Parser error: XSD 2015 with regular expression

The Oracle java parser is rejecting a document with the following error message:
SD-2015: (Error) Invalid facet 'pattern' in element 'simpleType'I'm not excatly certain what the parser is objecting to, because the error messages aren't document (subject of a different rant). Now the thing it's rejecting is this:
<xsd:simpleType name="TelCountryCodeType">
             <xsd:restriction base="xsd:string">
                     <xsd:pattern value="[0-9]{1,3}"/>
                </xsd:restriction>
        </xsd:simpleType>So is it choking because it doesn't like regular or for some other reason?
TIA, APC

Thanks - the code:
String regExp = new String ("\"(http://)([.[^\"]]*)\"");seems to work. (I awarded you the duke dollars from your first post, becaues that was the "ahha" moment. )
Thanks!!!

Similar Messages

Parsing href=".." with regular expression's

I need to get all the hyper links on a webpage, I use this code but it dont work 100%
public void parseLinks(){
String A = "([Hh][Rr][Ee][Ff]\\s*=\\s*\")";
String B = "(?!#|[Hh]ttp|[Mm]ailto|.cgi|.css)";
String C = "(.*)";
String D = "(\\s*\")";
String exp = A+B+C+D;
Pattern p = Pattern.compile(exp);
Matcher m = p.matcher(s);
while(m.find()){
System.out.println(m.group());
where s is the string that being parsed (html dokument). It works kind of on regular links e.g:
<a name="qwerty" href="qwerty.html"> gives output href="qwerty.html"
but I want it to give the output qwerty.html . How can I do this? It doesn't works on links like:
<a name="qwerty" href="qwerty.html" class="link"> gives the output href="/aktuell/index.html" class="link".
How can I just get the path?

If I got s = "<a name = \"asd\" href=\"asd.html\"" or s = " it works with group 3.
But it dont work with s = "<b>Open positions</b>" ,
gives output:
/openpos/index.html" class="link
Any suggestion ?, it seems that i fails if there is more then one " before the >
exempel code...
public void parseLinks(){
String s = "<a name = \"asd\" href=\"asd.html\"";
/*String s = "<a href=\"/openpos/index.html\" class=\"link\"><b>Open positions</b></a>";*/
String A = "([Hh][Rr][Ee][Ff]\\s*=\\s*\")";
String B = "(?!#|[Hh]ttp|[Mm]ailto|[Ll]ocation.|[Jj]avascript|.cgi|.css)";
String C = "(.*)";
String D = "(\\s*\")";
String exp = A+B+C+D;
Pattern p = Pattern.compile(exp);
Matcher m = p.matcher(s);
while(m.find()){
System.out.println(m.group(3));
}

DOM Parser fails with regular expression using anchor (carat, dollar)

I'm using version "Oracle XDK Java 9.0.4.0.0 Production"
In trying to parse XML against schema: a regular expression fails to parse the data "8:00" with the following simple regular expression: "^.*$" (used to narrow the error)
The error message is
<Line 14, Column 25>: XSD-2025: (Error) Invalid text '8:00' in element: 'XYZ'
If I remove the anchors and just have ".*", the data is parsed successfully.
I dont understand why the parse fails when I use a anchors in the regular expression, and the java Pattern/Matcher classes succeed with the anchors?

That "ns670" string is an xml namespace prefix. it should have a corresponding xml namespace declaration somewhere in the xml document (i'm guessing you have not shown the whole document). the actual value of an xml namespace prefix is meaningless. if you parse the xml with a namespace aware DOM parser, it should generate Nodes with the correct namespace. the namespace is the value you care about when extracting data from the document, not the namespace prefix.
alternately, if you parse the document using a namespace aware DOM parser, you can just look for nodes based on their "local" name (the part after the ":" separator) and ignore the namespace/prefix.
whatever you do, please do not parse the xml with a regex, see this http://stackoverflow.com/a/1732454/552759 for details (applies to xml as well).

Grouping & Back-references with regular expressions on Replace Text window

I really appreciate the inclusion of the Regular Expressions in the search & replace feature. One thing I am missing is back-references in the replacement expression. For instance, in the unix tools vi or sed, I might do something like this:
s/$firstPart$ $secondPart$ $oldThirdPart$/\2 \1 newThirdPart/g
which would allow me to switch the places of firstPart and secondPart, and totally replace thirdPart. If grouping and back-references are already present in the Replace Text window, how does one correctly invoke them?

duplicate of Grouping & Back-references with regular expressions on Replace Text window

