dual union all
            select 'jim' d1, 'john' d2, 'bob' d3 from dual)
select *
from   t1, (select t2.*, 'd1='||d1||'^d2='||d2||'^d3='||d3||'^' full_col
            from t2) t3
where t1.col2 = t3.full_col (+);
        ID COL2                      D1   D2   D3 FULL_COL
         1 d1=fred^d2=john^d3=bob^   fred john bob d1=fred^d2=john^d3=bob^
         1 d1=fred^d2=john^d3=george
with t1 as (select 1 id, 'd1=fred^d2=john^d3=bob^' col2 from dual union all
            select 1 id, 'd1=fred^d2=john^d3=george' col2 from dual),
     t2 as (select 'fred' d1, 'john' d2, 'bob' d3 from dual union all
            select 'jim' d1, 'john' d2, 'bob' d3 from dual)
select *
from   t1 left outer join t2 on (t1.col2 = 'd1='||d1||'^d2='||d2||'^d3='||d3||'^');
        ID COL2                      D1   D2   D3
         1 d1=fred^d2=john^d3=bob^   fred john bob
         1 d1=fred^d2=john^d3=george

Outer join two tables with two keys

Similar Messages

Maybe you are looking for