Parse file without xml specification or document element

Question

I have a large (600mb) log file that is in xml format but it does not have an xml specification and has no document element.
file looks like this:
<message>...</message>
<message>...</message>
<!-- ... many many many more <message> elements -->
<message>...</message>
<message>...</message>
I have written a class that overrides the SAX DefaultHandler but now want to be able to parse the document without having to add the xml spec and document element manually.
I've thought about writing a subclass of FileReader that adds the xml specification and document element before reading physical file but would also need to add closing document element at end of file.
Is there a simpler way?

Answer 1

Hi,
There is another way around the problem of adding a missing root node. This involves adding an extra DTD file and a xml file, like this one:
<?xml version='1.0' encoding='UTF-8' standalone="no"?>
<!DOCTYPE messageSet SYSTEM "logfile.dtd"
[<!ENTITY data SYSTEM "logfile.xml">]
>
<messageSet>
&data;
</messageSet>
This file "includes" the logfie.xml, as an external entity, with your messages as child nodes of element messageSet.
In your program you refer to this xml file when parsing the messages.