Assistance with Regular Expression and Tcl

Assistance with Regular Expression and Tcl
Hello Everyone,
I recently began learning Tcl to develop scripts for automating network switch deployments.
In my script, I want to name the device with a location and the last three octets of the base mac address.
I can get the Base MAC address by :
show version | include Base
Base ethernet MAC Address       : 00:00:00:DB:CE:00
And I can get the last three octets of the MAC address using the following regular expression.
([0-9a-f]{2}[:-]){2}([0-9a-f]{2}$)
But I have not been able to figure out how to call the regular expression in the tcl script.
I have checked several resources but have not been able to figure it out. Suggestions?
Ultimately, I want to set the last three octets to a variable (something like below) and then call the variable when I name the switch.
set mac [exec "sh version | i Base"] (include the regular expression)
ios_config "hostname location$mac"
Thanks for any assistance in advance.
Chris

This worked for me.
Switch_1(tcl)#set result [exec show ver | inc Base]
Base ethernet MAC Address       : 00:1B:D4:F8:B1:80
Switch_1(tcl)#regexp {([0-9A-F:]{8}\r)} $result -> mac
1
Switch_1(tcl)#puts $mac
F8:B1:80
Switch_1(tcl)#ios_config "hostname location$mac"
%Warning! Hostname should contain at least one alphabet or '-' or '_' character
locationF8:B1:80(tcl)#

How to search with regular expression

I make pdx files so that I can search text quickly. But Acrobat doesn't provide a way to search with regular expression. I'm wondering if there is a way that I don't know to search for regular expression in Acrobat Pro 9?

First, Acrobat must "mount" the PDX.
As "Find" does not use the cataloged index, use Shift+Ctrl+F to open the advanced search dialog.
It may be helpful to first enter Acrobat Preferences and for the Search category tick "Always use advanced search options".
Back to the Search dialog - use the drop down menu for "Look In" to pick "Select Index" then, if no PDXs show, click the Add button.
In the Open Index File dialog, browse to the location of the desired PDX and select it.
OK out and use "Return results containing" to pick a "Match ..." requirement or Boolean.
To become familiar with query syntax, for Acrobat, it is good to review Acrobat Help.
http://help.adobe.com/en_US/Acrobat/9.0/Professional/WS58a04a822e3e50102bd615109794195ff-7 c4b.w.html
Be well...

Problem with Regular Expression

Hi There!!
I have a problem with regular expression. I want to validate that one word and second word are same. For that I have written a regex
Pattern p=Pattern.compile("([a-z][a-zA-Z]*)\\s\1");
Matcher m=p.matcher("nikhil nikhil");
boolean t=m.matches();
if (t)
          System.out.println("There is a match");
     else
          System.out.println("There is no match");
The result I am getting is always "There is no match
Your timely help will be much appreciated.
Regards

Ram wrote:
ErasP wrote:
You are missing a backward slash in the regex
Pattern p = Pattern.compile("([a-z][a-zA-Z]*)\\s\\1");
But this will fail in this case.
Matcher m = p.matcher("Nikhil Nikhil");It is the reason for that *[a-z]*.The OP had [a-z][a-zA-Z]* in his code, so presumably he know what that means and wants that String not to match.

Get the string between li tags, with regular expression

I have a unordered list, and I want to store all the strings between the li tags (<li>.?</li>)in an array:
<ul>
<li>This is String One</li>
<li>This is String Two</li>
<li>This is String Three</li>
</ul>
This is what have so far:
<li>(.*?)</li>
but it is not correct, I only want the string without the li tags.
Thanks.

No one?
Anoyone here experienced with Regular Expression?

Parsing with regular expressions

Hi
I'm developing an application that is trying to parse a text in a text file. It's looking for strings like
" 0551 TIMERHIN, S.L. "
Then I think I could lok with matches method for a string with many white chars followed by 4 numbers...
I did
line.matches("^\\s+[0-9]{4}")
but it didn't work...
Any help will be appreciated.
<jl>

The String.matches tries to match the regular express against the whole string.
You regex pattern "^\\s+[0-9]{4}" will match
"                          0551"but not
"                          0551 TIMERHIN, S.L. "You can do it using this code:
import java.sql.*;
import java.io.*;
import java.util.regex.*;
import java.util.*;
public class RegExTest {
public static void main (String args[]) {
   Pattern pat = null;
   Matcher m = null;
   String patternToMatch = "^\\s+[0-9]{4}";
   pat = Pattern.compile(patternToMatch);
   System.out.println("Pattern to match = " + patternToMatch);
   String line = "                          0551 TIMERHIN, S.L. ";
   m = pat.matcher(line);
   if (m.find()) { System.out.println("Line matched"); }
} // end main
} //End Class Test

Help with Regular Expression for field validation

I'm fairly new to using regular expressions and using Acrobat. This is probably a simple question, but I've been unable to figure it out.
I have a text field on a PDF that I would like to be 9 characters in length. The first 2 characters can only be alphanumeric, the last 7 characters can only be numeric.
At first I was using the following, which allows all the characters to be alphanumeric:
var re = /^[A-Za-z0-9 :\\_]$/;
if (event.change.length >0) {
if (event.willCommit == false) {
    if (!re.test(event.change)) {
        event.rc = false
That works fine, but it's not quite what I needed. With some assistance I changed it (see below) to fit what I was looking for. However, this didn't work; it prevents anything from being entered in the field:
var re = /^[A-Za-z0-9]{2}\d{7}$/;
if (event.change.length >0) {
if (event.willCommit == false) {
    if (!re.test(event.change)) {
        event.rc = false
Any help would be greatly appreciated.
Thanks...

