Passing record type into function [error: identifier must be declared]

Question

Hi,
I have a record type defined in my procedure
type chk_tab is record(
effect date,
count number(9)
type chk_typ is table of chk_tab index by binary integer;
chk_typ_rec chk_typ;
I have to pass the effect and count into another function, i tried doin as below:
function name: func_chk_typ
func_chk_typ(effect, count);
this returns an saying "identifier effect needs to be declared"
I am required to pass these values from the record type into the function, How can i over come this??
Any help is very much appreciated.

Answer 1

Hi Hemz,
Find below code.
Function Code:
CREATE OR REPLACE FUNCTION fetch_band(eff in date,ineff in date)
return number
is
  lu_cb_sysid  NUMBER;
BEGIN
select fk_cb_sysid
into lu_cb_sysid
from ia_for_icon
where cr_ans_date >= eff
and cr_ans_date < ineff;
RETURN lu_cb_sysid;
END fetch_band;Procedure code. Here I have embedded the function.
CREATE OR REPLACE procedure abc(a varchar, b number) is
  type cns_tab_record is record(
    eff   date,
    ineff date);
  type cns_tab_typ is table of cns_tab_record index by binary_integer;
  cns_tab cns_tab_typ;
  v_lu_cb_sysid NUMBER;
BEGIN 
  -- Here you have to assign the values to your table type record.
  -- For example I am passing two values SYSDATE and SYSDATE - 10
  cns_tab(1).eff := SYSDATE;
  cns_tab(1).ineff := SYSDATE - 10;
  v_lu_cb_sysid:= fetch_band(cns_tab(1).eff, cns_tab(1).ineff);
END abc;But I am just wondering why you are using table type datatype here.
Hope above code will help you.
Thanks,
Suri