Parsing out numbers
Trying to parse out the number strings into its own columns with this expression:
WITH T as
(SELECT '53-2010-2-101' test_string FROM DUAL union all
SELECT '2219-2010-3-22' FROM DUAL union all
SELECT '236350-2010-4-3' FROM DUAL)
SELECT SUBSTR(test_string,INSTR(test_string,'-')-2) stu_id, --This is incorrect
SUBSTR(test_string,INSTR(test_string,'-',1,1)+1,4) fiscal_yr,
SUBSTR(test_string,INSTR(test_string,'-',1,2)+1,1) sess,
SUBSTR(test_string,INSTR(test_string,'-',1,3)+1,5) sch_id
FROM THaving problems with stu_id. How to count backwards with substr and instr? The results should look like so:
STU_ID FISCAL_YR SESS SCH_ID
53 2010 2 101
2219 2010 3 22
236350 2010 4 3Thanks
Would it be something like this?
WITH T as
(SELECT '53-2010-2-101' test_string FROM DUAL union all
SELECT '2219-2010-3-22' FROM DUAL union all
SELECT '236350-2010-4-3' FROM DUAL)
-- end of sample data
SELECT substr(test_string, 1, instr(test_string, '-') - 1) stu_id,
substr(test_string, instr(test_string, '-', 1, 1) + 1, 4) fiscal_yr,
substr(test_string,
instr(test_string, '-', 1, 2) + 1,
instr(test_string, '-', 1, 3) - instr(test_string, '-', 1, 2) - 1) sess,
substr(test_string, instr(test_string, '-', 1, 3) + 1, 5) sch_id
FROM tSample execution:
SQL> WITH T as
2 (SELECT '53-2010-2-101' test_string FROM DUAL union all
3 SELECT '2219-2010-3-22' FROM DUAL union all
4 SELECT '236350-2010-4-3' FROM DUAL)
5 -- end of sample data
6 SELECT substr(test_string, 1, instr(test_string, '-') - 1) stu_id,
7 substr(test_string, instr(test_string, '-', 1, 1) + 1, 4) fiscal_yr,
8 substr(test_string,
9 instr(test_string, '-', 1, 2) + 1,
10 instr(test_string, '-', 1, 3) - instr(test_string, '-', 1, 2) - 1) sess,
11 substr(test_string, instr(test_string, '-', 1, 3) + 1, 5) sch_id
12 FROM t;
STU_ID FISCAL_YR SESS SCH_ID
53 2010 2 101
2219 2010 3 22
236350 2010 4 3
SQL> With regular expressions would look something like this:
WITH T as
(SELECT '53-2010-2-101' test_string FROM DUAL union all
SELECT '2219-2010-3-22' FROM DUAL union all
SELECT '236350-2010-4-3' FROM DUAL)
SELECT regexp_substr(test_string, '\d+', 1, 1) stu_id,
regexp_substr(test_string, '\d+', 1, 2) fiscal_yr,
regexp_substr(test_string, '\d+', 1, 3) sess,
regexp_substr(test_string, '\d+', 1, 4) sch_id
FROM t;Edited by: fsitja on Jan 28, 2010 6:07 PM
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