Here's a function you can call form the field's custom Format script. It should be placed in a document-level JavaScript:
function custom_ks1() {
    // Define non-commited regular expression
    var re = /^[A-Za-z0-9]{0,2}([0-9]{0,7})?$/;
    // Get all of the characters the user has entered
    var value = AFMergeChange(event);
    // Allow field to be cleared
    if(!value) return;
    if (event.willCommit) {
        // Define commited regular expression
        var re = /^[A-Za-z0-9]{2}[0-9]{7}$/;
        if (!re.test(value)) { // If final value doesn't match, alert user
            app.alert("Your error message goes here.");
            // event.rc = false
    } else { // not commited
        // Only allow characters that match the regular expression
        event.rc = re.test(value);
Call it like this:
// Custom Keystroke script
custom1_ks();

input with regular expression

I am wondering how to use the _regex in a hidden
<input>. i have searched every where but there is no examples
on how to use this cfml form validation. Its not that i want
alternatives to do the regular expression just how to use it like
this......
if i had the form....
<form.........>
<input name="email">
<input type="hidden" name="email_regex"
value="*/.............">
</form>
How can i have a message if the input email does not coincide
with the regular expression. would i need to use a second
<input type="hidden" name="email_regex_Required"
value="please insert a valid email adress>

i am trying to get it to work like this. The validation type
is valid but i have not found anything on how to use it properly.
it like using the
<input type="hidden" name="email_required" value="the
field is blank, please go back and enter a filed">
I know javascript is the best option but if the browser does
not support this then at least in can attempt a alternative method.
All i would like to know is how do i use this validation type and
how can i get it also to produse a error message. as the "value"
field will contain the regular expresion itself.

CFFORM (Flash) Validation with Regular Expressions Not Working

I am having troubles getting regular expression validation to
work in a CFFORM. The below code is an extract of a much larger
form, the first name and last name have a regular expression
validation...and it doesn't work!
I'd appreciate any comments/info for help on this, have
searched high and low on information to get this working...but no
joy.
The code is:
<cffunction name="checkFieldSet" output="false"
returnType="string">
<cfargument name="fields" type="string" required="true"
hint="Fields to search">
<cfargument name="form" type="string" required="true"
hint="Name of the form">
<cfargument name="ascode" type="string" required="true"
hint="Code to fire if all is good.">
<cfset var vcode = "">
<cfset var f = "">
<cfsavecontent variable="vcode">
var ok = true;
var msg = "";
<cfloop index="f" list="#arguments.fields#">
<cfoutput>
if(!mx.validators.Validator.isValid(this,
'#arguments.form#.#f#')) { msg = msg + #f#.errorString + '\n';
ok=false; }
</cfoutput>
</cfloop>
</cfsavecontent>
<cfset vcode = vcode & "if(!ok)
mx.controls.Alert.show(msg,'Validation Error'); ">
<cfset vcode = vcode & "if(ok) #ascode#">
<cfset vcode =
replaceList(vcode,"#chr(10)#,#chr(13)#,#chr(9)#",",,")>
<cfreturn vcode>
</cffunction>
<cfform name="new_form" format="flash" width="600"
height="600" skin="halosilver" action="new_data.cfc">
<cfformgroup type="panel" label="New Form"
style="background-color:##CCCCCC;">
<cfformgroup type="tabnavigator" id="tabs">
<cfformgroup type="page" label="Step 1">
<cfformgroup type="hbox">
<cfformgroup type="panel" label="Requestor Information"
style="headerHeight: 13;">
<cfformgroup type="vbox">
<cfinput type="text" name="reqName" width="300"
label="First Name:" validate="regular_expression" pattern="[^0-9]"
validateat="onblur" required="yes" message="You must supply your
First Name.">
<cfinput type="text" name="reqLname" width="300"
label="Last Name:" validate="regular_expression" pattern="[^0-9]"
validateat="onblur" required="yes" message="You must supply your
Last Name.">
<cfinput type="text" name="reqEmail" width="300"
label="Email:" validate="email" required="yes" message="You must
supply your email or the address given is in the wrong format.">
<cfinput type="text" name="reqPhone" width="300"
label="Phone Extension:" validate="integer" required="yes"
maxlength="4" message="You must supply your phone number.">
</cfformgroup>
</cfformgroup>
</cfformgroup>
<cfformgroup type="horizontal"
style="horizontalAlign:'right';">
<cfinput type="button" width="100" name="cnt_step2"
label="next" value="Next"
onClick="#checkFieldSet("reqName,reqLname,reqEmail,reqPhone","new_form","tabs.selectedInd ex=tabs.selectedIndex+1")#"
align="right">
</cfformgroup>
</cfformgroup>
</cfformgroup>
</cfformgroup>
</cfform>

quote:
Originally posted by:
Luckbox72
The problem is not the Regex. I have tested 3 or 4 different
versions that all work on the many different test sites. The
problem is it that the validation does not seem to work. I have
changed the patter to only allow NA and I can still type anything
into the text box. Is there some issue with useing Regex as your
validation?
Bear in mind that by default validation does not occur until
the user attempts to submit the form. If you are trying to control
the characters that the user can enter into the textbox, as opposed
to validating what they have entered, you will need to provide your
own javascript validation.

Replace All with Regular Expression

Hi all,
I need a help to replace the String:
to
"<a href=\"1\"">Java Programming</a>"
I was trying to replace with
.replaceAll("\\[\\[*([^\\]]*?)*\\]\\]", "<a href=\"\"></a>")
but I don't know how to separate the parameters values.
Best regards

Hi prometheuzz,
you are the one!!
But how I could do to a Srting like this:
Ah, more requirements...
Things are getting a bit messy now:
import java.util.regex.Matcher;
import java.util.regex.Pattern;
class Main {
    public static void main(String[] args) {
        String line = "any text any text any text any text any text. "+
                      "Click - [[Code: 6 Title: Java Programming]]. "+
                      "any text any text any text any text any text. "+
                      "- [[C�digo: 2 T�tulo: Sun]] text text "+
                      "any text any text any text any text any text.";
        String newLine = line;
        String[] wikiTags = getWikiTags(newLine);
        for(String tag : wikiTags) {
            String newTag = "<a href=\""+get("(Code:|C�digo:)", " ", tag)+
                            "\">"+get("(Title:|T�tulo:)", "$", tag)+"</a>";
            newLine = newLine.replaceFirst("\\[\\["+tag+"\\]\\]", newTag);
        System.out.println(line);
        System.out.println(newLine);
    public static String[] getWikiTags(String text) {
        java.util.List<String> list = new java.util.ArrayList<String>();
        Pattern pattern = Pattern.compile("(?<=\\[\\[)(.*?)(?=\\]\\])");
        Matcher matcher = pattern.matcher(text);
        while(matcher.find()) {
            list.add(matcher.group());
        return list.toArray(new String[list.size()]);
    public static String get(String start, String end, String text) {
        Pattern pattern = Pattern.compile("(?<="+start+"\\s)(.*?)(?="+end+")");
        Matcher matcher = pattern.matcher(text);
        return matcher.find() ? matcher.group() : "#ERROR#";
}Details about regex:
http://java.sun.com/j2se/1.4.2/docs/api/java/util/regex/Pattern.html
http://www.regular-expressions.info/java.html
http://java.sun.com/docs/books/tutorial/essential/regex/
>
Thanks a lot for you helpLike I said, it's a bit of a messy solution. See if you can use (a part of) it.
Good luck.

Need help with regular expression

I'm trying to use the java.util.regex package to extract URLs from html files.
The URLs that I am interested in extracting from the HTML look like the following:
<font color="#008000">http://forum.java.sun.com -
So, the URL is always preceeded by:
<font color="#008000">
and then followed by a space character and then a hyphen character. I want to be able to put all these URLs in a Vector object. This doesn't seem like it should be too difficult but for some reason I can't get anywhere with it. Any help would be greatly appreciated. Thanks!

hi gupta am not sure of the java syntax but i can tell u about the regular expression...try this....
<font color="#008000">(http:\/\/[a-zA-Z0-9.]+) [-]
i dont know the java methods to call...just the reg exp...
Sanjay Acharya

Help with regular expression needed

Hi,
Perhaps someone here can help me with my regular expression I'm trying to build in my Java code.
The regular expression that I'm looking to build consists of any non-whitespace character up until it finds one or two <>= symbols and then any character thereafter. So both these Strings would match the expression:
City 1==London
Age>=18
The regular expression that I'm using is as follows:
(\\S+)([><=]){1,2}(.+)However, group 1 always retrieves the first <>= symbol as in "City 1=". How can I make the <>= part greedy so that it retrieves both operator symbols?
Thanks.

Make the first group, the non-spaces, reluctant:
"(\\S+?)([<>=]{1,2})(.+)"

Parser error: XSD 2015 with regular expression

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